Connect to OKEX private api using cURL? - json

I am trying to check my Perpetual Swap contracts on Okex Exchange, from the terminal.
I am using openssl to make the HMAC SHA256 signature.
But so far I am only getting a "code":405," error, and the docs are not very insightful:
https://www.okex.com/docs/en/#summary-yan-zheng
I wonder if someone who has more experience with the Okex Rest Api could help with this script?
#!/bin/bash
API_KEY=xxxxxx
API_SECRET=yyyyy
PASSPHRASE=zzzzzzzz
TIMESTAMP=$(date --utc +%FT%T.%3NZ)
TYPE='POST'
ENDPOINT='/api/swap/v3/BTC-USD-SWAP/position'
MESSAGE=$(printf "%s+%s+%s" "$TIMESTAMP" "$TYPE" "$ENDPOINT")
SIGNED_MESSAGE=$(echo -n "$MESSAGE" | openssl dgst -sha256 -hmac $API_SECRET -binary | base64 | tr -d "\n")
curl 'https://www.okex.com' \
--header "Content-Type: application/json" \
--request POST \
--data "\{\"OK-ACCESS-SIGN\":$SIGNED_MESSAGE, \"OK-ACCESS-KEY\":$API_KEY, \"OK-ACCESS-TIMESTAMP\":$TIMESTAMP, \"OK-ACCESS-PASSPHRASE\":$PASSPHRASE\}"

It's get not post for this call.
GET/api/swap/v3/<instrument_id>/position
TYPE='GET'
Secondly on other calls..
Make sure you add (body) to MESSAGE
--> timestamp + method + requestPath + json_encode(body)
Regards

Related

Convert log files to base64 and upload it using Curl to Github

I am trying to upload a file to Github using its API.
Following code works, but only with smaller size content which is approx less than 1MB.
tar -czvf logs.tar.gz a.log b.log
base64_logs=$(base64 logs.tar.gz | tr -d \\n)
content_response=$(curl \
-X PUT \
-u :"$GIT_TOKEN" \
-H "Accept: application/vnd.github.v3+json" \
"$content_url" \
-d '{"message": "Log files", "content": "'"$base64_logs"'"}')
For content that is a bit large, I get the following error:
/usr/bin/curl: Argument list too long
Now, there is already a question on SO about this error message, and it says that to upload a file directly. See here: curl: argument list too long
When I try this, I get a problem parsing JSON error message.
tar -czvf logs.tar.gz a.log b.log
base64_logs=$( base64 logs.tar.gz | tr -d \\ ) > base64_logs.txt
content_response=$(curl \
-X PUT \
-u :"$GIT_TOKEN" \
-H "Accept: application/vnd.github.v3+json" \
"$content_url" \
-d '{"message": "Log files", "content": #base64_logs.txt}')
Can anyone point me out where I am making mistake here? Thanks!
Use the base64 command rather than the #base64 filter from jq, because the later can only encode textual data and not binary data as from a .gz archive.
Pipe the base64 stream to jq to format it into a JSON data stream.
Curl will read the JSON data stream and send it.
# use base64 to encode binary data and -w0 all in one-line stream
base64 --wrap=0 logs.tar.gz |
# JSON format from raw input
jq \
--raw-input \
--compact-output \
'{"message": "Log files", "content": . }' |
# Pipe JSON to curl
curl \
--request PUT \
--user ":$GIT_TOKEN" \
--header "Accept: application/vnd.github.v3+json" \
--header 'Content-Type: application/json' \
--data-binary #- \
--url "$content_url"

Shell script not working for curl request

I want to make a curl request with Databox to push somemetrix and want to do it in shell script.
Here is the databox POST request example (which works like a charm)
curl https://push.test \
-u token
: \
-X POST \
-H 'Content-Type: application/json' \
-H 'Accept: application/vnd.databox.v2+json' \
-d '{
"data":[
{
"$testcount": 50,
"test_name": "test"
}
]
}'
When I form the json body as a separate json string and try to pass as parameter, it doesn't work and gives a json parsing error. I am not sure what am I am doing wrong here. can someone help? I am new to shell scripts
#!/bin/bash
JSON_STRING= '{"data" : [{"$testcount":50,"testname":"test"}]}'
echo "$JSON_STRING"
curl https://testpush \
-u token
: \
-X POST \
-H 'Content-Type: application/json' \
-H 'Accept: application/vnd.databox.v2+json' \
-d '$JSON_STRING'
error :
{"type":"invalid_json","message":"Invalid request body - JSON parse error"}
I have added my token for the request, so the authorisation should work.
You have excess whitespace around the =.
Also, $JSON_STRING in the last line of the second script should be in double quotes instead of the single quotes, to get it expanded into what you just set it to.
Btw., if data gets out of hand or is sensitive, you might want to look into the possibility to start the data with the letter # and then have the rest be a file name that contains the data.

