I used a CSS Grid Layout to display data in a table-like manner with the last column spanning multiple rows. While this basically works now , I absolutely cannot get the vertical alignment right. See the following snippet:
div {
border: 1px solid black;
padding: 3px;
}
.table {
display: grid;
grid-template-columns: min-content min-content min-content;
white-space: nowrap;
grid-auto-rows: auto;
grid-gap: 3px;
width: min-content;
grid-auto-flow: row dense;
}
.col1 {
grid-column-start: 1;
height: min-content;
}
.col2 {
grid-column-start: 2;
height: min-content;
}
.col3 {
grid-column-start: 3;
grid-row-end: span 2;
}
<div class="table">
<div class="col1">A1</div>
<div class="col2">B1</div>
<div class="col1">A2</div>
<div class="col2">B2</div>
<div class="col3">this<br>is<br>the first<br>very<br>very<br>long<br>cell</div>
<div class="col1">A3</div>
<div class="col2">B3</div>
<div class="col1">A4</div>
<div class="col2">B4</div>
<div class="col3">second cell</div>
</div>
I want the left two columns to always the minimum height and be aligned with the top of each multi-row cell. In this simplified example, that means that A2 and B2 should move up and be shown right under A1 and B1.
I also tried adding a dummy <div> before each col3 and make it take all extra height. But no matter what I tried, the height is always distributed equally among all rows.
Is there a way to make the cells top-aligned with the multi-row cell?
Related
Is it possible to use CSS grid to auto-fit the columns in a row to always take up the whole width?
I know this would be possible if you knew the number of columns, but is it possible with a dynamic number of columns?
Image for reference of what I'd like to achieve.
column example image
This is what I have so far, but you can see that the lower row item doesn't take up all the row width.
.wrapper {
display: grid;
grid-template-columns: 200px 200px;
column-gap: 20px;
}
.grid {
border: solid #FF8181 1px;
display: grid;
grid-template-rows: 40px repeat(8, minmax(0, 1fr));
width: 200px;
grid-template-columns: repeat(auto-fit, minmax(0, 1fr));
}
.row-item {
background: #FFC555;
border: 1px solid #835600;
width: 100%;
height: 40px;
}
.item-1, .item-1 {
grid-row: 2 / span 1;
}
.item-2 {
grid-row: 6 / span 1;
font-size: 12px;
}
<div class='wrapper'>
<div class='grid'>
<div class='row-item item-1'></div>
<div class='row-item item-1'></div>
<div class='row-item item-2'>I'm too short</div>
</div>
<div class='grid'>
<div class='row-item item-1'></div>
<div class='row-item item-1'></div>
<div class='row-item item-1'></div>
<div class='row-item item-2'>Should be the whole width</div>
</div>
</div>
you can stretch a element in a grid over the whole width by using:
grid-column: 1 / all;
or
grid-column: 1 / -1;
unfortunately does it affect the other elements in the same grid.
A solution like "span last-column" doesnt exist yet, but is already discussed: https://github.com/w3c/csswg-drafts/issues/2402
Maybe they will implement the function soon. Good luck anyways
What I need doesn't exist yet. This does indeed look like the latest update:
A solution like "span last-column" doesnt exist yet, but is already
discussed: https://github.com/w3c/csswg-drafts/issues/2402
I calculated overlapping grid items and rendered items in subgrids based on this answer:
Group multiple overlapping timeblocks that may not have a direct overlap
With js its different.
Find the grid
Get the Style of the Grid
Filter the Style of the Grid for grid-template-columns
Set the Element grid-column to the number of columns
Your code will look like this:
window.addEventListener("DOMContentLoaded", function(){
// find the elemen by the class and safe it as grid
let grid = document.querySelector(".grid")
// sage the style of the element
const gridComputedStyle = window.getComputedStyle(grid);
// get the grid-template-columns style poperty of the element and format them to a useful value
const gridColumnCount = gridComputedStyle.getPropertyValue("grid-template-columns").split(" ").length
// log for debug
console.log(gridColumnCount)
// set the column style of the element to the span of the variable
document.getElementById("item-2").style.gridColumn = "1 / span " + gridColumnCount;
// set the row style because it got overwritten by the line above
document.getElementById("item-2").style.gridRow = "6 / span " + gridColumnCount;
})
note that i have changed your html and css too:
html:
<div class='grid'>
<div class='row-item item-1'></div>
<div class='row-item item-1'></div>
<div class='row-item item-1'></div>
<div class="row-item" id="item-2">whole width</div>
</div>
Just deleted the wrapper for a better overview
CSS:
.grid {
border: solid #FF8181 1px;
display: grid;
grid-template-rows: repeat(8, minmax(0, 1fr));
width: 300px;
grid-template-columns: repeat(auto, minmax(0, 1fr));
}
.row-item {
background: #FFC555;
border: 1px solid #835600;
width: 100%;
height: 40px;
}
.item-1, .item-1 {
grid-row: 2;
}
.item-2 {
grid-row: 5;
font-size: 12px;
}
I had to change the grid-template-value of grid from auto-fit to auto. Otherwise there would be a bug when counting the columns
In this case, there are multiple input fields across multiple rows.
