I want to select a table with group by like this:
and i want to have a result like this
i compare the state, if i have one up state so the result will up
SELECT name,MAX(state)
FROM table
GROUP BY name
Because state is a varchar (assumption), the maximum is an alphabetical order, favouring 'up'.
If its an enum, it still will work if 'up' is the second element of the enum.
Try this:
Demo on DB Fiddle
select
name,
case
when max(state = 'up') then 'up'
else 'down'
end state
from
mytable
group by name;
result:
name | state
PLR | up
VRL | down
Please, try with below query:
select A.name, (case when A.up_state>0 then 'up' else 'down' end) as state
from (
select name, sum(case when state='up' then 1 else 0 end) as up_state
from table_name
group by name
) as A
Related
I'm trying to sum the results of count(id) at the same level, in order to find out the relative portion of the count(id) from the overall count.
The count is grouped by the respective previous number, and I want to stay at the same table and have it all together.
`
select totalattempts, count(totalattempts) allattempts, count(case when success>0 then totalattempts else null end) successfulattempts
from (
select *, case when success> 0 then attemptspresuccess+1 else attemptspresuccess end totalattempts
from (select orderid, count(orderid) attemptspresuccess, count(case when recoveredPaymentId is not null then recoveredPaymentId end ) success from (
select orderid, recoveredPaymentId
from errors
where platform = 'woo'
) alitable
group by orderid) minitable ) finaltable
group by totalattempts
order by totalattempts asc
`
I need to add another column that basically would have, to put it simply, count(totalattempts)/sum(count(totalattempts).
I'm running out of ideas basically.
I can't use windows as this is an app of retool which doesn't support that
Assuming some test data here:
DECLARE #table TABLE (AttemptNumber INT IDENTITY, Success BIT)
INSERT INTO #table (Success) VALUES
(0),(0),(0),(0),(1),(1),(0),(0),(0),(0),(0),(1),(0),(1),(0),(0),
(0),(0),(1),(0),(0),(0),(0),(1),(0),(1),(0),(0),(0),(1),(0),(0)
I sounds like you want to know how many attempts there were, how many were successful and what that is a percentage?
SELECT COUNT(Success) AS TotalCount,
COUNT(CASE WHEN Success = 1 THEN 1 END) AS SuccessCount,
COUNT(CASE WHEN Success = 1.0 THEN 1 END)/(COUNT(Success)+.0) AS SuccessPct
FROM #table
TotalCount SuccessCount SuccessPct
--------------------------------------
32 8 0.2500000000000
I am unable to derive a SQL query for the following table content.
When i tried below query i am getting above said output. Can someone help me to give the required query for it.
select Name, count(Status) from mytable where Status='Open' group by mytable union
select Name, count(Status) from mytable where Status='Cleared' group by mytable
Use case expressions in the select list to do conditional aggregation.
select Name,
count(case when Status = 'Open' then 1 end) as opencnt,
count(case when Status = 'Cleared' then 1 end) as clearedcnt
from mytable
where Status in ('Open', 'Cleared')
group by Name
COUNT() counts non-null values. The case expressions above returns null when the conditions aren't fulfilled.
I have an sql query problem . I don't want to execute three times query for same result.
In my table I have one field req_type which have three parameter ,
either 1, either 2, either 3 .
I want counter based on req_type in one query instead of by executing query 3 times like below
select count(id) as premium FROM tablename where req_type=1
select count(id) as premium1 FROm tablename where req_type=2
select count(id) as premium2 FROm tablename where req_type=3
I am stuck , can anybody help me?
You could use case for such type of count
select sum(case when req_type=1 then 1 else 0 end) as premium,
sum(case when req_type=2 then 1 else 0 end) as premium1,
sum(case when req_type=3 then 1 else 0 end) as premium2
FROM tablename
Use one query instead of threes by using group by cluase
select req_type , count(id) as premium
FROM tablename
where req_type in (1,2,3)
group by req_type
Use a GROUP BY
SELECT req_type, COUNT(id) AS count_premium
FROM tablename
GROUP BY req_type;
table looks something like this: (yes those are & signs. ignore the dashes)
ID-VALUE-NUM
-1-YES----2-
-1-NO-----3-
-2-YES----1-
-2-NO-----1-
-3-&&&----1-
-3-&------2-
-3-&&-----2-
what I need to do:
for each ID, I need to get the value with the highest NUM, in the case of a tie and VALUE has &s then it would pick the shortest. if the value is YES/NO then it will pick YES.
result desired
ID-VALUE-NUM
-1-NO-----3-
-2-YES----1-
-3-&------2-
I think I have to put a IF statement in there somewhere but I'm not sure how.
Here is one way. The join finds the maximum num. Then the select uses logic to choose the right value based on your rules:
select t.id,
(case when count(*) = 1 then min(value)
when max(value like '%&%') > 0 then min(value)
when max(value = 'Yes') > 0 and max(value = 'No') > 0 then 'Yes'
else max(value)
end) as value,
t.num
from t join
(select id, max(num) as maxnum
from t
group by id
) tm
on t.id = tm.id and t.num = tm.maxnum
group by t.id, t.num
I have about the following query:
SELECT *
FROM Product
ORDER BY (SELECT CASE
(SELECT MIN(date) FROM SomethingElse WHERE productId = Product.id) AS here
WHEN NULL
THEN 0
ELSE here
) DESC
However, AS in CASE doesn't work. I need a way to save the value in a variable and use it again.
So you are trying to do CASE when expression IS NULL THEN 0 ELSE expression END?
In this case you can just use COALESCE(expression, 0)