The table provided shows all new users signing up on a specific date in the format YYYY-MM-DD.
Your query should output the change from one month to the next. Because the first month has no preceding month, your output should skip that row. Your output should look like the following table.
My table data
Table data:
ID DateJoined
1 2017-01-06
2 2017-01-12
3 2017-01-16
4 2017-01-25
5 2017-02-05
6 2017-02-07
7 2017-02-21
8 2017-03-05
9 2017-03-07
10 2017-03-14
11 2017-03-16
12 2017-03-25
13 2017-03-25
14 2017-03-25
15 2017-03-25
16 2017-03-26
17 2017-04-05
18 2017-04-14
19 2017-04-21
20 2017-05-07
23 2017-05-14
24 2017-05-16
25 2017-05-25
26 2017-05-25
27 2017-05-25
28 2017-05-25
Enter image description here
I want this output:
count all records from every month and subtract it from the next month record.
This is my query:
SELECT
MONTH(L.joindate),
COUNT(L.joindate) - COUNT(R.joindate),
MONTH(R.joindate),
COUNT(R.joindate)
FROM
userlog AS L
LEFT JOIN
userlog AS R
ON MONTH(R.joindate)= (SELECT MIN(MONTH(joindate)) FROM userlog WHERE MONTH(joindate) < MONTH(L.joindate))
GROUP BY (MONTH(L.joindate)),(MONTH(R.joindate));
Use lag(), available in MySQL 8.0:
select date_format(joindate, '%Y-%m-01') joinmonth,
count(*) - lag(count(*), 1, 0) over(order by date_format(joindate, '%Y-%m-01')) m2m
from userlog
group by joinmonth
Note that I changed the logic to truncate dates to the first of month to use date_format().
In earlier versions, you can use a correlated subquery:
select date_format(joindate, '%Y-%m-01') joinmonth,
count(*) - (
select count(*)
from userlog l1
where l1.joindate >= date_format(l.joindate, '%Y-%m-01') - interval 1 month
and l1.joindate < date_format(l.joindate, '%Y-%m-01')
) m2m
from userlog l
group by joinmonth
LIMIT 12 OFFSET 1
You need to use Lag. Also, since it says you need to skip the first row so I have used the not null condition. I believe this query should work.
select
Month,
MonthToMonthChange
from
(
select
m_name as Month,
(total_id - diff) as MonthToMonthChange
from
(
select
total_id,
m_name,
Lag(total_id, 1) OVER(
ORDER BY
m_num ASC
) AS diff
from
(
select
MonthNAME(DateJoined) m_name,
Month(DateJoined) m_num,
count(*) total_id
from
maintable
Group by
m_name,
m_num
) as first_subquery
) as second_subquery
) as final_query
where
MonthToMonthChange IS NOT NULL;
select
MONTHNAME(UL1.DateJoined) as MONTH,
count(UL1.DateJoined) -
(
select count(UL2.DateJoined)
from tablename UL2
where MONTH(UL2.DateJoined )=MONTH(UL1.DateJoined) -1
) as MonthToMonthChange
from tablename UL1
where Month(UL1.DateJoined)!=1
Group by MONTHNAME(UL1.DateJoined)
order by UL1.DateJoined ASC;
https://i.stack.imgur.com/BXXDb.png
I tried this and it worked
select date_format(DateJoined, CONCAT('%M')) as Month,
count(*) - lag(count(*), 1, 0) over(order by date_format(DateJoined, CONCAT('%m'))) MonthToMonthChange
from maintable_OKLOT
group by Month
limit 12 offset 1
Related
I have a table with created_at and deleted_at timestamps. I need to know, for each week, how many records existed at any point that week:
week
records
2022-01
4
2022-02
5
...
...
Essentially, records that were created before the end of the week and deleted after the beginning of the week.
I've tried various variations of the following but it's under-reporting and I can't work out why:
SELECT
DATE_FORMAT(created_at, '%Y-%U') AS week,
COUNT(*)
FROM records
WHERE
deleted_at > DATE_SUB(deleted_at, INTERVAL (WEEKDAY(deleted_at)+1) DAY)
AND created_at < DATE_ADD(created_at, INTERVAL 7 - WEEKDAY(created_at) DAY)
GROUP BY week
ORDER BY week
Any help would be massively appreciated!
