Increment value depending other one - mysql

Let's assume I have the table:
id | val_1 | val_2
1 | 1 | 0
2 | 1 | 1
3 | 1 | 2
4 | 2 | 0
val_2 should be zero at first if there was no rows with val_1 before. Otherwise it should be previous val_2 + 1 for this val_1.
I can't figure it out by myself the best way to do it. The one thing I've invented is trigger after insert, but I think here maybe some other way to do it cleaner and faster?
My code is something like:
DELIMITER $$
CREATE TRIGGER after_table_insert
AFTER INSERT
ON table FOR EACH ROW
BEGIN
UPDATE table SET val_2 = t.val_2 + 1
FROM (
SELECT val_2 FROM table WHERE val_1 = new.val_1 ORDER BY id DESC LIMIT 1
) t
WHERE id = new.id;
END$$
DELIMITER ;
I will appreciate for any help!
Have a great day/night.

You have couple of issues with such setup:
What's going on if you UPDATE or DELETE rows? It can mess up everything with val2. Be careful with that.
Val2 can always be calculated and there is no need to store it.
Having said that, below I will show you a setup with which I will store only id and val1. Then val2 will be calculated within the SELECT statement (so it will always be correct).
CREATE TABLE vals(
id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY,
val INT NOT NULL
);
INSERT INTO vals(val) VALUES(1),(1),(1),(2);
Now what I am going to do is to use the ROW_NUMBER() function (which prints the row number) and run it over a PARTITION BY val:
SELECT id, val,
ROW_NUMBER() OVER (
PARTITION BY val
) AS val2
FROM vals;
We are almost there. Sadly it will offset them by 1 compared to what you need:
+----+-----+------+
| id | val | val2 |
+----+-----+------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 1 | 3 |
| 4 | 2 | 1 |
+----+-----+------+
The fix is simple. Just add "-1" to it and you are ready.
SELECT id, val,
-1+ROW_NUMBER() OVER (
PARTITION BY val
) AS val2
FROM vals;
This will produce:
+----+-----+------+
| id | val | val2 |
+----+-----+------+
| 1 | 1 | 0 |
| 2 | 1 | 1 |
| 3 | 1 | 2 |
| 4 | 2 | 0 |
+----+-----+------+
With this solution there is no need to store val2 at all (you can create it as a VIEW if you wish) and it is not vulnerable to the issue when you delete a row (it will continue to work properly).

This is one possibility
Schema (MySQL v5.7)
CREATE TABLE table1 (
`id` INTEGER,
`val_1` INTEGER,
`val_2` INTEGER
);
DELIMITER //
CREATE TRIGGER after_table_insert
BEFORE INSERT
ON table1 FOR EACH ROW
BEGIN
SET #maxval2 = 0;
SELECT max(val_2) + 1 into #maxval2 FROM table1 WHERE val_1 = new.val_1;
IF #maxval2 IS NULL THEN
SET #maxval2 = 0;
END IF;
SET NEW.val_2 = #maxval2;
END//
DELIMITER ;
INSERT INTO table1
(`id`, `val_1`, `val_2`)
VALUES
('1', '1', '0'),
('2', '1', '0'),
('3', '1', '0'),
('4', '2', '0'),
('4', '2', '0');
Query #1
SELECT * FROM table1;
| id | val_1 | val_2 |
| --- | ----- | ----- |
| 1 | 1 | 0 |
| 2 | 1 | 1 |
| 3 | 1 | 2 |
| 4 | 2 | 0 |
| 4 | 2 | 1 |
View on DB Fiddle

