How to convert MySQL query to equivalent Oracle sql Query - mysql

I want to convert below MY SQL query to Oracle SQL query, could someone please help ?
Below instructor table is parent entity, and instructor_detail table child entity.
CREATE TABLE `instructor_detail` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`youtube_channel` varchar(128) DEFAULT NULL,
`hobby` varchar(45) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;
CREATE TABLE `instructor` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`first_name` varchar(45) DEFAULT NULL,
`last_name` varchar(45) DEFAULT NULL,
`email` varchar(45) DEFAULT NULL,
`instructor_detail_id` int(11) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `FK_DETAIL_idx` (`instructor_detail_id`),
CONSTRAINT `FK_DETAIL` FOREIGN KEY (`instructor_detail_id`) REFERENCES `instructor_detail` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;
I have tried below but not working
CREATE TABLE instructor (
id numeric(11) NOT NULL PRIMARY KEY,
first_name varchar(45) DEFAULT NULL,
last_name varchar(45) DEFAULT NULL,
email varchar(45) DEFAULT NULL,
instructor_detail_id numeric(10) not null
);
CREATE TABLE instructor_detail (
id NUMERIC(11) NOT NULL PRIMARY KEY,
youtube_channel varchar(128) DEFAULT NULL,
hobby varchar(45) DEFAULT NULL,
CONSTRAINT fk_instructor
FOREIGN KEY (instructor_detail_id)
REFERENCES instructor(instructor_detail_id)
);
error : Error report -
ORA-00904: "INSTRUCTOR_DETAIL_ID": invalid identifier
00904. 00000 - "%s: invalid identifier"
*Cause:
*Action:
Appreciated

Oracle 11 doesn't support auto-generated primary keys, so you need a trigger for that. And there are some different rules on cascading constraints.
But otherwise:
CREATE TABLE instructor_detail (
id int PRIMARY KEY,
youtube_channel varchar2(128) DEFAULT NULL,
hobby varchar2(45) DEFAULT NULL
) ;
CREATE TABLE instructor (
id int NOT NULL PRIMARY KEY,
first_name varchar2(45) DEFAULT NULL,
last_name varchar2(45) DEFAULT NULL,
email varchar2(45) DEFAULT NULL,
instructor_detail_id int,
CONSTRAINT FK_DETAIL FOREIGN KEY (instructor_detail_id) REFERENCES instructor_detail (id)
) ;
CREATE INDEX idx_instructor_instruct_detail_id ON instructor(instructor_detail_id);
Here is a db<>fiddle.

Related

Trouble getting my primary and foreign key to work

I keep getting errors when I try to run the relational part of the database to pull the 3 columns in the relation table from the customer table and bill table.
DROP DATABASE IF EXISTS CreateDB2;
CREATE DATABASE CreateDB2;
USE CreateDB2;
CREATE TABLE `tbl_employee` (
`tbl_EmployeeName` varchar(20) NOT NULL,
`tbl_Department` varchar(15) NOT NULL,
`employee_id` int(11) NOT NULL AUTO_INCREMENT,
`department_location` varchar(20) NOT NULL,
`department_name` varchar(15) NOT NULL,
`supervisor` varchar(15) NOT NULL,
PRIMARY KEY (`employee_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
CREATE TABLE `customer` (
`c_ID` varchar(15) NOT NULL,
`c_address` varchar(50) NOT NULL,
`c_Time` time NOT NULL,
`c_order` int(100) NOT NULL,
PRIMARY KEY (`c_ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
CREATE TABLE `bill` (
`b_items` double DEFAULT NULL,
`b_price` double DEFAULT NULL,
`b_discount` double DEFAULT NULL,
`b_deliveryFee` double DEFAULT NULL,
`b_tax` double DEFAULT NULL,
`b_tip` double DEFAULT NULL,
`b_total` double NOT NULL,
`quantity` int(11) NOT NULL,
PRIMARY KEY (`b_total`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
CREATE TABLE `food` (
`code` int(11) NOT NULL AUTO_INCREMENT,
`f_catagory` varchar(20) NOT NULL,
`f_item` varchar(10) NOT NULL,
`f_info` varchar(50) NOT NULL,
`f_price` int(11) NOT NULL,
PRIMARY KEY (`code`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
CREATE TABLE `restaurantinfo` (
`name` varchar(20) NOT NULL,
`address` varchar(50) DEFAULT NULL,
`phone` int(13) DEFAULT NULL,
`email` varchar(20) DEFAULT NULL,
PRIMARY KEY (`name`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
CREATE TABLE `relationaltable` (
`c_ID` varchar(15) NOT NULL,
`c_order` int(100) NOT NULL,
`b_total` double NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
ALTER TABLE `customer` ADD CONSTRAINT `c_ID` FOREIGN KEY (`c_ID`) REFERENCES `relationaltable`(`c_ID`) ON DELETE RESTRICT ON UPDATE RESTRICT;
ALTER TABLE `order` ADD CONSTRAINT `c_order` FOREIGN KEY (`c_order`) REFERENCES `relationaltable`(`c_order`) ON DELETE RESTRICT ON UPDATE RESTRICT;
ALTER TABLE `bill` ADD CONSTRAINT `b_total` FOREIGN KEY (`b_total`) REFERENCES `relationaltable`(`b_total`) ON DELETE RESTRICT ON UPDATE RESTRICT;
On the last part here, it is not working. It gives error code 1005
The alter table at the bottom is the probably the issue. I am just not sure how to fix it. Any help is appreciated. Thanks.
The foreign key is incorrectly formed.
You connect customer.c_ID should be equal to relationaltable.c_order
customer.c_ID is varchar(15) NOT NULL
relationaltable.c_order is int(100) NOT NULL
The data type and also the length has to be matching

