I'm using Mockito 1.9.0. I want mock the behaviour for a single method of a class in a JUnit test, so I have
final MyClass myClassSpy = Mockito.spy(myInstance);
Mockito.when(myClassSpy.method1()).thenReturn(myResults);
The problem is, in the second line, myClassSpy.method1() is actually getting called, resulting in an exception. The only reason I'm using mocks is so that later, whenever myClassSpy.method1() is called, the real method won't be called and the myResults object will be returned.
MyClass is an interface and myInstance is an implementation of that, if that matters.
What do I need to do to correct this spying behaviour?
Let me quote the official documentation:
Important gotcha on spying real objects!
Sometimes it's impossible to use when(Object) for stubbing spies. Example:
List list = new LinkedList();
List spy = spy(list);
// Impossible: real method is called so spy.get(0) throws IndexOutOfBoundsException (the list is yet empty)
when(spy.get(0)).thenReturn("foo");
// You have to use doReturn() for stubbing
doReturn("foo").when(spy).get(0);
In your case it goes something like:
doReturn(resultsIWant).when(myClassSpy).method1();
In my case, using Mockito 2.0, I had to change all the any() parameters to nullable() in order to stub the real call.
My case was different from the accepted answer. I was trying to mock a package-private method for an instance that did not live in that package
package common;
public class AnimalĀ {
void packageProtected();
}
package instances;
class Dog extends Animal { }
and the test classes
package common;
public abstract class AnimalTest<T extends Animal> {
#Before
setup(){
doNothing().when(getInstance()).packageProtected();
}
abstract T getInstance();
}
package instances;
class DogTest extends AnimalTest<Dog> {
Dog getInstance(){
return spy(new Dog());
}
#Test
public void myTest(){}
}
The compilation is correct, but when it tries to setup the test, it invokes the real method instead.
Declaring the method protected or public fixes the issue, tho it's not a clean solution.
The answer by Tomasz Nurkiewicz appears not to tell the whole story!
NB Mockito version: 1.10.19.
I am very much a Mockito newb, so can't explain the following behaviour: if there's an expert out there who can improve this answer, please feel free.
The method in question here, getContentStringValue, is NOT final and NOT static.
This line does call the original method getContentStringValue:
doReturn( "dummy" ).when( im ).getContentStringValue( anyInt(), isA( ScoreDoc.class ));
This line does not call the original method getContentStringValue:
doReturn( "dummy" ).when( im ).getContentStringValue( anyInt(), any( ScoreDoc.class ));
For reasons which I can't answer, using isA() causes the intended (?) "do not call method" behaviour of doReturn to fail.
Let's look at the method signatures involved here: they are both static methods of Matchers. Both are said by the Javadoc to return null, which is a little difficult to get your head around in itself. Presumably the Class object passed as the parameter is examined but the result either never calculated or discarded. Given that null can stand for any class and that you are hoping for the mocked method not to be called, couldn't the signatures of isA( ... ) and any( ... ) just return null rather than a generic parameter* <T>?
Anyway:
public static <T> T isA(java.lang.Class<T> clazz)
public static <T> T any(java.lang.Class<T> clazz)
The API documentation does not give any clue about this. It also seems to say the need for such "do not call method" behaviour is "very rare". Personally I use this technique all the time: typically I find that mocking involves a few lines which "set the scene" ... followed by calling a method which then "plays out" the scene in the mock context which you have staged... and while you are setting up the scenery and the props the last thing you want is for the actors to enter stage left and start acting their hearts out...
But this is way beyond my pay grade... I invite explanations from any passing Mockito high priests...
* is "generic parameter" the right term?
One more possible scenario which may causing issues with spies is when you're testing spring beans (with spring test framework) or some other framework that is proxing your objects during test.
Example
#Autowired
private MonitoringDocumentsRepository repository
void test(){
repository = Mockito.spy(repository)
Mockito.doReturn(docs1, docs2)
.when(repository).findMonitoringDocuments(Mockito.nullable(MonitoringDocumentSearchRequest.class));
}
In above code both Spring and Mockito will try to proxy your MonitoringDocumentsRepository object, but Spring will be first, which will cause real call of findMonitoringDocuments method. If we debug our code just after putting a spy on repository object it will look like this inside debugger:
repository = MonitoringDocumentsRepository$$EnhancerBySpringCGLIB$$MockitoMock$
#SpyBean to the rescue
If instead #Autowired annotation we use #SpyBean annotation, we will solve above problem, the SpyBean annotation will also inject repository object but it will be firstly proxied by Mockito and will look like this inside debugger
repository = MonitoringDocumentsRepository$$MockitoMock$$EnhancerBySpringCGLIB$
and here is the code:
#SpyBean
private MonitoringDocumentsRepository repository
void test(){
Mockito.doReturn(docs1, docs2)
.when(repository).findMonitoringDocuments(Mockito.nullable(MonitoringDocumentSearchRequest.class));
}
Important gotcha on spying real objects
When stubbing a method using spies , please use doReturn() family of methods.
when(Object) would result in calling the actual method that can throw exceptions.
