I have these relationship between school and associate models:
// School model
public function associates()
{
return $this->belongsToMany('Associate', 'school_associate', 'school_id', 'associate_id')
->withPivot('start_date', 'end_date');
}
// Associate model
public function schools()
{
return $this->belongsToMany('School', 'school_associate', 'associate_id', 'school_id')
->withPivot('start_date', 'end_date');
}
I need to get all associates of one school ordered by start_date.
This is what I tried without success (in this try I am searching in all schools):
dd(\App\Associate::with(['schools' => function ($q) {
$q->orderBy('pivot_start_date', 'desc');
}])->toSql());
And I get this sql (notice no order by clause):
select * from `associate`
I tried to edit the relationship like this:
// Associate model
public function schools()
{
return $this->belongsToMany('School', 'school_associate', 'associate_id', 'school_id')
->withPivot('start_date', 'end_date')
->orderBy('pivot_start_date', 'desc'); // also tried without "pivot_"
}
And according to this post, I also tried :
// Associate model
public function schools()
{
return $this->belongsToMany('School', 'school_associate', 'associate_id', 'school_id')
->withPivot('start_date', 'end_date')
->orderBy('school_associate.start_date', 'desc');
}
But I always get the same query and the results are not ordered.
I solved using query builder in this way.
This function is in Associate model:
public function scopeLast($query, $school_ids = [])
{
$query->join('school_associate', "{$this->table}.{$this->primaryKey}", '=', 'school_associate.associate_id')
->join('school', 'school.school_id', '=', 'school_associate.school_id')
->whereIn('school.school_id', $school_ids)
->orderBy('school_associate.start_date', 'desc');
return $query;
}
Related
I have this query and it runs in like 0.5s I need it to be faster is there a way to make this happen
$events_id = Event::where('user_id', Auth::user()->id)
->select("id")
->orderByDesc('id')->pluck('id');
$total_visitors_count = Visitor::select(DB::raw('count(*) as num_visits'))
->join('event_visitor', 'visitors.id', '=', 'event_visitor.visitor_id')
->whereIn('event_visitor.event_id', $events_id)
->count();
Relationships in laravel are a good way to keep our queries simple and fast, you can make relations between your entities to handle this:
User model class:
public function events()
{
return $this->hasMany(Event::class);
}
Event model class:
public function user()
{
return $this->belongsTo(User::class);
}
public function visitors()
{
return $this->belongsToMany(Visitor::class, 'event_visitor');
}
Visitor model class:
public function events()
{
return $this->belongsToMany(Event::class, 'event_visitor');
}
now, your queries become like this:
$events_id = auth()->user()->events()->orderByDesc('id')->pluck('id');
$total_visitors_count = Visitor::with('events')
->whereHas('events', fn ($q) => $q->whereIn('id', $events_id))
->count();
I have a requirement.
My DB has tables like the following.
The tables have OneToMany (1-n) parent-child relation.
Table School (id, school_name)
Table Class (id, school_id, class_name)
Table Section (id, class_id, section_name, no_of_seats)
Table Student (id, section_id, student_name, ....)
When Some Student is registered, data is uploaded to the Student table.
