I would like to convert the following xml to JSON:
<?xml version='1.0' encoding='utf-8'?>
<map xmlns="http://www.w3.org/2005/xpath-functions">
<array key="ids">
<number>3218087</number>
</array>
</map>
using
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="3.0">
<xsl:output method="text" />
<xsl:template match="/">
<xsl:value-of select="xml-to-json(.)" />
</xsl:template>
</xsl:stylesheet>
This gives me:
{"ids":[3.218087E6]}
What I need is
{"ids":[3218087]}
Any help would be highly appreciated.
Cheers
Przemek
The spec https://www.w3.org/TR/xpath-functions/#func-xml-to-json for a number element suggests:
An element $E named number results in the output of the string result
of xs:string(xs:double(fn:string($E)))
and the cast to xs:string requires the E notation for values greater than 1000000 I think (https://www.w3.org/TR/xpath-functions/#casting-to-string).
So I don't think the xml-to-json result can be changed, unless a processor allows some options to choose a different formatting rule for numbers.
Related
I'm trying to transform an XML document to be in single-line and wrap it in a one-element JSON. Using XSLT 1.0
The problem is, XSL generates double quotes in the xmlns definitions so the resulting JSON is invalid.
This is my input:
<?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
<otm:Transmission xmlns:otm='http://xmlns.oracle.com/apps/otm/transmission/v6.4' xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance'>
<otm:TransmissionHeader/>
<otm:TransmissionBody>
<otm:GLogXMLElement>
<otm:Invoice>
<otm:Payment>
<otm:PaymentHeader>
<otm:DomainName>CompanyX</otm:DomainName>
<otm:TransactionCode>EX</otm:TransactionCode>
<otm:InvoiceDate>
<otm:GLogDate>20220414000000</otm:GLogDate>
</otm:InvoiceDate>
</otm:PaymentHeader>
</otm:Payment>
</otm:Invoice>
</otm:GLogXMLElement>
</otm:TransmissionBody>
</otm:Transmission>
This is what I'm getting:
{"jsonElement":"<otm:Transmission xmlns:otm="http://xmlns.oracle.com/apps/otm/transmission/v6.4" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><otm:TransmissionHeader/><otm:TransmissionBody><otm:GLogXMLElement><otm:Invoice><otm:Payment><otm:PaymentHeader><otm:DomainName>CompanyX</otm:DomainName><otm:TransactionCode>EX</otm:TransactionCode><otm:InvoiceDate><otm:GLogDate>20220414000000</otm:GLogDate></otm:InvoiceDate></otm:PaymentHeader></otm:Payment></otm:Invoice></otm:GLogXMLElement></otm:TransmissionBody></otm:Transmission>"}
The XSL that I use:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:otm='http://xmlns.oracle.com/apps/otm/transmission/v6.4'>
<xsl:output method="text" indent="no" suppress-indentation="otm:Transmission"/>
<xsl:strip-space elements="*" />
<xsl:template match="/">
{"jsonElement":"<xsl:apply-templates select="*"/>"}
</xsl:template>
<xsl:template match="#* | *">
<xsl:copy>
<xsl:apply-templates select="#* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
As you can see, the JSON is invalid due to double quotes in the xmlns definitons.
I tried several approaches and I am not able to get rid of the double quotes. In the input, they are single quotes but XSL is generating them differently.
What would be the best approach to have a valid JSON result?
The XML in the JSON has to be 1:1 copy of the input but transformed into a single line and I can only use XSLT 1.0
An XSLT 1.0 processor is going to reject the suppress-indentation attribute, and it's going to output the text of the source document without markup. Like #MartinHonnen, I don't see how any XSLT processor can give you the output you claim to be getting.
In XSLT 3.0 you can do
<xsl:output method="json">
<xsl:template match="/">
<xsl:map key="'jsonElement'"
select="serialize(., map{'method':'xml'})"/>
</xsl:template>
I have a variable containing non-numerical values, and I need to completely remove duplicate entries from this string using XSLT:
$string = a,b,c,c,d,d,e,f,g
needs to become: $newstring = a,b,e,f,g
An alternative option would be to compare the two variables and ignore/remove the overlapping entries.