I would create a table wktable that looks like so (for the last 5 weeks of last year):
yrweek | wkstart | wkstart
-------+------------+------------
202249 | 2022-11-27 | 2022-12-03
202250 | 2022-12-04 | 2022-12-10
202251 | 2022-12-11 | 2022-12-17
202252 | 2022-12-18 | 2022-12-24
202253 | 2022-12-25 | 2022-12-31
To get there, find a way to create 365 consecutive integers, make all the dates of 2022 out of that, and group them by year-week.
This is an example:
CREATE TABLE wk AS
WITH units(units) AS (
SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION
SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
)
,tens AS(SELECT units * 10 AS tens FROM units )
,hundreds AS(SELECT tens * 10 AS hundreds FROM tens )
,
i(i) AS (
SELECT hundreds +tens +units
FROM units
CROSS JOIN tens
CROSS JOIN hundreds
)
,
dt(dt) AS (
SELECT
DATE_ADD(DATE '2022-01-01', INTERVAL i DAY)
FROM i
WHERE i < 365
)
SELECT
YEAR(dt)*100 + WEEK(dt) AS yrweek
, MIN(dt) AS wkstart
, MAX(dt) AS wkend
FROM dt
GROUP BY yrweek
ORDER BY yrweek;
With that table, go:
SELECT
yrweek
, COUNT(*) AS records
FROM wk
JOIN input_table ON wk.wkstart < input_table.deleted_at
AND wk.wkend > input_table.created_at
GROUP BY
yrweek
;
I first build a list with the records, their open count, and the closed count
SELECT
created_at,
deleted_at,
(SELECT COUNT(*)
from records r2
where r2.created_at <= r1.created_at ) as new,
(SELECT COUNT(*)
from records r2
where r2.deleted_at <= r1.created_at) as closed
FROM records r1
ORDER BY r1.created_at;
After that it's just adding a GROUP BY:
SELECT
date_format(created_at,'%Y-%U') as week,
MAX((SELECT COUNT(*)
from records r2
where r2.created_at <= r1.created_at )) as new,
MAX((SELECT COUNT(*)
from records r2
where r2.deleted_at <= r1.created_at)) as closed
FROM records r1
GROUP BY week
ORDER BY week;
see: DBFIDDLE
NOTE: Because I use random times, the results will change when re-run. A sample output is:
week
new
closed
2022-00
31
0
2022-01
298
64
2022-02
570
212
2022-03
800
421
I have records with a start and end date, like so:
id start_date end_date
1 2016-01-01 2016-10-31
2 2016-06-01 2016-12-31
3 2016-06-01 2016-07-31
I have to know the number of records that were active per month (or better put: on the first day of all months in a given period). The counts would look like this when calculated for 2016:
jan: 1
feb: 1
mar: 1
apr: 1
may: 1
jun: 3
jul: 3
aug: 2
sep: 2
oct: 2
nov: 1
dec: 1
The solution I came up with, is to create a TEMP TABLE with all applicable dates for the given period:
date
2016-01-01
2016-02-01
...
Which makes the query very easy:
SELECT
COUNT(*),
m.date
FROM
months m
INNER JOIN table t
ON m.date BETWEEN t.start_date AND t.end_date
GROUP BY
m.date
This produces exactly the results I'm looking for. However; I do feel as if this could be done easier. I just don't know how.
Any suggestions?