Each field width given as no of characters that field should support
If field width is 10, it should support 10 characters
There is a fixed margin between fields
Ex:
First row have 3 input fields with widths as (10, 10 ,10)
Second row have 4 input fields with widths as (10, 5, 5, 10)
Third row have 2 input fields with widths as (15, 15)
In this case summation of field's widths is 30 in all three rows
So left and right ends of row's should be in a same vertical line
How to calculate field's widths?
Is that possible to keep alignment between rows?
Thanks
You can do it quite easily with CSS grid. Your html may change, but the solution lay on grid.
div {
display: grid;
grid-gap: 1rem;
grid-template-columns: repeat(6, 5fr);
grid-template-rows: repeat(3, 1fr);
}
section:nth-child(1),
section:nth-child(2),
section:nth-child(3),
section:nth-child(4),
section:nth-child(7) {
grid-column: span 2;
border: 3px solid orange;
}
section:nth-child(8),
section:nth-child(9) {
grid-column: span 3;
border: 3px solid red;
}
<div>
<section>10</section>
<section>10</section>
<section>10</section>
<section>10</section>
<section>5</section>
<section>5</section>
<section>10</section>
<section>15</section>
<section>15</section>
</div>
You could use flex grow, for example like this:
<div class="flexContainer">
<div class="flexItem10">…</div>
<div class="flexItem5>…</div>
<div class="flexItem5>…</div>
<div class="flexItem10">…</div>
.flexContainer {
display: flex;
gap: 20px;
}
.flexItem5 {
flex-grow: 5;
}
.flexItem10 {
flex-grow: 10;
}
I would like to divide a grid with an undetermined number of columns.
An example:
grid-template-columns: repeat(auto-fill, 90px);
A number of columns are created, but I don't know how many.
I would like to know if there is a way to fill out these columns proportionally.
Let's say:
.whatever-1 {
// would take up 2/3 of the grid columns
}
and
.whatever-2 {
// would take up 1/3 of the grid columns
}
But I am not even close to the answer. Please give me a hand.
This is just an example that I did to help me to explain my problem.
.container {
display: grid;
grid-template-columns: repeat(auto-fill, 90px);
width: 100%;
height: 100vh;
color: white;
}
.whatever-1 {
grid-column: 1 / span 2;
background-color: blue;
}
.whatever-2 {
grid-column: 3 / span 5;
background-color: red;
}
<div class="container">
<div class="whatever-1">Whatever 1</div>
<div class="whatever-2">Whatever 2</div>
</div>
If you want to divide it into 1/3 and 2/3 then it means that the first one will be equal to half the width of the second one thus we have a relation of 2x. In this case simply make one of them span two columns without the need of defining any column template:
.container {
display: grid;
grid-auto-flow:column;
height: 100vh;
color: white;
}
.whatever-1 {
background-color: blue;
}
.whatever-2 {
grid-column: span 2;
background-color: red;
}
<div class="container">
<div class="whatever-1">Whatever 1</div>
<div class="whatever-2">Whatever 2</div>
</div>
I want to use CSS grid and the following is a mock-up of the aim:
I'm building an interface that should expand rightward to fill the browser screen; my current code causes column 2 of the outer grid to be as wide as the browser in addition to column 1; or maybe one of it's children is causing this and it's just expanding to accommodate. Either way, it's spilling off the page horizontally
So the code:
#main {
width: 100%;
display: grid;
grid-template-columns: 250px 100%;
grid-template-rows: 100px 100%;
}
#col-2-outer {
display: grid;
grid-template-columns: 250px auto;
grid-template-rows: 100%;
}
#row-1-inner {
grid-column: span 2;
}
#col-2-inner table {
width: 100%;
}
<div id="main">
<div id="col-1-outer"></div>
<div id="col-2-outer">
<div id="row-1-inner"></div>
<div id="row-2-inner">
<div id="col-1-inner"></div>
<div id="col-2-inner">
<table></table>
</div>
</div>
</div>
</div>
FYI, for the time being I've forgone template areas until I get a handle on the basics (unless this somehow solves my problem but I gather this is strictly a code organization feature?).