$stringA = a,c
$stringB = a,b,c,d,e,f
needs to become:
$newstring = b,d,e,f
Concatenating the variables is straightforward but I need the opposite of that!
Please help,
XSLT is designed to process XML, not strings. XSLT 1.0 in particular is a poor tool for manipulating text.
IMHO, the best way to proceed here is to convert the problem to XML first. If you're using libxslt (as xsltproc does), this is quite easy to do using an extension function:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:str="http://exslt.org/strings"
extension-element-prefixes="str">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:param name="stringA">a,c,g</xsl:param>
<xsl:param name="stringB">a,b,c,d,e,f</xsl:param>
<xsl:variable name="setA" select="str:tokenize($stringA, ',')" />
<xsl:variable name="setB" select="str:tokenize($stringB, ',')" />
<xsl:template match="/">
<test>
<xsl:for-each select="$setA[not(.=$setB)] | $setB[not(.=$setA)]">
<xsl:value-of select="."/>
<xsl:if test="position()!=last()">,</xsl:if>
</xsl:for-each>
</test>
</xsl:template>
</xsl:stylesheet>
Result:
<?xml version="1.0" encoding="UTF-8"?>
<test>g,b,d,e,f</test>
In the html output file from an XSLT process (using saxon9he), there have been 155 occurrences of xmlns:fn="http://www.w3.org/2005/xpath-functions" inserted into a variety of tr elements
The part of xsl that uses xpath-functions is
<xsl:if test="(string(#hideIfHardwareIs)='') or (not(fn:matches(string($input_doc//inf[#id='5'), string(#hideIfHardwareIs), 'i')))">
unless I am reading it wrong, matches takes 3 arguments, a string, another string and then a flag in which case this is case-insensitive.
What I don't undestand is that the tr elements that are showing up with the xmlns arent close to the portion or xsl that the matches() function is done at.
The XSL file I am working with is 2100 lines and the XML file it parses is 12800 lines. So I don't think I can share it easily. I've inherited this and need to (at this time) maintain it.
What are somethings i can look for within the XSL that would insert the xmlns into the html output?
Those functions do not need to be prefixed.
Remove the xmlns:fn="http://www.w3.org/2005/xpath-functions" from your xsl:stylesheet and remove the fn: prefix from the xpath functions.
Examples:
XML Input
<foo>test</foo>
XSLT 2.0 #1
<xsl:stylesheet version="2.0" xmlns:fn="http://www.w3.org/2005/xpath-functions"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<xsl:if test="fn:matches(.,'^t')">
<bar><xsl:value-of select="."/></bar>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Output
<bar xmlns:fn="http://www.w3.org/2005/xpath-functions">test</bar>
XSLT 2.0 #2
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/*">
<xsl:if test="matches(.,'^t')">
<bar><xsl:value-of select="."/></bar>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Output
<bar>test</bar>
How to modify the below xsl to process parameters whose value is tags. Instead of using w:p and w:pPr/w:pStyle/#w:val i will be passing them as args
Actual XSl:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml"
>
<xsl:param name="styleName"/>
<xsl:output method="text"/>
<xsl:template match="w:p"/>
<xsl:template match="w:p[w:pPr/w:pStyle/#w:val[matches(., concat('^(',$styleName,')$'),'i')]]">
<xsl:value-of select="."/><xsl:text>
</xsl:text>
</xsl:template>
</xsl:stylesheet>
Required XSL:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ve="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml">
<xsl:param name="styleName" select="'articletitle'"/>
<xsl:param name="para" select="'//w:p[w:pPr/w:pStyle/#w:val[matches(.,concat('^(',$styleName,')$')]]'"/>
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:for-each select="$para">
<xsl:value-of select="."/><xsl:text>
</xsl:text>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
NOTE: You should get used to give information about which version of xslt and which processor you are using. In this case, the answer is valid only if you are using XSLT 2.0
This is not a complete answer, but you can start by looking at this approach:
Try using local-name and in-scope-prefixes (only available in XSLT 2.0) to match a node dynamically.
