i am trying to do assertion on a json. basically i have to compare two json:
cy.get('h4#idParameters').each(($e, index, $list) => {
const text = $e.text()
expect(text).to.eq(parameters)
})
but I get the following error:
in the assertion if I use "contain" instead of "eq" the result doesn't change
There exist a space after ":" char in the first parameter. These strings are not equal.
If you want to compare this as a string, ensure it does not have extra spaces, points, or is in a different order.
But the better approach is to compare as JSON. One interesting approach should be using the deep-equal-in-any-order plugin. This plugin compares objects independent of it order. But first ensure to transform JSON strings to objects.
in the end I solved it like this. Thanks for the advice #Erme.
cy.get('h4#idParameters').each(($e, index, $list) => {
const text = $e.text()
var p1 = JSON.stringify(text)
var p2 = JSON.stringify(parameters)
p1=p1.replace(/\s/g, '');
p2=p2.replace(/\s/g, '');
p2 = p2.substr(1,p2.length)
expect(p1).to.contain(p2)
})
Related
i have extracted the fix message as below from Unix server and now need to convert this message into JSON. how can we do this?
8=FIXT.1.1|9=449|11=ABCD1|35=AE|34=1734|49=REPOFIXUAT|52=20140402-11:38:34|56=TR_UAT_VENDOR|1128=8|15=GBP|31=1.7666|32=50000000.00|55=GBP/USD|60=20140402-11:07:33|63=B|64=20140415|65=OR|75=20140402|150=F|167=FOR|194=1.7654|195=0.0012|460=4|571=7852455|1003=2 USD|1056=88330000.00|1057=N|552=1|54=2|37=20140402-12:36:48|11=NOREF|453=4|448=ZERO|447=D|452=3|448=MBY2|447=D|452=1|448=LMEB|447=D|452=16|448=DOR|447=D|452=11|826=0|78=1|79=default|80=50000000.00|5967=88330000.00|10=111
Note: I tried to make this a comment on the answer provided by #selbie, but the text was too long for a comment, so I am making it an answer.
#selbie's answer will work most of the time, but there are two edge cases in which it could fail.
First, in a tag=value field where the value is of type STRING, it is legal for value to contain the = character. To correctly cope with this possibility, the Java statement:
pair = item.split("=");
should be changed to:
pair = item.split("=", 2);
The second edge case is when there are a pair of fields, the first of which is of type LENGTH and the second is of type DATA. In this case, the value of the LENGTH fields specifies the length of the DATA field (without the delimiter), and it is legal for the value of the DATA field to contain the delimiter character (ASCII character 1, but denoted as | in both the question and Selbie's answer). Selbie's code cannot be modified in a trivial manner to deal with this edge case. Instead, you will need a more complex algorithm that consults a FIX data dictionary to determine the type of each field.
Since you didn't tag your question for any particular programming language, I'll give you a few sample solutions:
In javascript:
let s = "8=FIXT.1.1|9=449|11=ABCD1|35=AE|34=1734|49=REPOFIXUAT|52=20140402-11:38:34|56=TR_UAT_VENDOR|1128=8|15=GBP|31=1.7666|32=50000000.00|55=GBP/USD|60=20140402-11:07:33|63=B|64=20140415|65=OR|75=20140402|150=F|167=FOR|194=1.7654|195=0.0012|460=4|571=7852455|1003=2 USD|1056=88330000.00|1057=N|552=1|54=2|37=20140402-12:36:48|11=NOREF|453=4|448=ZERO|447=D|452=3|448=MBY2|447=D|452=1|448=LMEB|447=D|452=16|448=DOR|447=D|452=11|826=0|78=1|79=default|80=50000000.00|5967=88330000.00|10=111"
let obj = {};
items = s.split("|")
items.forEach(item=>{
let pair = item.split("=");
obj[pair[0]] = pair[1];
});
let jsonString = JSON.stringify(obj);
Python:
import json
s = "8=FIXT.1.1|9=449|11=ABCD1|35=AE|34=1734|49=REPOFIXUAT|52=20140402-11:38:34|56=TR_UAT_VENDOR|1128=8|15=GBP|31=1.7666|32=50000000.00|55=GBP/USD|60=20140402-11:07:33|63=B|64=20140415|65=OR|75=20140402|150=F|167=FOR|194=1.7654|195=0.0012|460=4|571=7852455|1003=2 USD|1056=88330000.00|1057=N|552=1|54=2|37=20140402-12:36:48|11=NOREF|453=4|448=ZERO|447=D|452=3|448=MBY2|447=D|452=1|448=LMEB|447=D|452=16|448=DOR|447=D|452=11|826=0|78=1|79=default|80=50000000.00|5967=88330000.00|10=111"
obj = {}
for item in s.split("|"):
pair = item.split("=")
obj[pair[0]] = pair[1]
jsonString = json.dumps(obj)
Porting the above solutions to other languages is an exercise for yourself. There's comments below about semantic ordering and handling cases where the the = or | chars are part of the content. That's on you to explore if you need to support those scenarios.
I am working on a discord bot written in nodejs, the bot utilises a mysql database server to store information. The problem I have run into is that I cannot seem to retrieve the data from the database in a neat way, every single thing I try seems to run into some issue or another.