Passing variables (containing spaces) to curl --data field

Arguments containing spaces will not properly pass to the curl command.
Quotes are not passed correctly in the --data field.
If I just echo the variable 'curlData' that I use in the curl command I get everything as it should be; ex :
$echo $curlData
'{"name":"jason","description","service"}'
I don't understand why curl dont expend this 'curlData' variable as expected:
curl --data '{"name":"jason","description","service"}'
Here's a sample of my code:
read -p "Name : " repoName
read -p "Description []: " repoDescription
curlData="'"{'"'name'"':'"'$repoName'"','"'descripton'"':'"'$repoDescription'"'}"'"
curl --data $curlData $apiURL
And the error:
curl: (3) [globbing] unmatched close brace/bracket in column 26
Thank your for your help, I feel i'm in Quote-ception right now.
Quote all variable expansions,
To make sure that curlData is a valid JSON value with properly escaped special-characters etc., use jq for producing it.
curlData="$(jq --arg name "$repoName" --arg desc "$repoDescription" -nc '{name:$name,description:$desc}')"
curl --data "$curlData" "$apiURL"
If you have access to any form of package management, I highly recommend jo.
curlData=$(jo name="$repoName" description="$repoDescription")
curl -d "$curlData" "$apiURL"
I had similar issue, which was very difficult to even understand. I used the below construct in a number of curl commands present in my shell script. It always worked like a charm. Until one fine day I had to pass a variable which was string containing spaces (eg. modelName="Abc def").
curl -X 'PUT' \
'http://localhost:43124/api/v1/devices/'$Id'' \
-H 'accept:*/*' \
-H 'Authorization:Bearer '$token'' \
-H 'Content-Type:application/json' \
-d '{
"modelName":"'$modelName'",
"serialNumber":"'$childSN'"
}'
Worked for me after the below change
curl -X 'PUT' \
'http://localhost:43124/api/v1/devices/'$Id'' \
-H 'accept:*/*' \
-H 'Authorization:Bearer '$token'' \
-H 'Content-Type:application/json' \
-d '{
"modelName":'\""$modelName"\"',
"serialNumber":"'$childSN'"
}'
I took help from the accepted answer by #oguz. Pasting this response , just in case anyone is in similar situation

Unable to substitute json from a file into a json data passed to curl in bash

I have a CloudFormation script that contains a json content that I need to substitute for a json field within the post body or data of the curl POST request that I will make.
The CloudFormation file is like this:
{ "AWSTemplateFormatVersion": "2010-09-09", "Description":
...}
The problem is that I have tried some code below but it is not working.
However, I copy and past the content of the CloudFormation file into my POST request's body it works as expected. This implies that this is a substitution or scripting problem.
CLOUD_FORMATION_FILE=/home/developer/workspace/blah/blah/infrastructure/templates/component.json
template=`cat $CLOUD_FORMATION_FILE`
echo $template
curl -d '{"template": $(echo $template)}' \
-H 'Content-Type: application/json' https://base.url.com/v1/services/component-proxy/test/stacks/test-component-proxy-component \
--cert /etc/pki/tls/certs/client.crt --key /etc/pki/tls/private/client.key
I am getting the error:
{"error": "Invalid JSON. Expecting object: line 1 column 13 (char 13)"}
You need to use double quotes in order to substitute a variable in a string.
There's no need to use $(echo $variable), just use $variable.
curl -d "{\"template\": $template}" \
-H 'Content-Type: application/json' https://base.url.com/v1/services/component-proxy/test/stacks/test-component-proxy-component \
--cert /etc/pki/tls/certs/client.crt --key /etc/pki/tls/private/client.key

Interpolate command output into GitHub REST request

I am trying to create a pull request comment automatically whenever CI is run. The output of a given command is written to a file (could also just be stored inside an environment variable though). The problem is, I usually get the following response:
curl -XPOST -d "{'body':'$RESULT'}" https://api.github.com/repo/name/issues/number/comment
{
"message": "Problems parsing JSON",
"documentation_url": "https://developer.github.com/v3/issues/comments/#create-a-comment"
}
This is usually due to unescpaed characters, like \n, \t, " etc.
Is there any easy way to achieve this on the command line or in bash, sh, with jq or Python? Using the Octokit.rb library is works straight away, but I don't want to install Ruby in the build environment.
You can use jq to create your JSON object. Supposing you have your comment content in RESULT variable, the full request would be :
DATA=$(echo '{}' | jq --arg val "$RESULT" '.| {"body": $val}')
curl -s -H 'Content-Type: application/json' \
-H 'Authorization: token YOUR_TOKEN' \
-d "$DATA" \
"https://api.github.com/repos/:owner/:repo/issues/:number/comments"
The post "Using curl POST with variables defined in bash script functions" proposes multiple techniques for passing a varialbe like $RESULT in a curl POST parameter.
generate_post_data()
{
cat <<EOF
{
"body": "$RESULT"
}
EOF
}
Then, following "A curl tutorial using GitHub's API ":
curl -X POST \
-H "authToken: <yourToken" \
-H "Content-Type: application/json" \
--data "$(generate_post_data)" https://api.github.com/repo/name/issues/number/comment