Im trying to make a pattern that will allow input such as SB 0023467-01 or ST 0023467-02
<input type="text" name="surat_beranak" pattern="[S]+[B\s]+[0-9]{7}+[-]+[0]+[^0-1]"
oninvalid="this.setCustomValidity('Format SB 0029384-01')"value="<?= $surat_beranak;?>"
class="form-control" placeholder="Enter Surat Beranak Number" required>
This is my current input pattern, but it's not working as intended. I need help where the pattern will allow only S as the first letter, then B or T as the second letter, then have a space after. Then there will be 7 numeric digits followed by a dash and a number, 0 then 1 or 2
You're using + between every character, which allows a character to be repeated many times. It is the equivalent of using {1,}. [0-9]{7}+ is invalid.
You're using square brackets, allowing different characters to be used in a same place. A good place to use these would be for the beginning: S[BT] would allow SB or ST. There is no need to wrap single characters with these brackets.
Your current pattern ends with [^0-1], which means "every character except 0 and 1". It goes against your goal of having "01" or "02" at the end.
Your pattern, in HTML, would be S[BT] [0-9]{7}-0[12]. If you're using this pattern anywhere else, you should wrap it between ^ and $, in order to only allow the input you want, and nothing else.
In the future, please use regex testers in order to test your pattern. Example with the working pattern and a few input examples.
Related
I have different sign up pages that load for different countries, and I need the telephone input to be for that specific country, such as on one page it needs to be the country code 1234 followed by any 3 numbers and then any 4 numbers. so I need the pattern for the input in the html form. I am dealing with it on the server side with PHP, but I want to handle it on the client side via the input restriction pattern, as to be more efficient. Im sure its really simple but I cant seem to find a simple solution. thanks for your help
i tried the pattern restriction, i casn get the any 4 number, space, any 3 number, space any 4 numbers. but i could not get the: '1234' specific number, space, any 3 number, space, any 4 numbers.
In this example, the pattern attribute used in the input verifies that the input follows the E.164 standard. The pattern ^+(?:[0-9] ?){6,14}[0-9]$ accepts only strings beginning with + followed by 6-14 numeric characters(optionally separated by spaces) and a numeric character at the end:
<input type="tel" id="phone" name="phone" pattern="^\+(?:[0-9] ?){6,14}[0-9]$" placeholder="+391234567890" oninput="if(this.value.length==3) this.value= this.value + ' '; this.value=this.value.replace(/^(\+39[0-9]{2})([0-9]{4})([0-9]{4})$/,'$1 $2 $3')" value="+39 " minlength="14" maxlength="14" readonly onfocus="this.removeAttribute('readonly')">
The oninput attribute used to format the phone number as the user includes it, in this case to format it as +39 (XXX) XXXX XXXX (Italian prefix, my country for simplicity) In addition, the value attribute is set to +39 so that the user cannot delete the international prefix.
As a user is typing their new password, I want them to be able to see if their password meets the requirements or not. I have a Regex pattern set up inside the input tag, and if the requirements aren't met, the input box is outlined in red and the form can't be submitted. This looks like:
<input type="password" pattern="((?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.[!###$%&?]).{8,32})" placeholder="Password" required />
I adapted that pattern from here. I have it so that the user's password must contain 8-32 characters, one uppercase letter, one lowercase letter, one special character (!##$%&?), and one number, and that works fine. However, I also want to exclude some special characters from the input, for example, the semicolon (;). I have tried adding (?!.[;]) like so:
((?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.[!###$%&?])(?!.[;]).{8,32})
This breaks the entire pattern, though. Could someone explain what I am doing wrong and how I can fix it? Or would it be better to do this manually by using a Javascript listener to check if the password meets the requirements each time the user does a keypress?
Try with:
((?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[!###$%&?])(?!.*[;]).{8,32})
Fine-tunings from your regex:
Added back an asterisk * to the positive lookahead for symbols list [!###$%&?]
Added back an asterisk * to the negative lookahead for symbol [;]
You need an asterisk * after the dot . in order to allow matching of multiple characters (by *) for any character (by .). Otherwise, your regex allows only ONE single character before the symbols to include and exclude.
Currently, I have the following input defined on an HTML page inside an Angular 9 app:
<input type="text" formControlName="amountToWithholdInput"
onkeyup="this.value = this.value.replace(/[^0-9.%$]/, '');">
As a person types, it automatically removes any character that isn't a number, a $, a % or a decimal.
How do I modify this so it will remove a % if they've already typed a $, and vice-versa (remove the $ if they've already typed a %)? In other words, it needs to check and see if a particular character exists, then remove the "opposite" character if they try to type that.