You can do it the following way, even if it looks ugly:
Assuming you want to run a report and you are only interested in "months of a certain year", the following query might work:
select m,Count(id) FROM (
SELECT 1 as m UNION
SELECT 2 as m UNION
SELECT 3 as m UNION
SELECT 4 as m UNION
SELECT 5 as m UNION
SELECT 6 as m UNION
SELECT 7 as m UNION
SELECT 8 as m UNION
SELECT 9 as m UNION
SELECT 10 as m UNION
SELECT 11 as m UNION
SELECT 12 as m) AS tabseq
CROSS JOIN x WHERE
(year (start_date) = 2016 AND year (end_date) = 2016 AND m >= month(start_date) AND m <= month(end_date)) -- starts abd ends this year
or
(year (start_date) < 2016 AND year (end_date) = 2016 AND m <= month(end_date)) -- ends this year, consider months until end of contract
or
(year (start_date) < 2016 AND year (end_date) > 2016) -- spans the year, ignore month,
or
(year (start_date) = 2016 AND year (end_date) > 2016 AND m >= month(start_date)) -- starts this year, consider months until end of year
GROUP BY m;
result:
m count(id)
1 1
2 1
3 1
4 1
5 1
6 3
7 3
8 2
9 2
10 2
11 1
12 1
As suggested in the comments, I replaced the temp table with a permanent table called 'calendar'.
CREATE TABLE `calendar` (
`date` date NOT NULL,
PRIMARY KEY (`date`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
I filled this table with all dates from 2000-01-01 until 2100-12-31. I rewrote my query to this:
SELECT
COUNT(*),
c.date
FROM
calendar c
INNER JOIN table t
ON c.date BETWEEN t.start_date AND t.end_date
WHERE
DAYOFMONTH(c.date) = 1
AND
c.date BETWEEN '2016-01-01' AND '2016-12-31'
GROUP BY
c.date
I have an MySQL table, similar to this example:
c_id date value
66 2015-07-01 1
66 2015-07-02 777
66 2015-08-01 33
66 2015-08-20 200
66 2015-08-21 11
66 2015-09-14 202
66 2015-09-15 204
66 2015-09-16 23
66 2015-09-17 0
66 2015-09-18 231
What I need to get is count of periods where dates are in row. I don't have fixed start or end date, there can be any.
For example: 2015-07-01 - 2015-07-02 is one priod, 2015-08-01 is second period, 2015-08-20 - 2015-08-21 is third period and 2015-09-14 - 2015-09-18 as fourth period. So in this example there is four periods.
SELECT
SUM(value) as value_sum,
... as period_count
FROM my_table
WHERE cid = 66
Cant figure this out all day long.. Thx.
I don't have enough reputation to comment to the above answer.
If all you need is the NUMBER of splits, then you can simply reword your question: "How many entries have a date D, such that the date D - 1 DAY does not have an entry?"
In which case, this is all you need:
SELECT
COUNT(*) as PeriodCount
FROM
`periods`
WHERE
DATE_ADD(`date`, INTERVAL - 1 DAY) NOT IN (SELECT `date` from `periods`);
In your PHP, just select the "PeriodCount" column from the first row.
You had me working on some crazy stored procedure approach until that clarification :P
I should get deservedly flamed for this, but anyway, consider the following...
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(date DATE NOT NULL PRIMARY KEY
,value INT NOT NULL
);
INSERT INTO my_table VALUES
('2015-07-01',1),
('2015-07-02',777),
('2015-08-01',33),
('2015-08-20',200),
('2015-08-21',11),
('2015-09-14',202),
('2015-09-15',204),
('2015-09-16',23),
('2015-09-17',0),
('2015-09-18',231);
SELECT x.*
, SUM(y.value) total
FROM
( SELECT a.date start
, MIN(c.date) end
FROM my_table a
LEFT
JOIN my_table b
ON b.date = a.date - INTERVAL 1 DAY
LEFT
JOIN my_table c
ON c.date >= a.date
LEFT
JOIN my_table d
ON d.date = c.date + INTERVAL 1 DAY
WHERE b.date IS NULL
AND c.date IS NOT NULL
AND d.date IS NULL
GROUP
BY a.date
) x
JOIN my_table y
ON y.date BETWEEN x.start AND x.end
GROUP
BY x.start;
+------------+------------+-------+
| start | end | total |
+------------+------------+-------+
| 2015-07-01 | 2015-07-02 | 778 |
| 2015-08-01 | 2015-08-01 | 33 |
| 2015-08-20 | 2015-08-21 | 211 |
| 2015-09-14 | 2015-09-18 | 660 |
+------------+------------+-------+
4 rows in set (0.00 sec) -- <-- This is the number of periods
there is a simpler way of doing this, see here SQLfiddle:
SELECT min(date) start,max(date) end,sum(value) total FROM
(SELECT #i:=#i+1 i,
ROUND(Unix_timestamp(date)/(24*60*60))-#i diff,
date,value
FROM tbl, (SELECT #i:=0)n WHERE c_id=66 ORDER BY date) t
GROUP BY diff
This select groups over the same difference between sequential number and date value.
