Retention of users on an Ott platform - mysql

Question

I have table called user_info
It has two columns:
User_id
Date
How do I get to the table like the one mentioned below:
----------------------------------------------------------------
Date |total_number_of_users | D2 |D5 | D7 | D14|
--------------------------------------------------------------
2020-07-01 1000 700 500 200 150
2020-07-02 400 300 250 200 100
For example consider the first row in the table I am trying to achieve:
total_number_of_users = Total number of users who have visited the site on 2020-07- 01
D2=Out of total users who visited the site on 2020-07-01, visited on 2020-07-2
D7=Out of total users who visited the site on 2020-07-01, visited on 2020-07-7
I have tried the following, how do I get the exact the solution:
SELECT user_id, week(login_date) AS login_week
FROM user_info
GROUP BY user_id,week(login_date);
SELECT user_id, min(week(login_date)) AS first_week
FROM user_info
GROUP BY user_id;
select a.user_id,a.login_week,b.first_week as first_week from
(SELECT
user_id,
week(login_date) AS login_week
FROM user_info
GROUP BY user_id,week(login_date)) a,
(SELECT
user_id,
min(week(login_date)) AS first_week
FROM user_info
GROUP BY user_id) b
where a.user_id=b.user_id;

Answer 1

This seems painful, but you can use a self-join and aggregation:
select t.date,
sum( t2.date = t.date) as total_number_of_users,
sum( t2.date = t.date + interval 1 day ) as d2,
sum( t2.date = t.date + interval 4 day ) as d5,
sum( t2.date = t.date + interval 6 day ) as d7,
sum( t2.date = t.date + interval 13 day ) as d14
from (select distinct date, user_id
from t
) t1 left join
(select distinct date, user_id
from t
) t2
on t1.user_id = t2.user_id and
t2.date in (t1.date, t1.date + interval 1 day, t1.date + interval 4 day, t1.day + interval 6 day, t1.day + interval 13 day)
group by t.date;