Related

mysql insert trigger only if not duplicate

I am little bit confused with the usage of trigger event to get expected result
Here main table is fee. The structure is as follow
Fee
id | rn | fid | amount | f_month | year
====================================================
1 | 1 | 1 | 150000 | 1 | 1
2 | 1 | 2 | 50000 | 1 | 1
3 | 2 | 1 | 550500 | 2 | 1
4 | 2 | 2 | 200 | 2 | 1
5 | 3 | 1 | 550500 | 2 | 1
And the simply insert trigger has been used.
DROP TRIGGER IF EXISTS `insertinv`;
CREATE DEFINER=`root`#`localhost` TRIGGER `insertinv`
AFTER INSERT ON `fee` FOR EACH ROW INSERT INTO invoice VALUES(null, NEW.rn, NEW.year, '')
The output what I am getting
Invoice
inv | rn | y_d | status
==============================
1 | 1 | 1 | 0
2 | 1 | 1 | 0
3 | 2 | 1 | 0
4 | 2 | 1 | 0
5 | 3 | 1 | 0
But I want to apply condition
if fee.rn AND fee.f_month AND fee.year is same then stop to insert. I mean ignore the fee.fid.
and achieve following result. The expected one
Invoice
inv | rn | y_d | status
==============================
1 | 1 | 1 | 0
2 | 2 | 1 | 0
3 | 3 | 1 | 0
In trigger table inv is primary key and auto increment
Check if a inv exists for a matching year and rn.
If it does not exist, then use the insert statement.
Do the following:
DELIMITER $$
DROP TRIGGER IF EXISTS `insertinv` $$
CREATE DEFINER=`root`#`localhost` TRIGGER `insertinv`
AFTER INSERT ON `fee`
FOR EACH ROW
BEGIN
/* Declare a variable to store invoice id for matching year and rn */
DECLARE inv_exists INT(11) DEFAULT 0;
/* Fetch the invoice id if exists */
SELECT inv INTO inv_exists
FROM invoice
WHERE rn = NEW.rn AND
y_d = NEW.year;
/* if no invoice exists then insert into the table */
IF NOT(inv_exists > 0) THEN
/* Insert statement */
INSERT INTO invoice VALUES(null, NEW.rn, NEW.year, '') ;
END IF;
END $$
DELIMITER ;

MySQL auto populate number field base on another field

mysql question... So I would like to auto populate a number, but I would like it to be based on another field. I'm not sure how to explain it other than using this example:
Field 1 | Field 2 (auto populate)
1 | 1
2 | 1
2 | 2
2 | 3
3 | 1
3 | 2
2 | 4
2 | 5
Is there a mysql function expression that can be added to the column?
I know I could do this in my Python script that is feeding the values, but I have to assume it will be faster if the function is baked into mysql.
UPDATE:
Let me add some clarification...
Field 1 will get filled with a value from a script.
There will be multiple entries of Field 1 that are the same number.
I would like Field 2 to auto populate to have a unique number WITHIN that Field 1 number.
You can just store the field1 and generate field2 as increasing integer value within each field1 using user variables like this:
select
t.field1,
#rn := if(field1 = #f1, #rn + 1, if(#fi := field1, 1, 1)) field2
from (
select
t.*
from your_table t
order by field1 --very important
) t cross join (select #rn := 0, #f1 := -1) t2
You could use a trigger which is a function which automatically runs on certain conditions.
Here is the manual http://dev.mysql.com/doc/refman/5.7/en/trigger-syntax.html.
You could for example use a AFTER UPDATE or AFTER INSERT trigger for this purpose.
Setting aside the usual caveats relating to MyISAM tables...
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(field1 INT NOT NULL
,field2 INT NOT NULL AUTO_INCREMENT
,PRIMARY KEY(field1,field2)
) ENGINE = MyISAM;
INSERT INTO my_table (field1) VALUES
(1),(2),(2),(2),(3),(3),(2),(2);
SELECT * FROM my_table;
+--------+--------+
| field1 | field2 |
+--------+--------+
| 1 | 1 |
| 2 | 1 |
| 2 | 2 |
| 2 | 3 |
| 2 | 4 |
| 2 | 5 |
| 3 | 1 |
| 3 | 2 |
+--------+--------+
..but I would question whether there's really any sense storing this information at all...
...hence, a more robust approach...
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(field1 INT NOT NULL
,field2 INT NOT NULL AUTO_INCREMENT PRIMARY KEY
) ENGINE = InnoDB;
INSERT INTO my_table (field1) VALUES
(1),(2),(2),(2),(3),(3),(2),(2);
SELECT x.field1
, CASE WHEN #prev = field1 THEN #i:=#i+1 ELSE #i:=1 END i
, #prev:=field1 prev
FROM my_table x
, (SELECT #prev:=null,#i:=0) vars
ORDER
BY field1
, field2;
+--------+------+------+
| field1 | i | prev |
+--------+------+------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 2 | 2 | 2 |
| 2 | 3 | 2 |
| 2 | 4 | 2 |
| 2 | 5 | 2 |
| 3 | 1 | 3 |
| 3 | 2 | 3 |
+--------+------+------+
You probably want to create a trigger. Something like the following:
CREATE TRIGGER `populate_field_2` BEFORE INSERT ON `table_name` FOR EACH ROW BEGIN
DECLARE _new_val INT DEFAULT 0;
SELECT MAX(field_2)+1 INTO _new_val FROM 'table_name' WHERE field_1 = NEW.field_1;
SET NEW.field_2 = _new_val;
END
This would populate field_2 each time you created a new row. You can update the logic to create whatever value for field2 you need.

