Operand Should Contain 1 Column(s), Trying to generate volunteer data - mysql

I can't seem to troubleshoot my problem.
My stored procedure:
CREATE DEFINER=`myschoolusername`#`%` PROCEDURE `generate_volunteers`(in nfolks int)
BEGIN
set #i=0;
while #i < nfolks do
insert into Volunteer(firstname, lastname, dateofbirth)
values (((floor(1+(rand()*(4-1))), "Fred", "Wang", "Fatimah", "Marcella")),
((floor(1+(rand()*(3-1))), "Kaser", "Fang", "Kumar")),
DATE_ADD('1965-01-01', INTERVAL rand()*200000 DAY));
set #i = #i+1;
end while;
END
Additionally, here is my volunteer table in my MYSQL script:
drop table if exists Volunteer;
create Table Volunteer(
member_num int not null auto_increment primary key,
firstname varchar(20) not null,
lastname varchar(20) not null,
dateofbirth date not null
);
I am trying to insert 500 lines into this table, however error 1305 is coming up.
Any help is heavily appreciated, I am quite unsure of where to go from this point.

This logic doesn't do anything:
(floor(1+(rand()*(4-1))), "Fred", "Wang", "Fatimah", "Marcella"))
Although not the most efficient, this should be fine for 500 rows:
insert into Volunteer(firstname, lastname, dateofbirth)
select f.firstname, l.lastname,
DATE_ADD('1965-01-01', INTERVAL rand()*200000 DAY)
from (select 'Fred' as firstname union all
select 'Wang' union all
select 'Fatimah' union all
select 'Marcella'
) f cross join
(select 'Kaser' as lastname union all
select 'Fang' union all
select 'Kumar'
) l
order by rand()
limit 1;
I think you are actually trying to write:
insert into Volunteer(firstname, lastname, dateofbirth)
select elt(floor(rand() * 4) + 1,
'Fred', 'Wang', 'Fatimah', 'Marcella'
) as firstname,
elt(floor(rand() * 3) + 1,
'Kaser', 'Fang', 'Kumar'
) as lastname,
DATE_ADD('1965-01-01', INTERVAL rand()*200000 DAY);

Related

Return Value from sql commands

I am currently using the SQL command
Select * from where name='john'
Is it possible to return 20 no matter the query, for example
Select * from where name='john' or return = 20
EDIT
If you have an oracle database you can do something like that:
SELECT *
FROM dual
WHERE 1=0
UNION
SELECT '20'
FROM dual;
check my answer
if exists (Select * from item where ItemName='ABC Daycare1')
begin
Select * from item where ItemName='ABC Daycare1'
end
else
select '20'
Try running this. This should return the top result (which is never 20 due to the custom sort) and then when the name doesn't match a value it returns 'Mark' and 20
SQL
IF OBJECT_ID('tempdb..#temp') IS NOT NULL DROP TABLE #temp
CREATE TABLE #temp (id int NOT NULL, name varchar(255) NOT NULL)
INSERT INTO #temp (id, name) VALUES (88,'John')
INSERT INTO #temp (id, name) VALUES (20,'Mark')
SELECT TOP 1
*
FROM #temp
WHERE (name = 'Mark' OR name = 'John')
ORDER BY (
CASE
WHEN id = 20 THEN 0 ELSE 1
END) DESC
MySQL - MySQL fiddle
IF OBJECT_ID('tempdb..#temp') IS NOT NULL DROP TABLE #temp
CREATE TABLE #temp (id int NOT NULL, name varchar(255) NOT NULL)
INSERT INTO #temp (id, name) VALUES (88,'John')
INSERT INTO #temp (id, name) VALUES (20,'Mark')
SELECT
*
FROM temp
WHERE (name = 'Mark' OR name = 'John')
ORDER BY (
CASE
WHEN id = 20 THEN 0 ELSE 1
END) DESC
LIMIT 1