Edit
As Strawberry remarked quite rightly, there was a flaw in my apporach, when a period spans a month change or indeed a change into the next year. The unix_timestamp() function can cure this though: It returns the seconds since 1970-1-1, so by dividing this number by 24*60*60 you get the days since that particular date. The rest is simple ...
If you only need the count, as your last comment stated, you can do it even simpler:
SELECT count(distinct diff) period_count FROM
(SELECT #i:=#i+1 i,
ROUND(Unix_timestamp(date)/(24*60*60))-#i diff,
date,value
FROM tbl,(SELECT #i:=0)n WHERE c_id=66 ORDER BY date) t
Tnx. #cars10 solution worked in MySQL, but could not manage to get period count to echo in PHP. It returned 0. Got it working tnx to #jarkinstall. So my final select looks something like this:
SELECT
sum(coalesce(count_tmp,coalesce(count_reserved,0))) as sum
,(SELECT COUNT(*) FROM my_table WHERE cid='.$cid.' AND DATE_ADD(date, INTERVAL - 1 DAY) NOT IN (SELECT date from my_table WHERE cid='.$cid.' AND coalesce(count_tmp,coalesce(count_reserved,0))>0)) as periods
,count(*) as count
,(min(date)) as min_date
,(max(date)) as max_date
FROM my_table WHERE cid=66
AND coalesce(count_tmp,coalesce(count_reserved,0))>0
ORDER BY date;
The code i use gives me the correct information based on a date in a where clause. I want to have the same information on other dates. So now I have to change the date myself and run the code, copy/paste it somewhere else and start over again with a new date. That takes a lot of work if i want the information for every day of the year. Is it possible to automaticly change the date in the where clause and what is the best or easiest way to do that?
Select t4.Count, t4.Status
From(
SELECT count(l.VoerID) as Count, l.Datum, l.Status, l.LogID
FROM (
SELECT k.VoerID, k.Datum, MAX(k.LogID) AS LogID
FROM DB.LogStatus k
Where Datum < '2013-07-01'
GROUP BY k.VoerID
) m
JOIN DB.LogStatus l
ON l.VoerID = m.VoerID AND l.LogID = m.LogID
Where status in ('B','IN1','IN2''V','Reserv')
Group by Status
)t4
EDIT:
original table (selected on one VoerID) (table consist of thousands of VoerID's)
LogID Datum UserID Status Time VoerID
1299772 2013-04-17 259 N 14:09:11 50174
1319774 2013-05-23 68 B 11:19:17 50174
1320038 2013-05-23 197 IN1 16:53:30 50174
1322002 2013-05-28 68 IN2 09:22:32 50174
1325052 2013-05-31 161 G 09:00:59 50174
1325166 2013-05-31 10 400 09:15:12 50174
1325182 2013-05-31 10 V 09:30:07 50174
1325208 2013-05-31 10 V 09:45:06 50174
1325406 2013-05-31 10 Reserv 11:45:06 50174
1325522 2013-05-31 10 Reserv 12:15:06 50174
1325954 2013-05-31 10 Reserv 15:15:13 50174
1328474 2013-06-05 10 Reserv 13:15:06 50174
1329230 2013-06-06 10 Reserv 09:45:03 50174
1329244 2013-06-06 10 Archived 10:00:08 50174
1329268 2013-06-06 10 Archived 10:15:08 50174
1330286 2013-06-07 10 Archived 10:15:06 50174
I want to now what was the status of the VoerID on all first of months. so on 2013-05-01 status = N, on 2013-06-01 status = Reserv and from 2013-07-01 it is Archived.
