I have a table with the following schema in a SQL Azure DB (2019 compat level):
CREATE TABLE dbo.Properties
(
PropertyId int,
PropertyName nvarchar(100),
PropertyValue nvarchar(1000)
)
I'd like to take the data within this table and turn it into JSON using the value within the PropertyName column as the name of the JSON property, and obviously the PropertyValue value as the JSON property value.
EDIT 12/10/2021:
Importantly, the values within the PropertyName column will not be predictable ahead of time.
For example, consider this data in the table (3 rows):
1, "Color", "Blue"
1, "Name", "John"
1, "Cost", 5
The above would be turned into the following JSON:
{"Color":"Blue", "Name":"John", "Cost":5}
I'm obviously able to do this with a STRING_AGG function like the following:
SELECT '{' + STRING_AGG( '"' + p.PropertyName + '": ''' + p.PropertyValue,''',')
WITHIN GROUP (ORDER BY p.PropertyName) + '}' AS MyJson
FROM dbo.Properties p
GROUP BY p.Id
But I was hoping to use one of the build in JSON functions rather than hack together a big string.
FOR JSON AUTO works from the column names, so one method to get your desired result would be to PIVOT the property names into columns. For example:
SELECT Color, [Name], Cost
FROM dbo.Properties
PIVOT ( MAX( PropertyValue ) For PropertyName In ( [Color], [Name], Cost ) ) pvt
FOR JSON AUTO;
My results:
Of course this is only convenient if your JSON attributes / column names are always known and it's a simple example. For more complex examples, you are probably looking at dynamic pivot, or dynamic SQL and your STRING_AGG example isn't so bad.
I want to create two columns from a column of values containing JSON in Snowflake using SQL.
Say this table is called keywords_bids
then there is a column called keywords that has JSON in it
example json in a cell in the keywords column:
row1: {"apple":0.1, "peach":0.2, "banana":0.1} row2: similar JSON, etc....
input image
I want to create a columns called keyword and it is bid price from the JSON
output would be:
keyword | Bid
'apple' | 0.1
'peach' | 0.2
'banana'| 0.3
First for JSON you'll need to change the single quotes to double quotes.
Then you just need to flatten the json to get keys and values:
with data as (
select parse_json('{"apple":0.1, "peach":0.2, "banana":0.1}') j
)
select k.key, k.value
from data, table(flatten(j)) k
;
https://community.snowflake.com/s/article/Dynamically-extracting-JSON-using-LATERAL-FLATTEN
This article is to demonstrate various examples of using LATERAL FLATTEN to extract information from a JSON Document. Examples are provided for its utilization together with GET_PATH, UNPIVOT, and SEQ functions.
(This is an extension to this question, but my reputation is too low to comment or ask more questions on that topic...)
We work on bigquery, hence limited in importing packages or using other languages. And, as per the link above, js is a solution, but not what I'm looking for here. I implemented it in js, and it was too slow for our needs.
Suppose one of our columns is a string that look like this (array of json):
[{"location":[22.99902,66.000],"t":1},{"location":[55.32168,140.556],"t":2},{"location":[85.0002,20.0055],"t":3}]
I want to extract from the column the json for which "t":2
Where:
some columns don't have elements "t":2
Some columns have several elements "t":2
The number of json elements in each string can change
element "t":2 is not always in second position.
I don't know regexp well enough for this. We tried regexp_extract with this pattern: r'(\{.*?\"t\":2.*?\})')), but that doesn't work. It extracts everything that precedes "t":2, including the json for "t":2. We only want the json of element "t":2.
Could you advise a regexp pattern that would work?
EDIT:
I have a preference for a solution that gives me 1 match. Suppose I have this string:
[{"location":[22.99902,66.000],"t":1},{"location":[55.32168,140.556],"t":2},{"location":[55.33,141.785],"t":2}],
I would prefer receiving only 1 answer, the first one.
In that case perhaps regexp is less appropriate, but I'm really not sure?
How about this:
(?<=\{)(?=.*?\"t\"\s*:\s*2).*?(?=\})
As seen here
There is another solution but it is not regexp based (as I had originally asked). So this should not count as the final answer to my own question, nonetheless could be useful.
It is based on a split of the string in array and then chosing the element in the array that satisfies my needs.
