How to update video playing current time using ajax in laravel - mysql

Question

<script>
var vid = document.getElementById("player");
$(function() {
var timeout;
$("#player").on("playing pause", function(e) {
// Save reference
var v = this
// Clear previous timeout, if any
clearTimeout(timeout)
// Call immediately if paused or when started
performaction(v.currentTime, v.duration)
// Set up interval to fire every 5 seconds
if (e.type === "playing") {
timeout = setInterval(function() {
performaction(v.currentTime, v.duration)
}, 5000)
}
})
function performaction(currentTime, duration) {
console.log(currentTime);
console.log(' ajax action goes here');
var data = { pause_time : currentTime };
$.ajax({
type: "POST",
url: '/instructor/promo_video/84',
data: data,
success: function() {
console.log("Value added");
}
})
}
})
</script>
In my database I have a video table in which I have a column name as pause_time.
Now if I use this js code for video current playing time then I am getting the time after 5 seconds interval in the console.
I want to send this time to the database using ajax in laravel. And also how to take the currentTime value in the controller.
Thanks in Advance!!

Answer 1

If you created a video table, then you should make a video model:
php artisan make:model Video
When you're using POST methods in frontend, you need to pass a CSRF token too.
const data = {
_token: YOUR_TOKEN,
pause_time : currentTime,
};
To get data from database, you should use ORM, so:
$video = Video::where(SOME_CONDITIONS, value)->first();
$currentTime = $video->pause_time;
To get data from frontend, you should use $request:
public function yourController(Request $request)
{
$currentTime = $request->pause_time;
}