I'm using the following query to sort, using Order by for 4 different ranks: id, avg_rating, total_sent & points
However, I'm having trouble with including all the members in the results. I'd like to include all members, including the ones that have 0: total_sent, total_received, points, avg_rating, votes
Please help me understand what I'm missing. Thank you.
SELECT m.id,
m.Name,
m.City,
m.Zip_Code,
m.url,
r.avg_rating,
r.votes,
froms.from_ct total_sent,
tos.to_ct total_received,
froms.from_ct - tos.to_ct `points`
FROM members m
JOIN (
SELECT id_rated,
avg(rating) avg_rating,
count(*) votes
FROM member_ratings
GROUP BY id_rated
) r ON r.id_rated = m.id
JOIN ( SELECT id_from, COUNT(*) AS from_ct FROM member_points GROUP BY 1
) AS froms ON froms.id_from = m.id
JOIN ( SELECT id_received, COUNT(*) AS to_ct FROM member_points GROUP BY 1
) AS tos ON tos.id_received = m.id
WHERE m.Account_Active = 'TRUE'
GROUP BY m.id,
m.Name
ORDER BY `avg_rating` DESC;
Use LEFT JOINs for all tables
SELECT m.id,
m.Name,
m.City,
m.Zip_Code,
m.url,
r.avg_rating,
r.votes,
froms.from_ct total_sent,
tos.to_ct total_received,
froms.from_ct - tos.to_ct `points`
FROM members m
LEFT JOIN (
SELECT id_rated,
avg(rating) avg_rating,
count(*) votes
FROM member_ratings
GROUP BY id_rated
) r ON r.id_rated = m.id
LEFT JOIN ( SELECT id_from, COUNT(*) AS from_ct FROM member_points GROUP BY 1
) AS froms ON froms.id_from = m.id
LEFT JOIN ( SELECT id_received, COUNT(*) AS to_ct FROM member_points GROUP BY 1
) AS tos ON tos.id_received = m.id
LEFT JOIN member_points mp ON mp.id_points = m.id
WHERE m.Account_Active = 'TRUE'
GROUP BY m.id,
m.Name
ORDER BY `avg_rating` DESC;
Related
I wrote this query
SELECT
country,
COUNT(DISTINCT tmp_tbl.user_guid) AS number_of_customers
FROM complete_tests c INNER JOIN
( SELECT DISTINCT d.dog_guid,
u.user_guid,
u.country
FROM dogs d INNER JOIN users u ON d.user_guid = u.user_guid
WHERE (u.exclude = 0 OR u.exclude IS NULL)
AND (d.exclude = 0 OR d.exclude IS NULL)
)
AS tmp_tbl ON c.dog_guid = tmp_tbl.dog_guid
GROUP BY country
ORDER BY number_of_customers DESC
And I need to add another variable that calculates the percentage of total
when I add
number_of_customers/SUM(number_of_customers)
or SUM(COUNT(DISTINCT tmp_tbl.user_guid)) / COUNT(DISTINCT tmp_tbl.user_guid)
it gives me error
Analytic functions come in handy here. Assuming you are using MySQL 8+:
SELECT country,
COUNT(DISTINCT tmp_tbl.user_guid) AS number_of_customers,
100.0 * COUNT(DISTINCT tmp_tbl.user_guid) /
SUM(COUNT(DISTINCT tmp_tbl.user_guid)) OVER () AS pct_customers
FROM complete_tests c
INNER JOIN
(
SELECT DISTINCT d.dog_guid, u.user_guid, u.country
FROM dogs d
INNER JOIN users u ON d.user_guid = u.user_guid
WHERE (u.exclude = 0 OR u.exclude IS NULL) AND
(d.exclude = 0 OR d.exclude IS NULL)
) AS tmp_tbl
ON c.dog_guid = tmp_tbl.dog_guid
GROUP BY
country
ORDER BY
number_of_customers DESC;
-- Note: The actor should have acted in at least five Indian movies. -- (Hint: You should use the weighted average based on votes. If the ratings clash, then the total number of votes should act as the tie breaker
SELECT n.name as actor_name
, r.total_votes
, COUNT(r.movie_id) as movie_count
, r.avg_rating as actor_avg_rating
, RANK() OVER( PARTITION BY
rm.category = 'actor'
ORDER BY
r.avg_rating DESC
) actor_rank
FROM names as n
JOIN role_mapping as rm
ON n.id = rm.movie_id
JOIN movie as m
ON m.id = rm.movie_id
JOIN ratings as r
ON r.movie_id = m.id
where m.country regexp '^INDIA$'
and m.languages regexp '^HINDI$'
group
by actor_name
having count(rm.movie_id) >= 5;
The output gives no error but no result too.