Mysql - Check if VARCHAR column has a missing value on its incrementation

I'm trying to find out if my values inserted are auto-incrementing correctly or if for any reason one has failed to be inserted, deleted or gone "missing". I've tried several answers from Stackoverflow but they were mainly pointing out autoincrementable int values so they did not help since mine is a VARCHAR value that follows the following sequence:
AA000001
AA000002
...
AA000100
...
AA213978
and so on...
Thanks for your time.
You can declare SQL Vars in Query and calculate the difference in each iteration, as shown in the example below:
Schema
create table MyTable
( ai int auto_increment primary key,
id varchar(100) not null
);
insert MyTable (id) values
('AA000001'),
('AA000002'),
('AA000005'),
('AA000008'),
('AA000009'),
('AA000010');
Query
select id
FROM
(
select
t.id,
SUBSTRING(t.id,3) as s,
CAST(SUBSTRING(t.id,3) AS UNSIGNED) - #lastId as diff,
if( #lastId = 0, 0, CAST(SUBSTRING(t.id,3) AS UNSIGNED) - #lastId) as Difference,
#lastId := CAST(SUBSTRING(t.id,3) AS UNSIGNED) as dummy
from
`MyTable` t,
( select #lastId := 0) SQLVars
order by
t.id
) d
WHERE diff>1;
This is the inside query (not the final result set of the above)
+----------+--------+------+------------+-------+
| id | s | diff | Difference | dummy |
+----------+--------+------+------------+-------+
| AA000001 | 000001 | 1 | 0 | 1 |
| AA000002 | 000002 | 1 | 1 | 2 |
| AA000005 | 000005 | 3 | 3 | 5 |
| AA000008 | 000008 | 3 | 3 | 8 |
| AA000009 | 000009 | 1 | 1 | 9 |
| AA000010 | 000010 | 1 | 1 | 10 |
+----------+--------+------+------------+-------+
Actual Results of Above Query:
+----------+
| id |
+----------+
| AA000005 |
| AA000008 |
+----------+
Here's the SQL Fiddle.
To simply test if there are missing values,
select count(*) <> max(right(col, 6))-min(right(col, 6))+1 || count(*) <> count(distinct col)

