i need to filter the table by using order.id which is nested 2 levels deeper inside the item column
can we filter them in sequalize
i don't know how to filter them
code:
item: datatype.jsonb
item:[{
Order:[
{
id: 01,
name: xxxx,
},
{
id:02,
name:yyyy,
}
]
}]
model.findAll({
where: {
'$item.Order.id$': 2;
},
include: [{ model: item, include: [{ model: Order}] }]
})
You can filter them using outer where condition if you want to filter whole data setup according to that where condition, otherwise you can add where condition inside include object like this
model.findAll({
include: [{ model: item, include: [{ model: Order, where: { id: 2 } }] }]
})
I have three models, A, B and C, where:
A.hasMany(B);
B.belongsTo(A);
B.hasMany(C);
C.belongsTo(B);
I'm querying like this:
await A.findOne({
where: { id: id },
include: [
{
model: B,
},
],
});
How can I return the C objects that belongs to B when querying A?
In the end found the solution in the comments of another question.
I need to pass the include with a array like this [{ all: true, nested: true }], I end up having something like this:
await A.findOne({
where: { id: id },
include: [{ all: true, nested: true }],
});
I didn't tested what happens when it loops and also didn't found the docs about it, if a good soul find it feel free to comment it.
Edit:
Nested includes also works:
await A.findOne({
where: { id: id },
include: [
{
model: B,
include: [
{
model: C,
},
],
},
],
});
I have a three tables as shown in this diagram https://dbdiagram.io/d/602fa54dfcdcb6230b2095e5
I would like to get my result as below json.
"data": [{
"products": {
"id": 12,
"product_catalog_id": 1,
"product_catalog": {
"id": 1,
"full_name": "Test"
}
"product_images": {
"id": 11,
"product_catalog_id": 1
}
}
}]
For that I have applied like below association rules of sequelize ORM
ProductModel.belongsTo(ProductCatalogModel, {foreignKey: 'product_catalog_id', targetKey: 'id', as : 'products' })
ProductImagesModel.belongsToMany(ProductCatalogModel , {through: ProductModel, foreignKey: 'product_catalog_id', targetKey: 'id', as :'product_images' });
ProductCatalogModel.belongsToMany(ProductImagesModel , {through: ProductModel, foreignKey: 'product_catalog_id', targetKey: 'id', as :'product_images' });
To find the result have applied below query.
var associations: Array<FindOptions | any> = [];
associations.push({
model: ProductModel,
as: 'products',
include: [{
model: ProductImagesModel,
as: 'product_images,
}]
})
var execute = await this.model.findAll()
return execute;
But instead of mapping the productImages model with productCatalog model it is going to map it with products table model.
I have also tries with the sequelize.literal into ProductImagesModel but that is throwing me an error like
"Include unexpected. Element has to be either a Model, an Association or an object."
associations.push({
model: ProductModel,
as: 'products',
include: [{
// model: ProductImagesModel,
// as: 'product_images,
include: [sequelize.literal(`(
SELECT id, product_catalog_id FROM product_images AS product_images
WHERE product_images.product_catalog_id IN (1)
)`)]
}]
})
I think it is simpler than you are making it. Try following this pattern:
const pugs = await Pug.findAll({ include: [{ model: Owner }] })
This should result in a list of pugs with an owner attribute with the owner attributes nested inside.
I am using MySQL database, when I am doing:
models.modelA.findAll({
attributes: [
['modelA.id','id']
],
raw: true,
include:
[
{
model: models.modelB,
required: true
}
]
}).then(function (tenants) {
});
Nevertheless that I've selected only id, Sequelize is retrieving all attributes, from related table as well so I'm getting {id, ... All attributes here}.
How I can prevent this? Sometimes I want to select only 2/3 columns and Sequelize is always selecting all of them what is not efficient.
You can do something like the following
models.modelA.findAll({
attributes: [
'id'
],
raw: true,
include:
[
{
model: models.modelB,
attributes: ['fieldName1', 'fieldName2'], // Add column names here inside attributes array.
required: true
}
]
}).then(function (tenants) {
});
You can try sending empty array as attributes to exclude them:
models.modelA.findAll({
attributes: [
['modelA.id','id']
],
raw: true,
include:
[
{
model: models.modelB,
attributes: [],
required: true
}
]
}).then(function (tenants) {
});
I have two tables, locations and sensors. Each entry in sensors has a foreign key pointing to locations. Using Sequelize, how do I get all entries from locations and total count of entries in sensors that are associated with each entry in locations?