So above is for one VoerID. I want to count the number of VoerID's per first of month, per last LOGID before the first of next month and per status
Finally if I get the information i want to edit it in MSExcel to a crosstable and Chart:
1-1-2013 1-2-2013 1-3-2013 1-4-2013 1-5-2013
N 20 22 24 26 28
B 23 21,5 20 18,5 17
IN1 12 15 18 21 24
IN2 15 7 14 18 25
V 800 1000 1200 1400 1600
Reserv 50 63 76 89 102
Archived 100000 101220 102440 103660 104880
Doing a cross join of all the days of the year, then grouping by that day.
Something like this:-
SELECT COUNT(l.VoerID) as COUNT, m.aDate, l.Status
FROM
(
SELECT Sub1.aDate, k.VoerID, MAX(k.LogID) AS LogID
FROM DB.LogStatus k
CROSS JOIN
(
SELECT DATE_ADD('2013-01-01', INTERVAL units.i + tens.i * 10 + hundreds.i * 100 DAY) AS aDate -- return the first day of the year + all the numbers from 0 to 999
FROM (SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) units -- Select units of days
CROSS JOIN (SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) tens -- select tens
CROSS JOIN (SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9) hundreds -- select hundreds
WHERE DATE_ADD('2013-01-01', INTERVAL units.i + tens.i * 10 + hundreds.i * 100 DAY) <= '2013-12-31' -- limit the dates to the days of the specific year
) Sub1
WHERE k.Datum < Sub1.aDate -- This should give up multiple copies of record, one for each date where the d Datum is less that that date
GROUP BY Sub1.aDate, k.VoerID -- GRoup by date and id, so getting the max log id for each date and id
) m
JOIN DB.LogStatus l
ON l.VoerID = m.VoerID AND l.LogID = m.LogID -- Join where log it is the max log id
WHERE status in ('x','y','z')
GROUP BY m.aDate, Status
EDIT - or for each month:-
SELECT COUNT(l.VoerID) as COUNT, m.aDate, l.Status
FROM
(
SELECT Sub1.aDate, k.VoerID, MAX(k.LogID) AS LogID
FROM DB.LogStatus k
CROSS JOIN
(
SELECT DATE_ADD('2013-01-01', INTERVAL units.i MONTH) AS aDate -- return the first day of each month of the year
FROM (SELECT 0 AS i UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9 UNION SELECT 10 UNION SELECT 11) units -- Select units of days
) Sub1
WHERE k.Datum < Sub1.aDate -- This should give up multiple copies of record, one for each date where the d Datum is less that that date
GROUP BY Sub1.aDate, k.VoerID -- GRoup by date and id, so getting the max log id for each date and id
) m
JOIN DB.LogStatus l
ON l.VoerID = m.VoerID AND l.LogID = m.LogID -- Join where log it is the max log id
WHERE status in ('x','y','z')
GROUP BY m.aDate, Status
I have some difficulties with mySQL commands that I want to do.
SELECT a.timestamp, name, count(b.name)
FROM time a, id b
WHERE a.user = b.user
AND a.id = b.id
AND b.name = 'John'
AND a.timestamp BETWEEN '2010-11-16 10:30:00' AND '2010-11-16 11:00:00'
GROUP BY a.timestamp
This is my current output statement.
timestamp name count(b.name)
------------------- ---- -------------
2010-11-16 10:32:22 John 2
2010-11-16 10:35:12 John 7
2010-11-16 10:36:34 John 1
2010-11-16 10:37:45 John 2
2010-11-16 10:48:26 John 8
2010-11-16 10:55:00 John 9
2010-11-16 10:58:08 John 2
How do I group them into 5 minutes interval results?
I want my output to be like
timestamp name count(b.name)
------------------- ---- -------------
2010-11-16 10:30:00 John 2
2010-11-16 10:35:00 John 10
2010-11-16 10:40:00 John 0
2010-11-16 10:45:00 John 8
2010-11-16 10:50:00 John 0
2010-11-16 10:55:00 John 11
This works with every interval.
