Order by first results that do not go over - mysql

Question

How can you order by two fields based on the value not being greater than another? Here is an example of what I have written.
SELECT *
FROM contest_results r
LEFT
JOIN participant_users u
ON r.participant_id = u.id
LEFT
JOIN contest_entry_tie_answers t
ON u.id = t.participant_id
LEFT
JOIN contest_answers a
ON a.question_id = t.tie_breaker_question_id
WHERE r.contest_id = 20
ORDER BY r.correct_answers DESC,
t.answer <= a.possible_answer ASC
Now imagine that this query returns two rows and contest_entry_tie_answers.answer has a value of 103 and another of 106. Finally, imagine that contest_answers.possible_answer has a value of 105 because that field was checked as the correct answer. I want to be able to order the results as contest_entry_tie_answers.answer <= contest_answers.possible_answer.
That would mean the 103 answer would be shown first in the event that the previous order by contest_results.correct_answers returns a tie value for both. Then the 106 result would show last because it went over the actual correct answer of 105.
Is there a way to do this? I hope this made some sense.

Answer 1

I believe I found the solution by doing the following:
SELECT *
FROM contest_results r
LEFT
JOIN participant_users u
ON r.participant_id = u.id
LEFT
JOIN contest_entry_tie_answers t
ON u.id = t.participant_id
LEFT
JOIN contest_answers a
ON a.question_id = t.tie_breaker_question_id
WHERE r.contest_id = 20
ORDER BY r.correct_answers DESC,
case
when t.answer <= a.possible_answer then 0
when t.answer > a.possible_answer then 1
end,
t.answer
DESC
This seems to work well from my initial testing.