I am doing the data cleaning in a BigQuery. I managed to count each of the variables. However there are some redundant info with different variables, so I need to merge the number and save the overall total in a single row.
This is my work:
SELECT
day,
COUNT(*) as Total,
FROM
table
where day<> 'null'
GROUP BY day
-- HAVING COUNT(*) >= 10?
ORDER BY COUNT(*) DESC;
The result is
What should I add so the Monday and Mndy is added in a single row? Thanks
SELECT
CASE WHEN day in ('Monday', 'Mndy') THEN 'Monday' ELSE day END day,
COUNT(*) as Total,
FROM
table
where day<> 'null'
GROUP BY 1
-- HAVING COUNT(*) >= 10?
ORDER BY COUNT(*) DESC;
Related
My database table contains value in this way
IMAGE FOR TABLE DATA
I want to track down same email which has been used more than one times for a particular month and year.
In the above scenario, email that has been repeated multiple times was sandeshphuya#gmail.com, jes#gmail.com and ramu#gmail.com for different months. I want to track down customer repetition following their email for each month and year.
The query that I am using right now is
SELECT DATE_FORMAT(booked_on, '%Y-%m') as monthYear, email,
COUNT(*) AS 'Count'
FROM 'tablename'
GROUP BY email,DATE_FORMAT(booked_on, '%Y-%m') HAVING COUNT(*) > 1 ORDER BY `booked_on`;
GROUP BY email was used as it generates the repeated email and GROUP BY DATE_FORMAT(booked_on, '%Y'-%m') was used to track down total email repeated for each month/year.
This prints out data as
IMAGE FOR SELECT QUERY
How can I track down total repeated email following month and year? The expected result is
RESULT EXPECTED
You can use your query as a subquery for a new group by:
select sub.monthYear,count(*)
from
(SELECT DATE_FORMAT(booked_on, '%Y-%m') as monthYear,
email,
COUNT(*) AS 'Count'
FROM 'tablename'
GROUP BY email,DATE_FORMAT(booked_on, '%Y-%m')
HAVING COUNT(*) > 1
ORDER BY `booked_on`) as sub
GROUP BY sub.monthYear
There is a task: develop a fragment of the Web site that provides work with one table.
Attributes of the table:
Day of the week,
Time of the beginning of the lesson,
Subject name,
Number of the audience,
Full name of the teacher.
We need to make a query: determine the day of the week with the largest number of entries, if there are more than one maximum (ie, they are the same), then output them all. I did the query as follows:
SELECT COUNT (*) cnt, day
FROM schedule
GROUP BY day
ORDER BY cnt DESC
LIMIT 1;
But if there are several identical maxima, then only one is displayed. How to write a query which returns them all?
You can use your query as a subquery in the HAVING clause, e.g.:
SELECT day, count(*) as cnt
FROM schedule
GROUP BY day
HAVING count(*) = (
SELECT count(*) as cnt
FROM schedule
GROUP BY day
ORDER BY cnt DESC
LIMIT 1
)
ORDER BY day
Hi i am trying to get the count of records per day which i can do, but i also want the date to be show, for example,
Result
Date | Count
26/01/2015 20
25/01/2015 | 413
Here is an example of my data.
I would think this would work. Replace 'yourTable' with your table name
SELECT Date, COUNT(*) FROM yourTable GROUP BY Date;
Get the total count and group them by date.
SELECT `date`, COUNT(*) as Total
FROM `table`
GROUP BY `date`
ORDER BY `date`;
I'm looking for a function to return the most predominant non numeric value from a table.
My database table records readings from a weatherstation. Many of these are numeric, but wind direction is recorded as one of 16 text values - N,NNE,NE,ENE,E... etc in a varchar field. Records are added every 15 minutes so 95 rows represent a day's weather.
I'm trying to compute the predominant wind direction for the day. Manually you would add together the number of Ns, NNEs, NEs etc and see which there are most of.
Has MySQL got a neat way of doing this?
Thanks
It's difficult to answer your question without seeing your schema, but this should help you.
Assuming the wind directions are stored in the same column as the numeric values you want to ignore, you can use REGEXP to ignore the numeric values, like this:
select generic_string, count(*)
from your_table
where day = '2014-01-01'
and generic_string not regexp '^[0-9]*$'
group by generic_string
order by count(*) desc
limit 1
If wind direction is the only thing stored in the column then it's a little simpler:
select wind_direction, count(*)
from your_table
where day = '2014-01-01'
group by wind_direction
order by count(*) desc
limit 1
You can do this for multiple days using sub-queries. For example (assuming you don't have any data in the future) this query will give you the most common wind direction for each day in the current month:
select this_month.day,
(
select winddir
from weatherdatanum
where thedate >= this_month.day
and thedate < this_month.day + interval 1 day
group by winddir
order by count(*) desc
limit 1
) as daily_leader
from
(
select distinct date(thedate) as day
from weatherdatanum
where thedate >= concat(left(current_date(),7),'-01') - interval 1 month
) this_month
The following query should return you a list of wind directions along with counts sorted by most occurrences:
SELECT wind_dir, COUNT(wind_dir) AS count FROM `mytable` GROUP BY wind_dir ORDER DESC
Hope that helps
I have a table with emp_id, income, etc.
I wish to get number of records for a query like
select * from table_name where income <= 500;
There will be at least 3 such income groups - which will b given at report generation time.
Further I wish to get all 3 Counts - and group the results by the count of their respective income group - all this in a single query.
What is the easiest way to do this?
Can you try this ,if this doesn't suite your need you may need to write a custom stored procedure
SELECT
sum((income <= 500)) as range1,
sum((income <= 1000)) as range2
FROM table_name
sample fiddle
You can use a CASE expression to create your categories, and then a GROUP BY to summarize the categories.
SELECT COUNT(*) AS num,
CASE WHEN income IS NULL THEN 'missing'
WHEN income <= 0 THEN '0'
WHEN income <= 500 THEN '1 - 500'
WHEN income <= 1000 THEN '501-1000'
ELSE '> 1000'
END AS category
FROM table_name
GROUP BY category WITH ROLLUP
Including the WITH ROLLUP clause will give you an overall count as well as the count of each category.