Access query fields in mongodb inside forEach - json

In mongodb, we can use forEach() on find() method for iterating over documents inside the collection . Now the question is can we access the query field inside the forEach . For eg:-
db.mycollection.find({name : 'Mike'}).forEach(function(document) {
// var firstName = name;
})
Can we do something like this or what alternative we can use ? Please help.

You are almost there, try the below code:
db.mycollection.find({name : 'Mike'}).forEach(function(document) {
var firstName = document.name; // Just use the . operator
print(firsName)
// Rest of your operations.
})

Related

How to fetch data from database with 3 parameters Laravel

I'm still new to this laravel, for now I'm facing a trouble for fetching data from the database. What i want to get is when there are only one data available, the second parameters won't be executed, but if there are some data available on the second parameters, then all the data from first parameter and the second parameter will be called.
$detail = Barang_Keluar_Detail::findOrFail($id); //15
$cariid = $detail->pluck('barang_keluar_id');
$instansiquery = Barang_Keluar::where('id',$cariid)->first(); //21
$instansiid = $instansiquery->pluck('instansi_id');
$tanggal = $instansiquery->pluck('tanggal')->first();//2019-12-31
and the parameter are here
$cariinstasama = Barang_Keluar::where('id', $cariid)
->orWhere(function ($query) use($instansiid, $tanggal) {
$query->where('tanggal', "'$tanggal'")
->where('instansi_id', $instansiid);
});
Please any help will be appreciated, thank you.
Laravel query builder provides elegant way to put conditional clause using when() . You can put conditional clause on your query like this:
$cariinstasama = Barang_Keluar::where('id', $cariid)
->when($instansiid, function ($query, $instansiid) {
return $query->where('instansi_id', $instansiid);
})
->when($tanggal, function ($query, $tanggal) {
return $query->where('tanggal', $tanggal);
})->get();
For more info see https://laravel.com/docs/5.8/queries#conditional-clauses
You can try this as well.
$cariinstasama = Barang_Keluar::where('id', $cariid);
if($instansiid !== null)
{
$cariinstasama->where('instansi_id', $instansiid);
}
if($tanggal !== null)
{
$cariinstasama->where('instansi_id', $instansiid);
}
$result = $cariinstasama->get();
Its not clear what exactly you want.
Are you applying more than one parameter on the query if the first parameter result gives you more than one row in the database? If yes check out my approach :
$query = new Model(); // the model you want to query
if($query->where('col1', $param1)->count() > 1) // checks if the query from the 1st parameter produces more than one row in the database
$query = $query->where( // if yes apply more parameters to the query
[
['col1', $param1],
['col2', $param2]
]
);
else
$query = $query->where('col1', $param1);
$results = $query->get();
Hope it helps....

mySQL query for building dynamically populated model

I have some code below which demonstrates a hard-coded example of what I would like to accomplish dynamically.
At a high level, I wish to do something like select * from view_data_$app_state and then get all of the data from that views table into my mustache templates dynamically.
The code I currently must use to group multiple rows of data for a specific column along with the views data is:
<?php
error_reporting(E_ALL);
class Example {
function __construct(){
try {
$this->db = new PDO('mysql:host=localhost;dbname=Example', 'root','drowssap');
}
catch (PDOException $e) {
print($e->getMessage());
die();
}
}
function __destruct(){
$this->db = null;
}
function string_to_array($links_string){
return explode(",", $links_string);
}
function get_view_data(){
$q = $this->db->prepare('select *, GROUP_CONCAT(`links`) as "links" from `view_data_global` ');
$q->execute();
$result = $q->fetchAll(PDO::FETCH_ASSOC);
return $result;
}
}
$Example = new Example();
$result = $Example->get_view_data();
$result[0]["links"] = $Example->string_to_array($result[0]["links"]);
echo json_encode($result);
This gives me the perfect object while
GROUP_CONCAT seems to be doing the trick this way, however I MUST know the column name that will contain multiple rows before writing the query. I am trying to figure out an approach for this and wish to make a custom query + code example that will transform cols with multiple rows of null null and not empty data into an array like above - but return the data.. again like the code above.
Below is an output of the actual data:
[{"id":"1","title":"This is the title test","links":["main","about","store"]}];
How can I replicate this process dynamically on each view table?
Thank you so much SO!
You can use PDOStatement::fetch to retrieve your results, with fetch_style set to PDO::FETCH_ASSOC (some other values will also provide the same information). In this case, the result set will be array indexed by column name. You can access this information with foreach (array_expression as $key => $value)
See the documentation for additional information.

