MySQL - Daily overview only shows current bookings rather than all - mysql

Question

I'm trying to get a view where I can select a specific day and it will return a list of ALL rooms with the current days breakdown.
Currently it shows the daily overview for a specific day but lacks showing rooms which DONT have bookings for the day selected?
(I need to display the daily overview for all rooms even without bookings)
How do I change this so it will show ALL rooms even when there is not a booking for the specific room on that day as well as rooms that do?
Current display (for 2019-11-24):
SELECT * FROM `Daily Overview` WHERE '2019-11-24' >= StartDate AND '2019-11-24' <= EndDate;
3 Family 2 2019-11-24 2019-11-28 4 2 2,3 Ahri,Blitz
4 Dual 1 2019-11-22 2019-11-25 2 1 1 Aatrox
Desired output:
1
2
3 Family 2 2019-11-24 2019-11-28 4 2 2,3 Ahri,Blitz
4 Dual 1 2019-11-22 2019-11-25 2 1 1 Aatrox
5
6
8
9
10
View script:
CREATE VIEW `Daily Overview` AS
SELECT ROOMINFO.ID as Room, ROOMINFO.`Type`,
BOOKROOM.Ref as Ref,
BOOK.Start_Date as StartDate,
BOOK.End_Date as EndDate
FROM ROOMINFO
JOIN BOOKROOM ON ROOMINFO.ID = BOOKROOM.ID
JOIN BOOK ON ROOMINFO.ID AND BOOK.Ref = BOOKROOM.Ref
GROUP BY ROOMINFO.ID, ROOMINFO.`Type`, ROOMINFO.Max, Ref;
table data & structure script:
CREATE SCHEMA CATTERY2;
USE CATTERY2;
CREATE TABLE BOOK( Ref INT NOT NULL AUTO_INCREMENT, Start_Date DATE NOT NULL, End_Date DATE NOT NULL, PRIMARY KEY(Ref));
CREATE TABLE ROOMINFO( ID INT NOT NULL AUTO_INCREMENT,`Type` VARCHAR(10) NOT NULL, Max TINYINT NOT NULL, PRIMARY KEY(ID));
CREATE TABLE BOOKROOM( Ref INT NOT NULL, ID INT NOT NULL, FOREIGN KEY (Ref) REFERENCES BOOK(Ref), FOREIGN KEY (ID) REFERENCES ROOMINFO(ID));
INSERT INTO BOOK(Start_Date, End_Date) VALUES
("2019-11-22", "2019-11-25"), ("2019-11-24", "2019-11-28");
INSERT INTO ROOMINFO (ID, `Type`,Max) VALUES
(1, "Family", 4), (2, "Family", 4), (3, "Family", 4), (4, "Dual", 2),
(5, "Dual", 2), (6, "Dual", 2), (7, "Dual", 2), (8, "Dual", 2),
(9, "Dual", 2), (10, "Dual", 2);
INSERT INTO BOOKROOM( Ref, ID ) VALUES
(1, 4), (2, 3);

