I want to scrape the products that are listed in this webpage. So I tried to extract all of the data-tcproduct attributes from the div.product-tile. It contains numerous things including the url of the products I need to visit.
So I did:
def parse_brand(self, response):
for d in set(response.css('div.product-tile::attr(data-tcproduct)').extract()):
d = json.loads(d)
yield scrapy.Request(url=d['product_url_page'].replace("p","P"), callback=self.parse_item)
Yet, I noticed that some attributes from the div.product-tile seems to be hidden in the page and I am not interested by them. Those I want to scrape are rather on product-listing-title.
So how can I filter part of the HTML page when scraping results with Scrapy?
I don't think that you need product-listing-title. You need items from search-result-content div instead:
for d in response.css('div.search-result-content div.product-tile::attr(data-tcproduct)').extract():
d = json.loads(d)
yield scrapy.Request(url=d['product_url_page'].replace("p","P"), callback=self.parse_item)
Related
I'm trying to scrape text from a website, but specifically only the text that's linked to with one of two specific links, and then additionally scrape another text string that follows shortly after it.
The second text string is easy to scrape because it includes a unique class I can target, so I've already gotten that working, but I haven't been able to successfully scrape the first text (with the one of two specific links).
I found this SO question ( Find specific link w/ beautifulsoup ) and tried to implement variations of that, but wasn't able to get it to work.
Here's a snippet of the HTML code I'm trying to scrape. This patter recurs repeatedly over the course of each page I'm scraping:
<em>[女孩]</em> 寻找2003年出生2004年失踪贵州省黔西南布依族苗族自治州贞丰县珉谷镇锅底冲 黄冬冬289179
The two parts I'm trying to scrape and then store together in a list are the two Chinese-language text strings.
The first of these, 女孩, which means female, is the one I haven't been able to scrape successfully.
This is always preceded by one of these two links:
forum.php?mod=forumdisplay&fid=191&filter=typeid&typeid=19 (Female)
forum.php?mod=forumdisplay&fid=191&filter=typeid&typeid=15 (Male)
I've tested a whole bunch of different things, including things like:
gender_containers = soup.find_all('a', href = 'forum.php?mod=forumdisplay&fid=191&filter=typeid&typeid=19')
print(gender_containers.get_text())
But for everything I've tried, I keep getting errors like:
ResultSet object has no attribute 'get_text'. You're probably treating a list of items like a single item. Did you call find_all() when you meant to call find()?
I think that I'm not successfully finding those links to grab the text, but my rudimentary Python skills thus far have failed me in figuring out how to make it happen.
What I want to have happen ultimately is to scrape each page such that the two strings in this code (女孩 and 寻找2003年出生2004年失踪贵州省...)
<em>[女孩]</em> 寻找2003年出生2004年失踪贵州省黔西南布依族苗族自治州贞丰县珉谷镇锅底冲 黄冬冬289179
...are scraped as two separate variables so that I can store them as two items in a list and then iterate down to the next instance of this code, scrape those two text snippets and store them as another list, etc. I'm building a list of list in which I want each row/nested list to contain two strings: the gender (女孩 or 男孩）and then the longer string, which has a lot more variation.
(But currently I have working code that scrapes and stores that, I just haven't been able to get the gender part to work.)
Sounds like you could use attribute = value css selector with $ ends with operator
If there can only be one occurrence per page
soup.select_one("[href$='typeid=19'], [href$='typeid=15']").text
This is assuming those typeid=19 or typeid=15 only occur at the end of the strings of interest. The "," between the two in the selector is to allow for matching on either.
You could additionally handle possibility of not being present as follows:
from bs4 import BeautifulSoup
html ='''<em>[女孩]</em> 寻找2003年出生2004年失踪贵州省黔西南布依族苗族自治州贞丰县珉谷镇锅底冲 黄冬冬289179'''
soup=BeautifulSoup(html,'html.parser')
gender = soup.select_one("[href$='typeid=19'], [href$='typeid=15']").text if soup.select_one("[href$='typeid=19'], [href$='typeid=15']") is not None else 'Not found'
print(gender)
Multiple values:
genders = [item.text for item in soup.select_one("[href$='typeid=19'], [href$='typeid=15']")]
Try the following code.
from bs4 import BeautifulSoup
data='''<em>[女孩]</em> 寻找2003年出生2004年失踪贵州省黔西南布依族苗族自治州贞丰县珉谷镇锅底冲 黄冬冬289179'''
soup=BeautifulSoup(data,'html.parser')
print(soup.select_one('em').text)
OutPut:
[女孩]
So I am wanting to scrape some NBA data. The following is what I have so far, and it is perfectly functional:
install.packages('rvest')
library(rvest)
url = "https://www.basketball-reference.com/boxscores/201710180BOS.html"
webpage = read_html(url)
table = html_nodes(webpage, 'table')
data = html_table(table)
away = data[[1]]
home = data[[3]]
colnames(away) = away[1,] #set appropriate column names
colnames(home) = home[1,]
away = away[away$MP != "MP",] #remove rows that are just column names
home = home[home$MP != "MP",]
the problem is that these tables don't include the team names, which is important. To get this information, I was thinking I would scrape the four factors table on the webpage, however, rvest doesnt seem to be recognizing this as a table. The div that contains the four factors table is:
<div class="overthrow table_container" id="div_four_factors">
And the table is:
<table class="suppress_all sortable stats_table now_sortable" id="four_factors" data-cols-to-freeze="1"><thead><tr class="over_header thead">
This made me think that I could access the table via something along the lines of
table = html_nodes(webpage,'#div_four_factors')
but this doesnt seem to work as I am getting just an empty list. How can I access the four factors table?