Add a foregin key to a different table

I'm trying to add username from my st_accounts column into my table results using mySQL.
st_accounts table
`id` int(11) NOT NULL, //Primary Key
`firstname` varchar(50) NOT NULL,
`lastname` varchar(50) NOT NULL,
`username` varchar(50) NOT NULL,
`password` varchar(255) NOT NULL,
`email` varchar(100) NOT NULL,
`img` text NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
results table
`score_ID` int(11) NOT NULL, //Primary key
`score` int(20) NOT NULL,
`date` date NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
I think you want:
create table accounts (
account_id int auto_increment primary key,
. . .
);
create table results (
result_id int auto_increment primary key,
account_id int not null
score int NOT NULL,
score_date date NOT NULL,
constraint fk_results_accounts foreig key (accounts_id) references accounts(account_id)
) ;
Notes:
Declare the primary key explicitly, not in a comment.
My convention is to name the primary key after the name of the table (in singular) with _id after it.
The foreign key has the same name as the primary key -- self documenting.
I made the integer primary keys auto_increment, so the database can assign unique values.

mysql add foreign key constraint error

I have two tables which I'd like to connect with foreign key constraint
For some reason, when I try to do it, it fails and and says: #1215 - Cannot add foreign key constraint
Here is my first table:
CREATE TABLE `zmaneyhayom` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`zman_id` varchar(255) NOT NULL,
`tempHour` tinyint(1) NOT NULL,
`tempHourType` varchar(255) NOT NULL,
`tempHourNum` double NOT NULL,
`tempMinutes` tinyint(1) NOT NULL,
`tempMinutesType` varchar(255) NOT NULL,
`tempMinutesNum` double NOT NULL,
`regularMinutes` tinyint(1) NOT NULL,
`regularMinutesNum` double NOT NULL,
`equivalentMinutes` tinyint(1) NOT NULL,
`equivalentMinutesNum` double NOT NULL,
`degreesBelowHorizon` tinyint(1) NOT NULL,
`degreesBelowHorizonNum` double NOT NULL,
`beforeAfter` varchar(6) NOT NULL,
`riseSet` varchar(4) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `zman_id_2` (`zman_id`),
KEY `zman_id` (`zman_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
And this table holds ID and name, which eventually the ID in this table is the name for the previous table (zman_id column):
CREATE TABLE `zmaneyhayomlabels` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `id` (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
This is the code I'm attempting in order to create the constraint:
ALTER TABLE `zmaneyhayom` ADD FOREIGN KEY ( `zman_id` ) REFERENCES `luah_v2`.`zmaneyhayomlabels` (
`id`
) ON DELETE NO ACTION ON UPDATE NO ACTION ;
I have no idea why it's failing :/
What I want is that whenever I go on phpmyadmin and go to the first table, instead of typing some id in zman_id I will have a select box which I can select a name (which is stored in the second table) but the value it will store will be the ID.
they are not same type id is INT and zman_id is varchar.
you can change this
`zman_id` varchar(255) NOT NULL,
to
`zman_id` int(11) NOT NULL,

cannot add second FK : got error can't create table'.jobstatus\#sql-32c_12f2f.frm' (errno:150)