how to create a counting column for a particular item

I have the following schema (mysql)
create table test(
userid int(11) not null,
item varchar(15),
bookid int(11));
insert into test values ('1','journal',NULL);
insert into test values ('1','journal',NULL);
insert into test values ('1','book',NULL);
insert into test values ('2','book',NULL);
insert into test values ('2','journal',NULL);
insert into test values ('1','book',NULL);
insert into test values ('2','journal',NULL);
insert into test values ('3','book',NULL);
insert into test values ('1','book',NULL);
insert into test values ('1','journal',NULL);
insert into test values ('3','journal',NULL);
insert into test values ('1','journal',NULL);
insert into test values ('2','journal',NULL);
insert into test values ('2','book',NULL);
insert into test values ('2','journal',NULL);
insert into test values ('1','journal',NULL);
insert into test values ('3','book',NULL);
insert into test values ('3','book',NULL);
insert into test values ('3','book',NULL);
insert into test values ('3','book',NULL);
whenever there is a book, I'm trying assign an auto increment beginning with 1 in the bookid column. For each user, the numbering begins again from 1. I know a way this can be done by creating a separate table. Is there a way I can avoid that and accomplish that using some sort of update query in this very table and update the column bookid? I am trying to get output similar to the following:
userid,item,bookid
'1','journal',NULL
'1','journal',NULL
'1','book',1
'2','book',1
'2','journal',NULL
'1','book',2
'2','journal',NULL
'3','book',1
'1','book',3
'1','journal',NULL
'3','journal',NULL
'1','journal',NULL
'2','journal',NULL
'2','book',2
'2','journal',NULL
'1','journal',NULL
'3','book',2
'3','book',3
'3','book',4
'3','book',5
I appreciate if someone could guide me on how to accomplish this?
Here's one idea...
drop table if exists test;
create table test
(id INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,userid int not null
,item varchar(15) NOT NULL
);
insert into test (userid,item) values
(1,'journal')
,(1,'journal')
,(1,'book')
,(2,'book')
,(2,'journal')
,(1,'book')
,(2,'journal')
,(3,'book')
,(1,'book')
,(1,'journal')
,(3,'journal')
,(1,'journal')
,(2,'journal')
,(2,'book')
,(2,'journal')
,(1,'journal')
,(3,'book')
,(3,'book')
,(3,'book')
,(3,'book');
SELECT x.*
, COUNT(*) rank
FROM test x
JOIN test y
ON y.userid = x.userid
AND y.item = x.item
AND y.id <= x.id
GROUP
BY id
ORDER
BY userid
, item
, rank;
+----+--------+---------+------+
| id | userid | item | rank |
+----+--------+---------+------+
| 3 | 1 | book | 1 |
| 6 | 1 | book | 2 |
| 9 | 1 | book | 3 |
| 1 | 1 | journal | 1 |
| 2 | 1 | journal | 2 |
| 10 | 1 | journal | 3 |
| 12 | 1 | journal | 4 |
| 16 | 1 | journal | 5 |
| 4 | 2 | book | 1 |
| 14 | 2 | book | 2 |
| 5 | 2 | journal | 1 |
| 7 | 2 | journal | 2 |
| 13 | 2 | journal | 3 |
| 15 | 2 | journal | 4 |
| 8 | 3 | book | 1 |
| 17 | 3 | book | 2 |
| 18 | 3 | book | 3 |
| 19 | 3 | book | 4 |
| 20 | 3 | book | 5 |
| 11 | 3 | journal | 1 |
+----+--------+---------+------+
Note that MyISAM actually lets you use a composite PK in which part of that composite is an auto-incrementing id, but InnoDB prohinits this.
On larger datasets a query along these lines will likely be far more efficient...
SELECT id
, userid
, item
, IF(#userid=userid,IF(#item=item,#i:=#i+1,#i:=1),#i:=1) rank
, #userid := userid
, #item := item
FROM test
, (SELECT #userid = NULL,#item:='',#i:=1) vars
ORDER
BY userid,item,id;