Find an average age range over a span of ages

I need to find the most occurrences in a 10yr age range that can be Age 2 to 22, 15 to 25, 10 to 20, etc. in a table with name & age
I've created the SQL that returns the average age:
SELECT age, count(age)
FROM member
GROUP BY age
ORDER BY COUNT(age) DESC
LIMIT 1
Thanks for your help!
Create another table ages to hold the age ranges you are interested in with a field for age_lower, age_upper and a display name age_range such as '2 to 22'
Join the tables with a WHERE clause that puts the age between the lower and upper ranges.
SELECT `age_range`, COUNT(`age`) AS age_count
FROM `member` INNER JOIN `ages`
ON age BETWEEN age_lower AND age_upper
GROUP BY age_range
ORDER BY COUNT(`age`) DESC, `age_range` ASC
SQL Fiddle
This might solve the problem. The only thing I added was a table to hold values 1..x where x is your bucket count. The #T can easily be replaced with your MySQL table name. The results are all possible sets the age falls in, for each age. Then count of how many equal sets.
--IGNORE BUILDING TEST DATA IN SQL SERVER
DECLARE #T TABLE(member INT,age INT)
DECLARE #X INT
SET #X=1
WHILE(#X<=100) BEGIN
INSERT INTO #T SELECT #X, CAST(RAND() * 100 AS INT)
SET #X=#X+1
END
DECLARE #MinAge INT=1
DECLARE #MaxAge INT=100
--YOUR SET TABLE. TO MAKE LIFE EASY YOU NEED A TABLE OF 1..X
DECLARE #SET TABLE (Value INT)
DECLARE #SET_COUNT INT =10
DECLARE #LOOP INT=1
WHILE(#LOOP<=#SET_COUNT) BEGIN
INSERT #SET SELECT #LOOP
SET #LOOP=#LOOP+1
END
SELECT
MinAge,
MaxAge,
SetCount=COUNT(CountFlag)
FROM
(
SELECT
MinAge=AgeMinusSetCount,
MaxAge=AgePlusSetCount,
CountFlag=1
FROM
(
SELECT DISTINCT
ThisAge,
AgeMinusSetCount=(AgeMinusSetCount-1) + Value,
AgePlusSetCount=CASE WHEN (AgeMinusSetCount-1) + Value + #SET_COUNT > #MaxAge THEN #MaxAge ELSE (AgeMinusSetCount-1) + Value + #SET_COUNT END
FROM
(
SELECT
ThisAge=age,
AgeMinusSetCount=CASE WHEN (age - #SET_COUNT) < #MinAge THEN #MinAge ELSE (age) - #SET_COUNT END
FROM
#T
)RANGES
LEFT OUTER JOIN (SELECT Value FROM #SET) AS FanLeft ON 1=1
)AS DETAIL
)AS Summary
GROUP BY
MinAge,
MaxAge
ORDER BY
COUNT(CountFlag) DESC

Create trigger to increase value when found duplicate

I need to make trigger to increase the 2nd digit when the new value found to be a duplicate.
For Instance, I have a unique filed with 10 digits value. I want when someone insert same number it increase the second left digit like 0100012345. How I can do that? Thank you.
FirstName LastName Code
Houssam Salim 0100012345 to be 0200012345
Try this
I have found a solution with instead off trigger
'/*
CREATE TABLE [Employee1]
(
[id] VARCHAR(20) PRIMARY KEY,
[name] VARCHAR(50)
)
CREATE TRIGGER AutoIncrement_Trigger
ON [Employee1]
instead OF INSERT
AS
BEGIN
DECLARE #ch CHAR
DECLARE #num INT
IF EXISTS (SELECT 1
FROM Employee1 e
JOIN inserted i
ON i.id = e.id)
BEGIN
SET #num=(SELECT max(CONVERT(INT, substring(e.id, 1, 2))) + 1
FROM employee1 e
JOIN inserted i
ON substring(e.id, 3, len(e.id)) = substring(i.id, 3, len(i.id)))
INSERT INTO [Employee1]
(id,
name)
SELECT '0' + CONVERT(VARCHAR(10), #num)
+ substring(i.id, 3, len(i.id)),
e.name
FROM Employee1 e
JOIN inserted i
ON i.id = e.id
END
ELSE
BEGIN
INSERT INTO [Employee1]
(id,
name)
SELECT inserted.id,
inserted.name
FROM inserted
END
END
*/
INSERT INTO [Employee1]
VALUES ('0100012345',
'John')
SELECT *
FROM [Employee1]
INSERT INTO [Employee1]
VALUES ('0100012345',
'John')
SELECT *
FROM [Employee1]
'

