Is there a a way to overload 'is' operator? - json

I designed a class which wrap an internal json object.
My class acts like a real json, returning a Map or a List depending of the current intermediate node (a json is made of Maps, Lists and values).
This class overrides runtimeType to use it's current json type :
#override
get runtimeType{
return (_json.runtimeType);
}
This indeed overrides the type to an _InternalLinkedHashMap<String, dynamic> which is what the json uses for a Map or to an List<dynamic> for a List.
But this is not enough to override tests like (result is Map) or (result is List) which works for json but not for my class.
I try to overload operator is but i don't find how to.
is there a way to do that ?

Related

Dart: Generic which has .fromJson constructor

In Swift I'm used to setting up a protocol JSONInitializable which defines an init?(json: JSON) meaning that all classes and structs that conform to the protocol are initializable with a JSON object.
Is it true that this isn't possible in Dart (with an abstract class) because static methods and factory initializers are not inherited from an abstract class?
The reason I'm asking is because I'm writing a lot of similar methods for API GET requests, which could easily be merged into one, e.g.:
static Future<T> get<T extends JSONInitializable>(int id) async {
final resourceName = T; // TODO: transform to snake case
final uri = Uri.parse("$kApiHostname/api/$resourceName/$id");
final response = await _secureGet(uri);
if (response == null) {
return null;
}
final responseJson = json.decode(response.body);
final model = T.fromJson(responseJson);
return model;
}
But for that to work I'd need to constrain T to a protocol/interface that defines the .fromJson() initializer.
The feature you want is not available (or planned) in Dart, but there have been discussions on it.
Give this issue a thumbs up: https://github.com/dart-lang/language/issues/356
A MANUAL workaround could be having a map of serializers,deserializers like:
//Register object 1 in singleton
JsonMapper.register<MyObject>(JsonObjectMapper(
(mapper, map) => MyObject.fromJson(map),
(mapper, instance) => instance.toJson(),
));
//Register object 2 in singleton...
...
This way you can deserialize and serialize your objects as long as you have them registered without resorting to it's generic type.
The AUTOMATIC (technically code generated) way would be using a package like simple_json to help you workaround this with a little code generation so you don't mess up registering and eliminating mappers.
And the big plus is that the actual code that transforms your objecto from and to JSON is not stored in the object itself but in the generated classes, thus pushing the responsability of serializaition deserailization from the object into the generated code (in a decoupled manner).
Take my advice with a grain of salt as with both approaches you lose static type checking of wether a type has a registered mapper and can be converted.

My RCP Client is not returning a deep copy of an object

I have been working on an RCP Client to handle weather data.
What i do is 2 things, first i scraped the JSON i will be using and put it into a dart file. See: https://dartpad.dartlang.org/a9c1fe8ce34c608eaa28
My server.dart page, will import the weather data, and then carry out the following:
import "dart:io";
import "weather_data.dart";
import "dart:convert";
import "package:rpc/rpc.dart";
find ApiServer _apiServer = new ApiServer(prettyPrint:true);
main() async {
Weather w = new Weather(WeatherJson);
TestServer ts = new TestServer(w);
_apiServer.addApi(ts);
HttpServer server = await HttperServer.bind(InternetAddress.ANY_IP_V4, 12345);
server.listen(_apiServer.httpRequestHandler);
}
class Weather{
Map weather;
Weather(this.weather){
Map get daily => weather["daily"];
}
}
#ApiClass(name:"test_server", version: 'v1', description: 'This is a test server api to ping for some quick sample data.')
class TestServer {
Weather myWeather;
TestServer(this.myWeather){
}
#ApiMethod(method:'GET', path: 'daily')
Map<String, Object> getDaily(){
return myWeather.daily;
}
}
So, the server starts correctly, and i will go to localhost:12345/test_server/v1/daily and it will return this:
{
"summary": {},
"icon": {},
"data": {}
}
which is not correct. If you look up the JSON data, summary and icon are both strings and data is an array. They are also empty, and should contain the data i wanted to return.
Why does this occur? Is it because i am returning a Map<String, Object>? I was trying to set it up to be: Map<String, dynamic> but the dart compiler didnt like it.
How do i get this data to return the correct dataset?
The Dart website for RPC is located at: https://github.com/dart-lang/rpc
and you can see that under methods, the return value of a method can be either an instance of a class or a future. That makes sense as per usual, so I set it to be a Map<String,Object> though trying to be vague about it by saying: Map was not sufficient.
Edit:
When doing this mostly in dart pad without RPC, it seems to work correctly, by a sample of: https://dartpad.dartlang.org/3f6dc5779617ed427b75
This leads me to believe something is wrong with the Parsing tool as it seems the return type in dartpad allows to return Map, Map<String, Object>, and Map<String, dynamic>.
Having had a quick look at the RPC package README here https://pub.dartlang.org/packages/rpc, it seems that methods marked as Api methods (with #ApiMethod) should return an instance of a class with simple fields such as:
class ResourceMessage {
int id;
String name;
int capacity;
}
The RPC package will take that instance and serialize it into JSON based on the field names.
From the README:
The MyResponse class must be a non-abstract class with an unnamed
constructor taking no required parameters. The RPC backend will
automatically serialize all public fields of the the MyResponse
instance into JSON ...
You are returning a nested Map representation of the JSON you want the RPC operation to emit and would guess that the RPC package does not handle it as you are expecting it to.
Re: this from your question:
This leads me to believe something is wrong with the Parsing tool as
it seems the return type in dartpad allows to return Map, Map, and Map.
There is no 'parsing' on JSON going on on your example. The data you have is a set of nested literal Dart Maps, Lists and Strings with the same structure as the JSON it was derived from. It just happens to look like JSON.
In your example you are just selecting and printing a sub-map of your data map (data['daily']), which prints out the String that results from calling toString() - which is recursive so you get the contents of all the nested maps and lists within it.
So it's not a 'deep copy' issue, but a difference in how toString() and the RPC code processes a set of nested maps.
BTW: the return type of your getDaily() method is immaterial. What is returned is just a Map whatever the declared return type of the method is. Remember types in Dart are optional and there for editors and compilers to spot potentially incorrect code. See https://www.dartlang.org/docs/dart-up-and-running/ch02.html#variables.
I am going to piggyback off of #Argenti Apparatus here as there was a lot of information gained from him.
Long story short, the required return type of the method:
#ApiMethod(method:'GET', path: 'daily')
Map<String,Object> getDaily(){ // <-- Map<String,Object>
return myWeather.daily;
}
is the error.
I went through and updated the method signature to be Map<String,String> and it parsed it entirely correct. It did not parse the object as a string, but actually parsed it as a full recursed object.
I went through and for the sake of code cleanliness also changed signatures of Weather properties to reflect what they actually were, Map<String,Object> as well.
All in all, When defining it to be an value type of Object, it was returning curly braces, but setting it as a String parsed it correctly.
I ran it through JSLint to confirm it is correct as well.
I gave a +1 to the helper, I had to dig deeper into the code to see WHY it wasnt doing a Map correctly.
This also I feel, is plausibly a bug in RPC Dart.

