Trying to print ints in MIPS, coming out as ASCII? - mips

Question

Here is some relevant code. I extracted these ints from a .txt file into buffer, and then use extractInts to format them into an array (intArray). Then I use printArray to loop through it and print. The ints in intArray are stored in a .space of 80 bytes, each in their own word.
My current output:
The array: 14385 57 14130 53 14388 13873 50 13109 13366 14393
My expected output:
The array: 18 9 27 5 48 16 2 53 64 98
# put ints into array
extractInts:
la $s0, buffer # $s0 points to buffer
la $s1, intArray # $s1 points to intArray
li $t0, 0 # i = 0
li $t1, 3 # intLoop max = 3
li $t3, 4 # nextWord max = 4
# loop to place each int within its own word boundary in intArray
intLoop:
beq $t0, $t1, exitLoop # exit loop if i = end of word
lb $t2, ($s0) # $t2 = intArray[]
beq $t2, '\n', nextWord # if $t2 = \n, go to nextWord
beq $t2, '\0', exitLoop # if $t2 = \0, go to exitLoop
sb $t2, ($s1) # save byte in $t2 to intArray[]
addi $t0, $t0, 1 # i++
addi $s0, $s0, 1 # increment buffer
addi $s1, $s1, 1 # increment intArray
j intLoop
# skip to next word
nextWord:
sub $t4, $t3, $t0 # $t4 = 4 - i
add $s1, $s1, $t4 # increment intArray by $t4
li $t0, 0 # restore i to 0
addi $s0, $s0, 1 # increment buffer
j intLoop
printArray:
li $t0, 0 # i = 0
while:
beq $t0, 80, exit # exit if i = end of array
lw $t1, intArray($t0) # $t1 = intArray[$t0]
addi $t0, $t0, 4 # move to next word in intArray
# print current int
li $v0, 1
move $a0, $t1
syscall
# print space
li $v0, 11
li $a0, 32
syscall
j while