I have the following data,
id emp_id csa_taken
1 100 2
2 100 2
3 100 0
4 100 2
5 101 2
6 101 2
7 101 0
8 101 0
I expect a result with count where csa_taken=2 for individual employee.
expected result:
emp_id count_csa_taken
100 3
101 2
I have tried the following query with a failed attempt.
Select count(employee_id) From $employeeCSA where csa_taken=2
Please suggest as I am new to sql.
If I understand you correctly you like to count all employees with a cas_taken of two. As there are multiple entries for the csa_taken for one employee you need to group them.
E.g.:
SELECT COUNT(*) FROM $employeeCSA WHERE csa_taken = 2 GROUP_BY employee_id
Please note that COUNT(*) counts the rows (not the fields).
You also need group by. Try like:
Select count(employee_id),emp_id From $employeeCSA where csa_taken=2
group by emp_id
If i understand correctly, then you can try this:
SELECT emp_id,COUNT(emp_id) from dbo.Sample WHERE csa_token = 2 GROUP BY emp_id
Related
I have this table
**applications**
id user_id company_id shortlisted
1 10 99 0
2 10 100 1
3 10 101 1
4 10 102 0
5 11 99 1
6 12 99 0
6 12 101 0
What I want is to select all users
which have been shortlisted at-least once
which have not been shortlisted at all
For the first case, i have the following query:
SELECT user_id
from applications
where shortlisted=1
Group
By user_id
and this gives me the expected result like below
**applications**
user_id
10
11
But I'm trying the following query for the second case and it returns me an empty set:
Select user_id
from applications as Application
where shortlisted=0
and NOT EXISTS(Select user_id from applications where user_id=Application.user_id and shortlisted=1)
What am i missing?
PS: Please ignore any typos as i typed them manually for this post.
To get both results in a single query simply use aggregation:
select user_id, max(shortlisted) as was_shortlisted
from applications
group By user_id
You can use group by and having for both.
For the first:
select user_id
from applications
group By user_id
having max(shortlisted) = 1;
For the second:
select user_id
from applications
group By user_id
having max(shortlisted) = 0;
In all honesty, your version with the where is more efficient for the first query. This is just to show how closely related the queries are.
You can try following query;
select user_id from table1
group by user_id having MIN(shortlisted) = 1
This will give you to at least have shortlisted = 1 condition and don't have shortlisted = 0 records.
I have my data base like this
id project_id client_id price
1 1 1 200
2 2 1 123
3 2 1 100
4 1 1 87
5 1 1 143
6 1 1 100
7 3 3 123
8 3 3 99
9 4 3 86
10 4 3 43
11 4 3 145
12 4 3 155
Now here I want that it will sum the price columns with the same client_id.
For that I just made my query like this
Select `project_id`, SUM(`price`) FROM `table-name` GROUP BY `client_id`
This one is doing sum the price but I am getting only two project_id in the result. I want the result should be all the distinct project for the client id and the price will be summed for the group clients.
So can someone tell me how to do this? Any help and suggestions will be really appreciable. Thanks
You should not have "bare" column in a group by query that are not in the group by statement.
If you want the list of projects, you can get them in a list like this:
SELECT client_id, GROUP_CONCAT(project_id), SUM(price)
FROM table-name
GROUP BY client_id;
you only have two client that why you are getting only two record , you can group by two column,
Select `project_id`, SUM(`price`) FROM `table-name` GROUP BY `client_id`, `project_id`
I have read the different answers here on SO, but I am stuck on this question. Please help.
I have this mysql view named "activeuser":
userid COUNT(*) ACRONYM
1 23 admin
2 2 doe
3 4 tompa
12 4 Marre
13 1 Mia
1 2 admin
3 1 tompa
12 1 Marre
13 1 Mia
2 1 doe
3 1 tompa
12 1 Marre
How can I sum the COUNT column so that I get the following wanted result?
userid COUNT(*) ACRONYM
1 25 admin
2 3 doe
3 6 tompa
12 6 Marre
13 1 Mia
EDITED:
I used this query to create the view:
CREATE VIEW activeuser AS
(SELECT boats_comments.userid, COUNT(boats_comments.userid), boats_user.acronym, boats_user.email
FROM boats_comments
INNER JOIN boats_user
ON boats_comments.userid = boats_user.id
GROUP BY boats_comments.userid
ORDER BY COUNT(boats_comments.userid) DESC)
UNION ALL
(SELECT boats_answers.userid, COUNT(boats_answers.userid), boats_user.acronym, boats_user.email
FROM boats_answers
INNER JOIN boats_user
ON boats_answers.userid = boats_user.id
GROUP BY boats_answers.userid
ORDER BY COUNT(boats_answers.userid) DESC)
UNION ALL
(SELECT boats_questions.userid, COUNT(boats_questions.userid), boats_user.acronym, boats_user.email
FROM boats_questions
INNER JOIN boats_user
ON boats_questions.userid = boats_user.id
GROUP BY boats_questions.userid
ORDER BY COUNT(boats_questions.userid) DESC)
My goal is to see which users are the most active by checking the number of comments, questions and answers... but I got stuck...
As the results in your view has duplicates I guess the underlying code for the view is grouping on something it maybe shouldn't be grouping on.
You can get the results you want by applying SUM to it:
select userid, sum("whatever column2 is named") as "Count", Acronym
from activeuser group by userid, Acronym;
select userid, count(*) from activeuser group by userid;
i have a table like this
id genre genre2
1 25 0
2 12 25
3 25 12
4 18 17
5 19 14
and i want to count the different genres id and the count of them in both columns but merged into one
and want a result like this
genre count
25 3
12 2
18 1
19 1
17 1
14 1
0 1
i have tried unions, and counts, and everything i think of, but i cant achieve to get the result i want, the closest was making two querys and UNION them, but it doesnt work like i want
any ideas? thanks for the help
You must use UNION ALL instead UNION.
SELECT
genre, COUNT(*) cnt
FROM
(SELECT genre FROM tbl
UNION ALL
SELECT genre2 FROM tbl) a
GROUP BY genre
ORDER BY cnt DESC
You can try it on SQL FIDDLE
I have this result set from my query:
OrderId CustomerId ProducerId CustomerPayment ProducerPayment
1 1 3 10 5
1 1 4 10 5
1 2 3 10 5
1 2 4 10 5
I need to return this result into this:
OrderId UserId Payment
1 1 20
1 2 20
1 3 10
1 4 10
Just combining the CustomerId and ProducerId into UserId. Same with the Payment Columns.
Is there any way to achieve this with using just a simple select and group by? I'm avoiding temp tables, calling multiple same queries and like for optimization. I hope this is possible.
Thanks a lot
SELECT
OrderId,
CustomerID AS UserId,
SUM (CustomerPayment) As Payment
FROM orders
UNION ALL
SELECT
OrderId,
ProducerId AS UserId,
SUM (ProducerPayment) As Payment
FROM orders
Try something like this:
select
OrderId,
CustomerId,
sum(CustomerPayment) Payment,
group_concat(OrderId separator ',') listOrders /* list all OrderID's from the user and separates these with a , */
from your_table
group by CustomerId
Dont know how you query looks like atm?