I have the following MySql Query:
SELECT * FROM myTable ORDER BY FIELD(
priority,1,2,3,4,5,6,7,8,....,300,0),date_fixed ASC, sno DESC";
In fact, i need to display record ordered by priority ASC but also want to keep all the record having the priority = 0 at the end of the any other numerical value. The above query working fine but I think its not worth to write values starting from 1 to 300 and at the end i just put 0.
My Question is that any shortcut way to achieve the ResultSet as Orderby priority ASC and keeping the 0th priorities at the end?
Related
First of all, I am using MySQL. When I make the following query:
SELECT CodE,sum(tiempo) AS 'tiempo total'
FROM Participa
GROUP BY CodE
ORDER BY 'tiempo total' DESC LIMIT 1;
it shows me the first line of my table instead of the MAX value. However, If I make the following query:
SELECT CodE,sum(tiempo)
FROM Participa
GROUP BY CodE
ORDER BY 2 DESC LIMIT 1
I get the correct result.
I have just changed the alias 'tiempo total' for somthing that should be equivalent.
How it´s possible?
Only use single quotes for string and date constants -- never for column aliases. So:
SELECT CodE, sum(tiempo) AS `tiempo total`
FROM Participa
GROUP BY CodE
ORDER BY `tiempo total` DESC
LIMIT 1;
You are ordering by a constant string, not the name of a column. Hence, if you get the maximum in your query, it would be a total accident.
Note: You can get around these issues by giving columns names that never need to be escaped:
SELECT CodE, sum(tiempo) AS tiempo_total
FROM Participa
GROUP BY CodE
ORDER BY tiempo_total DESC
LIMIT 1;
Easier to type, too.
I am fetching rows from my DB using this request:
SELECT * FROM {$db_sales} WHERE date = '{$date}' ORDER BY 'amount' DESC
So, obviously, i expected the returned values to be sorted in descending order by the amount column in my DB, but it doesn't? it still fetches them, but just doesn't sort them?
Any ideas here? is my SQL statement wrong?
remove single quote around amount like this and try:
SELECT * FROM {$db_sales} WHERE date = '{$date}' ORDER BY amount DESC
Use below query
SELECT * FROM {$db_sales} WHERE date = '{$date}' ORDER BY amount DESC
ORDER BY clause uses column name.
Column name should not give in quotes.
there fore the query becomes as follows
SELECT * FROM {$db_sales} WHERE date = '{$date}' ORDER BY amount DESC
I am using phpMyAdmin to write some SQL code that I thought was simple but proving to be a headache. I'm using this tutorial to help me out. My goal is to get the first and last columns id's from a result set. When I do this query I get 5 rows starting at 15 and going through 11.
SELECT id
FROM boardPost
WHERE recipientId = 1
ORDER BY id DESC
LIMIT 0,5
However, when I try this query I get an error #1064: "You have an error in your SQL syntax."
SELECT FIRST(id)
FROM boardPost
WHERE recipientId = 1
ORDER BY id DESC
LIMIT 0,5
Something like this maybe?
SELECT min(id), max(id)
from (
select id
from boardPost
where recipientId = 1
order by id desc
limit 0,5
) t
I think that is what you want?
Select id from boardPost order by id asc limit 1
and
Select id from boardPost order by id desc limit 1
If you just want the first and the last id of a result set, you could consider this:
SELECT MIN(id) firstId, MAX(id) lastId FROM someTable WHERE aField = 1;
Note that it'll only work if you do use and ORDER BY an AUTO_INCREMENT field, else you might get unexpected results.
It'll only work with the full set. If you need the first and last id of a limited one, you're probably better of using 2 queries with ASC and DESC order and LIMIT 1.
MySQL does not support the FIRST() function. You will need to use the workaround they specified in that tutorial (using ORDER BY and LIMIT)
In some situations (like mine, that first brought me here), there are some rarely-used MySQL "windowing functions" such as FIRST_VALUE and LAST_VALUE that may provide the functionality you're seeking.
(Here's more info on Window Function Concepts and Syntax, and the Wikipedia description of the term.)
I have a MySQL database and a have a funny question.
I need to order the results of a query by a field which has entries of 1,2,3 or 4, ordered descending but with 4 at the end.
So I wish to have the results in the following order
3's
2's
1's
4's
Is this possible at all?
I know I can do order the result array in php but unfortunately I need to do this in an sql statement.
If the field is an int,
ORDER BY (fieldname = 4) DESC, fieldname DESC
should do the trick.
Here is another cool way
ORDER BY MOD(fieldname,4) DESC,fieldname
If the result is a CHAR(1) then
ORDER BY LOCATE(fieldname,'3214'),fieldname
add this to the order
ORDER BY
CASE field_name WHEN 4 THEN 1
ELSE 2
END
this will return the result of the query order using the value of the field
I have a column of states, and, depending on the query, I want to order by results by a particular state, then by id (Asc or Desc, depending). For instance, I might want to show all rows with state "HI", sorted by ID desc, and then all the other rows, sorted by id desc.
I was hoping I could do this in one query, rather than getting all my favored state results, and then getting the rest. Can I?
How about:
SELECT id, state
FROM sometable
ORDER BY IF(state = 'HI', 0, 1) ASC, id DESC;
This will sort 'HI' rows first. If you want them last, change the ASC to DESC.
You have two options:
do a union
write a function and use it to order rows by
In the first case, you could do something like
select 1 as res_order, ...
...
where state like 'hi%'
union
select 2 as res_order, ...
...
where state not like 'hi%'
order by res_order asc, id desc
In the second case, you could do something like
select my_function(state, "hi") as row_order, ...
...
order by row_order
where the function returns lower values for matching states.
The code is off the top of my head: it might need some tweaking to make it runnable.