Write database queries in Magento custom module

I created a custom module in my Magento. This is working good. My module's name is mymodule.
Mymodule.php
class Myshop_Mymodule_Block_Mymodule extends Mage_Core_Block_Template
{
public function myfunction()
{
return "Hello User";
}
}
The path of the Mymodule.php file is C:\wamp\www\magento\app\code\local\Myshop\Mymodule\Block.
Now I want to display some data from database. For example I would like to display the admin's email id. How can I display this??
I tried like this.
$read = Mage::getSingleton('core/resource')->getConnection('core_read');
//database write adapter
$write = Mage::getSingleton('core/resource')->getConnection('core_write');
$result = $read->fetchAll("select email from admin_user where user_id= 1");
var_dump($result);
I write these lines in Mymodule.php inside myfunction. But nothing displayed(display only "Hello User").
So my question is how to display or write database queries in magento custom module.
Please someone help me..Any help is really appreciable..
We generally avoid using adapters when magento by default provides models for the basic tables. In your case, you can fetch the admin details using following :
<?php
$userDetails = Mage::getModel('admin/user')->load(1);
//where 1 is your admin user id
echo $userDetails->getEmail();
?>
Hence, your function can be modified as :
<?php
class Myshop_Mymodule_Block_Mymodule extends Mage_Core_Block_Template
{
public function myfunction()
{
$userDetails = Mage::getModel('admin/user')->load(1);
return $userDetails->getEmail();
}
}
You can get data from database in magento as
$collection = Mage::getModel("mumodule/mymodule")->getCollection();
foreach($collection as $data){
..Your Code ..
}

Laravel Select Query within helper file

I'm coming from codeigniter background. Unlike codeigniter helper directory, i just created helper directory within app directory of Laravel. Just want to know how to execute query within this common function. Here is my codeigniter function.
function show_menu($primary_key_col, $parent_id, $sort_order)
{
$output = "";
$ci =& get_instance();
$ci->db->select("*");
$ci->db->where('is_active', "Y");
$ci->db->where('is_delete', "N");
$ci->db->where('parent_id', $parent_id);
($sort_order!="")?$ci->db->order_by($sort_order, "ASC"):"";
$query = $ci->db->get('tbl_cms_menus');
foreach ($query->result() as $row){
$output .= '<option value="'.$row->$primary_key_col.'">'.$indent.$row->menu_name.'</option>';
}
return $output;
}
I tried something like this in laravel file. but this code did't give me any result. Please tell me where i'm doing wrong in this code. thanks
function databaseTable()
{
$table = DB::table('tbl_cms_menus');
$get_rows = $table->get();
$count_rows = $table->count();
if($count_rows > 0){
foreach ($get_rows as $tbl)
{
echo $tbl->menu_name;
}
}
}
This code will rot so hard that it shipped pre-rotten.
But, if you want to just.. ram it into the app all dry like that.. then add something like this to your base controller class...
$whatever = crazyChainingStuff;
foreach ($whatever ...) { $topMenu .= ... }
View::share('topMenu', $topMenu);
If you want to learn how to write code that will do less damage to your company and your clients then I recommend starting by watching Uncle Bob's "Fundamentals" videos. At least the first 5-6. http://cleancoders.com
It looks like you are trying to generate a drop-down/select with some data from your database, in this case, you should pass the data required for the drop-down/select from your controller to the view where you have written your HTML, for example, in your view, you may have a select like this:
echo Form::select('cms_menu', $cms_menu, Input::old('cms_menu'));
Or this (If you are using Blade):
{{ Form::select('cms_menu', $cms_menu, Input::old('cms_menu')) }}
From your controller you should pass the $cms_menu which should contain the menu-items as an arrtay and to populate that array you may try something like this:
$menuItems = DB::table('tbl_cms_menus')->lists('menu_name','id');
return View::make('your_view_name', array('cms_menu' => $menuItems));
Also, you may use something like this:
// Assumed you have a Page model
$menuItems = Page::lists('menu_name', 'id');
return View::make('your_view_name', array('cms_menu' => $menuItems));
You may also read this article which is about building a menu from database using view composer (More Laravelish way). Read more about Form::select on documentation.
It was too late to give an answer. I was also from CodeIgniter background and when I learnt Laravel then first I try to find how can I write a query in Helper. My Team leader helped me.
I have converted your code in a helper function.
function show_menu($primary_key_col, $parent_id, $sort_order)
{
$query = DB::table('tbl_cms_menus')
->select('*')
->where('is_active', '=', 'Y')
->where('is_delete', '=', 'N')
->where('parent_id', '=', $parent_id);
($sort_order != "")? $query->orderBy($sort_order, "ASC") : "";
$resultData = $query->get()->toArray();
}
Here $resultData will be array format. Now, you can create a foreach loop according to your requirement.