Steps:
transform the string into something better for splits (using '|' as seperator):
replace(replace(replace(my_field,'},{','}|{'),'[{','{'),'}]','}')
split it using split(), which yields an array of strings (each one a json element)
find the relevant element ("t":2) - in my case, the first one is good enough, so I limit the query to 1: array( select data from unnest(split(replace(replace(replace(my_field,'},{','}|{'),'[{','{'),'}]','}'),'|')) as data where data like '%"t":2%' limit 1)
Convert that into a useable string with array_to_string() and use json_extract on that string to extract the relevant info from the element that I need (say for example, location coordinate x).
So putting it all together:
round(safe_cast(json_extract(array_to_string(array( select data from unnest(split(replace(replace(replace(my_field,'},{','}|{'),'[{','{'),'}]','}'),'|')) as data where data like '%"t":2%' limit 1),''),'$.location[0]') as float64),3) loc_x
May 1st, 2020 Update
A new function, JSON_EXTRACT_ARRAY, has been just added to the list of JSON
functions. This function allows you to extract the contents of a JSON document as
a string array.
so in below you can replace use of json2array UDF with just in-built function JSON_EXTRACT_ARRAY as in below example
#standardSQL
SELECT id,
(
SELECT x
FROM UNNEST(JSON_EXTRACT_ARRAY(json, '$')) x
WHERE JSON_EXTRACT_SCALAR(x, '$.t') = '2'
) extracted
FROM `project.dataset.table`
==============
Below is for BigQuery Standard SQL
#standardSQL
CREATE TEMP FUNCTION json2array(json STRING)
RETURNS ARRAY<STRING>
LANGUAGE js AS """
return JSON.parse(json).map(x=>JSON.stringify(x));
""";
SELECT id,
(
SELECT x
FROM UNNEST(json2array(JSON_EXTRACT(json, '$'))) x
WHERE JSON_EXTRACT_SCALAR(x, '$.t') = '2'
) extracted
FROM `project.dataset.table`
You can test, play with above using dummy data as in below example
#standardSQL
CREATE TEMP FUNCTION json2array(json STRING)
RETURNS ARRAY<STRING>
LANGUAGE js AS """
return JSON.parse(json).map(x=>JSON.stringify(x));
""";
WITH `project.dataset.table` AS (
SELECT 1 id, '[{"location":[22.99902,66.000],"t":1},{"location":[55.32168,140.556],"t":2},{"location":[85.0002,20.0055],"t":3}]' json UNION ALL
SELECT 2, '[{"location":[22.99902,66.000],"t":11},{"location":[85.0002,20.0055],"t":13}]'
)
SELECT id,
(
SELECT x
FROM UNNEST(json2array(JSON_EXTRACT(json, '$'))) x
WHERE JSON_EXTRACT_SCALAR(x, '$.t') = '2'
) extracted
FROM `project.dataset.table`
with output
Row id extracted
1 1 {"location":[55.32168,140.556],"t":2}
2 2 null
Above assumes that there is no more than one element with "t":2 in json column. In case if there can be more than one - you should add ARRAY as below
SELECT id,
ARRAY(
SELECT x
FROM UNNEST(json2array(JSON_EXTRACT(json, '$'))) x
WHERE JSON_EXTRACT_SCALAR(x, '$.t') = '2'
) extracted
FROM `project.dataset.table`
Even though, you have posted a work around your issue. I believe this answer will be informative. You mentioned that one of the answer selected more than what you needed, I wrote the query below to reproduce your case and achieve aimed output.