Answer 1

Consider the following. Note that I've modified your structure slightly to aid comprehension:
DROP SCHEMA IF EXISTS cattery2;
CREATE SCHEMA CATTERY2;
USE CATTERY2;
CREATE TABLE cats
(cat_id SERIAL PRIMARY KEY
,name VARCHAR(30)
,sex CHAR(1) NOT NULL
);
CREATE TABLE bookings
(booking_id SERIAL PRIMARY KEY
,start_Date DATE NOT NULL
,end_date DATE NOT NULL
);
CREATE TABLE rooms
(room_id SERIAL PRIMARY KEY
,capacity TINYINT NOT NULL
);
CREATE TABLE room_booking
(room_id INT NOT NULL
,booking_id INT NOT NULL
,PRIMARY KEY(room_id,booking_id)
);
CREATE TABLE cat_booking
(cat_id INT NOT NULL
,booking_id INT NOT NULL
,PRIMARY KEY(cat_id,booking_id)
);
INSERT INTO bookings(start_date, end_date) VALUES
("2019-11-22", "2019-11-25"),
("2019-11-24", "2019-11-28"),
("2019-12-01", "2019-12-02"),
("2019-12-01", "2019-12-06"),
("2019-12-02", "2019-12-03"),
("2019-12-04", "2019-12-10"),
("2019-12-04", "2019-12-10"),
("2019-12-05", "2019-12-13"),
("2019-12-16", "2019-12-19"),
("2019-12-26", "2019-12-28"),
("2019-12-26", "2020-01-01"),
("2019-12-28", "2020-01-02"),
("2019-12-31", "2020-01-05"),
("2020-01-03", "2020-01-08"),
("2020-01-05", "2020-01-11"),
("2020-01-06", "2020-01-09"),
("2020-01-06", "2020-01-11"),
("2020-01-08", "2020-01-18"),
("2020-01-11", "2020-01-15"),
("2020-01-15", "2020-01-17"),
("2020-01-15", "2020-01-18");
INSERT INTO rooms (room_id,capacity) VALUES
( 1,4),
( 2,4),
( 3,4),
( 4,2),
( 5,2),
( 6,2),
( 7,2),
( 8,2),
( 9,2),
(10,2);
INSERT INTO room_booking (booking_id,room_id) VALUES
( 1, 4),
( 2, 3),
( 3, 4),
( 4, 5),
( 5, 6),
( 6, 7),
( 7, 3),
( 8, 2),
( 9, 1),
(10, 8),
(11, 3),
(12, 9),
(13, 2),
(14, 10),
(15, 4),
(16, 5),
(17, 6),
(18, 7),
(19, 2),
(20, 1),
(21, 10);
INSERT INTO cats (name,sex) VALUES
('Aatrox', 'm'),
('Ahri', 'f'),
('Blitz', 'm'),
('Curley', 'm'),
('Mandy', 'm'),
('Nami', 'f'),
('Kog', 'm'),
('Caitlyn', 'f'),
('Barney', 'm'),
('Gnar', 'm'),
('Charley', 'f'),
('Bundy', 'm'),
('Ringo', 'm'),
('Smiley', 'm'),
('Bentley', 'f'),
('Barney', 'm'),
('Yuumi', 'f'),
('Rammus', 'm'),
('Viktor', 'm'),
('Xerath', 'm'),
('Azir', 'm'),
('Reginald', 'm'),
('Harry', 'm'),
('Indie', 'f'),
('Dotty', 'f'),
('Wesley', 'm'),
('Karma', 'f'),
('Nami', 'f'),
('Nautalus', 'm'),
('Tristy', 'f'),
('Kaisa', 'f'),
('Baron', 'm'),
('Braum', 'm'),
('Alistar', 'm'),
('Ahri', 'f');
INSERT INTO cat_booking(booking_id,cat_id) VALUES
( 1, 1),
( 2, 2),
( 2, 3),
( 3, 1),
( 4, 2),
( 5, 3),
( 5, 4),
( 6, 5),
( 7, 6),
( 7, 7),
( 7, 8),
( 8, 9),
( 8, 10),
( 8, 11),
( 9, 12),
( 9, 13),
( 9, 14),
(10, 15),
(11, 16),
(11, 17),
(11, 18),
(12, 19),
(12, 20),
(13, 21),
(13, 22),
(13, 23),
(14, 24),
(14, 25),
(15, 26),
(16, 27),
(16, 28),
(17, 29),
(18, 30),
(19, 31),
(19, 32),
(20, 33),
(20, 34),
(21, 35);
And the query...
SELECT DISTINCT r.room_id
, r.capacity
, x.booking_id
, x.start_date
, x.end_date
FROM rooms r
LEFT
JOIN
( SELECT b.booking_id
, b.start_date
, b.end_date
, rb.room_id
FROM bookings b
JOIN room_booking rb
ON rb.booking_id = b.booking_id
WHERE '2019-11-24' BETWEEN b.start_date AND b.end_date
) x
ON x.room_id = r.room_id
ORDER
BY r.room_id
, r.capacity
, x.start_date
, x.booking_id;
+---------+----------+------------+------------+------------+
| room_id | capacity | booking_id | start_date | end_date |
+---------+----------+------------+------------+------------+
| 1 | 4 | NULL | NULL | NULL |
| 2 | 4 | NULL | NULL | NULL |
| 3 | 4 | 2 | 2019-11-24 | 2019-11-28 |
| 4 | 2 | 1 | 2019-11-22 | 2019-11-25 |
| 5 | 2 | NULL | NULL | NULL |
| 6 | 2 | NULL | NULL | NULL |
| 7 | 2 | NULL | NULL | NULL |
| 8 | 2 | NULL | NULL | NULL |
| 9 | 2 | NULL | NULL | NULL |
| 10 | 2 | NULL | NULL | NULL |
+---------+----------+------------+------------+------------+
Also, note that there's no VIEW here. This is deliberate. Queries against VIEWS in MySQL have limited access to underlying indexes, making them (in my VIEW) almost useless.