how to output all the keys and values from json using jq? - json

Question

I am trying to out all the data from my json file that matches the value "data10=true" it does that but only grabs the names, how can i make it so it will output everything in my json file with anything that matches the "data10=true"?
this is what ive got data=$(jq -c 'to_entries[] | select (.value.data10 == "true")| [.key, .value.name]' data.json )
This is in my YAML template btw, running it as a pipeline in devops.

Answer 1

The detailed requirements are unclear, but hopefully you'll be able to use the following jq program as a guide:
..
| objects
| select( .data10 == "true" )
| to_entries[]
| select(.key != "data10")
| [.key, .value]
This will recursively (thanks to the initial ..) examine all the JSON objects in the input.
p.s.
If you want to make the selection based on whether .data10 is "true" or true, you could change the criterion to .data10 | . == true or . == "true".

Answer 2

jq 'to_entries | map(select(.value.data10=="true")) | from_entries' data.json
input data.json,
with false value:
{
"FOO": {
"data10": "false",
"name": "Donald",
"location": "Stockholm"
},
"BAR": {
"data10": "true",
"name": "Walt",
"location": "Stockholm"
},
"BAZ": {
"data10": "true",
"name": "Jack",
"location": "Whereever"
}
}
output:
{
"BAR": {
"data10": "true",
"name": "Walt",
"location": "Stockholm"
},
"BAZ": {
"data10": "true",
"name": "Jack",
"location": "Whereever"
}
}
based on: https://stackoverflow.com/a/37843822/983325