PHPMailer comma seperated emails - mysql

I have a database field that contains emails seperated by a comma as below
email1#domain.com,email2#domain.com, etc etc
I am using PHP Mailer and have found several articles on here explaining how to loop through each email to add each email to the emailto address
I'm clearly doing something wrong as my code below only sends to one email
$sql="SELECT Email FROM Managers WHERE Company = '$name';";
$result = mysqli_query($db,$sql);
while ($row = mysqli_fetch_assoc($result));
$address = explode (',' , $row['Email']);
foreach ($address as $key => $v) {$mail->addAddress($key);}
When I output the result to check the output I just see all the emails as one string with no commas
Any advice would be most appreciated as from what I have read on here this should work.
UPDATE: I now have this working as below. Thanks for your help:
$sql="SELECT Email FROM Managers WHERE Company = '$name';";
$result = mysqli_query($db,$sql);
while ($row = mysqli_fetch_array($result)) {
$address = $row['Email'];
$address2 = explode (',',$address);
foreach ($address2 as $v) {$mail->addAddress($v);}

Always check what your code is really doing, don't assume it's doing what you think it is.
There is a simple bug in your code:
foreach ($address as $key => $v) {$mail->addAddress($key);}
Should be:
foreach ($address as $v) {$mail->addAddress($v);}
otherwise you're submitting the column name as the email address.

Related

Retrieve every model and return three values

I am looking for a way to retrieve all models in a database. Then loop through all of the models and read out the values for name, firstname and phonenumber.
So far I've gotten this and failed to go past it:
$searchModel = new EmployeeSearch();
$dataProvider = $searchModel->search(Yii::$app->request->queryParams);
I am then looking to implement those three values in a simple HTML table:
<tr><td>$firstname</td><td>$name</td><td>$phone</td></tr>
The table should be part of a PDF output, so ideally I would save it to a variable:
$html_table = '<tr><td>$firstname</td><td>$name</td><td>$phone</td></tr>';
I would need to get this for every model that fulfills the criteria of status = 'active' in the database.
So far I've only been able to get tables via gridView and not in a HTML template either.
You don't really need a data provider to achieve this, you could simply try :
$models = Employee::find()->where(['status'=>'active'])->orderBy('name ASC')->all();
foreach ($models as $model) {
echo "<tr><td>{$model->firstname}</td><td>{$model->name}</td><td>{$model->phone}</td></tr>";
}
Read more : http://www.yiiframework.com/doc-2.0/guide-db-active-record.html#querying-data
You can get all models like this:
$employees = Employee::find()
->select('firstname, name, phone')
->asArray()
->where(['status'=>'active'])
->all();
This way you will get an array of arrays containing the 3 selected fields, so now you only need to use a foreach to loop through them and create the table:
$html = '<table>';
foreach($employees as $employee) {
$html .= '<tr><td>'.$employee['firstname'].'</td><td>'.$employee['name'].'</td><td>'.$employee['phone'].'</td></tr>';
}
$html .= '</table>'

It is possible to retrieve specific part from a string variable in html?

I have set names to a variable, but i want part of the name.
var data = fullName
and lets say the full name 1 is VAN7324 high expense and full name 2 is 632-123A blog and i want to take out the name VAN7324 from the full name 1 and 632-123A from full name 2.
so the end result would be
name = VAN7324
name = 632-123A
is there anyways i can do this?
Use PHP
<?php
$fullName1 = "VAN7324 high expense";
$fullName2 = "632-123A blog";
$fullName1 = explode(" ", $fullName1);
$fullName2 = explode(" ", $fullName2);
echo $fullName1[0];
echo $fullName2[0];
?>
In the case it was a variable entered, for simplicity we will assume via post
<?php
$name = $_POST['name'];
$name = explode(" ", $name);
echo $name[0];
?>
This will output everything up to a space.

