I have some troubles and hope you will help me. I need to calculate how many contracts there are in which hcb.sum:
<= 10k
greater than 10k but < AVG
greater than AVG
In the first case, everything is simple, but the problem arises when I need to count the following two cases: "> 10 but < AVG" and "> AVG". I can't solve this problem. How to integrate the calculated AVG into this query. Hope you understand what i need. Perhaps you can help me. Thanks in advance. Select is below:
SELECT hcb.id AS 'ID'
,hcb.name AS 'Name'
,SUM(CASE WHEN hcb.kind = 'NEW' AND hcb.opt = 'CI' AND hcb.summ <= 10000 THEN 1 ELSE 0 END) AS '<= 10k'
,SUM(CASE WHEN hcb.kind = 'NEW' AND hcb.opt = 'CI' AND hcb.summ BETWEEN 10000.01 AND **AVG** THEN 1 ELSE 0 END) AS '> 10k < AVG'
,SUM(CASE WHEN hcb.kind = 'NEW' AND hcb.opt = 'CI' AND hcb.summ > **AVG** THEN 1 ELSE 0 END) AS '> AVG'
,AVG(hcb.summ) AS 'AVG summ'
FROM DBO AS hcb
WHERE hcb.stat IN (15, 20)
AND hcb.optstat <> 2999
AND hcb.opt = 'CI'
GROUP BY hcb.id, hcb.name
Use window functions. Presumably, you want the average with the where conditions, so:
SELECT hcb.id AS id,
hcb.name AS Name,
SUM(CASE WHEN hcb.kind = 'NEW' AND hcb.opt = 'CI' AND hcb.summ <= 10000
THEN 1 ELSE 0
END) AS "<= 10k",
SUM(CASE WHEN hcb.kind = 'NEW' AND hcb.opt = 'CI' AND hcb.summ > 10000 AND hcb.summ <= hcb.avg_summ
THEN 1 ELSE 0
END) AS "> 10k < AVG",
SUM(CASE WHEN hcb.kind = 'NEW' AND hcb.opt = 'CI' AND hcb.summ > hcb.avg_summ
THEN 1 ELSE 0
END) AS "> AVG",
avg_summ
FROM (SELECT hcb.*,
AVG(summ) OVER () as avg_summ
FROM DBO AS hcb
WHERE hcb.stat IN (15, 20) AND
hcb.optstat <> 2999 AND
hcb.opt = 'CI'
) hcb
GROUP BY hcb.id, hcb.name, avg_summ;
Note other changes to the query:
The column aliases are defined using double quotes not single quotes. Only use single quotes for string and date constants -- otherwise, you will one day have a confusion where you refer to a column using single quotes.
The second between is removed, replaced with >, so values between 10000 and 10000.01 are included.
If you want the overall average not subject to the filtering conditions, then move the WHERE conditions to the outer query.
I have used 3 different joins and then in SELECT statement brought up 3 different values trough something like COALESCE(MAX(d.[<10k]),0) AS '<10k'
LEFT JOIN (
SELECT r.id AS 'ID'
,COUNT(r.name) AS '<10k'
FROM DBO as r
WHERE r.stat IN (15, 20)
AND r.optstat <> 2999
AND r.opt = 'CI'
AND r.kind = 'NEW'
AND r.summ BETWEEN 10000 AND (SELECT AVG(ci.summ)
FROM DBO as ci
WHERE ci.stat IN (15, 20)
AND ci.optstat <> 2999
AND ci.opt = 'CI'
AND ci.kind = 'NEW')
GROUP BY r.id) AS d ON a.id = d.ID
Maybe it's not a best way to solve a problem, but it works for me. Thax a lot for some suggestions, they helped me. Cheers!
