I have a json file filled with a list of data where each element has one field called url.
[
{ ...,
...,
"url": "us.test.com"
},
...
]
In a different file I have a list of mappings that I need to replace the affected url fields with, formatted like this:
us.test.com test.com
hello.com/se hello.com
...
So the end result should be:
[
{ ...,
...,
"url": "test.com"
},
...
]
Is there a way to do this in Vim or do I need to do it programmatically?
Well, I'd do this programmatically in Vim ;-) As you'll see it's quite similar to Python and many other scripting languages.
Let's suppose we have json file open. Then
:let foo = json_decode(join(getline(1, '$')))
will load json into VimScript variable. So :echo foo will show [{'url': 'us.test.com'}, {'url': 'hello.com/se'}].
Now let's switch to a "mapping" file. We're going to split all lines and make a Dictionary like that:
:let bar = {}
:for line in getline(1, '$') | let field = split(line) | let bar[field[0]] = field[1] | endfor
Now :echo bar shows {'hello.com/se': 'hello.com', 'us.test.com': 'test.com'} as expected.
To perform a substitution we do simply:
:for field in foo | let field.url = bar->get(field.url, field.url) | endfor
And now foo contains [{'url': 'test.com'}, {'url': 'hello.com'}] which is what we want. The remaining step is to write the new value into a buffer with
:put =json_encode(foo)
You could…
turn those lines in your mappings file (/tmp/mappings for illustration purpose):
us.test.com test.com
hello.com/se hello.com
...
into:
g/"url"/s#us.test.com#test.com#g
g/"url"/s#hello.com/se#hello.com#g
...
with:
:%normal Ig/"url"/s#
:%s/ /#
The idea is to turn the file into a script that will perform all those substitutions on all lines matching "url".
If you are confident that those strings are only in "url" lines, you can just do:
:%normal I%s#
:%s/ /#
to obtain:
%s#us.test.com#test.com#g
%s#hello.com/se#hello.com#g
...
write the file:
:w
and source it from your JSON file:
:source /tmp/mappings
See :help :g, :help :s, :help :normal, :help :range, :help :source, and :help pattern-delimiter.
Related
As an example, I have a .csv which uses the Excel dialect which uses something like Python's csv module doubleQuote to escape quotes.
For example, consider the row below:
"XX ""YYYYYYYY"", ZZZZZZ ""QQQQQQ""","JJJJ ""MMMM"", RRRR ""TTTT""",1234,RRRR,60,50
I would want the schema to then become:
[
'XX "YYYYYYYY", ZZZZZZ "QQQQQQ"',
'JJJJ "MMMM", RRRR "TTTT"',
1234,
'RRRR',
60,
50
]
Is there a way to set the schema of a dataset in a programmatic/automated fashion?
While you can do this in code, foundrys dataset-app can also do this natively. This means you can skip writing the code (which is nice) but also means you can potentially save a step in your pipeline (which might save you on runtime.)
After uploading the files to a dataset, press "edit schema" on the dataset:
Then apply settings like the following, which would result in the desired outcome in your case:
Then press "save and validate" and the dataset should end up with the correct schema:
Starting with this example:
Dataset<Row> dataset = files
.sparkSession()
.read()
.option("inferSchema", "true")
.csv(csvDataset);
output.getDataFrameWriter(dataset).write();
Add the header, quote, and escape options, like so:
Dataset<Row> dataset = files
.sparkSession()
.read()
.option("inferSchema", "true")
.option("header", "true")
.option("quote", "\"")
.option("escape", "\"")
.csv(csvDataset);
output.getDataFrameWriter(dataset).write();
Given the following json:
Full file here: https://pastebin.com/Hzt9bq2a
{
"name": "Visma Public",
"domains": [
"accountsettings.connect.identity.stagaws.visma.com",
"admin.stage.vismaonline.com",
"api.home.stag.visma.com",
"api.workbox.dk",
"app.workbox.dk",
"app.workbox.co.uk",
"authz.workbox.dk",
"connect.identity.stagaws.visma.com",
"eaccounting.stage.vismaonline.com",
"eaccountingprinting.stage.vismaonline.com",
"http://myservices-api.stage.vismaonline.com/",
"identity.stage.vismaonline.com",
"myservices.stage.vismaonline.com"
]
}
How can I transform the data to the below. Which is, to identify the domains in the format of site.SLD.TLD present and then remove the duplication of them. (Not including the subdomains, protocols or paths as illustrated below.)
