I am using MYSQL Query Browser version 1.2.11, and write the below SQL query cannot work in MYSQL Query Browser version 1.2.11.
select id,name
from(select t.*,cast(regexp_substr(name,'[0-9]+') as unsigned) col1
,cast(regexp_substr(name,'[0-9]+',1,2) as unsigned) col2
,cast(regexp_substr(name,'[0-9]+',1,3) as unsigned) col3
,cast(regexp_substr(name,'[0-9]+',1,4) as unsigned) col4
from filing_code_management t) c
order by col1,col2,col3,col4
I have tried this SQL query to use in the online dbfiddle, just SQL 8.0 can work in https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=e43d94d0418854375a07c2bbf1e44339
May I know got any method can replace this SQL query code to suitable in my old MYSQL DB version 5.5? My side need to use old version to run the SQL. Hope someone can guide me, thanks.
The error appears FUNCTION db_12668458.regexp_substr does not exist in This old version of DB.
Related
The statement is like SELECT * FROM db.table group by id desc;
Would raise an error like
15:02:24 SELECT * FROM db.table group by id
desc LIMIT 0, 10 Error Code: 1064. You have an error in your SQL
syntax; check the manual that corresponds to your MySQL server version
for the right syntax to use near 'desc LIMIT 0, 10' at line 1 0.00014
sec
on MySQL 8.0.13 in Ubuntu 18.04 Desktop 64bit
which would be fine on MySQL 5.7 in Windows or CentOS or Ubuntu.
I know basically, the select statement is like.
SELECT statement... [WHERE condition | GROUP BY `field_name(s)` HAVING condition] ORDER BY `field_name(s)` [ASC | DESC];
So is this 5.7's problem not to issue the error?
Or something more complicated on SQL standard?
I have the same issue, so for MySQL 8, I used the sql like that:
SELECT * FROM db.table
group by id
order by id desc
Taking from #P.Salmon's comment for the question.
If you look up the select statement in the manual
http://dev.mysql.com/doc/refman/5.7/en/select.html you will see
that up to 5.7 asc|desc are optional modifiers to the group by
statement which are no longer present from 8.0.and if you look at the
upgrade documentation
https://dev.mysql.com/doc/refman/8.0/en/upgrading-from-previous-series.html#upgrade-sql-changes
This deprecation is documented.
Since this situation, #Linda Li's answer could be a good option.
This query makes no sense:
SELECT *
FROM db.table
GROUP BY id DESC;
You are doing an aggregation query. So (presumably), the table has multiple rows per id. Those are condensed down to one row. What values should be used for the other columns? It is sad that MySQL ever supported this syntax. So a welcome change is that ONLY_FULL_GROUP_BY is now the default.
A small hint is that using an aggregation query with no aggregation functions is suspicious.
Perhaps you want:
select id, min(col1), min(col2), . . .
from t
group by id;
Or more likely, you want a particular row, such as the "earliest" or "most recent", something like:
select t.*
from t
where t.createdAt = (select min(t2.createdAt) from t t2 where t2.id = t.id);
I'd like to run a query like the following:
SELECT GROUP_CONCAT((SELECT columnA WHERE columnB)) AS filtered_list FROM ...
This works on MySQL 5.7 but not 5.6. I'm wondering if there's a workaround or if this is simply unsupported before 5.7. I can't find anything in the update documentation that would explain the change in syntax.
Here's a simpler version for testing:
SELECT 1 AS a, (SELECT 1) AS b, (SELECT 1 WHERE 1) AS c
This works fine on MySQL v5.7, but on v5.6 the last column will throw a syntax error. Does anyone know a way to make this work?
I'm trying to use MySQL to create a view with the "WITH" clause
WITH authorRating(aname, rating) AS
SELECT aname, AVG(quantity)
FROM book
GROUP BY aname
But it doesn't seem like MySQL supports this.
I thought this was pretty standard and I'm sure Oracle supports this. Is there anyway to force MySQL to use the "WITH" clause? I've tried it with the MyISAM and innoDB engine. Both of these don't work.
Update: MySQL 8.0 is finally getting the feature of common table expressions, including recursive CTEs.
Here's a blog announcing it: http://mysqlserverteam.com/mysql-8-0-labs-recursive-common-table-expressions-in-mysql-ctes/
Below is my earlier answer, which I originally wrote in 2008.
MySQL 5.x does not support queries using the WITH syntax defined in SQL-99, also called Common Table Expressions.
