Replace character using google apps script - google-apps-script

Question

I have a column which is a date in string format with this format
2020-02-23T12:14:06+0000
And i want to remove the T and replace it with space and also just completely remove the last part (+0000)
I have tried this
var A1 = CONTENT.getRange("B:B").getValue();
var A1String = A1.toString().replace("T*", "");
but it doesn't work.
Any ideas?
This is the original script in which i want to incorporate it into.
var spreadsheet = SpreadsheetApp.getActiveSpreadsheet();
var sheet = spreadsheet.getSheetByName('sheetname');
var range = sheet.getRange("A:C");
var response = UrlFetchApp.fetch("API CALL");
var dataAll = JSON.parse(response.getContentText());
var dataSet = dataAll.data;
var rows = [],
data;
for (i = 0; i < dataSet.length; i++) {
data = dataSet[i];
rows.push([new Date(),data.created_time,data.message,data.permalink_url,
data.reactions.summary.total_count
,data.comments.summary.total_count,data.insights.data[1].values[0].value,data.insights.data[2].values[0].value,data.insights.data[3].values[0].value,data.insights.data[0].values[0].value['link clicks'],data.insights.data[0].values[0].value['photo view'],data.insights.data[0].values[0].value['other clicks'],data.insights.data[0].values[0].value['video play'],data.insights.data[4].values[0].value,data.insights.data[5].values[0].value,data.insights.data[6].values[0].value,data.insights.data[7].values[0].value["like"],data.insights.data[7].values[0].value["love"],data.insights.data[7].values[0].value["wow"],data.insights.data[7].values[0].value["haha"],data.insights.data[7].values[0].value["sorry"]]); //your JSON entities here
}
Logger.log(rows)
//sheet.getRange(getlastRow() + 1, 1, rows.length, 2).setValues(rows);
sheet.getRange(sheet.getLastRow() + 1, 1, rows.length, 22).setValues(rows);
/**
* Removes duplicate rows from the current sheet.
*/
var sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('sheetname');
var data = sheet.getDataRange().getValues();
data.reverse(); //reverses the row order.
var last=sheet.getLastRow();
var newData = new Array();
for(i in data){
//Logger.log(i);
var row = data[i];
//Logger.log(row[5]);
var duplicate = false;
for(j in newData){
//Logger.log(newData[j][3]);
if(row[3] == newData[j][3]){
duplicate = true;
}
}
if(!duplicate){
newData.push(row);
}
}
newData.reverse(); // reverses your data back to its original order.
sheet.clearContents();
sheet.getRange(1, 1, newData.length, newData[0].length).setValues(newData);
}
//
//

Answer 1

If you want to remove always the same thing (i.e. "T" and "+0000"), you could use the following script:
The result obtained: 2020-02-23 12:14:06
CODE:
// ---------- Menu ----------
// Add a Menu named Format Date to run the script
function onOpen() {
var ui = SpreadsheetApp.getUi();
ui.createMenu('Format Date')
.addItem('Go!', 'FormatDate')
.addToUi();
}
function FormatDate() {
var ss = SpreadsheetApp.getActiveSheet(),
array = [];
ss.getRange("B2:B") // Choose the range here
.getValues()
.forEach(function (dates) {
// "T" is replaced with a space: " " and "+0000" is replace with empty:""
[["T", " "], ["+0000", ""]]
.map(function (a, i) {
return dates = replace(dates.toString(), a[0], a[1])
})
array.push([dates])
});
// You can set a different column to write the data
// Or keep B2:B to overwrite your data
ss.getRange("B2:B")
.setValues(array)
}
function replace(d, a, r) {
return d.indexOf(a) > -1 ? d.split(a)
.join(r) : d;
}
Credit: got inspired by JPV's code to a different question long time ago