I am practicing in hackerEarth SQL and I came to this
My answer is : SELECT name FROM places WHERE rating >= 4.0.
Why is it wrong? The expected output should be
what is something wrong in my query? Thank you
You have to add another condition in where clause along with rating>4
-Execute only "Select Category" and you will find the relevant info
Related
I am trying to figure out how to put in line comments in Access.
I have seen the below post and have been trying to put through the solution from Dan which includes the WHERE Clause however it comes up with a "Syntax error (missing operator) in query expression AND "Comment FYI, This is a comment"<>"".
Script I have put through below for reference:
SELECT prod_name
FROM products
WHERE
AND "Comment: FYI, This is a comment"<>"";
How do you comment an MS-access Query?
Thanks!
The answer assumes that there is something else in the WHERE clause.
If there isn't, you would simply do:
SELECT prod_name
FROM products
WHERE "Comment: FYI, This is a comment"<>"";
I need to make a search request to Apache Solr similar to MySQL BETWEEN query.
In Solr document I have two fields: "postcode_from" and "postcode_to". This is a range of postal codes for some country region or city.
Only integer numbers!!!
I have a value (for example 1234) which is between "postcode_from" and "postcode_to" and I need to find all records which are pass this criteria.
In MySQL it is solving very easy:
SELECT * FROM `postal_location_network` WHERE 1234 BETWEEN `postcode_from` AND `postcode_to`;
How can I compose a proper query for Solr?
Thank you for help!
I'am not sure what you need but something like that is this what you are expected?
q = postcode_from:[yourValue TO *] AND postcode_to:[* TO yourValue]
Right solution is:
q = postcode_from:[* TO yourValue] AND postcode_to:[yourValue TO *]
Thanks ever
I want to be able to use the results of the first query and place into the second query, sorry if this doesn't make much sense, im new to all of this.
First Query
SELECT "NAME", "TYPE","CATEGORY" "Meters" FROM BBT_Locations
WHERE SQRT(Power((:myLocX-LOCX), 2) + Power((:MyLocY - LOCY),2)) < :Distance;
Second Query
Select Round((:Distance/20)*4)as "Meters";
Can you please elaborate more as in which field value of 1st query you would like to use in 2nd query ? There are JOIN query and Sub query concept in SQL which can be used. But we should know the field that we would like to use and get value for, based on that we can select the kind of query to write.
I have the following query:
INSERT INTO insertlog (Inforamtion) VALUES (
concat("Row Was Inserted",curdate());
MySQL is returning an error, but I cannot figure out why. My google searches do not show examples on how to perform something like this.
use it simpler like that
INSERT INTO insertlog (Inforamtion)
SELECT concat("Row Was Inserted ",curdate()) ;
be sure if your column is Information or Inforamtion
your query also works but you missed ) in the end . here demo with both solutions :
Demo to try here
I think you are missing one closing )
Moreover as Bill pointed, you may have spelled your column name incorrectly - information
I have a query which retrieves 3 columns from table which works fine in phpmyadmin
SELECT cab_id,
SUM(IF(rating=1,1,0)) as up,
SUM(IF(rating=0,1,0)) as down
FROM rating WHERE cab_id=101
table->'rating'
Can anyone help me to find how I can get this query worked using redbeanphp ?
I tried ,
R::getRow(),R::getAll(),R::$adapter->getAssoc()
none is working!!!
To check the correctness of code I tried,
SELECT * FROM rating group by cab_id having cab_id=101
and found working.But I need the first query statement to work! Any help ,please?
I got the answer finally, This one works.
$val = R::getAll($query);