Related
I want to select the sum of T_No where Transactions are equal to R and subtract it by T_No where Transactions are equal to D and the answer of this should greater than zero for a CustomerID which would be a input (an int input declared in a stored procedure)
((Sum(T_No) where Transactions = R - Sum(T_No) where Transactions = D ) > 0) where CoustomerID = #input
Example : for ID = 1 it would be ((20+15) - 10) > 0
I Have tried so many things but either syntax is wrong, wrong value or it does not accept, and I am literally Stuck, this was my final attempt
SELECT
(select ( select Sum(T_No) where Transactions = R) - (select Sum(T_No) where Transactions = D) as C_T )
FROM CustomerTrans WHERE C_T > 0 ;
Conditional aggregation should help:
SELECT
SUM(CASE WHEN Transaction = 'R' THEN t_no ELSE 0 END) - SUM(CASE WHEN Transaction = 'D' THEN t_no ELSE 0 END)
FROM CustomerTrans
WHERE CoustomerID = #yourCustomerIdVariable
As you're writing a sproc you can assign the result of this to a variable and then decide what to do if the result is negative. (I would personally log an error for example, rather than just hide those results). If the result is null, then there were no transactions for that customer
ps; I used Transaction because that's what your screenshot showed, and I figured a screenshot is less likely to contain a typo than code with syntax errors. Adjust if required
you where kinda close, I would sum like you, only the syntax is a bit off, you can't have aggregate fields in Where, thats why you should use having, also case when syntax is not correct.
Select
CoustomerID,
Sum(case when Transactions = 'R' then T_No else 0 end) -
Sum(case when Transactions = 'D' then T_No else 0 end) as C_T
FROM CustomerTrans
group by CoustomerID
having (Sum(case when Transactions = 'R' then T_No else 0 end) -
Sum(case when Transactions = 'D' then T_No else 0 end))>0
I have a table which traces the users records I want to know which are the complete and process users's records based on their status
Here is the sql query
SELECT users.UserID,users.UserName,users.FirstName,users.LastName,users.Email,
CASE WHEN inword.inword_status = '3' THEN count(*) END As 'Process' ,
CASE WHEN inword.inword_status = '4' THEN count(*) END AS 'Complete'
FROM tbl_user users
INNER JOIN tbl_inword inword on users.UserID=inword.UserID
Where inword.Status=1 and users.Status=1 and
inword.CreatedDate BETWEEN '2020-10-01' and '2020-10-31' and inword.inword_status in (3)
group by users.UserID
Here is Query Output
My Expected result is
UserID Name Total Process Complete
1 Umair 1 1 0
1 Basit 20 20 0
1 Zaidi 34 32 2
Any Help would be Appreciated
You're not doing your conditional aggregation correctly, you should use something like:
COUNT(CASE WHEN inword.inword_status = '3' THEN inword.UserId END) As 'Process' ,
COUNT(CASE WHEN inword.inword_status = '4' THEN inword.UserId END) AS 'Complete'
Or you can take advantage of MySQL treating booleans as 1 or 0 in a numeric context and simplify to:
SUM(inword.inword_status = '3') As 'Process' ,
SUM(inword.inword_status = '4') AS 'Complete'
new to MySQL..so pls help me out with this basic code..
i have a query something like this...
select weekofyear(id_time),
(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
and it gives correct results as--here
however i want to use sum after case when statement so that I can get total values where BO=1 and group by week of year , so i made following changes-
select weekofyear(id_time),
count(id),
#Tat1:=exp1,
#Tat2:=exp2,
#check1:=exp3,
#check2:=exp4,
sum(case when #check2=0 then
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+10))) then 1 else 0 end)
else
(case when (#Tat1>(#Tat2+30) or (#check1=1 and (#Tat1>#Tat2+20))) then 1 else 0 end)
end) as BO
from datb
where cid=18
and id_time between '2019-11-01 06:00:00' and '2019-11-25 06:00:00'
group by weekofyear(id_time)
but it always returns 0 as output.
Output --here 2
Please help , I don't know what am I doing wrong here.
Thanx !
As others have already said, session variables can be unpredictable (especially when aggregation gets mixed in). That said, it doesn't look like you're using the session variables to carry over values from one row to the next (as is often done), but to just make aliases of sorts for calculations you don't want to repeat.
A better way to handle that is just through subqueries.
SELECT woy, id, Tat1, Tat2, check1, check2
, CASE
WHEN check2=0 THEN (
CASE
WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+10))) THEN 1
ELSE 0
END
)
ELSE (
CASE WHEN (Tat1>(Tat2+30) OR (check1=1 AND (Tat1>Tat2+20))) THEN 1
ELSE 0
END
)
END AS BO
FROM (
SELECT WEEKOFYEAR(id_time) AS woy
, id
, exp1 AS Tat1
, exp2 AS Tat2
, exp3 AS check1
, exp4 AS check2
FROM datb
WHERE cid=18
AND id_time BETWEEN '2019-11-01 06:00:00' AND '2019-11-25 06:00:00'
) AS subQ
;
You can then tweak the above query for aggregation, or use it as a subquery for an aggregating outer query.