This has been a feature request for MySQL since January 2006: http://bugs.mysql.com/bug.php?id=16244
Other RDBMS products that support common table expressions:
Oracle 9i release 2 and later:
http://www.oracle-base.com/articles/misc/with-clause.php
Microsoft SQL Server 2005 and later:
http://msdn.microsoft.com/en-us/library/ms190766(v=sql.90).aspx
IBM DB2 UDB 8 and later:
http://publib.boulder.ibm.com/infocenter/db2luw/v8/index.jsp?topic=/com.ibm.db2.udb.doc/admin/r0000879.htm
PostgreSQL 8.4 and later:
https://www.postgresql.org/docs/current/static/queries-with.html
Sybase 11 and later:
http://dcx.sybase.com/1100/en/dbusage_en11/commontblexpr-s-5414852.html
SQLite 3.8.3 and later:
http://sqlite.org/lang_with.html
HSQLDB:
http://hsqldb.org/doc/guide/dataaccess-chapt.html#dac_with_clause
Firebird 2.1 and later (the first Open Source DBMS to support recursive queries):
http://www.firebirdsql.org/file/documentation/release_notes/html/rlsnotes210.html#rnfb210-cte
H2 Database (but only recursive):
http://www.h2database.com/html/advanced.html#recursive_queries
Informix 14.10 and later:
https://www.ibm.com/support/knowledgecenter/SSGU8G_14.1.0/com.ibm.sqls.doc/ids_sqs_with.htm
You might be interested in something like this:
select * from (
select * from table
) as Subquery
You've got the syntax right:
WITH AuthorRating(AuthorName, AuthorRating) AS
SELECT aname AS AuthorName,
AVG(quantity) AS AuthorRating
FROM Book
GROUP By Book.aname
However, as others have mentioned, MySQL does not support this command. WITH was added in SQL:1999; the newest version of the SQL standard is SQL:2008. You can find some more information about databases that support SQL:1999's various features on Wikipedia.
MySQL has traditionally lagged a bit in support for the SQL standard, whereas commercial databases like Oracle, SQL Server (recently), and DB2 have followed them a bit more closely. PostgreSQL is typically pretty standards compliant as well.
You may want to look at MySQL's roadmap; I'm not completely sure when this feature might be supported, but it's great for creating readable roll-up queries.
Oracle does support WITH.
It would look like this.
WITH emps as (SELECT * FROM Employees)
SELECT * FROM emps WHERE ID < 20
UNION ALL
SELECT * FROM emps where Sex = 'F'
#ysth WITH is hard to google because it's a common word typically excluded from searches.
You'd want to look at the SELECT docs to see how subquery factoring works.
I know this doesn't answer the OP but I'm cleaning up any confusion ysth may have started.
Building on the answer from #Mosty Mostacho, here's how you might do something equivalent in MySQL,for a specific case of determining what entries don't exist in a table, and are not in any other database.
select col1 from (
select 'value1' as col1 union
select 'value2' as col1 union
select 'value3' as col1
) as subquery
left join mytable as mytable.mycol = col1
where mytable.mycol is null
order by col1
You may want to use a text editor with macro capabilities to convert a list of values to the quoted select union clause.
MariaDB is now supporting WITH. MySQL for now is not.
https://mariadb.com/kb/en/mariadb/with/
Have you ever tried Temporary Table?
This solved my convern:
create temporary table abc (
column1 varchar(255)
column2 decimal
);
insert into abc
select ...
or otherwise
insert into abc
values ('text', 5.5), ('text2', 0815.8);
Then you can use this table in every select in this session:
select * from abc inner join users on ...;
WITH authorRating as (select aname, rating from book)
SELECT aname, AVG(quantity)
FROM authorRating
GROUP BY aname
What is the correct syntax to get the over clause to work in mysql?
I would like to see the total sms's sent by each user without grouping it with the group by clause.
SELECT
username,
count(sentSmsId) OVER (userId)
FROM
sentSmsTable,
userTable
WHERE
userId = sentUserId;
MySQL 8 has got the window functions! Therefore, you can write your query in it like this:
SELECT username,
count(sentSmsId) OVER (partition by userId)
FROM sentSmsTable
JOIN userTable ON userId = sentUserId;
There is no OVER clause in MySQL that I know of, but here is a link that might assist you to accomplish the same results:
http://explainextended.com/2009/03/10/analytic-functions-first_value-last_value-lead-lag/
Hope this helps.
MySQL does not currently support window functions, so over() will only yield syntax errors (or garbage, if it's accepted regardless).
MySQL Doesn't have window functions until the most recent release: MySQL 8 (release in April, 2018). MS SQL Server also accepts OVER clause.
The syntax is:
function(col1) OVER (PARTITION BY col2 ORDER BY col3)
Check out https://mysqlserverteam.com/mysql-8-0-2-introducing-window-functions/ for more examples.