Yii JSON with relations

How I can return object with all relations(ans sub objects relations?).
Now I use EJsonBehavior but it returns only first level relations, not sub related objects.
My source code:
$order = Order::model()->findByPk($_GET['id']);
echo $order->toJSON();
Yii::app()->end();
The eager loading approach retrieves the related AR instances together with the main AR instance(s). This is accomplished by using the with() method together with one of the find or findAll methods in AR. For example,
$posts=Post::model()->with('author')->findAll();
The above code will return an array of Post instances. Unlike the lazy approach, the author property in each Post instance is already populated with the related User instance before we access the property. Instead of executing a join query for each post, the eager loading approach brings back all posts together with their authors in a single join query!
We can specify multiple relationship names in the with() method and the eager loading approach will bring them back all in one shot. For example, the following code will bring back posts together with their authors and categories:
$posts=Post::model()->with('author','categories')->findAll();
We can also do nested eager loading. Instead of a list of relationship names, we pass in a hierarchical representation of relationship names to the with() method, like the following,
$posts=Post::model()->with(
'author.profile',
'author.posts',
'categories')->findAll();
The above example will bring back all posts together with their author and categories. It will also bring back each author's profile and posts.
Eager loading may also be executed by specifying the CDbCriteria::with property, like the following:
$criteria=new CDbCriteria;
$criteria->with=array(
'author.profile',
'author.posts',
'categories',
);
$posts=Post::model()->findAll($criteria);
or
$posts=Post::model()->findAll(array(
'with'=>array(
'author.profile',
'author.posts',
'categories',
)
);
I found the solution for that. you can use $row->attributes to create data
$magazines = Magazines::model()->with('articles')->findAll();
$arr = array();
$i = 0;
foreach($magazines as $mag)
{
$arr[$i] = $mag->attributes;
$arr[$i]['articles']=array();
$j=0;
foreach($mag->articles as $article){
$arr[$i]['articles'][$j]=$article->attributes;
$j++;
}
$i++;
}
print CJSON::encode(array(
'code' => 1001,
'magazines' => $arr,
));
This is the best piece of code I found after a long time search to meet this requirement.
This will work like Charm.
protected function renderJson($o) {
//header('Content-type: application/json');
// if it's an array, call getAttributesDeep for each record
if (is_array($o)) {
$data = array();
foreach ($o as $record) {
array_push($data, $this->getAttributes($record));
}
echo CJSON::encode($data);
} else {
// otherwise just do it on the passed-in object
echo CJSON::encode($this->getAttributes($o));
}
// this just prevents any other Yii code from being output
foreach (Yii::app()->log->routes as $route) {
if ($route instanceof CWebLogRoute) {
$route->enabled = false; // disable any weblogroutes
}
}
Yii::app()->end();
}
protected function getAttributes($o) {
// get the attributes and relations
$data = $o->attributes;
$relations = $o->relations();
foreach (array_keys($relations) as $r) {
// for each relation, if it has the data and it isn't nul/
if ($o->hasRelated($r) && $o->getRelated($r) != null) {
// add this to the attributes structure, recursively calling
// this function to get any of the child's relations
$data[$r] = $this->getAttributes($o->getRelated($r));
}
}
return $data;
}