I am trying to display information from various fields on a per client basis. In some instances a client will have no entries in a column, sometimes they will have one or more. I don't want to end up with any duplicate rows.
I've tried various combinations of parent and child groupings but can't get it to look the way I want.
SELECT DISTINCT
E.EntCode AS [Member],
A.Reference AS [Fixed Assets],
C.Reference AS [Cash],
L.Reference AS [Loans]
FROM
dbo.CR_Entity AS E
LEFT OUTER JOIN dbo.CR_FixedAssets AS A ON E.EntCode = A.EntCode
LEFT OUTER JOIN dbo.CR_Cash AS C ON E.EntCode = C.EntCode
LEFT OUTER JOIN dbo.CR_Loans AS L ON E.EntCode = L.EntCode
WHERE E.Status = '0'
Related
IMPLEMENTATION: A buyer purchase a product and after it paid the product it will transfer to the seller balance.
PROBLEM: total.seller has id of 1,1,2 but it only manage to update 1,2 only and disregard the other 1 id. Any solution for this? to update same id
UPDATE tbclientdetails cd2
JOIN(
SELECT cd.client_id, cd.money_balance AS buyerbalance, lp.sellerid AS seller, lp.product_price AS price
FROM tbclientlogin cl
LEFT JOIN tbclientdetails cd ON cd.client_id = cl.client_login_id
LEFT JOIN tbclientrole cr ON cr.client_role_id = cd.role
LEFT JOIN tbpurchasedetails pd ON pd.client_purchase_id =cd.client_id
LEFT JOIN tbpaymentstatus ps ON ps.status_id = pd.payment_status
LEFT JOIN tblazardoproduct lp ON lp.product_id = pd.client_product_purchase_id
WHERE ps.status_option = "UNPAID" AND cd.client_email = "justin#gmail.com" AND cr.client_role_type = "BUYER"
) total
SET cd2.money_balance = total.price
WHERE cd2.client_id = total.seller
You don't want to join the single purchase rows, because then one table rows get several updates and the last one wins. You want one update per client with the SUM of the related unpaid purchases.
UPDATE tbclientdetails cd2
JOIN(
SELECT lp.sellerid AS seller, SUM(lp.product_price) AS price
FROM tbclientlogin cl
LEFT JOIN tbclientdetails cd ON cd.client_id = cl.client_login_id
LEFT JOIN tbclientrole cr ON cr.client_role_id = cd.role
LEFT JOIN tbpurchasedetails pd ON pd.client_purchase_id =cd.client_id
LEFT JOIN tbpaymentstatus ps ON ps.status_id = pd.payment_status
LEFT JOIN tblazardoproduct lp ON lp.product_id = pd.client_product_purchase_id
WHERE ps.status_option = 'UNPAID'
AND cd.client_email = 'justin#gmail.com'
AND cr.client_role_type = 'BUYER'
GROUP BY lp.sellerid
) total
SET cd2.money_balance = total.price
WHERE cd2.client_id = total.seller;
I am not sure about the rest. The client is the seller? And the balance is the sum of unpaid product prices? This may or may not be correct. I just copied it from your query. Also, I am not sure whether all the IDs are correctly stated. I just took what you showed us. Maybe you want to try the subquery as a standalone query first to see whether it gets yu what you expect.
At last: Your outer joins don't work. If there is a cl without a cd, then the outer joined row has nulls for all cd columns. WHERE cd.client_email = 'justin#gmail.com' dismisses hence all outer joined rows and you remain with a mere inner join. You should correct this by either moving the criteria to the ON clause to get the outer join working or by making the inner join explicit with INNER JOIN instead of LEFT [OUTER] JOIN.
By the way: string literals get quoted with single quotes in SQL. Double quotes are for names. Confusing the two can sometimes lead to unexpected results.
I'm populating a table which is fetching the ids from 2 other tables to display their information, for example, delivery has a Hamburguer and the box, but the user might register the delivery with out the box, only with the hamburguer.
When I make a INNER JOIN SELECT to get the data from the DB it will return 0 results since there is no box and I'm trying to compare the ids that don't exist. It doesn't populate the table then.
SELECT
entrega_telemovel.*,
telemovel.id_telemovel,
telemovel.nroserie,
nro_telemovel.numero_telemovel,
nro_telemovel.id_nrotelemovel,
funcionarios.id_funcionario,
funcionarios.nome
FROM entrega_telemovel
INNER JOIN telemovel
ON entrega_telemovel.telemovel = telemovel.id_telemovel
INNER JOIN nro_telemovel
ON nro_telemovel.id_nrotelemovel = entrega_telemovel.numero_telemovel
INNER JOIN funcionarios
ON funcionarios.id_funcionario = entrega_telemovel.funcionario_entrega
ORDER BY funcionarios.nome;
In this query above entrega_telemovel.telemovel=telemovel.id_telemovel the value in entrega_telemovel.telemovel is null like the example I gave above. So 0 results are returned from the query.