{
"name": "Visma Public",
"domains": [
"workbox.co.uk",
"workbox.dk",
"visma.com",
"vismaonline.com"
]
}
I would like to do so in jq as that is what I've used to wrangled the data into this format so far, but at this stage any solution that I can run on Debian (I'm using bash) without any extraneous tooling ideally would be fine.
I'm aware that regex can be used within jq so I assume the best way is to regex out the domain and then pipe to unique however I'm unable to get anything working so far I'm currently trying this version which seems to me to need only the text transformation stage adding in somehow either during the jq process or with a run over with something like awk after the event perhaps:
jq '[.[] | {name: .name, domain: [.domains[]] | unique}]' testfile.json
This appears to be useful: https://github.com/stedolan/jq/issues/537
One solution was offered which does a regex match to extract the last two strings separated by . and call the unique function on that & works up to a point but doesn't cover site.SLD.TLD that has 2 parts. Like google.co.uk would return only co.uk with this jq for example:
jq '.domains |= (map(capture("(?<x>[[:alpha:]]+).(?<z>[[:alpha:]]+)(.?)$") | join(".")) | unique)'
A programming language is much more expressive than jq.
Try the following snippet with python3.
import json
import pprint
import urllib.request
from urllib.parse import urlparse
import os
def get_tlds():
f = urllib.request.urlopen("https://publicsuffix.org/list/effective_tld_names.dat")
content = f.read()
lines = content.decode('utf-8').split("\n")
# remove comments
tlds = [line for line in lines if not line.startswith("//") and not line == ""]
return tlds
def extract_domain(url, tlds):
# get domain
url = url.replace("http://", "").replace("https://", "")
url = url.split("/")[0]
# get tld/sld
parts = url.split(".")
suffix1 = parts[-1]
sld1 = parts[-2]
if len(parts) > 2:
suffix2 = ".".join(parts[-2:])
sld2 = parts[-3]
else:
suffix2 = suffix1
sld2 = sld1
# try the longger first
if suffix2 in tlds:
tld = suffix2
sld = sld2
else:
tld = suffix1
sld = sld1
return sld + "." + tld
def clean(site, tlds):
site["domains"] = list(set([extract_domain(url, tlds) for url in site["domains"]]))
return site
if __name__ == "__main__":
filename = "Hzt9bq2a.json"
cache_path = "tlds.json"
if os.path.exists(cache_path):
with open(cache_path, "r") as f:
tlds = json.load(f)
else:
tlds = get_tlds()
with open(cache_path, "w") as f:
json.dump(tlds, f)
with open(filename) as f:
d = json.load(f)
d = [clean(site, tlds) for site in d]
pprint.pprint(d)
with open("clean.json", "w") as f:
json.dump(d, f)
May I offer you achieving the same query with jtc: the same could be achieved in other languages (and of course in jq) - the query is mostly how to come up with the regex to satisfy your ask:
bash $ <file.json jtc -w'<domains>l:>((?:[a-z0-9]+\.)?[a-z0-9]+\.[a-z0-9]+)[^.]*$<R:' -u'{{$1}}' /\
-ppw'<domains>l:><q:' -w'[domains]:<[]>j:' -w'<name>l:'
{
"domains": [
"stagaws.visma.com",
"stage.vismaonline.com",
"stag.visma.com",
"api.workbox.dk",
"app.workbox.dk",
"workbox.co.uk",
"authz.workbox.dk"
],
"name": "Visma Public"
}
bash $
Note: it does extract only DOMAIN.TLD, as per your ask. If you like to extract DOMAIN.SLD.TLD, then the task becomes a bit less trivial.
Update:
Modified solution as per the comment: extract domain.sld.tld where 3 or more levels and domain.tld where there’s only 2
PS. I'm the creator of the jtc - JSON processing utility. This disclaimer is SO requirement.
One of the solutions presented on this page offers that:
A programming language is much more expressive than jq.
It may therefore be worthwhile pointing out that jq is an expressive, Turing-complete programming language, and that it would be as straightforward (and as tedious) to capture all the intricacies of the "Public Suffix List" using jq as any other programming language that does not already provide support for this list.
