I want two tables calculate - mysql

Question

I want to add and calculate using data from 2 tables.
The results I want are as follows.
However, if I send a query as follows:
SELECT COUNT(IF(treatment_fees_check_division = 'test',
treatment_fees_check_division, NULL)) AS COUNT, SUM(CASE WHEN
treatment_fees_check_division = 'test' THEN treatment_fees_difference
END) + SUM(advenced_amount) AS if_treatment_fees_check_division,
SUM(advenced_amount) AS sum_init_amount FROM ( SELECT
treatment_fees_check_division, treatment_fees_difference,
advenced_amount FROM hospital_payment_data, advenced_payment WHERE
hospital_payment_data.id = advenced_payment.chart_num ) AS a
These results occur.
create table of hospital_payment_data and data
CREATE TABLE `hospital_payment_data` (
`id` INT(11) NOT NULL AUTO_INCREMENT,
`date` TIMESTAMP NOT NULL DEFAULT current_timestamp(),
`chart_num` INT(11) NOT NULL ,
`chart_name` VARCHAR(50) NOT NULL,
`visit` DATE NOT NULL,
`non_payment_sales` VARCHAR(50) NOT NULL,
`total_medical_bills` VARCHAR(50) NOT NULL,
`total_amount` VARCHAR(50) NOT NULL,
`amount_asked` VARCHAR(50) NOT NULL,
`medical_bills_payment` VARCHAR(50) NOT NULL,
`personal_liability_amount` VARCHAR(50) NOT NULL,
`non_payment` VARCHAR(50) NOT NULL,
`insurance_division` VARCHAR(50) NOT NULL,
`division` VARCHAR(50) NOT NULL,
`cash_amount_received` VARCHAR(50) NOT NULL,
`cash_receipt` VARCHAR(50) NOT NULL,
`cash_receipt_non_payment` VARCHAR(50) NOT NULL,
`cash_receipt_payment` VARCHAR(50) NOT NULL,
`card_amount_received` VARCHAR(50) NOT NULL,
`card_non_payment` VARCHAR(50) NOT NULL,
`card_payment` VARCHAR(50) NOT NULL,
`medical_bills_check` VARCHAR(50) NOT NULL,
`medical_bills_check_modify` VARCHAR(50) NOT NULL DEFAULT 'N',
`treatment_fees_difference` VARCHAR(50) NOT NULL,
`init_amount` VARCHAR(50) NOT NULL DEFAULT '0',
`treatment_fees_check_division` VARCHAR(50) NOT NULL DEFAULT '-',
`treatment_fees_check` VARCHAR(50) NOT NULL,
`treatment_fees_check_modify` VARCHAR(50) NOT NULL DEFAULT 'N',
`treatment_fees_check_memo` VARCHAR(50) NOT NULL,
PRIMARY KEY (`id`)
)
COLLATE='euckr_korean_ci'
ENGINE=InnoDB
AUTO_INCREMENT=18
;
create table of advenced_payment and data
CREATE TABLE `advenced_payment` (`id` INT(11) NOT NULL AUTO_INCREMENT,
`date` TIMESTAMP NULL DEFAULT NULL,
`chart_num` VARCHAR(50) NULL DEFAULT NULL,
`chart_name` VARCHAR(50) NULL DEFAULT NULL,
`advenced_amount` VARCHAR(50) NULL DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE INDEX `chart_num` (`chart_num`)) COLLATE='euckr_korean_ci' ENGINE=InnoDB AUTO_INCREMENT=2 ;
How do fix my query??

Answer 1

You have numerous issues with you query. This won't fix your problems, but I recommend writing it as:
SELECT SUM(hpd.treatment_fees_check_division = 'test') AS COUNT,
(SUM(CASE WHEN hpd.treatment_fees_check_division = 'test' THEN hpd.treatment_fees_difference END) +
SUM(advenced_amount)
) AS if_treatment_fees_check_division,
SUM(advenced_amount) AS sum_init_amount
FROM hospital_payment_data hpd JOIN
advanced_payment ap
ON hpd.id = ap.chart_num;
This simplifies and fixes some issues:
The JOIN uses proper, explicit, standard, readable syntax. Never use commas in the FROM clause.
The subquery is utterly unnecessary and probably adversely affects performance.
All tables have table aliases.
All column references are qualified.
The condition count is much simplified using sum(<boolean>).
I note that treatment_fees_difference is a string, yet you are using SUM(). That is really, really bad.
In any case, your problem, is that one of the tables has multiple rows. It is hard to know which one but my guess is advanced_payment. The solution is to preaggregate before the JOIN:
SELECT SUM(hpd.treatment_fees_check_division = 'test') AS COUNT,
(SUM(CASE WHEN hpd.treatment_fees_check_division = 'test' THEN hpd.treatment_fees_difference END) +
SUM(ap.sum_init_amount)
) AS if_treatment_fees_check_division,
SUM(ap.sum_init_amount) AS sum_init_amount
FROM hospital_payment_data hpd JOIN
(SELECT ap.chart_num, COUNT(*) as cnt, SUM(advenced_amount) as sum_init_amount
FROM advanced_payment ap
GROUP BY ap.chart_num
) ap
ON hpd.id = ap.chart_num;