How can I solve this ?
You are looking for a LEFT JOIN.
INNER JOIN only combines rows, that exist in both tables. A LEFT JOIN on the other hand always produces at least one row. If on table does not have a match for it, all columns are set to NULL.
SELECT
entrega_telemovel.*,
telemovel.id_telemovel,
telemovel.nroserie,
nro_telemovel.numero_telemovel,
nro_telemovel.id_nrotelemovel,
funcionarios.id_funcionario,
funcionarios.nome
FROM entrega_telemovel
LEFT JOIN telemovel
ON entrega_telemovel.telemovel = telemovel.id_telemovel
LEFT JOIN nro_telemovel
ON nro_telemovel.id_nrotelemovel = entrega_telemovel.numero_telemovel
LEFT JOIN funcionarios
ON funcionarios.id_funcionario = entrega_telemovel.funcionario_entrega
ORDER BY funcionarios.nome;
You want to show all entrega_telemovel entries, no matter whether they have a match in entrega_telemovel or not. This is what an outer join does.
SELECT ...
FROM entrega_telemovel et
LEFT OUTER JOIN telemovel t ON et.telemovel = t.id_telemovel
...
I have 7 tables to work with inside a query:
tb_post, tb_spots, users, td_sports, tb_spot_types, tb_users_sports, tb_post_media
This is the query I am using:
SELECT po.id_post AS id_post,
po.description_post as description_post,
sp.id_spot as id_spot,
po.date_post as date_post,
u.id AS userid,
u.user_type As tipousuario,
u.username AS username,
spo.id_sport AS sportid,
spo.sport_icon as sporticon,
st.logo_spot_type as spottypelogo,
sp.city_spot AS city_spot,
sp.country_spot AS country_spot,
sp.latitud_spot as latitudspot,
sp.longitud_spot as longitudspot,
sp.short_name AS spotshortname,
sp.verified_spot AS spotverificado,
u.profile_image AS profile_image,
sp.verified_spot_by as spotverificadopor,
uv.id AS spotverificador,
uv.user_type AS spotverificadornivel,
pm.media_type AS mediatype,
pm.media_file AS mediafile,
GROUP_CONCAT(tus.user_sport_sport) sportsdelusuario,
GROUP_CONCAT(logosp.sport_icon) sportsdelusuariologos,
GROUP_CONCAT(pm.media_file) mediapost,
GROUP_CONCAT(pm.media_type) mediaposttype
FROM tb_posts po
LEFT JOIN tb_spots sp ON po.spot_post = sp.id_spot
LEFT JOIN users u ON po.uploaded_by_post = u.id
LEFT JOIN tb_sports spo ON sp.sport_spot = spo.id_sport
LEFT JOIN tb_spot_types st ON sp.type_spot = st.id_spot_type
LEFT JOIN users uv ON sp.verified_spot_by = uv.id
LEFT JOIN tb_users_sports tus ON tus.user_sport_user = u.id
LEFT JOIN tb_sports logosp ON logosp.id_sport = tus.user_sport_sport
LEFT JOIN tb_post_media pm ON pm.media_post = po.id_post
WHERE po.status = 1
GROUP BY po.id_post,uv.id
I am having problems with some of the GROUP_CONCAT groups:
GROUP_CONCAT(tus.user_sport_sport) sportsdelusuario is giving me the right items but repeated, all items twice
GROUP_CONCAT(logosp.sport_icon) sportsdelusuariologos is giving me the right items but repeated, all items twice
GROUP_CONCAT(pm.media_file) mediapost is giving me the right items but repeated four times
GROUP_CONCAT(pm.media_type) mediaposttype s giving me the right items but repeated four times
I can put here all tables structures if you need them.
Multiple one-to-many relations JOINed in a query have a multiplicative affect on aggregation results; the standard solution is subqueries:
You can change
GROUP_CONCAT(pm.media_type) mediaposttype
...
LEFT JOIN tb_post_media pm ON pm.media_post = po.id_post
to
pm.mediaposttype
...
LEFT JOIN (
SELECT media_post, GROUP_CONCAT(media_type) AS mediaposttype
FROM tb_post_media
GROUP BY media_post
) AS pm ON pm.media_post = po.id_post
If tb_post_media is very big, and the po.status = 1 condition in the outer query would significantly reduce the results of the subquery, it can be worth replicating the original join within the subquery to filter down it's results.