It may be useful to illustrate an approach to the problem that passes the (revised) test presented in the Q. This approach could easily be extended in any one of a number of ways:
def extract:
sub("^[^:]*://";"")
| sub("/.*$";"")
| split(".")
| (if (.[-1]|length) == 2 and (.[-2]|length) <= 3
then -3 else -2 end) as $ix
| .[$ix : ]
| join(".") ;
{name, domain: (.domains | map(extract) | unique)}
Output
{
"name": "Visma Public",
"domain": [
"visma.com",
"vismaonline.com",
"workbox.co.uk",
"workbox.dk"
]
}
Judging from your example, you don't actually want top-level domains (just one component, e.g. ".com"), and you probably don't really want second-level domains (last two components) either, because some domain registries don't operate at the TLD level. Given www.foo.com.br, you presumably want to find out about foo.com.br, not com.br.
To do that, you need to consult the Public Suffix List. The file format isn't too complicated, but it has support for wildcards and exceptions. I dare say that jq isn't the ideal language to use here — pick one that has a URL-parsing module (for extracting hostnames) and an existing Public Suffix List module (for extracting the domain parts from those hostnames).
I have a data structure that I want to convert to json and preserve the key order.
For example:
%{ x: 1, a: 5} should be converted to "{\"x\": 1, \"a\": 5}"
Poison does it without any problem. But when I upgrade to Jason, it changes to "{\"a\": 5, \"x\": 1}".
So I use JasonHelpers json_map to preserve the order like this:
Jason.Helpers.json_map([x: 1, a: 5])
It creates a fragment with correct order.
However, when I use a variable to do this:
list = [x: 1, a: 5]
Jason.Helpers.json_map(list)
I have an error:
** (Protocol.UndefinedError) protocol Enumerable not implemented for {:list, [line: 15], nil} of type Tuple.
....
QUESTION: How can I pass a pre-calculated list into Jason.Helpers.json_map ?
The calculation is complicated, so I don't want to repeat the code just to use json_map, but use the function that returns a list.
json_map/1 is a macro, from its docs:
Encodes a JSON map from a compile-time keyword.
It is designed for compiling JSON at compile-time, which is why it doesn't work with your runtime variable.
Support for encoding keyword lists was added to the Jason library a year ago, but it looks like it hasn't been pushed to hex yet. I managed to get it work by pulling the latest code from github:
defp deps do
[{:jason, git: "https://github.com/michalmuskala/jason.git"}]
end
Then by creating a struct that implements Jason.Encoder (adapted from this solution by the Jason author):
defmodule OrderedObject do
defstruct [:value]
def new(value), do: %__MODULE__{value: value}
defimpl Jason.Encoder do
def encode(%{value: value}, opts) do
Jason.Encode.keyword(value, opts)
end
end
end
Now we can encode objects with ordered keys:
iex(1)> Jason.encode!(OrderedObject.new([x: 1, a: 5]))
"{\"x\":1,\"a\":5}"
I don't know if this is part of the public API or just an implementation detail, but it appears you have some control of the order when implementing the Jason.Encoder protocol for a struct.
Let's say you've defined an Ordered struct:
defmodule Ordered do
#derive {Jason.Encoder, only: [:a, :x]}
defstruct [:a, :x]
end
If you encode the struct, the "a" key will be before the "x" key:
iex> Jason.encode!(%Ordered{a: 5, x: 1})
"{\"a\":5,\"x\":1}"
Let's reorder the keys we pass in to the :only option:
defmodule Ordered do
#derive {Jason.Encoder, only: [:x, :a]}
defstruct [:a, :x]
end
If we now encode the struct, the "x" key will be before the "a" key:
iex> Jason.encode!(%Ordered{a: 5, x: 1})
"{\"x\":1,\"a\":5}"
So I have the following dictionaries that I get by parsing a text file
keys = ["scientific name", "common names", "colors]
values = ["somename1", ["name11", "name12"], ["color11", "color12"]]
keys = ["scientific name", "common names", "colors]
values = ["somename2", ["name21", "name22"], ["color21", "color22"]]
and so on. I am dumping the key value pairs using a dictionary to a json file using a for loop where I go through each key value pair one by one
for loop starts
d = dict(zip(keys, values))
with open("file.json", 'a') as j:
json.dump(d, j)
If I open the saved json file I see the contents as
{"scientific name": "somename1", "common names": ["name11", "name12"], "colors": ["color11", "color12"]}{"scientific name": "somename2", "common names": ["name21", "name22"], "colors": ["color21", "color22"]}
Is this the right way to do it?