List spy = spy(new LinkedList());
//Incorrect , spy.get() will throw IndexOutOfBoundsException
when(spy.get(0)).thenReturn("foo");
//You have to use doReturn() for stubbing
doReturn("foo").when(spy).get(0);
I've found yet another reason for spy to call the original method.
Someone had the idea to mock a final class, and found about MockMaker:
As this works differently to our current mechanism and this one has different limitations and as we want to gather experience and user feedback, this feature had to be explicitly activated to be available ; it can be done via the mockito extension mechanism by creating the file src/test/resources/mockito-extensions/org.mockito.plugins.MockMaker containing a single line: mock-maker-inline
Source: https://github.com/mockito/mockito/wiki/What%27s-new-in-Mockito-2#mock-the-unmockable-opt-in-mocking-of-final-classesmethods
After I merged and brought that file to my machine, my tests failed.
I just had to remove the line (or the file), and spy() worked.
One way to make sure a method from a class is not called is to override the method with a dummy.
WebFormCreatorActivity activity = spy(new WebFormCreatorActivity(clientFactory) {//spy(new WebFormCreatorActivity(clientFactory));
#Override
public void select(TreeItem i) {
log.debug("SELECT");
};
});
As mentioned in some of the comments, my method was "static" (though being called on by an instance of the class)
public class A {
static void myMethod() {...}
}
A instance = spy(new A());
verify(instance).myMethod(); // still calls the original method because it's static
Work around was make an instance method or upgrade Mockito to a newer version with some config: https://stackoverflow.com/a/62860455/32453
Bit late to the party but above solutions did not work for me , so sharing my 0.02$
Mokcito version: 1.10.19
MyClass.java
private int handleAction(List<String> argList, String action)
Test.java
MyClass spy = PowerMockito.spy(new MyClass());
Following did NOT work for me (actual method was being called):
1.
doReturn(0).when(spy , "handleAction", ListUtils.EMPTY_LIST, new String());
2.
doReturn(0).when(spy , "handleAction", any(), anyString());
3.
doReturn(0).when(spy , "handleAction", null, null);
Following WORKED:
doReturn(0).when(spy , "handleAction", any(List.class), anyString());
Related
Using Junit version 5.9.2 I am trying to programmatically add parameter resolvers extension for a test class constructor with a #TestTemplate annotation.
I am trying to add the extensions programmatically using #RegisterExtension.
Example:
public class MyTestClass {
#RegisterExtension
static final TestDependencyResolver resolverExt = new TestDependencyResolver(/*...*/);
private final TestDependency dependency;
public MyTestClass(TestDependency dependency) {
this.dependency = dependency;
}
#TestTemplate
#ExtendWith(SomeContextProvider.class)
void test() {
//...
}
}
I have tried:
making resolverExt field non static
Movine #ExtendWith(SomeContextProvider.class) to class level
And other possible combinations of 1 and 2.
In all cases the ctor parameter dependency is not injected and TestDependencyResolver::resolveParameter is not called, which to my understanding means the object was created without/before registering TestDependencyResolver, please correct me if I am wrong.
Is what I am trying to achieve possible? thanks.
Turns out the issue was not Junit5 but TestTemplateInvocationContextProvider I was using.
I used PactVerificationInvocationContextProvider which seems to have a bug and throws NullPointerException when resolving Ctor params, I have opened an issue for it if you want more details.
This is a similar pattern to ones stated elsewhere and detailed in this blog post. I have this working using Windsor 2.5.4 pretty much as stated in the blogpost, but decided to switch to using Windsor 3. When I did this I noticed that the memory usage of the application go up over time - I guessed this would be that components were'nt being released.
There were a couple of modifications to the code in the blogpost, which may have caused the behaviour to differ.
