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I have 3 tables:
users (id_user)
achievements (id_achievement)
user_achievements (id_user, id_achievement)
I need help selecting every achievement that a user has not yet completed.
Consider a cross join that generates all combinations of users and achievements, and a not exists condition with a correlated subquery to filter out those that were completed already:
select u.id_user, a.id_achievement
from users u
cross join achievements a
where not exists (
select 1
from user_achievements ua
where ua.id_user = u.id_user and ua.id_achievement = a.id_achievement
)
Related
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[![table named teams and Matches ][2]][2]I have 2 tables
[2]: https://i.stack.imgur.com/7v4nT.png**strong text**
I need data from these 2 tables in such a ways that a new table is formed with the following data
mid, result, date, team1id, team2id from matches table on the basis of tourid=6 and from table of team i need to show the Tname as team1 and Tname as team2.
Sounds like you need a join:
select matches.*,t1.Tname as team1,t2.Tname as team2 from matches
join team t1 on t1.Teamid=matches.team1id
join team t2 on t2.Teamid=matches.team2id
where tourid=6
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I have a simple entry in the oracle, there are 3 columns, date, API name and status. I want that in the answer I had not all history, and only the last on each of Names of API (only 7). I will be grateful for your help. I know that asked of the very difficult but I'm just new to oracle.
select l.log_date,l.job_name,l.status from user_scheduler_job_log l
could be you want the related status for name and last log_date
select u.job_name, u.status, t.max_date
from user_scheduler_job_log u
INNER JOIN(
select MAX(l.log_date) max_date, l.job_name
from user_scheduler_job_log l
GROUP BY l.job_name
) t on t.max_date = u.log_date
AND t.job_name = u.job_name
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Have a common schema, with two tables.
users table contains the columns id, name.
checkins table contains the columns user_id, checkin_date.
in this hypothetical, users can have many instances of rows in the checkins table.
checkin_date in this case is of type date
I want to be able to query for all users who have at minimum 1 checkin in the checkins table where the checkin is after 2016.
I would suggest using exists:
select u.*
from users u
where exists (select 1
from checks c
where c.user_id = u.id and c.checkin_date >= '2016-01-01'
);
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I want to retrieve all the 'events' of a user (given user_id) using his subscriptions.
I know this can be done using subquery but it is slow.
Please suggest the best approach to achieve it.
Here is the sqlfiddle link:
http://sqlfiddle.com/#!2/dd48e3
And here is the design image:
If u remove the where clause you will get the events corresponding to each user
select e.*,s.fname
from users s
join routine r ON (s.user_id = r.user_id)
join events e ON (e.r_id = r.r_id)
where s.user_id = ?
select * from events e left join subscriptions s on s.r_id = e.r_id where s.user_id = ?
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I have three tables say 'user', 'user_resources' and 'desktop_resources'.
'user' contains - emp_id,name and other attributes
'user_resources' - emp_id and desktop_id foreign key relation
'desktop_resources' - desktop_id and other attributes
Now i want a sql query from where i can get a table which shows me name from 'user' table and 'desktop_resources' attributes only where "emp_id=d_id"
how to go about it??
I don't see d_id column there, but if you think so, it would look like this:
SELECT name, desktop_resources.*
FROM desktop JOIN user_resources USING (desktop_id) JOIN user USING (emp_id)
This is a straightforward series of joins:
select u.name, dr.*
from user u
join user_resources ur on ur.emp_id = u.emp_id
join desktop_resources dr on dr.desktop_id = ur.desktop_id
where u.emp_id = $d_id
Finally found this query useful:
SELECT name, desktop.*
FROM desktop
NATURAL JOIN (
user
JOIN user_resource ON user.emp_id = user_resource.emp_id
)
I am sure there may be other ambiguous queries for this..if u have got a better query..please put it in comments...