I'm trying to use MySQL to create a view with the "WITH" clause
WITH authorRating(aname, rating) AS
SELECT aname, AVG(quantity)
FROM book
GROUP BY aname
But it doesn't seem like MySQL supports this.
I thought this was pretty standard and I'm sure Oracle supports this. Is there anyway to force MySQL to use the "WITH" clause? I've tried it with the MyISAM and innoDB engine. Both of these don't work.
Update: MySQL 8.0 is finally getting the feature of common table expressions, including recursive CTEs.
Here's a blog announcing it: http://mysqlserverteam.com/mysql-8-0-labs-recursive-common-table-expressions-in-mysql-ctes/
Below is my earlier answer, which I originally wrote in 2008.
MySQL 5.x does not support queries using the WITH syntax defined in SQL-99, also called Common Table Expressions.
This has been a feature request for MySQL since January 2006: http://bugs.mysql.com/bug.php?id=16244
Other RDBMS products that support common table expressions:
Oracle 9i release 2 and later:
http://www.oracle-base.com/articles/misc/with-clause.php
Microsoft SQL Server 2005 and later:
http://msdn.microsoft.com/en-us/library/ms190766(v=sql.90).aspx
IBM DB2 UDB 8 and later:
http://publib.boulder.ibm.com/infocenter/db2luw/v8/index.jsp?topic=/com.ibm.db2.udb.doc/admin/r0000879.htm
PostgreSQL 8.4 and later:
https://www.postgresql.org/docs/current/static/queries-with.html
Sybase 11 and later:
http://dcx.sybase.com/1100/en/dbusage_en11/commontblexpr-s-5414852.html
SQLite 3.8.3 and later:
http://sqlite.org/lang_with.html
HSQLDB:
http://hsqldb.org/doc/guide/dataaccess-chapt.html#dac_with_clause
Firebird 2.1 and later (the first Open Source DBMS to support recursive queries):
http://www.firebirdsql.org/file/documentation/release_notes/html/rlsnotes210.html#rnfb210-cte
H2 Database (but only recursive):
http://www.h2database.com/html/advanced.html#recursive_queries
Informix 14.10 and later:
https://www.ibm.com/support/knowledgecenter/SSGU8G_14.1.0/com.ibm.sqls.doc/ids_sqs_with.htm
You might be interested in something like this:
select * from (
select * from table
) as Subquery
You've got the syntax right:
WITH AuthorRating(AuthorName, AuthorRating) AS
SELECT aname AS AuthorName,
AVG(quantity) AS AuthorRating
FROM Book
GROUP By Book.aname
However, as others have mentioned, MySQL does not support this command. WITH was added in SQL:1999; the newest version of the SQL standard is SQL:2008. You can find some more information about databases that support SQL:1999's various features on Wikipedia.
MySQL has traditionally lagged a bit in support for the SQL standard, whereas commercial databases like Oracle, SQL Server (recently), and DB2 have followed them a bit more closely. PostgreSQL is typically pretty standards compliant as well.
You may want to look at MySQL's roadmap; I'm not completely sure when this feature might be supported, but it's great for creating readable roll-up queries.
Oracle does support WITH.
It would look like this.
WITH emps as (SELECT * FROM Employees)
SELECT * FROM emps WHERE ID < 20
UNION ALL
SELECT * FROM emps where Sex = 'F'
#ysth WITH is hard to google because it's a common word typically excluded from searches.
You'd want to look at the SELECT docs to see how subquery factoring works.
I know this doesn't answer the OP but I'm cleaning up any confusion ysth may have started.
Building on the answer from #Mosty Mostacho, here's how you might do something equivalent in MySQL,for a specific case of determining what entries don't exist in a table, and are not in any other database.
select col1 from (
select 'value1' as col1 union
select 'value2' as col1 union
select 'value3' as col1
) as subquery
left join mytable as mytable.mycol = col1
where mytable.mycol is null
order by col1
You may want to use a text editor with macro capabilities to convert a list of values to the quoted select union clause.
MariaDB is now supporting WITH. MySQL for now is not.
https://mariadb.com/kb/en/mariadb/with/
Have you ever tried Temporary Table?
This solved my convern:
create temporary table abc (
column1 varchar(255)
column2 decimal
);
insert into abc
select ...
or otherwise
insert into abc
values ('text', 5.5), ('text2', 0815.8);
Then you can use this table in every select in this session:
select * from abc inner join users on ...;
WITH authorRating as (select aname, rating from book)
SELECT aname, AVG(quantity)
FROM authorRating
GROUP BY aname