Convert grails domain object to JSON and manipulate it

I have a grails object that I am converting using def json = object as JSON. After I have it converted I want to add one more property called pin to the JSON which looks like the following.
[location:[lat:23.03, lon:72.58]]
Only way to do this so far seems like following
Serialize the DomainClass to JSON using grails.converters.json
Convert the JSON to string
Create JSONBoject using the string from Step 2
Add the property
Convert it back to String
Any other way to do this using grails.converters.json? I have tried using Gson but I do not want to go that route because I am getting many Circular Reference Errors
Try this:
domainInstance.properties + [pin: pinInstance] as JSON
I recently needed to do a similar thing. Some caveats:
This is using Grails 2.4.5
I use MongoDB as a backend. As such, I created an object marshaller for MongoDB domain classes. It is printed below, and you can wrap a similar marshaller for your domain class(es):
Marshaller:
class MongodbObjectMarshaller implements ObjectMarshaller<JSON> {
#Override
boolean supports(Object o) { return o?.properties?.dbo }
#Override
void marshalObject(Object obj, JSON converter) throws
ConverterException {
Map propertiesToOutput = obj.properties.dbo
propertiesToOutput.remove("_id") //don't print org.bson.types.ObjectId
propertiesToOutput.remove("version") //don't print gorm verson column
converter.build {
_id obj.id.toString()
propertiesToOutput.each{ entry ->
"$entry.key" entry.value
}
}
}
}
What that marshaller does, it allow in JSON output any of the domain class's properties. obj.properties.dbo is special to MongoDB, but for a regular domain class, you can just grab the properties and exclude the ones you don't need.
Then in my controller, this works:
domainInstance.pin = [location:[lat:23.03, lon:72.58]]
def content = tacticalCard as JSON
because my marshaller now picks up the pin property and prints it.

How to add extra fields to an Object during Jackson's json serialization?