Here you have an example template to replace your empty template:
<xsl:template match="*[local-name()=substring-after($para,':') and in-scope-prefixes(.)[.=substring-before($para,':')]]"/>
For the second part of the expression ($parastyle), I can only think about writing your own function to evaluate it dynamically.
I'll try to post an example of such a function later on.
I fugured out the problem in my coding, is in second line,
<xsl:param name="para" select="'//w:p[w:pPr/w:pStyle/#w:val[matches(.,concat('^(',$styleName,')$')]]'"/>
Since i have given the quotes in select attribute the value has been considered as string instead of xpath expression.
I am trying to do a simple transform of XML using XSLT to generate HTML, but I'm having difficulties and I can't seem to figure out what the problem is. Here is a sample of the XML I am working with:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="C:\Users\cgubata\Documents\Digital Measures\jcamp_fac_ex_xslt.xsl"?>
<Data xmlns="http://www.digitalmeasures.com/schema/data" xmlns:dmd="http://www.digitalmeasures.com/schema/data-metadata" dmd:date="2012-02-27">
<Record userId="310106" username="jcamp" termId="453" dmd:surveyId="1154523">
<dmd:IndexEntry indexKey="COLLEGE" entryKey="School of Business" text="School of Business"/>
<dmd:IndexEntry indexKey="DEPARTMENT" entryKey="Accountancy" text="Accountancy"/>
<dmd:IndexEntry indexKey="DEPARTMENT" entryKey="MBA" text="MBA"/>
<PCI id="11454808064" dmd:lastModified="2012-02-08T13:17:39">
<PREFIX>Dr.</PREFIX>
<FNAME>Julia</FNAME>
<PFNAME/>
<MNAME>M.</MNAME>
<LNAME>Camp</LNAME>
<SUFFIX/>
<ALT_NAME>Julia M. Brennan</ALT_NAME>
<ENDPOS/>
All I want to do is have the value for some of the nodes to be displayed in HTML. So for example, I might want the PREFIC, FNAME, LNAME nodes to display as "Dr. Julia Camp" (no quotes - I'll do styling later). Here's the XSL that I am using:
<?xml version="1.0" encoding="utf-8"?><!-- DWXMLSource="jcamp_fac_ex.xml" -->
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:dmd="http://www.digitalmeasures.com/schema/data-metadata">
<xsl:output method="html" encoding="utf-8"/>
<xsl:template match="/">
<xsl:value-of select="/Data/Record/PCI/PREFIX"/>
</xsl:template>
</xsl:stylesheet>
From what I been researching, that should show the value of that PREFIX field. But instead, it is outputting all of the values from all of the nodes (so if there are 4000 nodes with a text value, I am getting 4000 values returned in HTML). My goal will be to pull out the values from certain nodes, and I will probably arrange them in a table.
How do I pull out the values from a specific node? Thanks in advance.
Well, I can't reproduce your symptoms. When I test what you've posted it doesn't produce any output at all. Which looks correct because your xpath is testing the wrong namespace. You need to add in your xslt a namespace-prefix mapping for the http://www.digitalmeasures.com/schema/data namespace, and then use it in the value-of xpath. Like this:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:dmd="http://www.digitalmeasures.com/schema/data-metadata"
xmlns:dm="http://www.digitalmeasures.com/schema/data">
<xsl:output method="html" encoding="utf-8"/>
<xsl:template match="/">
<xsl:value-of select="/dm:Data/dm:Record/dm:PCI/dm:PREFIX"/>
</xsl:template>
</xsl:stylesheet>
I'm afraid you've fallen into the number one XSLT trap for beginners: we see this question at least once a day on this forum. Your elements are in a namespace and your stylesheet is trying to match nodes in no namespace.