PostgreSQL
SELECT
TIMESTAMP WITH TIME ZONE 'epoch' +
INTERVAL '1 second' * round(extract('epoch' from timestamp) / 300) * 300 as timestamp,
name,
count(b.name)
FROM time a, id
WHERE …
GROUP BY
round(extract('epoch' from timestamp) / 300), name
MySQL
SELECT
timestamp, -- not sure about that
name,
count(b.name)
FROM time a, id
WHERE …
GROUP BY
UNIX_TIMESTAMP(timestamp) DIV 300, name
I came across the same issue.
I found that it is easy to group by any minute interval is
just dividing epoch by minutes in amount of seconds and then either rounding or using floor to get ride of the remainder. So if you want to get interval in 5 minutes you would use 300 seconds.
SELECT COUNT(*) cnt,
to_timestamp(floor((extract('epoch' from timestamp_column) / 300 )) * 300)
AT TIME ZONE 'UTC' as interval_alias
FROM TABLE_NAME GROUP BY interval_alias
interval_alias cnt
------------------- ----
2010-11-16 10:30:00 2
2010-11-16 10:35:00 10
2010-11-16 10:45:00 8
2010-11-16 10:55:00 11
This will return the data correctly group by the selected minutes interval; however, it will not return the intervals that don't contains any data. In order to get those empty intervals we can use the function generate_series.
SELECT generate_series(MIN(date_trunc('hour',timestamp_column)),
max(date_trunc('minute',timestamp_column)),'5m') as interval_alias FROM
TABLE_NAME
Result:
interval_alias
-------------------
2010-11-16 10:30:00
2010-11-16 10:35:00
2010-11-16 10:40:00
2010-11-16 10:45:00
2010-11-16 10:50:00
2010-11-16 10:55:00
Now to get the result with interval with zero occurrences we just outer join both result sets.
SELECT series.minute as interval, coalesce(cnt.amnt,0) as count from
(
SELECT count(*) amnt,
to_timestamp(floor((extract('epoch' from timestamp_column) / 300 )) * 300)
AT TIME ZONE 'UTC' as interval_alias
from TABLE_NAME group by interval_alias
) cnt
RIGHT JOIN
(
SELECT generate_series(min(date_trunc('hour',timestamp_column)),
max(date_trunc('minute',timestamp_column)),'5m') as minute from TABLE_NAME
) series
on series.minute = cnt.interval_alias
The end result will include the series with all 5 minute intervals even those that have no values.
interval count
------------------- ----
2010-11-16 10:30:00 2
2010-11-16 10:35:00 10
2010-11-16 10:40:00 0
2010-11-16 10:45:00 8
2010-11-16 10:50:00 0
2010-11-16 10:55:00 11
The interval can be easily changed by adjusting the last parameter of generate_series. In our case we use '5m' but it could be any interval we want.
You should rather use GROUP BY UNIX_TIMESTAMP(time_stamp) DIV 300 instead of round(../300) because of the rounding I found that some records are counted into two grouped result sets.
For postgres, I found it easier and more accurate to use the
date_trunc
function, like:
select name, sum(count), date_trunc('minute',timestamp) as timestamp
FROM table
WHERE xxx
GROUP BY name,date_trunc('minute',timestamp)
ORDER BY timestamp
You can provide various resolutions like 'minute','hour','day' etc... to date_trunc.
The query will be something like:
SELECT
DATE_FORMAT(
MIN(timestamp),
'%d/%m/%Y %H:%i:00'
) AS tmstamp,
name,
COUNT(id) AS cnt
FROM
table
GROUP BY ROUND(UNIX_TIMESTAMP(timestamp) / 300), name
Not sure if you still need it.