Update the next row of the target row in MySQL

Suppose I have a table that tracks if a payment is missed like this:
+----+---------+------------+------------+---------+--------+
| id | loan_id | amount_due | due_at | paid_at | missed |
+----+---------+------------+------------+---------+--------+
| 1 | 1 | 100 | 2013-08-17 | NULL | NULL |
| 5 | 1 | 100 | 2013-09-17 | NULL | NULL |
| 7 | 1 | 100 | 2013-10-17 | NULL | NULL |
+----+---------+------------+------------+---------+--------+
And, for example, I ran a query that checks if a payment is missed like this:
UPDATE loan_payments
SET missed = 1
WHERE DATEDIFF(NOW(), due_at) >= 10
AND paid_at IS NULL
Then suppose that the row with id = 1 gets affected. I want the amount_due of row with id = 1 be added to the amount_due of the next row so the table would look like this:
+----+---------+------------+------------+---------+--------+
| id | loan_id | amount_due | due_at | paid_at | missed |
+----+---------+------------+------------+---------+--------+
| 1 | 1 | 100 | 2013-08-17 | NULL | 1 |
| 5 | 1 | 200 | 2013-09-17 | NULL | NULL |
| 7 | 1 | 100 | 2013-10-17 | NULL | NULL |
+----+---------+------------+------------+---------+--------+
Any advice on how to do it?
Thanks
Take a look at this :
SQL Fiddle
MySQL 5.5.32 Schema Setup:
CREATE TABLE loan_payments
(`id` int, `loan_id` int, `amount_due` int,
`due_at` varchar(10), `paid_at` varchar(4), `missed` varchar(4))
;
INSERT INTO loan_payments
(`id`, `loan_id`, `amount_due`, `due_at`, `paid_at`, `missed`)
VALUES
(1, 1, 100, '2013-09-17', NULL, NULL),
(3, 2, 100, '2013-09-17', NULL, NULL),
(5, 1, 100, '2013-10-17', NULL, NULL),
(7, 1, 100, '2013-11-17', NULL, NULL)
;
UPDATE loan_payments AS l
LEFT OUTER JOIN (SELECT loan_id, MIN(ID) AS ID
FROM loan_payments
WHERE DATEDIFF(NOW(), due_at) < 0
GROUP BY loan_id) AS l2 ON l.loan_id = l2.loan_id
LEFT OUTER JOIN loan_payments AS l3 ON l2.id = l3.id
SET l.missed = 1, l3.amount_due = l3.amount_due + l.amount_due
WHERE DATEDIFF(NOW(), l.due_at) >= 10
AND l.paid_at IS NULL
;
Query 1:
SELECT *
FROM loan_payments
Results:
| ID | LOAN_ID | AMOUNT_DUE | DUE_AT | PAID_AT | MISSED |
|----|---------|------------|------------|---------|--------|
| 1 | 1 | 100 | 2013-09-17 | (null) | 1 |
| 3 | 2 | 100 | 2013-09-17 | (null) | 1 |
| 5 | 1 | 200 | 2013-10-17 | (null) | (null) |
| 7 | 1 | 100 | 2013-11-17 | (null) | (null) |
Unfortunately I don't have time at the moment to write out full-blown SQL, but here's the psuedocode I think you need to implement:
select all DISTINCT loan_id from table loan_payments
for each loan_id:
set missed = 1 for all outstanding payments for loan_id (as determined by date)
select the sum of all outstanding payments for loan_id
add this sum to the amount_due for the loan's next due date after today
Refer to this for how to loop using pure MySQL: http://dev.mysql.com/doc/refman/5.7/en/cursors.html
I fixed my own problem by adding a missed_at field. I put the current timestamp ($now) in a variable before I update the first row to missed = 1 and missed_at = $now then I ran this query to update the next row's amount_due:
UPDATE loan_payments lp1 JOIN loan_payments lp2 ON lp1.due_at > lp2.due_at
SET lp1.amount_due = lp2.amount_due + lp1.amount_due
WHERE lp2.missed_at = $now AND DATEDIFF(lp1.due_at, lp2.due_at) <= DAYOFMONTH(LAST_DAY(lp1.due_at))
I wish I could use just use LIMIT 1 to that query but it turns out that it's not possible for an UPDATE query with a JOIN.
So all in all, I used two queries to achieve what I want. It did the trick.
Please advise if you have better solutions.
Thanks!