I need to add new property to an object, when serializing to JSON. The value for the property is calculated on runtime and does not exist in the object. Also the same object can be used for creation of different JSON with different set ot fields (kind of having a base class with subclasses, but I don't want to create ones just for JSON generation).
What is the best way of doing that, which doesn't involve creation of custom serializer class, which will take care of serializing of whole set of object's fields? Or may be it is possible to inherit some "basic" serializer, and simply take it's output and add new field to it somehow?
I learned about mixins, and looks like it is possible to rename/hide some fields, however it seems not be possible to add an extra one.
Can you not just add a method in value class? Note that it does not have to be either public, or use getter naming convention; you could do something like:
public class MyStuff {
// ... the usual fields, getters and/or setters
#JsonProperty("sum") // or whatever name you need in JSON
private int calculateSumForJSON() {
return 42; // calculate somehow
}
}
Otherwise you could convert POJO into JSON Tree value:
JsonNode tree = mapper.valueToTree(value);
and then modify it by adding properties etc.
2021 calling...
Simplest way I found to do this is #JsonUnwrapped:
public class Envelope<T> {
#JsonUnwrapped // content's fields are promoted alongside the envelope's
public T content;
// Transmission specific fields
public String url;
public long timestamp;
}
This works (bi-directionally) so long as Envelope's fieldnames do not clash with those of content. Also has a nice feature of keeping the transmission properties at the end of the serialised JSON.
One option is to add a field for this property and set it on the object before writing to JSON. A second option, if the property can be computed from other object properties you could just add a getter for it, for example:
public String getFullName() {
return getFirstName() + " " + getLastName();
}
And even though there's no matching field Jackson will automatically call this getter while writing the JSON and it will appear as fullName in the JSON output. If that won't work a third option is to convert the object to a map and then manipulate it however you need:
ObjectMapper mapper //.....
MyObject o //.....
long specialValue //.....
Map<String, Object> map = mapper.convertValue(o, new TypeReference<Map<String, Object>>() { });
map.put("specialValue", specialValue);
You're question didn't mention unmarshalling but if you need to do that as well then the first option would work fine but the second two would need some tweaking.
And as for writing different fields of the same object it sounds like a job for #JsonView

Dynamically ignore properties with JacksonJson

I'm aware that there are multiple way to tell JacksonJson to ignore
properties during rendering but all of them are static. (JasonIgnore, MixIn classes, ..).
This is my scenario. A domain object can implement a interface called FilteredDomain to
allow it to be dynamically filtered. The interface is simple and only exposes one method
"getIgnoreProperties". (A list of properties to ignore).
I then register a Custom Serializer that binds to the FilteredDomain object. The
code looks something like:
private class FilteredDomainSerializer extends JsonSerializer<FilteredDomain> {
public void serialize(FilteredDomain arg, JsonGenerator jgen,
SerializerProvider provder) throws IOException,
JsonProcessingException {
final BeanWrapper wrapper = PropertyAccessorFactory.forBeanPropertyAccess(arg);
for (PropertyDescriptor pd : wrapper.getPropertyDescriptors()) {
final String name = pd.getName();
if (arg.getIgnoreProperties().containsKey(name))
continue;
final Object value = wrapper.getPropertyValue(name);
jgen.writeObjectField(name, value);
}
}
}
First, I really dislike that I need to use the Spring Bean wrapper to get a list of all properties and iterate through them (There must be a way to do this is jackson json).
Second, The code still dosen't work. I get the error:
org.codehaus.jackson.JsonGenerationException: Can not write a field name, expecting a value
at org.codehaus.jackson.impl.JsonGeneratorBase._reportError(JsonGeneratorBase.java:480)
at org.codehaus.jackson.impl.Utf8Generator.writeFieldName(Utf8Generator.java:270)
at org.codehaus.jackson.JsonGenerator.writeObjectField(JsonGenerator.java:1088)
at com.rootmusic.util.SystemJsonObjectMapper$ValueObjectSerializer.serialize(SystemJsonObjectMapper.java:65)
at com.rootmusic.util.SystemJsonObjectMapper$ValueObjectSerializer.serialize(SystemJsonObjectMapper.java:1)
at org.codehaus.jackson.map.ser.ContainerSerializers$IndexedListSerializer.serializeContents(ContainerSerializers.java:304)
at org.codehaus.jackson.map.ser.ContainerSerializers$IndexedListSerializer.serializeContents(ContainerSerializers.java:254)
at org.codehaus.jackson.map.ser.ContainerSerializers$AsArraySerializer.serialize(ContainerSerializers.java:142)
at org.codehaus.jackson.map.ser.MapSerializer.serializeFields(MapSerializer.java:287)
at org.codehaus.jackson.map.ser.MapSerializer.serialize(MapSerializer.java:212)
at org.codehaus.jackson.map.ser.MapSerializer.serialize(MapSerializer.java:23)
at org.codehaus.jackson.map.ser.StdSerializerProvider._serializeValue(StdSerializerProvider.java:606)
at org.codehaus.jackson.map.ser.StdSerializerProvider.serializeValue(StdSerializerProvider.java:280)
The error comes from the fact that you are not writing START_OBJECT / END_OBJECT around field-name/value pairs, so that should be easy to fix.
As to more dynamic filtering, you could read this blog entry which includes standard methods. #JsonView works if you have sets of static definitions (one of which you can dynamically select on per-serialization basis), but if you want yet more dynamic system, #JsonFilter is the way to go.
Alternatively, another relatively simple way would be to first "convert" your POJO into a Map:
Map props = objectMapper.convertValue(pojo, Map.class);
(which is similar to serializing it as JSON, except that result is a Map which would render as JSON)
and then selectively trim Map, and serialize that as JSON. Or, if you prefer, you can use JsonNode ("tree model") as the intermediate thing to modify and then serialize.