Raw SQL:
SELECT
`locations`.*,
COUNT(`sensors`.`id`) AS `sensorCount`
FROM `locations`
JOIN `sensors` ON `sensors`.`location`=`locations`.`id`;
GROUP BY `locations`.`id`;
Models:
module.exports = function(sequelize, DataTypes) {
var Location = sequelize.define("Location", {
id: {
type: DataTypes.INTEGER.UNSIGNED,
primaryKey: true
},
name: DataTypes.STRING(255)
}, {
classMethods: {
associate: function(models) {
Location.hasMany(models.Sensor, {
foreignKey: "location"
});
}
}
});
return Location;
};
module.exports = function(sequelize, DataTypes) {
var Sensor = sequelize.define("Sensor", {
id: {
type: DataTypes.INTEGER.UNSIGNED,
primaryKey: true
},
name: DataTypes.STRING(255),
type: {
type: DataTypes.INTEGER.UNSIGNED,
references: {
model: "sensor_types",
key: "id"
}
},
location: {
type: DataTypes.INTEGER.UNSIGNED,
references: {
model: "locations",
key: "id"
}
}
}, {
classMethods: {
associate: function(models) {
Sensor.belongsTo(models.Location, {
foreignKey: "location"
});
Sensor.belongsTo(models.SensorType, {
foreignKey: "type"
});
}
}
});
return Sensor;
};
Use findAll() with include() and sequelize.fn() for the COUNT:
Location.findAll({
attributes: {
include: [[Sequelize.fn("COUNT", Sequelize.col("sensors.id")), "sensorCount"]]
},
include: [{
model: Sensor, attributes: []
}]
});
Or, you may need to add a group as well:
Location.findAll({
attributes: {
include: [[Sequelize.fn("COUNT", Sequelize.col("sensors.id")), "sensorCount"]]
},
include: [{
model: Sensor, attributes: []
}],
group: ['Location.id']
})
For Counting associated entries with Sequelize
Location.findAll({
attributes: {
include: [[Sequelize.fn('COUNT', Sequelize.col('sensors.location')), 'sensorCounts']]
}, // Sequelize.col() should contain a attribute which is referenced with parent table and whose rows needs to be counted
include: [{
model: Sensor, attributes: []
}],
group: ['sensors.location'] // groupBy is necessary else it will generate only 1 record with all rows count
})
Note :
Some how, this query generates a error like sensors.location is not exists in field list. This occur because of subQuery which is formed by above sequelize query.
So solution for this is to provide subQuery: false like example
Location.findAll({
subQuery: false,
attributes: {
include: [[Sequelize.fn('COUNT', Sequelize.col('sensors.location')), 'sensorCounts']]
},
include: [{
model: Sensor, attributes: []
}],
group: ['sensors.location']
})
Note:
**Sometime this could also generate a error bcz of mysql configuration which by default contains only-full-group-by in sqlMode, which needs to be removed for proper working.
The error will look like this..**
Error : Expression #1 of SELECT list is not in GROUP BY clause and contains nonaggregated column 'db.table.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
So to resolve this error follow this answer
SELECT list is not in GROUP BY clause and contains nonaggregated column .... incompatible with sql_mode=only_full_group_by
Now this will successfully generate all associated counts
Hope this will help you or somebody else!
