I'm trying to combine two regexes. One will ensure that input contains 14 digits: ^\\d{14}$ and I need another regex to check if all the input is not of the same digit.
Please suggest how I proceed with this. I want my regex to check for that the input is 14 digits and those digits are not all same numbers [0-9].
Is there a way I add the test for finding not all digits are the same with my regex that checks for if the input is exactly 14 digits? I would need one regex expression which combines them both. Thank you!
You can use negative lookahead with a back reference to the first digit:
(?!(\d)\1{13})\d{14}$
NB: This is pure regex syntax. I did not escape backslashes for use in a programming language.
There is no regex operation for "match here for all-of-these except a back-reference". You have a two-step test here, not a single one.
Related
python pattern => ^(?=.\bABDUL\b)(?=.\bHAI\b.)(?=.\bMANSOOR\b).*$
need equalent mysql pattern
can you please help me out ?
The regex in question is a quite strange way how to match simple words. It is not clear what is the expected input. Maybe, the input justifies this approach.
^(?=.\bABDUL\b)(?=.\bHAI\b.)(?=.\bMANSOOR\b).*$
Which means: At the beginning there must be any character which is not a part of a word, then ABDUL, a non word character, HAI, a non word character, MANSOOR, a non word character or the end of the string.
^[^[:alnum:]]ABDUL[^[:alnum:]]HAI[^[:alnum:]]MANSOOR([^[:alnum:]]?.*)?$
Which is: At the beginning, not a number or alphabet character (alphanumerical), ABDUL, one non-alphanumerical, HAI, one non-alphanumerical, MANSOOR one non-alphanumerical or the end of the string.
I did not test it and did not intended to make it 100% the same as the first one, but it should be close enough.
For anyone who would like to copy it to their code:
Matching the first character is not very common and can be a bug in the original regexp.
(?=...) is an "lookahead assertion" which does not consume any characters, the POSIX version does not have it, but for a simple string searching it may not be important.
Both versions should match strings like !ABDUL$HAI)MANSOOR - make sure that this is what you want.
For someone who would like to understand the regular expressions I used
https://dev.mysql.com/doc/refman/8.0/en/regexp.html for mysql (POSIX syntax) and https://docs.python.org/3/library/re.html for python (PCRE = Perl compatible syntax)
I'm trying to make a number input field using the pattern attribute since the regular type number didn't support the validations I needed.
Essentially, I want to allow any numbers that make sense, including $, + or - at the start and a % at the end. Also, users should be able to separate their numbers with commas to avoid mistakes on long numbers, but this is not necessary and they should still be able to submit a long number without any type of separation. The field should also allow for decimals.
<input required pattern="[+-]?\$?\d+(,\d{3})*(\.\d+)?%?" type="text" />
I need to allow for the following examples:
Pass:
2000
-20%
2,000
$2,000.00
999,999,999,999,999,999,999.99
Fail:
123e9
Anything that has letters on it
This is the regex that I have so far, but it doesn't seem to work, even for the most basic numbers. I've been using scriptular to test my regex, but that doesn't seem to reflect the results of the actual HTML validation.
Regex: [+-]?\$?\d+(,\d{3})*(\.\d+)?%?
EDIT: For any Ruby on Rails devs, I realized one of my mistakes is that you must escape any backslashes in your regex when you are generating your text_field. So for example, the regex in the answer should look like (?:\\+|\\-|\\$)?\\d{1,}(?:\\,?\\d{3})*(?:\\.\\d+)?%?
Try with following regex.
Regex: (?:\+|\-|\$)?\d{1,}(?:\,?\d{3})*(?:\.\d+)?%?
Explanation:
(?:\+|\-|\$)? matches either + - or $ in-front of a number which is optional as ? quantifier is used.
\d{1,} matches integer part even if it doesn't have ,.
(?:\,?\d{3})* matches multiple occurrences of comma separated digits if present.
(?:\.\d+)? matches optional decimal part.
%? matches optional % character in the end.
?: stands for non-capturing groups. It will match but won't store it for back-referencing.
Regex101 Demo
I am using the following RegEx in MySQL to match two consecutive digits that are the same anywhere in a string:
^.*([[:digit:]])\1+.*$
It matches correctly the following strings:
8831
5011
9931
but it also matches
9318
and it doesn't match
3449
Is the problem around .* or is it something else?
There's no way to check to the same thing twice directly, instead you would need to check for all possibilities. Luckily since you are only looking at 10 digits, it's relatively easy:
(11|22|33|44|55|66|77|88|99|00)
I don't think MySQL regular expressions have back references. You can do the more verbose:
where col regexp '00|11|22|33|44|55|66|77|88|99'
I'm trying to use a regex to detect URLs in all the rows of my table, here's the regex
\b(([\w-]+:\/\/?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|\/)))
However, I invariably get the "repetition-operator operand invalid" error, which, after hours of search on the internet, still remains obscure.
Where have I gone wrong? What can I do to fix this? And alternaltively, is there a better way to detect URLs in messages in SQL other than a Regex?
Thank you.
You cannot use ? quantifier in MySQL regex as the syntax is POSIX-based. Still, you can use * to match 0 or more characters. Also, \b in MySQL regex should be replaced with [[:<:]] (since this matches at the beginning of a word).
Thus, I suggest using
[[:<:]](([a-zA-Z0-9-]+:\/\/*|www[.])[^ ()<>]+(\([a-zA-Z0-9_]+\)|([^ [:punct:]]|\/)))
I am expanding \w to [a-zA-Z0-9_] as it is exactly what \w is. Instead of \s, I am using a literal space. Instead of \d, I am using [0-9]. This is done for readability and better compatibility. If \w, \d and \s work for you, you can use them, but I do not see them among the supported entities in POSIX specs.
Also, instead of literal space, you could use [:space:], it matches space, tab, newline, and carriage return. Instead of [a-zA-Z] you can use [:alpha:], and instead of [0-9], you can use [:digit:]. Please also check this:
[[:<:]](([[:alpha:][:digit:]-]+:\/\/*|www[.])[^[:space:]()<>]+(\([[:alpha:][:digit:]_]+\)|([^[:space:][:punct:]]|\/)))
I have writen an sql statement to retrieve data from Mysql db and I wanted to select data where myId start with three alpha and 4 digits example : ABC1234K1D2
myId REGEXP '^[A-Z]{3}/d{4}'
but it gives me empty result(data is available in DB). Could someone point me to correct way.
In most regex variants the answer would be: /d matches a / followed by a d; I think you want \d which matches a digit.
However MySQL has a somewhat limited regex implementation (see documentation).
There is no shortcut to character sets like \d for any digit.
You need to either use a named character set ([[:digit:]]), or just use [0-9].
Try this out :
[A-Z]{3}[0-9]{4}
If you want characters to be case insensitive. Try this :
[a-zA-Z]{3}[0-9]{4}
First, in regular regular expressions, to match a digit, you have to use \d instead of /d (which makes you match / followed by d).
Then, I had never noticed, but I think \d (and the others like \w, etc.) don't seem to be available in MySQL. The doc lists the accepted spacial chars, and those generic classes don't appear. You could use [:digit:] instead, even if [0-9] is quite shorter ;)
You are doing fine, just replace /d with \d.Final regex: ^[A-Z]{3}\d{4}
You could use the following pattern :
^[a-zA-Z]{3}\d{4}