Insert query based on number of rows

I want a query to insert a row into a table I know it is simple but the scenario is the table should not have more than 5 rows. If table has more than five rows I need to remove the old row(Or replace with new row ) (Based on the insert time stamp) then i need to insert a new row.If number of rows less than count 5 then i can directly insert a row.
Please share me the query.
How about something like this.
declare #count int
SELECT #count=COUNT(*)
from EP_ANSWERS
IF (#count<5)
// DO your insert here
ELSE
DELETE FROM TABLE
WHERE inserttimestamp = (SELECT x.inserttimestamp
FROM (SELECT MAX(t.inserttimestamp) AS inserttimestamp
FROM TABLE t) x)
// DO your insert here
If it is impossible for the table to have more than 5 rows:
DELETE FROM yourtable
WHERE 5 <= (SELECT COUNT(*) FROM yourtable)
AND yourtimestamp = (SELECT MIN(yourtimestamp) FROM yourtable)
;
INSERT INTO yourtable ...
;
If it is possible for the table to have more than 5 rows:
DELETE FROM yourtable
WHERE 5 <= (SELECT COUNT(*) FROM yourtable)
AND yourtimestamp NOT IN (SELECT yourtimestamp
FROM yourtable
ORDER BY yourtimestamp DESC
LIMIT 4)
;
INSERT INTO yourtable ...
;
It sounds like you want to put a trigger on the table to maintain this rule, in MySQL the something like this should work
CREATE TRIGGER trg__my_table__limit_rows
BEFORE INSERT
ON my_table
FOR EACH ROW
BEGIN
IF ((SELECT COUNT(1) FROM my_table) = 5)
BEGIN
DELETE FROM my_table
WHERE id = (SELECT MIN(id) FROM my_table) -- change this to fit your logic for which record should be removed
END
END
Some of the code here is in pseudo (you didn't wrote your schema), but i wrote where you need to complete your own code.
DECLARE #NumberOfRowsToInsert INT = -- select from the data you want to insert
DECLARE #MaxNumberOfRows INT = 5
DECLARE #NumberOfExistingRows INT
DECLARE #Query VARCHAR(MAX) = 'SELECT TOP #rows id FROM SomeTable ORDER BY createdDate ASC'
SELECT #NumberOfExistingRows = COUNT(*)
FROM SomeTable
SET #Query = REPLACE(#Query,'#rows',
CAST(#NumberOfRowsToInsert - (#MaxNumberOfRows - #NumberOfExistingRows))) AS VARCHAR(1))
CREATE TABLE #IdsToDelete(id INT PRIMARY KEY)
INSERT INTO #IdsToDelete
EXEC(#Query)
DELETE FROM SomeTable
WHERE id IN (SELECT * FROM #IdsToDelete)
-- insert here..

Sql query to fetch the next token number

I have a column TokenId list in my SQL table "Tokendata".
The TokenId has values say 1,2,3,4,6,7,8,10,11
Here the above tokenIds are occupied. When I query this table, it should give me the next free tokenId, in this case it should be 5.
If TokenId has values say "1,2,3,4,5,6,7,8,10,11,13,20", the query should return me 9.
Can anyone help me with a SQL query for this?
Note: updated to account for cases where 1 is missing, as per the comment.
SELECT
t.TokenId + 1
FROM (
SELECT TokenId
FROM Tokendata
UNION ALL
SELECT 0
) t
LEFT JOIN Tokendata t2 ON t.TokenId = t2.TokenId - 1
WHERE t2.TokenId IS NULL
ORDER BY t.TokenId
LIMIT 1
Here is the answer to my question. But it may not be the optimistic solution. Optimized solutions are welcome
DECLARE #TempTable TABLE
(
TableID int PRIMARY KEY IDENTITY,
TokenId int
)
Insert Into #TempTable
Select tt.TokenId from XLBDataPoint tt where tt.TokenId= 1
DECLARE #RowCount INT
SET #RowCount = (SELECT COUNT(*) FROM #TempTable )
(SELECT
Top 1 t.TokenId + #RowCount
FROM TokenData t
Where t.TokenId+ #RowCount NOT in
(select t2.TokenId FROM TokenData t2)