Now, I want to have a statistic like
| school_name | total_seats | student_registered |
and for a particular school
| class_name | total_seats | student_registered |
How to achieve this in Laravel/Eloquent
Thanks in Advance
Probably it works with:
Counting/Summarizing HasMany relations
Counting/Summarizing HasManyThrough relations
Counting/Summarizing HasManyDeep relations
Definition
class Section extends Model
{
public function students(): HasMany
{
return $this->hasMany(Student::class);
}
public function scopeWithRegisteredStudents(Builder $query): Builder
{
// Count HasMany relation
return $query->withCount('students as students_registered');
}
}
// The word "Class" is reserved, so we need to use "SchoolClass" instead
class SchoolClass extends Model
{
protected $table = 'classes';
public function sections(): HasMany
{
return $this->hasMany(Section::class, 'class_id');
}
public function students(): HasManyThrough
{
return $this->hasManyThrough(Student::class, Section::class, 'class_id');
}
public function scopeWithTotalSeats(Builder $query): Builder
{
// Summarize field from HasMany relation
return $query->withSum('sections as total_seats', 'no_of_seat');
}
public function scopeWithRegisteredStudents(Builder $query): Builder
{
// Count HasManyThrough relation
return $query->withCount('students as students_registered');
}
}
class School extends Model
{
public function classes(): HasMany
{
return $this->hasMany(SchoolClass::class);
}
public function sections(): HasMany
{
return $this->hasManyThrough(Section::class, SchoolClass::class, null, 'class_id');
}
public function students(): HasManyThrough
{
// https://github.com/staudenmeir/eloquent-has-many-deep
return $this->hasManyDeep(Student::class, [SchoolClass::class, Section::class], ['school_id', 'class_id', 'section_id'], ['id', 'id', 'id']);
}
public function scopeWithTotalSeats(Builder $query): Builder
{
// Summarize field from HasManyThrough relation
return $query->withSum('sections as total_seats', 'no_of_seat');
}
public function scopeWithRegisteredStudents(Builder $query): Builder
{
// Count HasManyDeep relation
return $query->withCount('students as students_registered');
}
}
Example
// Fetching simply
Section::query()
->withRegisteredStudents()
->get();
SchoolClass::query()
->withTotalSeats()
->withRegisteredStudents()
->get();
School::query()
->withTotalSeats()
->withRegisteredStudents()
->get();
// Fetching with nested relations
School::query()
->withTotalSeats()
->withRegisteredStudents()
->with(['classes' => function (HasMany $query) {
return $query
->withTotalSeats()
->withRegisteredStudents();
}])
->get();
If you use a static analyzer like PHPStan or Psalm, you can alternatively use scopes method to prevent errors.
School::query()
->scopes(['withTotalSeats', 'withRegisteredStudents'])
->get();
This is not what you asked for as it uses Query Builder instead of Eloquent. I have not tested it as I have nothing to test against currently but this should work -
use Illuminate\Support\Facades\DB;
$students_per_section = DB:table('students')
->select('section_id', DB::raw('COUNT(id) AS num_students'))
->groupBy('section_id')
$query = DB:table('schools')
->join('classes', 'schools'.'id', '=', 'classes.school_id')
->join('sections', 'classes.id', '=', 'sections.class_id')
->leftJoinSub($students_per_section, 'students_per_section', function($join) {
$join->on('sections.id', '=', 'students_per_section.section_id')
});
if ($school_id) {
$query
->select('classes.class_name', DB::raw('SUM(no_of_seats) AS total_seats'), DB::raw('SUM(students_per_section.num_students) AS student_registered'))
->where('schools.id', '=', $school_id)
->groupBy('classes.class_name')
} else {
$query
->select('schools.school_name', DB::raw('SUM(no_of_seats) AS total_seats'), DB::raw('SUM(students_per_section.num_students) AS student_registered'))
->groupBy('schools.school_name')
}
$stats = $query->get();
Current laravel models relations: ParentModel can have many documents, ChildModel can have many documents, same Documents can be belonged to any of ParentModel and ChildModel.
Also ChildModel always belongs to one ParentModel. ParentModel can have multiple ChildModels.
App\ParentModel relationships
...
public function childmodels()
{
return $this->hasMany('App\ChildModel');
}
public function documents()
{
return $this->morphToMany('App\Document', 'documentable');
}
...
App\ChildModel relationships
...
public function parentmodel()
{
return $this->belongsTo('App\ParentModel');
}
public function documents()
{
return $this->morphToMany('App\Document', 'documentable');
}
...
App\Document
...
public function parentmodels()
{
return $this->morphedByMany('App\ParentModel','documentable');
}
public function childmodels()
{
return $this->morphedByMany('App\ChildModel','documentable');
}
...
Now I'm trying to get all records of ChildModels (1) which have documents with specific type and (2) its ParentModel can also have documents.
The (1) first goal can be reached with such ChildModel method.
