How would I add 1 to the first value in memory and store the value in the adjacent word, and also place a copy of this value in register $v0 - mips

.data
A: .word 0xcafebeee
.text
#Your code goes here
How would I write code to add 1 the first value in memory, which will be found at 0x1001000
Store this value in the adjacent word, and also place a copy of this value in register $v0
-By default, the value 0xcafebee will be placed at address 0x1001000. Your program must add 1 to the value found at address 0x1001000. For example 0xcafebeee incremented by 1 is the value 0xcafebeef. This answer will be placed in two places:
the adjacent word space, and in register $v0.Do NOT change the .data segment. All of your work MUST be contained in .text
-What a successful ouput looks like: https://content.screencast.com/users/profbsmith/folders/Snagit/media/34becefb-ed96-4c23-8bbc-69b3181c63cc/10.28.2020-09.17.png

.data
A: .word 0xcafebeee
.text
#Your code goes here
la $t1,A
lw $t2,0($t1)
addi $t2,$t2,1
addi $t1,$t1,4
sw $t2,0($t1)
move $v0,$t2

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How can I declear mips array?

I would like to declare
int A[] = {1,2,3,4,5,6,7,8,9,10} in c language as mips.
Here's my code, please give me a solution.
A: .word 1,2,3,4,5,6,7,8,9,10
Is it right?
yes, it's right, then you can use A as the addresss, and A+offset to get the position of every element.

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Plotting a histogram using a csv file

I have a csv file with the following format.
Label 1, 20
Label 2, 10
Label 3, 30
.
.
.
LabelN, 5
How do I plot the second column using the labels given in the csv file as labels on the x-axis?
(Something like this, where 1891-1900 is a label)
EDIT:
Found these questions which are quite similar to mine,
Plotting word frequency histogram using gnuplot
Gnuplot xticlabels with several lines
After trying the commands given in answer 1.
set xtics border in scale 1,0.5 nomirror rotate by -90 offset character 0, 0, 0
plot "data.txt" using 2:xticlabels(1) with histogram
I'm getting a not so clean histogram because the number of labels is quite large. I've tried the formatting given in answer 2. Can anyone suggest a way to get a cleaner histogram?
You have several options:
Plot only the important labels (extremes, mean etc. for example)
Skip every 5th label or so if labels form a series
Split your graph if you must plot every single label.
Seems like case 2) applies here, and thus skipping some of the labels before plotting will make the plot look better.
You can pre-process the file to skip every 5th label (say) using something like the following script:
line_number = 0
for line in open("d1.txt", "r"):
line_split = line.split(",")
if(line_number % 5 == 0):
print line,
else:
print ",",line_split[1],
line_number += 1
You can now plot with appropriate font size
set xtics border in scale 1,0.5 nomirror rotate by -90 offset character 0, 0, 0
set xtics font ",9"
plot "d2.txt" using 2:xticlabels(1) with histogram title "legend_here"

How do I remove the last item of an array?

I have an array of questions for an interactive quiz game. When you answer a question, functionally I want that question to be removed from the array (cat4Questions) so that it won't come back for the player so I tried to splice it.
I wasn't sure if it was working so I traced the array. While I was expecting "question1, question2, question3, question4" to be traced, "question1, question2, question3, question4, question5" was the result of my trace.
This is the line of code where I try to splice the array:
cat4Questions.splice(cat4Questions.length,1);
trace(cat4Questions);
You should take a look at shift() and pop() array methods.
shift()
Removes the first element from an array and returns that element. The remaining array elements are moved from their original position, i, to i-1.
pop()
Removes the last element from an array and returns the value of that element.
In your case, you probably need the pop() function to remove the last element of the array.
Arrays are zero-indexed, so you should use Array.length-1; to get the index position of the array.
cat4Questions.splice(cat4Questions.length-1,1);
trace(cat4Questions);
trace now.
You are probably going to remove items other than the last item in the array. If for example the user answers another question.
You can use this code to remove any question:
cat4Questions.splice(cat4Questions.indexOf(question), 1);
Edit
As I said in the comments below, you don't really have to look at the performance of this. But here is how to use pop instead of splice.
cat4Questions[cat4Questions.indexOf(question)] = cat4Questions.pop();
You can also remove the calls to pop and indexOf because they are not efficient either
lastQuestion = cat4Questions[--numQuestions];
cat4Questions[question.index] = lastQuestion;
lastQuestion.index = question.index;
Where question is the question to be removed, index is the index of the question (you have to keep track of that) and numQuestions is the total number of questions. This way, you never use length, indexOf, pop, splice, ...