SELECT FROM_UNIXTIME(FLOOR((UNIX_TIMESTAMP(timestamp))/300)*300) AS t,timestamp,count(1) as c from users GROUP BY t ORDER BY t;
2016-10-29 19:35:00 | 2016-10-29 19:35:50 | 4 |
2016-10-29 19:40:00 | 2016-10-29 19:40:37 | 5 |
2016-10-29 19:45:00 | 2016-10-29 19:45:09 | 6 |
2016-10-29 19:50:00 | 2016-10-29 19:51:14 | 4 |
2016-10-29 19:55:00 | 2016-10-29 19:56:17 | 1 |
You're probably going to have to break up your timestamp into ymd:HM and use DIV 5 to split the minutes up into 5-minute bins -- something like
select year(a.timestamp),
month(a.timestamp),
hour(a.timestamp),
minute(a.timestamp) DIV 5,
name,
count(b.name)
FROM time a, id b
WHERE a.user = b.user AND a.id = b.id AND b.name = 'John'
AND a.timestamp BETWEEN '2010-11-16 10:30:00' AND '2010-11-16 11:00:00'
GROUP BY year(a.timestamp),
month(a.timestamp),
hour(a.timestamp),
minute(a.timestamp) DIV 12
...and then futz the output in client code to appear the way you like it. Or, you can build up the whole date string using the sql concat operatorinstead of getting separate columns, if you like.
select concat(year(a.timestamp), "-", month(a.timestamp), "-" ,day(a.timestamp),
" " , lpad(hour(a.timestamp),2,'0'), ":",
lpad((minute(a.timestamp) DIV 5) * 5, 2, '0'))
...and then group on that
How about this one:
select
from_unixtime(unix_timestamp(timestamp) - unix_timestamp(timestamp) mod 300) as ts,
sum(value)
from group_interval
group by ts
order by ts
;
I found out that with MySQL probably the correct query is the following:
SELECT SUBSTRING( FROM_UNIXTIME( CEILING( timestamp /300 ) *300,
'%Y-%m-%d %H:%i:%S' ) , 1, 19 ) AS ts_CEILING,
SUM(value)
FROM group_interval
GROUP BY SUBSTRING( FROM_UNIXTIME( CEILING( timestamp /300 ) *300,
'%Y-%m-%d %H:%i:%S' ) , 1, 19 )
ORDER BY SUBSTRING( FROM_UNIXTIME( CEILING( timestamp /300 ) *300,
'%Y-%m-%d %H:%i:%S' ) , 1, 19 ) DESC
Let me know what you think.
select
CONCAT(CAST(CREATEDATE AS DATE),' ',datepart(hour,createdate),':',ROUNd(CAST((CAST((CAST(DATEPART(MINUTE,CREATEDATE) AS DECIMAL (18,4)))/5 AS INT)) AS DECIMAL (18,4))/12*60,2)) AS '5MINDATE'
,count(something)
from TABLE
group by CONCAT(CAST(CREATEDATE AS DATE),' ',datepart(hour,createdate),':',ROUNd(CAST((CAST((CAST(DATEPART(MINUTE,CREATEDATE) AS DECIMAL (18,4)))/5 AS INT)) AS DECIMAL (18,4))/12*60,2))
This will do exactly what you want.
Replace
dt - your datetime
c - call field
astro_transit1 - your table
300 as seconds for each time gap increase
SELECT
FROM_UNIXTIME(300 * ROUND(UNIX_TIMESTAMP(r.dt) / 300)) AS 5datetime,
(SELECT
r.c
FROM
astro_transit1 ra
WHERE
ra.dt = r.dt
ORDER BY ra.dt DESC
LIMIT 1) AS first_val
FROM
astro_transit1 r
GROUP BY UNIX_TIMESTAMP(r.dt) DIV 300
LIMIT 0 , 30
Based on #boecko answer for MySQL, I used a CTE (Common Table Expression) to accelerate the query execution time :
so this :
SELECT
`timestamp`,
`name`,
count(b.`name`)
FROM `time` a, `id` b
WHERE …
GROUP BY
UNIX_TIMESTAMP(`timestamp`) DIV 300, name
becomes :
WITH cte AS (
SELECT
`timestamp`,
`name`,
count(b.`name`),
UNIX_TIMESTAMP(`timestamp`) DIV 300 AS `intervals`
FROM `time` a, `id` b
WHERE …
)
SELECT * FROM cte GROUP BY `intervals`
In a large amount of data, the speed is accelerated by more than 10!
As timestamp and time are reserved in MySQL, don't forget to use `...` on each table and column name !
Hope it will help some of you.