Location.findAll({
attributes: {
include: [[Sequelize.fn("COUNT", Sequelize.col("sensors.id")), "sensorCount"]]
},
include: [{
model: Sensor, attributes: []
}]
});
and it works. but when i add "limit", i got error: sensors undefined
Example of HAVING, ORDER BY, INNER vs OUTER JOIN + several bugs/unintuitive behavior
I went into more detail at: Sequelize query with count in inner join but here's a quick summary list of points:
you must use row.get('count'), row.count does not work
you must parseInt on PostgreSQL
this code fails on PostgreSQL with column X must appear in the GROUP BY clause or be used in an aggregate function due to a sequelize bug
OUTER JOIN example which includes 0 counts by using required: false:
sqlite.js
const assert = require('assert');
const { DataTypes, Op, Sequelize } = require('sequelize');
const sequelize = new Sequelize('tmp', undefined, undefined, Object.assign({
dialect: 'sqlite',
storage: 'tmp.sqlite'
}));
;(async () => {
const User = sequelize.define('User', {
name: { type: DataTypes.STRING },
}, {});
const Post = sequelize.define('Post', {
body: { type: DataTypes.STRING },
}, {});
User.belongsToMany(Post, {through: 'UserLikesPost'});
Post.belongsToMany(User, {through: 'UserLikesPost'});
await sequelize.sync({force: true});
const user0 = await User.create({name: 'user0'})
const user1 = await User.create({name: 'user1'})
const user2 = await User.create({name: 'user2'})
const post0 = await Post.create({body: 'post0'})
const post1 = await Post.create({body: 'post1'})
const post2 = await Post.create({body: 'post2'})
// Set likes for each user.
await user0.addPosts([post0, post1])
await user1.addPosts([post0, post2])
let rows = await User.findAll({
attributes: [
'name',
[sequelize.fn('COUNT', sequelize.col('Posts.id')), 'count'],
],
include: [
{
model: Post,
attributes: [],
required: false,
through: {attributes: []},
where: { id: { [Op.ne]: post2.id }},
},
],
group: ['User.name'],
order: [[sequelize.col('count'), 'DESC']],
having: sequelize.where(sequelize.fn('COUNT', sequelize.col('Posts.id')), Op.lte, 1)
})
assert.strictEqual(rows[0].name, 'user1')
assert.strictEqual(parseInt(rows[0].get('count'), 10), 1)
assert.strictEqual(rows[1].name, 'user2')
assert.strictEqual(parseInt(rows[1].get('count'), 10), 0)
assert.strictEqual(rows.length, 2)
})().finally(() => { return sequelize.close() });
with:
package.json
{
"name": "tmp",
"private": true,
"version": "1.0.0",
"dependencies": {
"pg": "8.5.1",
"pg-hstore": "2.3.3",
"sequelize": "6.5.1",
"sqlite3": "5.0.2"
}
}
and Node v14.17.0.
INNER JOIN version excluding 0 counts:
let rows = await User.findAll({
attributes: [
'name',
[sequelize.fn('COUNT', '*'), 'count'],
],
include: [
{
model: Post,
attributes: [],
through: {attributes: []},
where: { id: { [Op.ne]: post2.id }},
},
],
group: ['User.name'],
order: [[sequelize.col('count'), 'DESC']],
having: sequelize.where(sequelize.fn('COUNT', '*'), Op.lte, 1)
})
assert.strictEqual(rows[0].name, 'user1')
assert.strictEqual(parseInt(rows[0].get('count'), 10), 1)
assert.strictEqual(rows.length, 1)
How about defining a database view for it and then a model for that view? You can just get the relationship to the view included in your query whenever you need the number of sensors. The code may look cleaner this way, but I'm not aware if there will be performance costs. Somebody else may answer that...
CREATE OR REPLACE VIEW view_location_sensors_count AS
select "locations".id as "locationId", count("sensors".id) as "locationSensorsCount"
from locations
left outer join sensors on sensors."locationId" = location.id
group by location.id
When defining the model for the view you remove the id attribute and set the locationId as the primary key.
Your model could look like this:
const { Model, DataTypes } = require('sequelize')
const attributes = {
locationID: {
type: DataTypes.UUIDV4, // Or whatever data type is your location ID
primaryKey: true,
unique: true
},
locationSensorsCount: DataTypes.INTEGER
}
const options = {
paranoid: false,
modelName: 'ViewLocationSensorsCount',
tableName: 'view_location_sensors_count',
timestamps: false
}
/**
* This is only a database view. It is not an actual table, so
* DO NOT ATTEMPT insert, update or delete statements on this model
*/
class ViewLocationSensorsCount extends Model {
static associate(models) {
ViewLocationSensorsCount.removeAttribute('id')
ViewLocationSensorsCount.belongsTo(models.Location, { as:'location', foreignKey: 'locationID' })
}
static init(sequelize) {
this.sequelize = sequelize
return super.init(attributes, {...options, sequelize})
}
}
module.exports = ViewLocationSensorsCount
In the end, in your Location model you set a hasOne relationship to the Sensor model.