Cannot use window function 'count' in having statement - mysql

Question

I'm new to MYSQL, and I'm trying to validate the number of data which have the same name from 2 column that occurs more than one time, which I already try to use 'having' statement in this case and it throws me an error like this
Error Code: 3593. You cannot use the window function 'count' in this context.'
below I include an image of what I'm trying to do
you can see there a column named "number_of_same_year" represent the "COUNT OVER PARTITION" output, which has numbers that logically could be validated. I only want to show where the numbers are above 1 (which means occur more than one time)
ps: I'm using MySQL in Windows 10

Answer 1

You cannot use having and a window function. You would want to instead do as follows
select * from (
select unit_name
,month(transaction_date)
,year(transaction_date) as year
,budget
,count(*) over(partition by unit_name,year(transaction_date)) as number_of_same_year
from sql_advertising.history_transaction
)x
where x.number_of_same_year >1
order by x.unit_name

Answer 2

SELECT {fieldset}
FROM {tableset}
WHERE {conditions-1}
GROUP BY {expression-1}
HAVING {conditions-2}
AND {expression-2} = COUNT({expression-3}) OVER ({window})
Window function is applied to output dataset, but HAVING alters it. So window function cannot be used in HAVING. The above code is invalid.
You may solve it by:
WITH `cte` AS ( SELECT {fieldset},
{expression-2} = COUNT({expression-3}) OVER ({window}) AS `criteria`
FROM {tableset}
WHERE {conditions-1}
GROUP BY {expression-1}
HAVING {conditions-2} )
SELECT {fieldset}
FROM `cte`
WHERE `criteria`