I'd suggest to change your markup with a 3x2 grid like below:
Remove the hierarchical structure like you have in your code and add one element for each section in the grid.
Note that in the rule grid-template-columns: 250px 150px auto, 250px is the width of your col-1-outer and 150px is the width of the col-1-inner.
Span the first column over the two rows by using grid-row: span 2
Span the first row in the second column by using grid-column: span 2.
Extend the table over the last grid item by using 100% width and height.
See demo below:
* {
border: 1px solid; /* For illustration */
}
#main {
width: 100%;
display: grid;
grid-template-columns: 250px 150px auto;
grid-template-rows: 100px auto;
}
#col-1-outer {
grid-row: span 2;
}
#row-1-inner {
grid-column: span 2;
}
#col-2-inner table {
width: 100%;
height: 100%;
}
<div id="main">
<div id="col-1-outer">col-1-outer</div>
<div id="row-1-inner">col2-row-1-inner</div>
<div id="col-1-inner">col2-row2-inner</div>
<div id="col-2-inner">
<table><tr><td>table</td></tr></table>
</div>
</div>
The 100% for the 2nd column in your grid-template-columns is based on the width of the container - rather than occupying the space outstanding within the container, it will push out to the right because the 2nd column is trying to match the width of the container.
Try changing this to auto and this should rectify the issue, as it will only take up the space up to the end of the container and no further.
Source: https://developer.mozilla.org/en-US/docs/Web/CSS/grid-template-columns
I was hoping to use CSS Grid to reverse the apparent order of two side-by-side divs, where one of the divs grows arbitrarily (I don't want to use floats).
I've created a plunkr here: http://plnkr.co/edit/6WZBnHbwhD7Sjx2ovCO7?p=preview
#container {
grid-template-columns: 240px 1fr;
display: grid;
}
.a {
background: yellow;
}
.b {
background: blue;
color: white;
}
#container>.a {
grid-column: 1;
}
#container>.b {
grid-column: 2;
}
#container.reverse>.a {
grid-column: 2;
}
#container.reverse>.b {
grid-column: 1;
}
<div id="container" class="reverse" style="width: 800px;">
<div class="a">A</div>
<div class="b">B</div>
</div>
The crux of it is that when I have the .reverse class applied (so that you should see B | A), B is offset to a new line so it looks more like:
| A
B
If I invert the document ordering of .a with .b, this goes back to normal (but of course, if I drop the .reverse class, I get the same problem).
Why is this, and how can I address?
As the Grid auto-placement algorithm lays out items in the container, it uses next available empty cells (source).
In your source code the A element comes before the B element:
<div id="container" class="reverse" style="width: 800px;">
<div class="a">A</div>
<div class="b">B</div>
</div>
Therefore, the grid container first places A, then uses the next available space to place B.
By default, the auto-placement algorithm looks linearly through the grid without backtracking; if it has to skip some empty spaces to place a larger item, it will not return to fill those spaces. To change this behavior, specify the dense keyword in grid-auto-flow.
http://www.w3.org/TR/css3-grid-layout/#common-uses-auto-placement
grid-auto-flow: dense
One solution to this problem (as you have noted) is to override the default grid-auto-flow: row with grid-auto-flow: dense.
With grid-auto-flow: dense, the Grid auto-placement algorithm will look to back-fill unoccupied cells with items that fit.
#container {
display: grid;
grid-template-columns: 240px 1fr;
grid-auto-flow: dense; /* NEW */
}
7.7. Automatic Placement: the grid-auto-flow
property
Grid items that aren’t explicitly placed are automatically placed into
an unoccupied space in the grid container by the auto-placement
algorithm.
grid-auto-flow controls how the auto-placement algorithm works,
specifying exactly how auto-placed items get flowed into the grid.
dense
If specified, the auto-placement algorithm uses a “dense” packing
algorithm, which attempts to fill in holes earlier in the grid if
smaller items come up later. This may cause items to appear
out-of-order, when doing so would fill in holes left by larger items.
#container {
display: grid;
grid-template-columns: 240px 1fr;
grid-auto-flow: dense; /* NEW */
}
.a {
background: yellow;
}
.b {
background: blue;
color: white;
}
#container>.a {
grid-column: 1;
}
#container>.b {
grid-column: 2;
}
#container.reverse>.a {
grid-column: 2;
}
#container.reverse>.b {
grid-row: 1;
grid-column: 1;
}
<div id="container" class="reverse" style="width: 800px;">
<div class="a">A</div>
<div class="b">B</div>
</div>
grid-row: 1
Another solution would be to simply define the row for the second item.