The purpose is to query the common name or colors for a given scientific name. So then I do
with open("file.json", "r") as j:
data = json.load(j)
I get the error, json.decoder.JSONDecodeError: Extra data:
I think this is because I am not dumping the dictionaries in json in the for loop correctly. I have to insert some square brackets programatically. Just doing json.dump(d, j) won't suffice.
JSON may only have one root element. This root element can be [], {} or most other datatypes.
In your file, however, you get multiple root elements:
{...}{...}
This isn't valid JSON, and the error Extra data refers to the second {}, where valid JSON would end instead.
You can write multiple dicts to a JSON string, but you need to wrap them in an array:
[{...},{...}]
But now off to how I would fix your code. First, I rewrote what you posted, because your code was rather pseudo-code and didn't run directly.
import json
inputs = [(["scientific name", "common names", "colors"],
["somename1", ["name11", "name12"], ["color11", "color12"]]),
(["scientific name", "common names", "colors"],
["somename2", ["name21", "name22"], ["color21", "color22"]])]
for keys, values in inputs:
d = dict(zip(keys, values))
with open("file.json", 'a') as j:
json.dump(d, j)
with open("file.json", 'r') as j:
print(json.load(j))
As you correctly realized, this code failes with
json.decoder.JSONDecodeError: Extra data: line 1 column 105 (char 104)
The way I would write it, is:
import json
inputs = [(["scientific name", "common names", "colors"],
["somename1", ["name11", "name12"], ["color11", "color12"]]),
(["scientific name", "common names", "colors"],
["somename2", ["name21", "name22"], ["color21", "color22"]])]
jsonData = list()
for keys, values in inputs:
d = dict(zip(keys, values))
jsonData.append(d)
with open("file.json", 'w') as j:
json.dump(jsonData, j)
with open("file.json", 'r') as j:
print(json.load(j))
Also, for python's json library, it is important that you write the entire json file in one go, meaning with 'w' instead of 'a'.
I had a question concerning some basic transformations in Haskell.
Basically, I have a written Input file, named Input.md. This contains some markdown text that is read in my project file, and I want to write a few functions to do transformations on the text. After completing these functions under a function called convertToHTML, I have output the file as an .html file in the correct format.
module Main
(
convertToHTML,
main
) where
import System.Environment (getArgs)
import System.IO
import Data.Char (toLower, toUpper)
process :: String -> String
process s = head $ lines s
convertToHTML :: String -> String
convertToHTML str = do
x <- str
if (x == '#')
then "<h1>"
else return x
--convertToHTML x = map toUpper x
main = do
args <- getArgs -- command line args
let (infile,outfile) = (\(x:y:ys)->(x,y)) args
putStrLn $ "Input file: " ++ infile
putStrLn $ "Output file: " ++ outfile
contents <- readFile infile
writeFile outfile $ convertToHTML contents
So,
How would I read through my input file, and transform any line that starts with a # to an html tag
How would I read through my input file once more and transform any WORD that is surrounded by _word_ (1 underscore) to another html tag
Replace any Character with an html string.
I tried using such functions such as Map, Filter, ZipWith, but could not figure out how to iterate through the text and transform each text. Please if anybody has any suggestions. I've been working on this for 2 days straight and have a bunch of failed code to show for a couple of weeks and have a bunch of failed code to show it.
I tried using such functions such as Map, Filter, ZipWith, but could not figure out how to iterate through the text and transform each text.
Because they work on appropriate element collection. And they don't really "iterate"; you simply have to feed the appropriate data. Let's tackle the # problem as an example.
Our file is one giant String, and what we'd like is to have it nicely split in lines, so [String]. What could do it for us? I have no idea, so let's just search Hoogle for String -> [String].
Ah, there we go, lines function! Its counterpart, unlines, is also going to be useful. Now we can write our line wrapper:
convertHeader :: String -> String
convertHeader [] = [] -- that prevents us from calling head on an empty line
convertHeader x = if head x == '#' then "<h1>" ++ x ++ "</h1>"
else x
and so:
convertHeaders :: String -> String
convertHeaders = unlines . map convertHeader . lines
-- ^String ^[String] ^[String] ^String
As you can see the function first converts the file to lines, maps convertHeader on each line, and the puts the file back together.
See it live on Ideone
Try now doing the same with words to replace your formatting patterns. As a bonus exercise, change convertHeader to count the number of # in front of the line and output <h1>, <h2>, <h3> and so on accordingly.