I am by no means an HTML expert but it appears that the table you are interested in is commented out in the source code then the comment is overridden at some point before being rendered.
If we assume that the Home team is always listed second, we can just use positional arguments and scrape another table on the page:
table = html_nodes(webpage,'#bottom_nav_container')
teams <- html_text(table[1]) %>%
stringr::str_split("Schedule\n")
away$team <- trimws(teams[[1]][1])
home$team <- trimws(teams[[1]][2])
Obviously not the cleanest solution but such is life in the world of web scraping
I have looked at some of the XPath threads on here and read 2 XPath guides but I am having trouble writing a working code to scrape a webpage that is full of restaurants, phone numbers, addresses with scrapy.
A picture of the source code of the site and the highlighted data I want.
def parse(self, response):
hxs = HtmlXPathSelector(response)
titles = hxs.select("//b")
items = []
for titles in titles:
item = kosherscrapeitem
item ["BusinessName"] = titles.select('//td[#class="line-content"]//html/body/table/tbody/tr[()').extract()
This is the data from copying the xpath on chrome:
/html/body/table/tbody/tr[485]/td[2]/text()
Can someone help me with my Xpath expression?
there's a webpage with many pages. And I'd like to know the total pages for each search.
Like the pictures shown below. Since the last page is page 41 and it becomes un_clickable. So I want to extract that value 41 from those 2 span tags.
Any help?
I tried with xpath. But would prefer a CSS solution
Thanks
page_temp = Nokogiri::HTML(browser.html)
page_temp.xpath('tr[#td = "colspan="32""]').each do |node|
puts node.text
Click here to view the snapshot
Since you are using Ruby here's a simple code you can use
page_temp = Nokogiri::HTML(browser.html)
all_pages = page_temp.search("td[colspan='32'] tr td")
puts all_pages.map{|p| p.text} # list all page numbers
puts all_pages.last.text # list the last page number
I have the following mini basic spider I use to get all links from a website.
from scrapy.item import Field, Item
from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors import LinkExtractor
class SampleItem(Item):
link = Field()
class SampleSpider(CrawlSpider):
name = "sample_spider"
allowed_domains = ["example.com"]
start_urls = ["http://www.example.com/"]
rules = (
Rule(LinkExtractor(), callback='parse_page', follow=True),
)
def parse_page(self, response):
item = SampleItem()
item['link'] = response.url
return item
I was wondering wether it would be possible to add to have this same spider scraping some html (like the one below)from these same links and to list link and info in a csv in two separate columns?
<span class="price">50,00 €</span>
marko
Yes, that's possible of course. First of all you need to use a feed export. This can be set in the settings.py with the options:
FEED_FORMAT = 'csv'
FEED_URL = 'file:///absolute/path/to/the/output.csv'
Then you will have to adjust your items to allow more elements. Currently, you only use the link. You will want to add a price field.
class SampleItem(Item):
link = Field()
price = Field()
One sidenote: Usually we define items in the items.py file, because generally multiple spiders should scrape the same type of item from several pages. You would then import them into your spider using from scrapername.items import SampleItem. An example application for this would be a price scraper which scrapes both Amazon and some smaller shops.
Finally, you will have to adjust the parse_page method of your spider. Currently you only save the URL into your item. You want to find the price and also save it. Finding numbers or texts on a page is a key element of scraping. For this purpose we have selectors. Scapy supports XPath, CSS and regular expression selectors. The first two are especially useful, because they can be nested. Regular expressions would generally be used when you found the correct HTML element, but there is too much information within one element.
A problem you might encounter is that a page might have multiple .price elements. Have you made sure there only is one? Otherwise the selector will give you all of them and you might have to refine your selector using more other tags.
So, let's assume there is only this one .price element and construct our selector. We use CSS selector here, because it's more intuitive in this case. You can call the selectors directly on the response using css and xpath methods. Both of them always return elements on which you might use css() and xpath() again. To get the textual representation you need to call extract() on them. This might be annoying at the beginning, but nesting selectors is very convenient. Note that the selectors give you the full HTML element including the tag. To only get the text content, you need to make this explicit. For CSS selectors via ::text, for XPath via /text().
def parse_page(self, response):
item = SampleItem()
item['link'] = response.url
try:
item['price'] = response.css('.price::text')[0].extract()
except IndexError:
# do whatever is best if price cannot be found
item['price'] = None
return item