mysql select distinct n row that has a certain value - mysql

Question

Considering here is my table query:
id name number Code
1 red 1 A
2 red 3 B
3 blue 3 C
4 blue 5 A
5 purple 2 D
6 yellow 3 D
7 yellow 4 C
Now I need to query to get 2 random row such that there is 1 name is red and 1 number is 3, kinda like this:
SELECT * FROM table WHERE name = "red" LIMIT 1 and number = 3 LIMIT 1
So like row 1+3,1+6 or 2 + any other row.
Here is my query:
SELECT * FROM table
group by name,number
having count(name="red") = 1
and count(number=3) = 1
ORDER BY RAND()
LIMIT 2;
However, it seems like it just query the row randomly and not satisfying my requirement. Can anyone show me what is wrong ?
Thank you.

Answer 1

I think that this will do what you want:
select t1.*
from tablename t1
inner join (
select t1.id id1, t2.id id2
from tablename t1 inner join tablename t2
on t2.id > t1.id
and ('red' in (t1.name, t2.name)) + ('3' in (t1.number, t2.number)) = 2
order by rand() limit 1
) t2 on t1.id in (t2.id1, t2.id2)
Note that the row with the highest probability to be returned is id = 2, because it can be combined with any other row of the table.
See the demo.

Answer 2

If you can live with odd formatting...
select x.id x_id
, x.name x_name
, x.number x_number
, x.code x_code
, y.id y_id
, y.name y_name
, y.number y_number
, y.code y_code
from my_table x
join my_table y
on y.id <> x.id
where x.name = 'red'
and y.number = 3
order by rand()
limit 1;
https://www.db-fiddle.com/f/6JmLKq1RwaPrSwS3zx4Qmt/0
Previously, I posted this solution, but it too has some flaws, I think. But TB liked it, so I'll keep it here...
select *
from my_table where name = 'red'
union distinct
select *
from my_table where number = 3
order by rand()
limit 2