How can we get record of first or second month of current year in MySQL query?
Like I want this data for January and then for February:
select Sum(amount) as Amount from tbl_incomes where created_at = 'here the month January OR February of current year should be claused'
You can use the following, using YEAR and MONTH:
SELECT SUM(amount) AS Amount
FROM tbl_incomes
WHERE YEAR(created_at) = YEAR(NOW()) AND MONTH(created_at) IN (1, 2)
In case you want the SUM for January and February in separate rows you can use this:
SELECT SUM(amount) AS Amount
FROM tbl_incomes
WHERE YEAR(created_at) = YEAR(NOW()) AND MONTH(created_at) IN (1, 2)
GROUP BY YEAR(created_at), MONTH(created_at)
You should use a range expression.
SELECT sum(amount) amount
FROM tbl_incomes
WHERE created_at >= concat(year(now), '-01-01')
AND created_at < concat(year(now), '-03-01');
That way an index on created_at can support the query.
Related
i tried this query
select id, year(created_at) as year,month(created_at) as month,sum(grandtotal) as monthtotalsale
from bookings
WHERE YEAR(created_at)=YEAR(CURRENT_DATE) group by month(created_at)
order by id, year(created_at),month(created_at)
but this query return the total sale of each month
This would give you the three month with the highest sale monthly for this year
SELECT
id,
YEAR(created_at) AS year,
MONTH(created_at) AS month,
SUM(grandtotal) AS monthtotalsale
FROM
bookings
WHERE
YEAR(created_at) = YEAR(CURRENT_DATE)
GROUP BY MONTH(created_at)
ORDER BY monthtotalsale DESC
LIMIT 3
I want to get a statistic for every month of the years i have in DB
SELECT monthname(created_at) AS month, YEAR(created_at) AS year, count(*) AS number
FROM tableName
WHERE type_of_user = "someType"
GROUP BY year, month(created_at)
ORDER BY created_at DESC
Now it gives me only month that I have, but I need to get statistics for every month, even if I don't have any stored data for that month
Create a calendar table. This will need one entry per month, for every year that you intend to use.
Then select from the calendar table, and join in the values that you get from your current query. Use COALESCE() to put a zero-value where the entry is NULL (e.g. when there are no records in the tableName for that month and year).
SELECT MONTHNAME(date) as month,
YEAR(date) as year,
COALESCE(number, 0) as number
FROM calendar AS C
LEFT JOIN (
SELECT created_at, COUNT(*) as number
FROM tableName AS T
WHERE T.type_of_user = 'someType'
GROUP BY YEAR(created_at), MONTH(created_at)
) AS T
ON MONTH(T.created_at) = MONTH(C.date) AND YEAR(T.created_at) = YEAR(C.date)
GROUP BY month, YEAR(created_at)
ORDER BY MONTH(date), YEAR(date)
SQL fiddle at http://sqlfiddle.com/#!9/e0a4dc/
SELECT month(created_at) as month
FROM tableName
RIGHT JOIN (select row_number() over (order by 1) as i
from someTableWithMoreThan12Records limit 12) x
ON x.i=month(created_at)
ORDER BY I;
JOINing with a table that has all the records will give you every month.
SR_ AREA INS_PRODUCT DATEADD TOTAL
Clinical Question PS 2016-01-06 280
I'm trying to show the month by name say January and I want all the totals for the month of January not just for one day in the month.
I got it to show just Month and total how do I get it to show all the months this is the code I have so far.
SELECT DATENAME(MM,GETDATE()) AS MONTH, COUNT(*) AS TOTAL
FROM S_SRV_REQ WITH (NOLOCK)
WHERE (dbo.fn_dstoffset(CREATED) >= '11-15-2015')
AND (dbo.fn_dstoffset(CREATED) <= DATEADD(D, 1, '3-31-2016'))
AND (INS_PRODUCT IN ('PS'))
AND [SR_AREA] IS NOT NULL
AND (SR_AREA IN ('Clinical Question'))
select date_format(dateadd, '%M'), sum(total)
from your_table
group by date_format(dateadd, '%M')
You can use MONTH
select month(dateadd), sum(total)
from your_table
group by month(dateadd)
I have a table event, where i have records with a field end_date, so my problem is i want to fetch number of records, grouping month wise, where end_date should with in that month only, so for example:
If a record have end_date as 2013-01-01 00:00:00 then it should be counted in January 2013, and i am not able to do that. I am unable to put that where condition, how to do tell database that end_date should be between the month for which it is currently grouping.
SELECT COUNT(*) AS 'count', MONTH(created) AS 'month', YEAR(created) AS 'year' FROM event WHERE is_approved =1 GROUP BY YEAR(created), MONTH(created)
Please help me out.