CREATE TABLE `job` (
`jobId` int(11) NOT NULL auto_increment,
`jobcode` varchar(25) default NULL,
`jobname` varchar(255) default NULL,
`location` varchar(255) default NULL,
`budget` int(10) unsigned default NULL,
`year_type` varchar(100) default NULL,
`worklineId` int(11) default NULL,
PRIMARY KEY (`jobId`),
KEY `NewIndex` (`worklineId`),
FOREIGN KEY (`worklineId`) REFERENCES `workline` (`worklineId`)
) TYPE=InnoDB;
CREATE TABLE `subjob` (
`subjobId` int(11) NOT NULL auto_increment,
`subjobcode` varchar(25) default NULL,
`subjobname` varchar(255) default NULL,
`subjobbudget` int(11) unsigned default NULL,
`jobgoal_date` date default '0000-00-00',
`jobId` int(11) default NULL,
PRIMARY KEY (`subjobId`),
KEY `NewIndex` (`jobId`),
FOREIGN KEY (`jobId`) REFERENCES `job` (`jobId`)
) TYPE=InnoDB;
CREATE TABLE `contract` (
`contractId` int(11) NOT NULL auto_increment,
`contractcode` varchar(25) default NULL,
`price` int(11) unsigned default NULL,
`contractprice` int(11) unsigned default NULL,
`company` varchar(50) default NULL,
`signdate` date default '0000-00-00',
`begindate` date default '0000-00-00',
`enddateplan` date default '0000-00-00',
`note` text,
PRIMARY KEY (`contractId`)
) TYPE=InnoDB;
CREATE TABLE `subjob_contract` (
`subjobcontractId` int(11) NOT NULL auto_increment,
`status` varchar(11) default NULL,
`contractId` int(11) default NULL,
`subjobId` int(11) default NULL,
PRIMARY KEY (`subjobcontractId`),
KEY `NewIndex` (`contractId`),
KEY `NewIndex2` (`subjobId`),
FOREIGN KEY (`contractId`) REFERENCES `contract` (`contractId`)
) TYPE=InnoDB
I m using mysql front 3.2 to manage database,I can add first fk but when i add second fk i got an error following this :
sql execution error #1005. response from the database: can't create table'.jobstatus#sql-32c_12f2f.frm' (errno:150). i already define the new index for fk subjobId reference to subjob table what could be the possibility of this error? thank you
Check the datatype and size of the subjobId column on primary table and referenced table. both must be same than it will allow you to create foreign key.
Answer is: You can not refer that column/table which is not created yet. Try to execute tables having foreign keys after the referenced tables.
Obviously you should have consistency in datatypes of foreign key and referenced column as well
Correct Execution Demo. Also You should use Engine=InnoDB instead of Type=InnoDB

mysql stored procedure not accepting Foreign key Constraint

I had created a table using StoredProcedure in mysql and i had applied primary key constraint also when i tried to apply foreign key constraint..iam getting error 'Cant create table dbname.tablename'..and here is my Simple StoredProcedure
delimiter |
CREATE PROCEDURE SP_CREATE_TABLE_SAMP()
BEGIN
CREATE TABLE anan_user (
user_id bigint(15) NOT NULL AUTO_INCREMENT,
name varchar(70) DEFAULT NULL,
last_name varchar(70) DEFAULT NULL,
gender varchar(10) DEFAULT NULL,
username varchar(40) DEFAULT NULL,
password varchar(40) DEFAULT NULL,
dateofbirth date DEFAULT NULL,
email varchar(100) DEFAULT NULL,
phone varchar(25) DEFAULT NULL,
mobile varchar(25) DEFAULT NULL,
address varchar(250) DEFAULT NULL,
pincode varchar(15) DEFAULT NULL,
state_id bigint(15) DEFAULT NULL,
district_id bigint(15) DEFAULT NULL,
constituency_id bigint(15) DEFAULT NULL,
profile_Img varchar(100) DEFAULT NULL,
is_pwd_changed varchar(10) DEFAULT 'false',
registered_time timestamp NULL DEFAULT NULL,
updated_date timestamp NULL DEFAULT NULL,
PRIMARY KEY ( user_id )
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
END;
how to give foreign key constraints in stored procedures?
Check your syntax against the MySQL reference on foreign key constraints. It would also be helpful for you to post what you tried, and how you're trying to set the foreign key constraint.
An example constraint definition is:
CREATE TABLE parent (id INT NOT NULL,
PRIMARY KEY (id)
) ENGINE=INNODB;
CREATE TABLE child (id INT, parent_id INT,
INDEX par_ind (parent_id),
FOREIGN KEY (parent_id) REFERENCES parent(id)
ON DELETE CASCADE
) ENGINE=INNODB;
The relevant syntax is the FOREIGN KEY (parent_id) REFERENCES parent(id).