How to print an string without the newline Mips Assembly language - mips

Question

I am trying to get the output in the same line with the result(string). I have found examples, but none of them explained the process. I know that the string has to be store in memory and then access it through bit by bit, but I got lost in the process.
.data
prompt: .asciiz "Enter your name: "
name: .space 101
result: .asciiz " ...that's the name"
.text
.globl main
main:
la $a0, prompt
li $v0, 4
syscall
la $a0, name # Get the input
li $v0, 8
li $a1,101
syscall
la $a0, name # print the result
li $v0, 4
syscall
la $a0, result
li $v0, 4
syscall
li $v0,10
syscall

Answer 1

The problem comes from that, when you read in the input the new line will be read also, so it has to be removed in order to achieve your needs.
This is one way to do it:
.data
prompt: .asciiz "Enter your name: "
name: .space 101
result: .asciiz " ...that's the name"
.text
.globl main
main:
la $a0, prompt
li $v0, 4
syscall
la $a0, name # Get the input
li $v0, 8
li $a1,101
syscall
addi $t1, $t1, 0 # len = 0
len_to_new_line:
lb $t2, ($a0) # t2 = *a0
beq $t2, '\n', end # if t2 == '\n' -> stop
addi $t1, $t1, 1 # len++
addi $a0, $a0, 1 # a0++
b len_to_new_line
end:
la $a0, name
add $a0, $a0, $t1
sb $zero, ($a0) # overwrite '\n' with 0
la $a0, name # print the result
li $v0, 4
syscall
la $a0, result
li $v0, 4
syscall
li $v0,10
syscall
Output
Enter your name: David
David ...that's the name
EDIT: The len is not even needed and code can be reduced to this (only the changed part)
len_to_new_line:
lb $t2, ($a0) # t2 = *a0
beq $t2, '\n', end # if t2 == '\n' -> stop
addi $a0, $a0, 1 # a0++
b len_to_new_line
end:
sb $zero, ($a0) # overwrite '\n' with 0