EDIT :
Data say i have is like:
Record name end_date
record_1 2013-11-01 00:00:00
record_2 2013-11-30 00:00:00
record_3 2013-12-01 00:00:00
record_4 2013-12-04 00:00:00
record_5 2013-12-06 00:00:00
record_6 2013-12-10 00:00:00
...many more
Result Expected is:
Count month year
2 11 2013
4 12 2013
....so on
Try this:
SELECT COUNT(1) AS 'count', MONTH(end_date) AS 'month', YEAR(end_date) AS 'year'
FROM event
WHERE is_approved = 1
GROUP BY EXTRACT(YEAR_MONTH FROM end_date);
OR
SELECT COUNT(1) AS 'count', MONTH(end_date) AS 'month', YEAR(end_date) AS 'year'
FROM event
WHERE is_approved = 1
GROUP BY YEAR(end_date), MONTH(end_date);
::EDIT::
1. end date is greater than that particular month - Simply add where condition in your query and pass particular month in format of YYYYMM instead of 201411
2. event is started - Add one more where condition to check whether the created date is less then current date
SELECT COUNT(1) AS 'count', MONTH(end_date) AS 'month', YEAR(end_date) AS 'year'
FROM event
WHERE is_approved = 1 AND
EXTRACT(YEAR_MONTH FROM end_date) > 201411 AND
DATE(created) <= CURRENT_DATE()
GROUP BY EXTRACT(YEAR_MONTH FROM end_date);
OR
SELECT COUNT(1) AS 'count', MONTH(end_date) AS 'month', YEAR(end_date) AS 'year'
FROM event
WHERE is_approved = 1 AND
EXTRACT(YEAR_MONTH FROM end_date) > 201411 AND
DATE(created) <= CURRENT_DATE()
GROUP BY YEAR(end_date), MONTH(end_date);
The count is aggregated based on the month and year so if you are spanning years, you wont have Jan 2013 mixed with Jan 2014, hence pulling those values too and that is the same basis of the group by.
As for your criteria, that all goes in the WHERE clause. In this case, I did anything starting with Jan 1, 2013 and ending Dec 31, 2014 via 'yyyy-mm-dd' standard date recognized format. That said, and the structure of the table you provided, I am using the "end_date" column.
SELECT
YEAR(end_date) AS EventYear,
MONTH(end_Date) AS EventMonth,
COUNT(*) AS EventCount
FROM
event
WHERE is_approved = 1
and end_date between '2013-01-01' and '2014-12-31'
GROUP BY
YEAR(end_date),
MONTH(end_Date)
Now, if you want them to have the most recent events on the top, I would put the year and month descending so 2014 is listed first, then 2013, etc and months within them as December (month 12), before the others.
GROUP BY
YEAR(end_date) DESC,
MONTH(end_Date) DESC
Your criteria could be almost anything from as simple as just a date change, approved status, or even get counts per account status is so needed, such as (and these are just EXAMPLES if you had such code status values)
SUM( is_approved = 0 ) as PendingEvent,
SUM( is_approved = 1 ) as ApprovedEvent,
SUM( is_approved = 2 ) as CancelledEvent
Per comment feedback.
For different date ranges, ignore the between clause and change the WHERE to something like
WHERE end_date > '2014-08-01' or all after a date...
where end_date < '2014-01-01' or all before a date...
They will still group by month / year. If you wanted based on a start date of the event, just change that column in instead, or do IN ADDITION to the others.
MySQL has a bunch of date and time functions that can help you with that. For example:
MONTH() Return the month from the date passed
or
YEAR() Return the year
So you can just get the month and year of your dates. And group your results by them.
SELECT
COUNT(*) cnt
,MONTH(end_date) month
,YEAR(end_date) year
FROM events
GROUP BY month, year
Result :
cnt month year
2 11 2013
4 12 2013
Update:
For filtering only the records that have an end_date greater than a particular month AND have already started, you just need to add a WHERE clause. For example, if the particular month were February 2015:
SELECT
COUNT(*) cnt
,MONTH(end_date) month
,YEAR(end_date) year
FROM events
WHERE end_date >= '2015-03-01'
AND created < NOW()
GROUP BY month, year
Alternatively, the first part of the WHERE clause can be rewritten in the following way, which is probably more comfortable to use if you have to pass the year and month as distinct parameters.
...
WHERE (YEAR(end_date) > 2015
OR (YEAR(end_date) = 2015 AND MONTH(end_date) > 02))
AND created...
SELECT COUNT(*) AS 'count', MONTH(created) AS 'month', YEAR(created) AS 'year' FROM event WHERE is_approved =1 and month(created) = "the month u want" and year(created) = "the year you want" group by GROUP BY YEAR(created), MONTH(created)
you will need to pull the month and year... i could help with that but not sure how you are getting it but months would be 01/02/03 ect and year is 2013/2014/2015 ect
I have the following relevant columns in my 'orders' table:
Date_Day (is a range from 1 to 31 with no trailing 0)
Date_Month (is a range from January to December, not numerical)
Date_Year (is the year in 4 digit format, ex: 2005)
Total (number with 2 decimal places)
I know the way of storing date is absolutely awful, but this was the database I was given. I am trying to find a few things and I'm not sure if there is a way to do it in SQL instead of doing the math in PHP:
The SUM of each day of each year.
The SUM of this day last year
(where this day is the nth weekday of the month. So for today, it
would be the 1st Tuesday of October in 2012)
The highest grossing
day in history
MySQL is not my forte, and while I can figure it out in PHP, I would love to see it done in MySQL so I can start to learn it more.
If you want to keep your database structured as it is, you could use these queries:
The SUM of each day of each year:
SELECT Date_Year, Date_Month, Date_Day, SUM(Total)
FROM tablename
GROUP BY Date_Year, Date_Month, Date_Day
The SUM of this day last year:
SELECT SUM(Total)
FROM tablename
WHERE
Date_Year = YEAR(CURDATE())-1
AND Date_Month = MONTHNAME(CURDATE())
AND Date_Day = DAY(CURDATE())
The highest grossing day in history:
SELECT Date_Year, Date_Month, Date_Day, SUM(Total)
FROM tablename
GROUP BY Date_Year, Date_Month, Date_Day
ORDER BY SUM(Total) DESC
LIMIT 1