Here is my AutoRelease interceptor (straight out of the blogpost, here for convenience and the lazy ;) )
[Transient]
public class AutoReleaseHandlerInterceptor : IInterceptor
{
private static readonly MethodInfo Execute = typeof(IDocumentHandler).GetMethod("Process");
private readonly IKernel _kernel;
public AutoReleaseHandlerInterceptor(IKernel kernel)
{
_kernel = kernel;
}
public void Intercept(IInvocation invocation)
{
if (invocation.Method != Execute)
{
invocation.Proceed();
return;
}
try
{
invocation.Proceed();
}
finally
{
_kernel.ReleaseComponent(invocation.Proxy);
}
}
}
One of my deviations from the blog post is the selector that the typed factory uses:-
public class ProcessorSelector : DefaultTypedFactoryComponentSelector
{
protected override Func<IKernelInternal, IReleasePolicy, object> BuildFactoryComponent(MethodInfo method,
string componentName,
Type componentType,
IDictionary additionalArguments)
{
return new MyDocumentHandlerResolver(componentName,
componentType,
additionalArguments,
FallbackToResolveByTypeIfNameNotFound,
GetType()).Resolve;
}
protected override string GetComponentName(MethodInfo method, object[] arguments)
{
return null;
}
protected override Type GetComponentType(MethodInfo method, object[] arguments)
{
var message = arguments[0];
var handlerType = typeof(IDocumentHandler<>).MakeGenericType(message.GetType());
return handlerType;
}
}
What might be noticeable is that I do not use the default resolver. (This is where, perhaps, the problem lies...).
public class MyDocumentHandlerResolver : TypedFactoryComponentResolver
{
public override object Resolve(IKernelInternal kernel, IReleasePolicy scope)
{
return kernel.Resolve(componentType, additionalArguments, scope);
}
}
(I omitted the ctor for brevity- nothing special happens there, it just calls the base ctor).
The reason I did this was because the default resolver would try to resolve by name and not by Type- and fail. In this case, I know I only ever need to resolve by type, so I just overrode the Resolve method.
The final piece of the puzzle will be the installer.
container.AddFacility<TypedFactoryFacility>()
.Register(
Component.For<AutoReleaseHandlerInterceptor>(),
Component.For<ProcessorSelector>().ImplementedBy<ProcessorSelector>(),
Classes.FromAssemblyContaining<MessageHandler>()
.BasedOn(typeof(IDocumentHandler<>))
.WithService.Base()
.Configure(c => c.LifeStyle.Is(LifestyleType.Transient)),
Component.For<IDocumentHandlerFactory>()
.AsFactory(c => c.SelectedWith<ProcessorSelector>()));
Stepping through the code, the interceptor is called and the finally clause is executed (e.g. I didn't get the method name wrong). However, the component does not seem to be released (using the performance counter shows this. Each invocation of the factory's create method increases the counter by one).
So far, my workaround has been to add a void Release(IDocumentHandler handler) method to my factory interface, and then after it executes the handler.Process() method, it explicitly releases the handler instance, and this seems to do the job- the performance counter goes up, and as the processing is done, it goes down).
Here is the factory:
public interface IDocumentHandlerFactory
{
IDocumentHandler GetHandlerForDocument(IDocument document);
void Release(IDocumentHandler handler);
}
And here is how I use it:
IDocumentHandlerFactory handler = _documentHandlerFactory.GetHandlerForDocument(document);
handler.Process();
_documentHandlerFactory.Release(handler);
Doing the Release explicitly therefore negates the need for the interceptor, but my real question is why this behaviour differs between the releases?
Note to self:- RTFM. Or in fact, read the Breakingchanges.txt file.
Here's the change that affects this behaviour (emphasis is mine):-
change - IReleasePolicy interface has a new method: IReleasePolicy
CreateSubPolicy(); usage of sub-policies changes how typed factories
handle out-of-band-release of components (see description)
impact - medium fixability - easy
description - This was added as an attempt to enable more fine grained
lifetime scoping (mostly for per-typed-factory right now, but in the
future also say - per-window in client app). As a side-effect of that
(and change to release policy behavior described above) it is no
longer possible to release objects resolved via typed factories, using
container.Release. As the objects are now tracked only in the scope
of the factory they will be released only if a call to factory
releasing method is made, or when the factory itself is released.
fix - Method should return new object that exposes the same behavior
as the 'parent' usually it is just best to return object of the same
type (as the built-in release policies do).
I didn't find the fix suggestion terribly helpful in my instance, however my solution in the question is what you should actually do (release using the factory). I'll leave it up in case anyone else has this (non) issue.
Hi I am new to unit testing. Is it possible to access methods that are private?
A very simple example
ObjectA
----------
File file;
private void setupFile (){
//do something
file = "C:\file.dat"
}
In TestCase
File sth = ObjectA.setupFile();
assertNotNull(sth);
I am unable to test whether the file variable is null in method ObjectA.setup()
as I cannot run ObjectA.setupFile()
I am not sure about whether doing like this make sense in terms of unit testing.
So is that a better practice to write every method returning sth and set them public for easier unit testing?
Thanks in advance
In general, you should avoid changing the access of a method/field to enable testing. If you do this then you risk developers using the method directly.