The select query returns an object called RowDataPacket. When googling every single result will reference this solution: Object.values(JSON.parse(JSON.stringify(rows)))
It postulates that I should get the values back, but I dont I get an array back that is as hard to work with as the rowdatapacket object.
This is a snippet of my code:
const kenneledMemberRolesTableName = 'kenneled_member_roles'
const kenneledMemberKey = 'kenneled_member'
const kenneledMemberRoleKey = 'kenneled_member_role_id'
const kenneledStaffMemberKey = 'kenneled_staff_member'
const kenneledDateKey = 'kenneled_date'
const kenneledReturnableRoleKey = 'kenneled_role_can_be_returned'
async function findKenneledMemberRoles(kenneledMemberId) {
let sql = `SELECT CAST(${kenneledMemberRoleKey} AS Char) FROM ${kenneledMemberRolesTableName} WHERE ${kenneledMemberKey} = ${kenneledMemberId}`
let rows = await databaseAccessor.runQuery(sql)
let result = JSON.parse(JSON.stringify(rows)).map(row => {
return row.kenneled_member_role_id
})
return result
}
This seemed to work, until I had to do a type conversion on the value, now the dot notations requires me to reference row.CAST(kenneled_member_role_id AS Char), this cannot work, and I have found no other way to retrieve the data than through dot notation. I swear there must be a better way to work with mysql rowdatapackets but the solution eludes me
I figured out something that works, however I still feel like this is an inelegant solution, I would love to hear from others if I am misunderstanding how to work with mysql code in nodejs, or if this is just a consequence of the library:
let result = JSON.parse(JSON.stringify(rows)).map(row => {
return row[`CAST(${kenneledMemberRoleKey} AS CHAR)`];
})
So what I did is I access the value through brackets instead of dot notation, this seems to work, and at least makes me able to store part of or the whole expression in a constant variable, hiding the ugliness.
How to convert a msg.payload like 12345,67890 into "12345","67890" ?
Basically I receive a payload with many values and need to pass them to a mysql node.
Thanks in advance.
Sep
Depending on the exact type of input there are a couple options
First the core CSV node will split a payload into either an array or an object (if the first line of multiple lines contains the column names).
Second if you just have a single input then you can break it up with a function node using the normal NodeJS/Javascript functions for working with Strings. e.g.
var chunks = msg.payload.split(',');
msg.payload = {};
msg.paylaod.first = chunks[0];
msg.payload.second = chunk[1];
return msg;
is there anyway to make a query in MongoDB using a JSON and returning a object if one field of the json matches with some in the database?
for example, I have the this object called keysArray
{ house: 'true', garden: 'false' }
and I would like to make a query in Mongo passing this object as a query field and return if some object in my database matches with at least one of those fields :
keysArray.forEach(function(key){
collection.find({keysArray}, function(err, propertyMatch){
console.log(propertyMatch)
})
})
I got no objects back, even if I have one object in my database that matches these fields.
Thanks in advance
...and I would like to make a query in Mongo passing this object as a
query field and return if some object in my database matches with at
least one of those fields.
It sounds like OR logic - if I understood it well.
On this specific case it's not possible to pass in JSON-like object to query as it would be a implicit AND logic condition.
So you should build first a OR expression and use it in collection.find(), something like this:
var myjson = {'status': 32, 'profile': {$exists: false}};
function build_logic_or(json) {
var orExpr = [];
for (var field in json) {
var expr = {};
expr[field] = json[field];
orExpr.push(expr);
}
return {'$or': orExpr};
}
It would build an expression like this:
{"$or":[{"status":32},{"profile":{"$exists":false}}]}
So:
db.collection.find(build_logic_or(myjson))
Hello I'm attempting delete a certain index in my array while using Angular2 and Typescript. I would like to retrieve the index from the value.
My array is declared normally...
RightList = [
'Fourth property',
'Fifth property',
'Sixth property',
]
I start out with a basic premise to set up my remove function.
removeSel(llist: ListComponent, rlist:ListComponent){
this.selectedllist = llist;
console.log(JSON.stringify(this.selectedllist)); // what is to be searched turned into a string so that it may actually be used
My console.log of my JSON.Stringify tells me that the value that I will attempt to remove is "Sixth property". However when I attempt to look for this value in my array using the following code. It returns -1 which means my value is not found in the array.
var rightDel = this.RightList.indexOf((JSON.stringify(this.selectedllist))); // -1 is not found 1 = found
console.log(rightDel);
On my output to the console it does return the item that is to be searched for but does not find the item in the array
CONSOLE OUTPUT:
"Sixth property" // Item to be searched for
-1 // not found
Is there something wrong in my implementation of my function that searches the array?
Of course indexOf will not find you item in array because
JSON.stringify(this.selectedllist) !== this.selectedllist
This is because JSON stringified string encodes quotes around literal, that original string doesn't have. It is easy to test:
var a = 'test';
console.log( JSON.stringify(a), a, JSON.stringify(a) === a )
Remove JSON.stringify and it should work. In general, to cast something to String type you should use its .toString() method, or simply wrap this something into String(something).