Parse json object from table via php connected to phpmyadmin

I'm using a json-parser in Xcode to fetch a table from phpmyadmin. The parser gets (or should get) the json-formated document via a php-file uploaded on my ftp-server. The file is successfully parsed but it doesn't recognize any objects. I think this is because there are multiple arrays in the json-document.
When there's only one entry the document looks like this:
[{"id":"1","Name":"Eric","Message":"first from web"}]
but when i add an entry it looks like this:
[{"id":"1","Name":"Eric","Message":"first from web"}]
[{"id":"1","Name":"Eric","Message":"first from web"},{"id":"6","Name":"Claes","Message":"Hurrburr"}]
As you can see the old array (containing only the single entry) is still there in the second array with both entries.
I suspect the problem is that the old arrays are still there when i update the database because when i tried parsing the json document with only one entry (only one array) it worked.
So my question is first if thereĀ“s something i missed in my code, or if you know why the old arrays are still there when I update the database or how to remove all previous arrays when the document is updating.
Here is my .php-file:
<?php
$username = "perhaps not sharing this information";
$password = "or this";
$database = "nah";
mysql_connect("the server url",$username, $password);
#mysql_select_db($database) or die("Error here");
$query = "SELECT * FROM debug_db";
$result = mysql_query($query) or die(mysql_error());
$num = mysql_numrows($result);
mysql_close();
$rows = array();
while($r = mysql_fetch_assoc($result))
{
$rows[] = $r;
echo json_encode($rows);
}
?>
And check out the json-document at: http://app.levinnovation.se/getjson.php
Thank you!

use a single return from a sql query

I'm using PHP to make a very specific sql query. For example sake, I have the user's ID number, but I need their name. So I do a sql query from that table with the ID number in order to return the name.
$result = mysql_query("SELECT name FROM users WHERE userID=$thisuserid",$db);
Now I want to use that. What's the most succinct way to go about making that result into a variable ths I can use?
edit:
I'm hoping that this is not the answer:
$rowCheck = mysql_num_rows($result);
if ($rowCheck > '0') {
while ($row = mysql_fetch_assoc($result)){
foreach ($row as $val){
$username = $val;
}
}
}
I have used something like this to keep it short in the past:
list($name) = mysql_fetch_row(mysql_query("SELECT name FROM users WHERE userID=$thisuserid",$db));
echo $name;
In my opinion, the best way to fetch any SQL result is through mysql_fetch_assoc(). To use it, you would do something like this:
$result = mysql_query("SELECT name FROM users WHERE userID=$thisuserid",$db);
while ($row = mysql_fetch_assoc($result)) {
echo $row['name']; // You get an array with each column returned from your query.
}
Still, MySQL extension has been replaced for MySQLi, which is acknowledged to be faster and more practical. It has both OOP and structural bindings, and takes more into account your server settings.
$result = mysql_query("SELECT name FROM users WHERE userID=$thisuserid",$db);
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
$name = mysql_fetch_row($result)[0];
You should use MySQLi as bellow:
$db = new MySQLi($host,$user,$pass,$db);
$query = $db->query('SELECT name FROM users WHERE userID='.$thisuserid);
$result = $query->fetch_object();
echo $result->name;
If you use SELECT * so you also can access via $result->{field_name}

JSON encode comma delimited row

I'm trying to add an autocomplete tokenizer script to some form fields and one issue I'm having is if a person saves multiple values for the field the autocomplete suggestions come back with all of his values as one long value instead of them being single values delimited by the comma. I first tried to simply explode the value but it doesn't format it correctly in the JSON encode.
Here is my PHP file:
//connection information
$host = "localhost";
$user = "myuser";
$password = "mypass";
$database = "mydb";
$param = ($_GET["term"]);
//make connection
$server = mysql_connect($host, $user, $password);
$connection = mysql_select_db($database, $server);
//query the database
$query = mysql_query("SELECT cb_activities FROM jos_comprofiler WHERE cb_activities REGEXP '^$param'");
//build array of results
for ($x = 0, $numrows = mysql_num_rows($query); $x < $numrows; $x++) {
$row = mysql_fetch_assoc($query);
$activities[$x] = array(cb_activitiesterm => $row[cb_activities]);
}
//echo JSON to page
$response = $_GET["callback"] . "(" . json_encode($activities) . ")";
echo $response;
mysql_close($server);
This gives the output like this:
[{"cb_activities":"Kicking Cats,"},{"cb_activities":"baseball,hockey,"}]
but I need it to output like this:
[{"cb_activities":"Kicking Cats,"},{"cb_activities":"baseball,"},"cb_activities":"hockey,"}]
I also need to find a way to prevent duplicate entries from populating. For instance, the way it is now, say 10 people all have kicking cats selected as a value, it will display 10 times in the autocomplete suggestions.
How do I set this up to correctly delimit at the commas and then weed out duplicate values?
NM the duplicate issue, I just added select distinct instead of just select, this json thing has me overcomplicating things now lol. Now if I can just figure out how to delimit properly at the comma all will be good.