#container>.b {
grid-column: 2;
grid-row: 1; /* NEW */
}
#container {
display: grid;
grid-template-columns: 240px 1fr;
}
.a {
background: yellow;
}
.b {
background: blue;
color: white;
}
#container>.a {
grid-column: 1;
}
#container>.b {
grid-column: 2;
grid-row: 1; /* NEW */
}
#container.reverse>.a {
grid-column: 2;
}
#container.reverse>.b {
grid-row: 1;
grid-column: 1;
}
<div id="container" class="reverse" style="width: 800px;">
<div class="a">A</div>
<div class="b">B</div>
</div>
The simplest way is to add order: 1 to element B or order: -1 to element A in .reverse
It's also correct CSS rather than hack-y
I'm not sure how to reverse more grid items. But if you have 2 grid items in your grid, you can simply position 2nd grid item using below code.
#container > .b {
grid-column-start: 1;
grid-row-start: 1;
}
I had this same issue just now. I tried auto-row-dense and then set the direction of the container parent to rtl. It worked.
Just this, on the plunker link, seemed to do the trick.
.reverse{
display: grid;
grid-template-columns: repeat(2, 1fr);
grid-auto-flow: dense;
direction: rtl;
}
You can use direction property to reverse a grid x-axis order.
Nested elements will be reversed too so you have to make sure to add additional styles to fix this behavior.
<div class="grid">
<div class="grid-item"><div>
</div>
<style>
.grid { direction : rtl; }
.grid-item { direction : ltr; }
</style>
Edit: this may work but could cause accessibilty issues.
Round peg in square hole
Remember even if you're using fancy 'new' grid features the older flex layout will still work. You can combine them, nest them and sometime you have to admit that certain problems like this may just be better solved with good old
flex-direction: row-reverse
But I know some people will want to downvote me for that so here's another way with grid.
Use named template regions
You can use named template regions and reverse them in the definition.
#container
{
grid-template-areas: a b;
grid-template-rows: 240px 1fr;
display: grid;
}
#container.reverse
{
// note the order is flipped for both these properties
grid-template-areas: b a;
grid-template-rows: 1fr 240px;
}
.a {
grid-area: a;
background: yellow;
}
.b {
grid-area: b;
background: blue;
color: white;
}
Here's an more complex example that uses that technique with media queries
I found out: I need to apply grid-auto-flow: dense; on the container:
#container {
grid-template-columns: 240px 1fr;
display: grid;
grid-auto-flow: dense;
}
According to MDN, this algorithm attempts to fill in holes earlier in the grid.
I want to mention a solution which is also relevant to this question in some cases. When having a multi-row layout, and you want a reversed look of how you grid fills up.
You can play with grid-start combined with some :nth-child & :last-child selectors to achieve a reverse auto flow.
Reversed grid-auto-flow: column
.container{
display: grid;
width: 10rem;
gap: 0.5rem;
grid-template-rows: repeat(2, 1fr);
grid-auto-flow: column; /* => vertical grid*/
}
/* REMOVE THIS TO SEE THE DIFFERENCE */
.pixel:nth-child(odd):last-child { /* reversed auto-flow: column */
grid-row-start: 2;
}
.pixel{
width: 2rem;
height: 2rem;
background: red;
border: 1px solid black
}
<div class="container">
<!-- ADD/REMOVE SOME PIXELS to see the result -->
<div class="pixel"></div>
<div class="pixel"></div>
<div class="pixel"></div>
<div class="pixel"></div>
<div class="pixel"></div>
<div class="pixel"></div>
<div class="pixel"></div>
</div>
Reversed: horizontal & vertical
.container{
display: grid;
width: 10rem;
gap: 0.5rem;
grid-template-rows: repeat(2, 1fr);
grid-auto-flow: column;
direction: rtl; /* reversed horizontal */
}
/* REMOVE THIS TO SEE THE DIFFERENCE */
.pixel:nth-child(odd):last-child { /* reversed vertical */
grid-row-start: 2;
}
.pixel{
width: 2rem;
height: 2rem;
background: red;
border: 1px solid black
}
<div class="container">
<!-- ADD/REMOVE SOME PIXELS to see the result -->
<div class="pixel">1</div>
<div class="pixel">2</div>
<div class="pixel">3</div>
<div class="pixel">4</div>
<div class="pixel">5</div>
<div class="pixel">6</div>
<div class="pixel">7</div>
</div>
I found out: I need to apply grid-auto-flow: dense; on the container: