MySQL get just one row duplicated result on select - mysql

Question

I have the following select query. I want to avoid getting the duplicated "EN" row when "ES" row is present. Like prefer ES over EN.
SELECT s.soft_id,s.groupby,s.packageid,s.name,s.area,l.min,GROUP_CONCAT(DISTINCT JSON_ARRAY(s.version,s.detailid,s.filesize,s.updatetime)) versions
FROM software s
INNER JOIN langs l ON s.lang_id=l.lang_id
INNER JOIN devices_type t ON (s.familylock_id=t.familylock_id OR (s.familylock_id=0 AND s.devicelock_id=t.device_type_id))
INNER JOIN devices d ON t.device_type_id=d.device_type_id
INNER JOIN users u ON d.user_id=u.user_id
WHERE s.groupby IN(1,2,3)
AND u.token="abc"
AND d.serialno="123456789"
AND l.min IN("ES","EN")
GROUP BY s.soft_id,s.groupby,s.packageid,s.name,s.area,l.min ORDER BY s.name ASC
This is the example result. And i want to get rid of AUDI and AUTOSEARCH "EN" rows.
Image

Answer 1

You need to change your WHERE condition to exclude a row with l.min = 'EN' if a row with l.min = 'ES' exists. You can do this using a NOT EXISTS clause; changing the
AND l.min IN("ES","EN")
condition to
AND (l.min = 'ES' OR
l.min = 'EN' AND NOT EXISTS (SELECT *
FROM software s2
JOIN langs l2 ON l2.lang_id = s2.lang_id
WHERE s2.soft_id = s.soft_id
AND l2.min = 'ES')
)
Small sample demo on SQLFiddle

Answer 2

Is the below helps? I could not validate the script as I don't have sample data but below idea should help you to set the priority.
DB Fiddle
WITH preference AS
(
SELECT s.*, row_number() OVER (PARTITION BY s.soft_id
ORDER BY s.packageid,
CASE
WHEN l.min = 'ES'
THEN 'A'
ELSE 'B'
END) priority
FROM software s
INNER JOIN langs l ON s.lang_id=l.lang_id
WHERE l.min IN("ES","EN")
)
SELECT *
FROM preference
WHERE priority = 1;