Or am I going about this all wrong? Is there some other way to do this that I haven't thought of?
Essentially you are asking your users to insert a numeric value with an optional fractional part and a trailing $ or % sign and everything else should be dropped on key input.
So, we could use a regex that matches any string but keeps the fractional numbers and a single sign in an optional group and then replace the original string only with that group $1 while the remainder in the full match gets dropped. Try it:
<input type="text" formControlName="amountToWithholdInput"
onkeyup="this.value = this.value.replace(/^((?:[0-9]+\.?[0-9]*)[%$]?)?.*/, '$1')">
To make this work we need to ensure the inner regex can also match an incomplete version of the final string, i.e. the number, dot, and sign part need to be made optional as well. If you need a more specific (e.g. only two fractional numbers) or different order (e.g. dollar sign first, percent last) we can adjust the inner regex easily but the same concept can be applied, i.e.
<input type="text" formControlName="amountToWithholdInput"
onkeyup="this.value = this.value.replace(/((?:[0-9]*\.?[0-9]{0,2}[%]?)|(?:[$]?[0-9]*\.?[0-9]{0,2}))?.*/, '$1')">
Here, the order of the sub-patterns becomes important as we want to match only one sign and only in a specific position.
Recently I tried alot but I still unable to figure how should I able to validation for my text field. I hope I can get some help from here, my questions is I want to validate input text field only accept A-Z a-z 0-9 and space within word. And at least one char or number.
For example, "abc def" , "abc092", "abcdef"
Only in HTML input tag element .
I tried this
but this pattern unable to fullfil my requirements.
the pattern i want to achieve is
1) abc def
2) abcdef
3) abc123
4) a1b2c3 d4e5
5) allow to have empty space within words
the pattern i dont want to accept is
1) empty string
2) no alot of whitespace at the begining or end of the string
3) no bracket and etc special characters
Try
<input type="text" pattern="^\w+([\w ]*\w)*$">
Basically the break down is this:
\w+ - Select a word character ("A-z0-9") one or more times
()* - Select what's in here 0 or more times, which is
[\w ]*\w - Select a word character or space one or more times followed by another word character
No leading or trailing white space allowed. Only word characters allowed and internal spaces.
For some unit tests and breakdown of the regex see: https://regex101.com/r/7UnL9J/1
You can use the Pattern attribute with regex but it is supported only in HTML 5.
Like this " id="username" pattern="[A-Za-z0-9]+"
Check the below link for more information
https://html.com/attributes/input-pattern/#Username_Patterns
Have you tried this?
<input type="text" pattern="[a-zA-Z0-9\s]+">
I am trying to make an HTML input to only be able to receive float numbers like: x.123 x,123 x.123456 x,123456
Where x can have one or 2 digits: x or xx.
Basically I would like to know how to make a pattern that only accepts those kind of numbers.
Reading around the WEB I found two patterns that should've matched my needs, but they do not work.
^[+-]?([0-9]*[.])?[0-9]+$
^(?=.)(\d{1,2}(,\d{3,6})*)?(\.\d+)?$
These were found, I don't understand how this works.
Googling Regex I found a lot of tools that work for,on or with (I don't have any idea) JavaScript, PHP, RUBY, PCRE.
I don't understand what coding language they use or how. And after digging into it more I found myself even more lost and having more questions.
Is there any reverse tool that actually makes the regex ?
I found this http://buildregex.com/ but I don't know how it works...
This is me trying to make my pattern...
/(?:(?:(?:(?:(?:(?:)|(?:(?:22\.123))|(?:(?:2\.123))|(?:(?:22\.123))|(?:)|(?:)|(?:))))))/
EDIT:
This is is the input:
<input id="text-input" type="text" inputmode="numeric" pattern="/^[\d]{1,2}[.,][\d]{3,6}$/"
oninvalid="this.setCustomValidity('Please enter a number with 3-6 decimals')"
onchange="try{setCustomValidity('')}catch(e){}"
oninput="setCustomValidity(' ')"
>
You can use pattern="^\d{1,2}[.,]\d{3,6}$"
^\d{1,2} starting with 1 to 2 digit(s)
[.,] followed by either a comma, either a dot
\d{3,6}$ ending by 3 to 6 digits
There're no needs for delimiters and anchors, use:
pattern="\d{1,2}[.,]\d{3,6}"
^\d{1,2}[\.]\d{3,6}$ ,
^d{1,2} means: max 2 digit start with.
[\.] means : having . in middle.
d{3,6} means min 3 and max 6 digit of decimal points at the end.