Convert and parse json string to key value pairs using NewtonSoft - json

Question

Trying to convert a json string to key value pairs using Newtonsoft but no luck so far.
Response from the API:
var response = #"{'result':{'0199 - B344EE33':
{
'6400_00260100':{'1':[{'val':336688}]},
'6400_00462500':{'1':[{'val':null}]},
'6800_00832A00':{'1':[{'low':3000,'high':3000,'val':3000}]},
'6800_008AA200':{'1':[{'low':0,'high':null,'val':0}]}
}}}";
Result I want is a new object of key value pairs:
{
"6400_00260100" : 336688,
"6400_00462500" : null,
"6800_00832A00" : 3000,
"6800_008AA200" : 0
}
In the response the result will always be the first and only prop. In the next level the code 0199 - B344EE33 can change but there will be only one prop in this level so we can always take the first one. Then in the last level we always need the val property.
What I have is the following but for getting the key value pairs in a clean way I got stuck:
var json = JObject.Parse(response);
var result = json["result"].First;
var path = result.Path;
UPDATE
var jObjectResult = new JObject();
var response = #"{'result':{'0199 - B344EE33':
{
'6800_10821E00':{'1':[{'val':'SMA Sunny Boy'}]},
'6800_00A21E00':{'1':[{'val':'3.0.0.2222'}]},
'6800_00823400':{'1':[{'low':3000,'high':3000,'val':3000}]},
'6800_08822B00':{'1':[{'val':'SMA'}]},
'6800_08822000':{'1':[{'val':'Sunny Boy 3.0'}]}
}}}";
var json = JObject.Parse(response);
var json_serial = json["result"].First.Children<JObject>().ToList()[0];
foreach(var token in json_serial)
{
var tokenKey = token.Key;
var tokenVal = token.Value.SelectToken("$.1[0].val");
jObjectResult.Add(tokenKey, tokenVal);
}

Answer 1

You could use SelectTokens with the recursive descent operator .. to find all the val properties, then walk up the chain using .Parent repeatedly to get the corresponding key. Create new JProperties from this information and put them into a new JObject to get your result. Here is a "one-liner":
var result = new JObject(
JObject.Parse(response)
.SelectTokens("$..val")
.Select(jt => new JProperty(
((JProperty)jt.Parent.Parent.Parent.Parent.Parent.Parent).Name,
jt
))
);
Fiddle: https://dotnetfiddle.net/TbZ7LS

Answer 2

At the end with some pointers form #Brian Rogers I came with the following solution:
// Arrange
var response = #"{'result':{'0199 - B344EE33':
{
'6800_10821E00':{'1':[{'val':'SMA Sunny Boy'}]},
'6800_00A21E00':{'1':[{'val':'3.0.0.2222'}]},
'6800_00823400':{'1':[{'low':3000,'high':3000,'val':3000}]},
'6800_08822B00':{'1':[{'val':'SMA'}]},
'6800_08822000':{'1':[{'val':'Sunny Boy 3.0'}]}
}}}";
// Act
var json = JObject.Parse(response);
var json_serial = (JProperty)json["result"].First();
var jObjectResult = new JObject(
json_serial.Value.Select(p =>
{
return new JProperty(
((JProperty)p).Name,
p.First.SelectToken("$.1[0].val")
);
}));