This would work:
SELECT a.name as actor_name, c.total_votes, COUNT(c.movie_id) as movie_count,c.avg_rating as actor_avg_rating,
RANK() OVER( PARTITION BY
d.category = 'actor'
ORDER BY
c.avg_rating DESC
) actor_rank
FROM names a, movie b, ratings c, role_mapping d
where b.country = 'INDIA'
and b.id = c.movie_id
and b.id= d.movie_id
and a.id = d.name_id
group by actor_name
having count(d.movie_id) >= 5
order by actor_avg_rating desc
;
You had tried joining nameid with movie id which is the mistake
SELECT NAME AS actor_name,
Cast(Sum(total_votes)/Count(movie_id) AS DECIMAL(8,0)) AS total_votes,
Count(movie_id) AS movie_count,
avg_rating AS actor_avg_rating,
Dense_rank() OVER(ORDER BY avg_rating DESC) AS actor_rank
FROM names n INNER JOIN role_mapping r ON n.id=r.name_id
INNER JOIN ratings using (movie_id) INNER JOIN movie m ON m.id=r.movie_id
WHERE country="india" AND category="actor"
GROUP BY actor_name
HAVING Count(movie_id)>=5;
WITH top_actor
AS (SELECT b.NAME
AS
actor_name,
Sum(c.total_votes)
AS
total_votes,
Count(DISTINCT a.movie_id)
AS
movie_count,
Round(Sum(c.avg_rating * c.total_votes) / Sum(c.total_votes), 2)
AS
actor_avg_rating
FROM role_mapping a
INNER JOIN names b
ON a.name_id = b.id
INNER JOIN ratings c
ON a.movie_id = c.movie_id
INNER JOIN movie d
ON a.movie_id = d.id
WHERE a.category = 'actor'
AND d.country LIKE '%India%'
GROUP BY a.name_id,
b.NAME
HAVING Count(DISTINCT a.movie_id) >= 5)
SELECT *,
Rank()
OVER (
ORDER BY actor_avg_rating DESC) AS actor_rank
FROM top_actor;
Getting multiple records from table with subquery joins
SELECT
COUNT(*) AS total_count,
(SELECT
chat_box.user_id,
chat_box.message,
members.id,
members.display_name
FROM chat_box INNER JOIN members
ON chat_box.user_id = members.id
ORDER BY chat_id DESC LIMIT 1),
(SELECT COUNT(DISTINCT user_id) FROM chat_box) AS users_count
FROM chat_box
This is what I have so far, I want to get the members.display_name from the inner join where the chat_box.user_id = members.id as an output along aside the chat_box.message and save members.display_name and chat_box.message to a variable. Any help is appreciated.
It is not exactly clear what you are trying to do, but it seems like you could use something like this:
select u.user_id,
u.message,
u.id,
u.display_name,
cb1.total_count,
cb1.users_count
from
(
SELECT cb.user_id ,
cb.message,
m.id,
m.display_name
FROM chat_box cb
INNER JOIN members m
ON cb.user_id = m.id
) u
CROSS JOIN
(
select COUNT(*) AS total_count,
COUNT(DISTINCT user_id) AS users_count
FROM chat_box
) cb1
SELECT cm.commenter_id,
cm.comment,
m.id,
(
SELECT COUNT(*) AS r_count
FROM comments
GROUP BY comments.commenter_id
) AS count,
m.display_name
FROM comments cm
INNER JOIN members m
ON cm.commenter_id = m.id
From this query I want to get the display_name for the person with the highest count of comments. Any guidance is appreciated.
SELECT m.id, m.display_name, COUNT(*) totalComments
FROM comments cm
INNER JOIN members m
ON cm.commenter_id = m.id
GROUP BY m.id, m.display_name
HAVING COUNT(*) =
(
SELECT COUNT(*) totalCount
FROM Comments
GROUP BY commenter_id
ORDER BY totalCount DESC
LIMIT 1
)
SQLFiddle Demo
SQLFiddle Demo (with duplicates)
I think the simplest way is just to sort your query and take the first row:
SELECT cm.commenter_id,
cm.comment,
m.id,
(
SELECT COUNT(*) AS r_count
FROM comments
GROUP BY comments.commenter_id
) AS count,
m.display_name
FROM comments cm
INNER JOIN members m
ON cm.commenter_id = m.id
order by count desc
limit 1
Say I have this query
SELECT ft.*, m.*
FROM forum_topics ft
INNER JOIN members m ON ft.author = m.id
WHERE ft.forum = '$forum'
ORDER BY ft.lastpost DESC
I want to also get a row count in that from the table forum_replies where the id = ft.id.
How could I do that?
Depending on your DB implementation this might work:
SELECT ft.*,
m.*,
( SELECT count(1)
FROM forum_replies fr
WHERE fr.id = ft.id) AS nr_of_replies
FROM forum_topics ft
INNER JOIN members m ON ft.author = m.id
WHERE ft.forum = '$forum'
ORDER BY ft.lastpost DESC
HTH
SELECT ft.*, m.*, fr.ReplyCount
FROM forum_topics ft
INNER JOIN members m ON ft.author = m.id
inner join (
Select Id, Count(*) as ReplyCount
from forum_replys
group by id
) as fr
on ft.Id = fr.Id
WHERE ft.forum = '$forum'
ORDER BY ft.lastpost DESC