(SQL) WHERE clause not working in its most simple way? [closed] - mysql

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SQL beginner here. I have this database: https://github.com/socratica/data/blob/master/earthquake.csv
I'm running a simple Query such as:
SELECT place, DEPTH1 , OCCURED_ON from EARTHQUAKE1;
I execute it, and get the info I need. However, when I add WHERE depth1 = 35; (I edited the depth col just in case it was conflicting with some other clause)
the GUI returns an error. I tried adding ' and using like, also using TRIM but no luck. I also tried retrieving data from another col, but still no good. What is it that I'm doing brutally wrong?
Thanks in advance!

You have a semicolon after your FROM and before your WHERE.
SQL is reading the WHERE as a separate statement and failing.
The ; is a statement terminator.

Related

Select from MySQL with LIKE condition [closed]

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I have fields (pay_area, varchar(20)) with different values in my MySQL database. Some of them are like blabla.one blabla.two etc and others are completely different.
For example:
blabla.one, ads, blabla.one, payment, blabla.tree and so on.
I have to count all the fields starting only with blabla.
How can I do that?
SELECT count(id)
FROM TABLE
WHERE pay_area LIKE 'blabla.%'
If you want to fetch more fields then you can select other columns as well

How can I eliminate the errors in SQL [closed]

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I wrote a simple code to create a table in SQL. It is generating errors I am unable to understand even though I am sure the syntax are correct. Here is the output of my problem in the image:
Your query should be like below :
CREATE TABLE Users (
name varchar(128),
email varchar(128)
)
I highly recommend you to avoid using reserved words like Users.
A guide to help you creating tables.
As far as I get, the SQL syntax uses no curly braces, but just braces.
Have a look at this:
https://www.w3schools.com/sql/sql_create_table.asp
In fact, I would recommend you to use W3 schools for every extremely simple question like this one.
Create Table Users(
Name varchar(50),
Email varchar(100)
);
You should use () this brackets not {} this

SQL expecting 'with' command [closed]

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I started using MySQL recently and I am facing a problem. I created two tables using create table command and inserted value in the table. These two commands were executed successfully. Then I tried using select command. When I try to execute this command it shows
"select" is not valid at this position for this server version, expecting: (, WITH
Here is my command:
select
*
from Employee,
where Gender="M" and NativePlace="Mumbai",
order Hobby by desc;
What is the reason for this?
There are a couple of syntax errors in your query, try this:
select
*
from Employee
where Gender='M' and NativePlace='Mumbai'
order by Hobby desc;
Remove the commas after Employee and "Mumbai" and you should be good.

MySQL Starts with search [closed]

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Closed 5 years ago.
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I have a list of zip codes in this format:
ZIP CODES
84038-4323
93434-4320
The user types it in like this: 84038
I'm trying to figure out how to do something like this in MySQL
SELECT * FROM locations WHERE ZipCode STARTSWITH '${userZip}'
I need the first part of the zip code to match exactly.
I tried this
SELECT * FROM locations WHERE ZipCode LIKE '${userZip}%'
But it's returning extra data, it appears the LIKE command is not strict enough.
I think you should consider using - too in where condition. Something like below using REGEXP
SELECT * FROM locations WHERE ZipCode REGEXP '^{userZip}-'

MySQL server version for the right syntax to use near 'IN (10,13,8,11,6,14,9,12,7,15)' [closed]

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I don't get it, this line should work perfectly fine, yet it doesn't. For some reason I am unable to understand why? Can anyone see what I'm missing.
$resclients=$mysqli->query("SELECT id,client_name FROM clients WHERE id = IN ($result)");
The correct SQL query in your case is:
SELECT id,client_name FROM clients WHERE id IN ($result)
as the SQL IN syntax is as follows:
SELECT column_name(s)
FROM table_name
WHERE column_name IN (value1,value2,...);
Try this code:
$resclients=$mysqli->query("SELECT id,client_name FROM clients WHERE id IN ($result)");