Generate new spreadsheet from a selected row based on template - google-apps-script

Question

With this script I can generate new tab from all the row in a spreadsheet:
function onOpen() {
SpreadsheetApp.getUi().createMenu('Tab Orari')
.addItem('Genera Tab Orari', 'createTabs')
.addToUi()}
function createTabs() {
var ss = SpreadsheetApp.getActive();
var templateSheet = ss.getSheetByName('xxx');
ss.getSheetByName('Generale').getRange('I2:I').getValues().filter(String)
.forEach(function (sn) {
if (!ss.getSheetByName(sn[0])) {
ss.insertSheet(sn[0], ss.getSheets().length, {template: templateSheet});
}
});
}
I would generate a new spreadsheet (and so not a tab), based on a template tab (in this case, the tab "xxx") only when I select a specific row and rename this Spreadsheet as the value in the cell in column I for that corresponding row.
How to do that?

Answer 1

Instead of insertSheet use copyTo(spreadsheet)
The spreadsheet name can be obtained by obtaining the row number of the selected cell and finding the entry in column 9 ("I") of this row.
Sample:
function onOpen() {
SpreadsheetApp.getUi().createMenu('Tab Orari')
.addItem('Genera spreadsheet', 'createSpreadsheet')
.addToUi()}
function createSpreadsheet() {
var ss = SpreadsheetApp.getActive();
// the following line means that the function will search for the spreadsheet name in the active sheet, no matter which one it is
var sheet = ss.getActiveSheet();
//the selected row
var row = sheet.getActiveCell().getRow();
// column 9 corresponds to "I"
var name = sheet.getRange(row, 9).getValue();
var templateSheet = ss.getSheetByName('xxx');
var newSpreadsheet = SpreadsheetApp.create(name);
templateSheet.copyTo(newSpreadsheet);
}