Similarly, the correlated version I mentioned in the comments can also be more performant if the outer query has relatively few results. (Calculating the GROUP_CONCAT() for each individually can cost less than calculating it for all once if you would only actually using very few of the results of the latter).
or just add DISTINCT to all the group_concat, e.g., GROUP_CONCAT(DISTINCT pm.media_type)
Hi dev's i'm new with "advanced" SQL I've try alone but I dont understand how to have the good result.
I'll try to take information from 4 tables in the same DB.
The first table items only have id and name.
2 others tables take the id from items to extract data.
The last tables takes one data from items_buy for print another data.
Lastly I concat 2 column from 2 DB for having a full information.
SELECT items.id, items.name, items_buy.item_cost AS item_cost, items_sales.item_price AS item_price, CONCAT(trader.name, planet.name) AS name_point
FROM ((((items
INNER JOIN items_buy ON items_buy.id = items.id)
INNER JOIN trader ON trader.id = items_buy.name_point)
INNER JOIN items_sales ON items_sales.id = items.id)
INNER JOIN planet ON planet.id = trader.planet)
WHERE items.id = 1;
I dont know how to make it work, she doesnt return an error in SQLyog or on my server.
In order:
ID / NAMEITEM / PRICE / SELLINGPRICE / NAME from concat
If you need more, some test data:
https://pastebin.com/6Bs4kbN9
I've run your test data and run your script against it. As I suggested in my commment, the problem is with the INNER JOIN you are using.
I am not sure whether you are aware, but when using an INNER JOIN, if the joined table is NULL for the current row, then nothing at all will be returned.
If you modify your query to use a LEFT JOIN, you will see the results that are available regardless of whether the joined tables are NULL or otherwise:
SELECT items.id, items.name, items_buy.item_cost AS item_cost, items_sales.item_price AS item_price, CONCAT(trader.name, planet.name) AS name_point
FROM ((((items
LEFT JOIN items_buy ON items_buy.id = items.id)
LEFT JOIN trader ON trader.id = items_buy.name_point)
LEFT JOIN items_sales ON items_sales.id = items.id)
LEFT JOIN planet ON planet.id = trader.planet)
WHERE items.id = 1;
This produces:
1 Agricium 24.45 25.6 NULL
1 Agricium 24.6 25.6 NULL
The problem in the case of your example is that the join to trader or planet has no result and therefore produces no output.
SELECT a.acikkapali,
b.onay, b.evrakno,
b.tarih,
a.kod,
d.ad,
a.note0,
a.sf_miktar,
a.sf_sf_unit,
a.rtalepedilentestarih,
c.evrakno
FROM stok47T a
LEFT JOIN stok47e b on a.evrakno = b.evrakno
LEFT JOIN stok46t1 c on a.evrakno = c.talepno
LEFT JOIN stok00 d on a.kod = d.kod
WHERE a.tarih = '2013/04/15'
I need to add two my tables into that script with right way that means If I mapped one of them then the normal row count increases this makes me crazy, I have been trying to solve that issue for a couple days but I had been fail many times.
I couldn't find a good mapped fields between stok47t and the others. But there are still a few columns(fields) matches for their types and data.
I need to listen ppl opinions and learns something.
Here is a big part of my query
If you are getting increase in row count then chances are it could be due to using LEFT JOIN. An INNER join might help (see http://www.codinghorror.com/blog/2007/10/a-visual-explanation-of-sql-joins.html guidance)
SELECT a.acikkapali,
b.onay, b.evrakno,
b.tarih,
a.kod,
d.ad,
a.note0,
a.sf_miktar,
a.sf_sf_unit,
a.rtalepedilentestarih,
c.evrakno
FROM stok47T a
INNER JOIN stok47e b on a.evrakno = b.evrakno
INNER JOIN stok46t1 c on a.evrakno = c.talepno
INNER JOIN stok00 d on a.kod = d.kod
WHERE a.tarih = '2013/04/15'
However without understanding your data structure then there is a chance you might lose the information that you are after.
If you are getting multiple rows, it is probably due to a Cartesian product occurring in the joins. This is unrelated to the type of join (left/right/full/inner). It is based on the relationships between the tables. You have 1-N relationships along different dimensions.
Your conditions are:
FROM stok47T a
LEFT JOIN stok47e b on a.evrakno = b.evrakno
LEFT JOIN stok46t1 c on a.evrakno = c.talepno
LEFT JOIN stok00 d on a.kod = d.kod
I have no idea what these tables and fields mean. But, if you have a case where there is one row per evrakno in table stok47t, and there are two rows in table stok47e and three in table stok46t1, then you will get six rows in the output.
Without more information, it is impossible to tell you the best solution. One method is to summarize the tables. Another is to take the first or last corresponding row, by doing something like:
from stok47T a left join
(select s.*, row_number() over (partition by evrakno order by id desc) as seqnum
from stok47e s
) b
on a.evrakno = b.evrakno and b.seqnum = 1