WITH
data AS (
SELECT
" [{ \"location\":[22.99902,66.000]\"t\":1},{\"location\":[55.32168,140.556],\"t\":2},{\"location\":[85.0002,20.0055],\"t\":3}] " AS string_j
UNION ALL
SELECT
" [{ \"location\":[22.99902,66.000]\"t\":1},{\"location\":[55.32168,140.556],\"t\":3},{\"location\":[85.0002,20.0055],\"t\":3}] " AS string_j
UNION ALL
SELECT
" [{ \"location\":[22.99902,66.000]\"t\":1},{\"location\":[55.32168,140.556],\"t\":3},{\"location\":[85.0002,20.0055],\"t\":3}] " AS string_j
UNION ALL
SELECT
" [{ \"location\":[22.99902,66.000]\"t\":1},{\"location\":[55.32168,140.556],\"t\":3},{\"location\":[85.0002,20.0055],\"t\":3}] " AS string_j ),
refined_data AS (
SELECT
REGEXP_EXTRACT(string_j, r"\{\"\w*\"\:\[\d*\.\d*\,\d*\.\d*\]\,\"t\"\:2\}") AS desired_field
FROM
data )
SELECT
*
FROM
refined_data
WHERE
desired_field IS NOT NULL
Notice that I have used the dummy described in the temp table, populated inside the WITH method. As below:
Afterwords, in the table refined_data, I used the REGEXP_EXTRACT to extract the desired string from the column. Observe that for the rows which there is not a match expression, the output is null. Thus, the table refined_data is as follows :
As you can see, now it is just needed a simple WHERE filter to obtain the desired output, which was done in the last select.
In addition you can see the information about the regex expression I provided here.
I have some problems converting tabular data to JSON using the FOR JSON PATH syntax:
If i do a standard query:
SELECT b.Name FROM dbo
I get results of the form: 12/5-A-1. I need this converted to JSON data without escaping the backslash character. However, when i convert it to JSON:
SELECT b.Name FROM dbo FOR JSON PATH, WITHOUT ARRAY_WRAPPER
the result is of the form: {"Name": "12\/5-A-1"}
How can i do this transformation without escaping the backslash character and get the result {"Name": "12/5-A-1"}?
One option is to use a common table expression to generate the json, and then simply use replace when selecting from the common table expression.
First, create and populate sample data (Please save us this step in your future questions):
DECLARE #T AS TABLE
(
[Name] nvarchar(10)
)
INSERT INTO #T ([Name]) VALUES ('12/5-A-1');
The cte:
WITH CTE(Escaped) AS
(
SELECT [Name]
FROM #T
FOR JSON PATH, WITHOUT_ARRAY_WRAPPER
)
The final select:
SELECT REPLACE(Escaped, '\/','/') As Result
FROM CTE
Result:
{"Name":"12/5-A-1"}
I am accessing an array (a json object called 'choice_values') in a jsonb field, and would like to parse its contents into a comma-separated text field.
SELECT
jsonb_array_elements(doc -> 'form_values' -> '8189' -> 'choice_values')
FROM
field_data.exports;
That jsonb_array_elements function returns a "setof text", which I would like converted to a comma separated list of the array values, contained within a single field.
Thank you.
Set returning functions (like jsonb_array_elements_text()) can be called in SELECT list, but then they cannot be used in aggregate functions.
This is a good practice to call set returning functions in FROM clause, often in a lateral join like in this example:
with the_data as (
select '["alfa", "beta", "gamma"]'::jsonb as js
)
select string_agg(elem, ',')
from
the_data,
jsonb_array_elements_text(js) elem;
string_agg
-----------------
alfa,beta,gamma
(1 row)
So your query should look like this:
select string_agg(elem, ',')
from
field_data.exports,
jsonb_array_elements_text(doc -> 'form_values' -> '8189' -> 'choice_values') elem;
Using the string_agg aggregate function with a sub-select from jsonb_array_elements_text seems to work (tested on PG 9.5). Note the use of jsonb_array_elements_text, added in PostgreSQL 9.4, rather than jsonb_array_elements, from PostgreSQL 9.3.
with exports as (
select $${"form_values": {"8189": {"choice_values": ["a","b","c"]}}}$$::jsonb as doc
)
SELECT
string_agg(values, ', ')
FROM
exports, jsonb_array_elements_text(doc -> 'form_values' -> '8189' -> 'choice_values') values
GROUP BY
exports.doc;
Output:
'a, b, c'
Also see this question and its answers.
Maybe not best practice: convert the json array to text, then remove the brackets.
WITH input AS (
SELECT '["text1","text2","text3"]'::jsonb as data
)
SELECT substring(data::text,2,length(data::text)-2) FROM input
It has the advantage that it converts "in-place", not by aggregating. This could be handy if you can only access part of the query, e.g. for some synchronization tool where there's field-based conversion rules, or something like the following:
CREATE TEMP TABLE example AS (SELECT '["text1","text2","text3"]'::jsonb as data);
ALTER TABLE example ALTER COLUMN data TYPE text USING substring(data::text,2,length(data::text)-2);