/* checking GET param to join this condition to final query */
if($request->has('report') && $request->input('report') == 'on') {
/* get all documents related to CurrentModel */
$query->whereHas('documents',function (Builder $query) {
$query->where('type', 1);
});
}
But this obviously doesnt include records of ChildModels, ParentModel of which has documents with specific type.
So the question is: how to include such condition into ChildModel query builder?
Found the easy way to access relations in builder
$query->whereHas('parentmodels.documents', function(Builder $query){
$query->where('type',1);
});
I have a customer table which has a field called 'policy_id', where policy_id points to policy table. It is a null-able field, ie. Some customers may not have a policy.
I have a relationship code like this in Customer.php
public function policy() {
return $this->hasOne('App\Models\Policy', "id", "policy_id");
}
But when I issue a search request I am getting error like this:
Illuminate\Database\Eloquent\ModelNotFoundException: No query results for model [App\Models\Policy]
If I modify the function like this:
public function policy() {
if ($this->getAttribute('policy_id')) {
return $this->hasOne('App\Models\Policy', "id", "policy_id");
} else {
return null
}
}
But I am getting an error like this:
Call to a member function getRelationExistenceQuery() on null
Here is my search code:
$c = new Customer();
return Customer::doesntHave('policy')->orWhere(function (Builder $query) use ($req) {
$query->orWhereHas('policy', function (Builder $query) use ($req) {
$p = new Policy();
$query->where($req->only($p->getFillable()))
->orWhereBetween("policy_period_from", [$req->policy_period_start_from, $req->policy_period_start_to])
->orWhereBetween("policy_period_to", [$req->policy_period_end_from, $req->policy_period_end_to])
->orWhereBetween("payment_date", [$req->payment_date_from, $req->payment_date_to]);
});
})->where($req->only($c->getFillable()))->get();
Am I missing something or are there any other ways to do this?
PS: While debugging the above search code is returning successfully, but the exception happening from somewhere inside Laravel after the prepareResponse call.
Thanks in advance.
return $this->hasOne('App\ModelName', 'foreign_key', 'local_key');
Change the order, put the foreign_key policy_id in front of id
In your Customer Model, you need to use belongsTo method:
public function policy() {
return $this->belongsTo('App\Models\Policy', "policy_id", "id");
}
And In your Policy Model, use hasOne:
public function customer() {
return $this->hasOne('App\Models\Customer', "policy_id", "id");
}
First of all, you placed the wrong params.
$this->belongsTo('App\Models\Policy', "FK", "PK");
public function policy() {
return $this->belongsTo('App\Models\Policy','policy_id', 'id');
}
And for null value of policy_id you can use withDefault();
public function policy() {
return $this->belongsTo('App\Models\Policy','policy_id', 'id')->withDefault([
'name' => 'test'
]);;
}
there's a number of problems there but can you perhaps specify the namespace and the class of both your models - Customer and Policy.
By default, the models you create with php artisan make:model will use the \App namespace e.g. \App\Customer and \App\Policy.
Just double check that.
Also, with regards to the relationship, if the Laravel conventions have been followed you could just:
In the Customer model
public function policy() {
return $this->belongsTo(Policy::class);
}
In the Policy model
public function customer() {
return $this->hasOne(Customer::class);
}
of if a multiple customers can be under one policy
public function customers() {
return $this->hasMany(Customer::class);
}
Good luck
I want to get users filtered by category, so I send category_id as a parameter and should select users who haven't records in users_categories_restrictions table with this category_id.
How can I make this eloquent query ??
You could use whereDoesntHave
$users = App\User::whereDoesntHave('categories', function ($query) use($cat_id) {
$query->where('categories.id', '=', $cat_id);
})->get();
I assume you have defined many to many relation between user and category model
class User extends Model
{
public function categories()
{
return $this->belongsToMany(Category::class, 'users_categories_restrictions', 'user_id');
}
}
class Category extends Model
{
public function users()
{
return $this->belongsToMany(User::class, 'users_categories_restrictions', 'category_id');
}
}