However, if you do need to, then making it protected as Deco says is a good way, so it's accessible from the JUnit tests. If you do this, make sure that it is well documented that this is an method for internal use.
A better way is to test the behaviour of the public methods; you shouldn't care about internal implementation details of a class, so you should only be testing public methods. It's hard to tell from your code, but presumably, the setupFile() has effects later on other methods, so you can test those effects, not the fact that file is not null.
External dependencies (such as dependencies on file system, environment variables) can be worked around in your tests, or injected directly into the class. For the general principle, see my answer to How to test code dependent on environment variables using JUnit?
If it is not absolutely necessary to have the method as private, you can have it as package private (i.e. default access) so that you can call it directly in a JUnit test.
Package private methods can only be used in the package that they are declared, and do not become part of the API of the class. You declare a method package private by putting no modifier on it's declaration.
Here's an example to demonstrate:
public class MyClass() {
int foo;
public MyClass() {
this.foo = 0;
}
void notSoComplexCalculationMethod(int a) {
foo = a * 2;
}
//Other methods here . . .
}
public class MyClassTest extends TestCase {
private MyClass myClass;
protected void setUp() {
super.setUp();
myClass = new MyClass();
}
public void testNotSoComplexCalculationMethod() {
int a = 2;
assertEquals(4, myClass.notSoComplexCalculationMethod(a));
//Unit test passes, yay! Now you've tested a package private method.
}
}
It seems impossible to create an object using its default constructor when there is a static .New() method defined on the class:
.NET class:
public class Tester
{
public static void New()
{
Console.WriteLine("In Tester.New()");
}
public Tester()
{
Console.WriteLine("In constructor");
}
}
IronRuby code:
Tester.new
Tester.New
Both of these lines call Tester.New(), not the constuctor. It seems impossible to call the constructor of the Tester class.
Is there a workaround, or is this a bug?
The first one is just an unavoidable ambiguity. If you want to make CLI classes look like Ruby classes, you have no choice but to map the constructor to a new method. So, if you have both a real new method and a synthesized one which maps to a constructor, whatever you do, either the synthetic method shadows the real one or the other way around. Either way, you lose.
That's why all CLI classes have a synthetic clr_new method:
Tester.clr_new
# In constructor
I have a service class which has overloaded constructors. One constructor has 5 parameters and the other has 4.
Before I call,
var service = IoC.Resolve<IService>();
I want to do a test and based on the result of this test, resolve service using a specific constructor. In other words,
bool testPassed = CheckCertainConditions();
if (testPassed)
{
//Resolve service using 5 paramater constructor
}
else
{
//Resolve service using 4 parameter constructor
//If I use 5 parameter constructor under these conditions I will have epic fail.
}
Is there a way I can specify which one I want to use?
In general, you should watch out for ambiguity in constructors when it comes to DI because you are essentially saying to any caller that 'I don't really care if you use one or the other'. This is unlikely to be what you intended.
However, one container-agnostic solution is to wrap the conditional implementation into another class that implements the same interface:
public class ConditionalService : IService
{
private readonly IService service;
public ConditionalService()
{
bool testPassed = CheckCertainConditions();
if (testPassed)
{
// assign this.service using 5 paramater constructor
}
else
{
// assign this.service using 4 parameter constructor
}
}
// assuming that IService has a Foo method:
public IBaz Foo(IBar bar)
{
return this.service.Foo(bar);
}
}
If you can't perform the CheckCertainConditions check in the constructor, you can use lazy evaluation instead.
It would be a good idea to let ConditionalService request all dependencies via Constructor Injection, but I left that out of the example code.
You can register ConditionalService with the DI Container instead of the real implementation.
My underlying problem was that I was trying to resolve my class which had the following signature:
public DatabaseSchemaSynchronisationService(IDatabaseService databaseService, IUserSessionManager userSessionManager)
This was basically useless to me because my usersessionmanager had no active NHibernate.ISession because a connection to my database had not yet been made. What I was trying to do was check if I did have a connection and only then resolve this class which served as a service to run database update scripts.
When changing my whole class to perform the scripts in a different way, all I needed in its constructor's signature was:
public DatabaseSchemaSynchronisationService(ISessionFactory sessionFactory)
This allowed me to open my own session. I did, however have to first check if the connection was ready before attempting to resolve the class, but having IDatabaseSchemaSynchronisationService as a parameter to another class's constructor; this class also gettting resolved somewhere where I could not check the db connection was a bad idea.
Instead in this second class, I took the IDatabaseSchemaSynchronisationService paramater out of the constructor signature and made it a local variable which only gets instantiated (resolved) :
if (connectionIsReady)
Thanks to everyone who answered.