I'm doing a select on two tables with this:
SELECT m.torneio, m.deck, m.top, m.lugar, sum( m.quantidade ) AS quantidade, m.formato AS formato, q.quantidade AS qtorneio, t.season AS season, sum( m.top ) AS totaltops, count( m.lugar = '1' ) AS venceu
FROM `metagame` AS m, quantidade AS q, torneios AS t
WHERE m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY m.deck
My problem is that venceu is counting all instances instead of only the ones when lugar = 1. Why is that?
tried with sum() too with no good results too. How can i fix this?
I am surprised that count( m.lugar = '1' ) syntaxs but it does and returns the sames as count(*). You should probably change it to sum(case when lugar = 1 else 0 end) as venceu. You should also look closely at the group by to be sure it works as you expect (i suspect not).
count(x) does not accept an expression.
It's only counting how many times x is returned.
What you should do is check if m.lugar is 1 and yes add one to the counter else do nothing.
Inline checks can be done like so:
case when m.lugar = '1' then 1 else 0 end
Then add all the one you gets :
sum(case when m.lugar = '1' then 1 else 0 end)
Your final query should look like this:
SELECT
m.torneio,
m.deck,
m.top,
m.lugar,
sum( m.quantidade ) AS quantidade,
m.formato AS formato,
q.quantidade AS qtorneio,
t.season AS season,
sum( m.top ) AS totaltops,
sum(case when m.lugar = '1' then 1 else 0 end) AS venceu
FROM
`metagame` AS m,
quantidade AS q,
torneios AS t
WHERE
m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY
m.deck
If I understand your question you can use this:
sum(case when m.lugar = '1' then 1 else 0 end)
or you can try having clause
SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);
I'm trying to output a friendly price table in MySQL for export/import into a spreadsheet. Let's use fruits and their price breaks as an example.
Here's a fiddle for the schema I'm referring to:
http://sqlfiddle.com/#!9/c526e3/4
Simply:
Table: fruit
id
name
Table: fruit_pricing
id
fruit_id
min_quantity
max_quantity
price
When executing the query:
SELECT
F.name,
IF(FP.min_quantity = 1, FP.price, '0') as qty_1,
IF(FP.min_quantity = 10, FP.price, '0') as qty_10,
IF(FP.min_quantity = 25, FP.price, '0') as qty_25,
IF(FP.min_quantity = 50, FP.price, '0') as qty_50,
IF(FP.min_quantity = 100, FP.price, '0') as qty_100
FROM Fruit F
LEFT JOIN FruitPricing FP ON FP.fruit_id = F.id
It displays the results like this:
What I'd like to do is group the fruit names so there are only three rows: Apple, Grape, and Orange. Then, I'd like all the 0 values to be replaced with the appropriate quantities. I'm trying to get the same output as the spreadsheet in this screenshot:
Are there any nice tricks for accomplishing this? I'm unsure of the sql-tech-speak for this particular question, making it difficult to search for an answer. I'd be happy to update my question subject if I can and somebody has a better suggestion for it.
SELECT f.name
, SUM(CASE WHEN fp.min_quantity = 1 THEN fp.price ELSE 0 END) qty_1
, SUM(CASE WHEN fp.min_quantity = 10 THEN fp.price ELSE 0 END) qty_10
, SUM(CASE WHEN fp.min_quantity = 25 THEN fp.price ELSE 0 END) qty_25
, SUM(CASE WHEN fp.min_quantity = 50 THEN fp.price ELSE 0 END) qty_50
, SUM(CASE WHEN fp.min_quantity = 100 THEN fp.price ELSE 0 END) qty_100
FROM fruit f
LEFT
JOIN fruitpricing fp
ON fp.fruit_id = f.id
GROUP
BY name;
Although, if it was me, I'd probably just do the following, and handle any remaining display issues in the presentation layer...
SELECT f.name
, fp.min_quantity
, SUM(fp.price) qty
FROM fruit f
LEFT
JOIN fruitpricing fp
ON fp.fruit_id = f.id
GROUP
BY name
, min_quantity;