I have database which contains string like this
22 Jan 2019 11:03
I would like to convert this string to date so I apply this query
select DATE_FORMAT(STR_TO_DATE('22 Jan 2019 11:03','%d-%m-%Y') ,'%d-%m-%Y');
but I get a null result
All you have to do is change small letter m to big letter M in your str_to_date function.
select STR_TO_DATE('22 Jan 2019 11:03','%d %M %Y');
so the final query would be:
select DATE_FORMAT(STR_TO_DATE('22 Jan 2019 11:03','%d %M %Y') ,'%d-%m-%Y');
Here is a demo
SELECT STR_TO_DATE('22 Jan 2019 11:03','%d,%m,%Y');
Basically you first need to understand the values to pass in STR_TO_DATE() and DATE_FORMAT() functions
STR_TO_DATE(my date string , current format of my date string)
Now what you are not doing right is that in STR_TO_DATE() you are passing the format '%d-%m-%Y' , this format says that the input string has hyphen separated date month and year values which is not true.
Now in your case the actual format of your date string is the following
'%d %M %Y %h:%i'
STR_TO_DATE('22 Jan 2019 11:03','%d %M %Y %h:%i')
%d - day
%M - month
%Y - year
%h - hour
%i - minute
For more info on formats click
Now that we have a complete valid value from string to date including hour and minutes, we can convert this date into any of our required format using correct parameters
SELECT DATE_FORMAT(STR_TO_DATE('22 Jan 2019 11:03','%d %M %Y %h:%i') ,'%d-%m-%y %h:%i');
You can try out various examples here
https://www.mysqltutorial.org/tryit/query/mysql-str_to_date/#1
Related
I have a column in a MySQL database that has dates in the form:
Tue Oct 25 2016. I am trying to get it in the form 10/25/2016.
I did some research and tried this:
SELECT DATE_FORMAT(Date, '%d/%m/%Y') FROM table;
But it is returning null
Any help would be greatly appreciated.
Firstly, you will need to convert your date string to MySQL date format ('YYYY-MM-DD'), using STR_TO_DATE function. To convert from string, we have to specify the current format of the date string. In your case, it is '%a %b %d %Y'. Note that the % character is required before format specifier characters.
Details:
%a Abbreviated weekday name (Sun to Sat)
%b Abbreviated month name (Jan to Dec)
%d Day of the month as a numeric value (01 to 31)
%Y Year as a numeric, 4-digit value
Now, you can utilize DATE_FORMAT function to convert the MySQL date into the desired date string format. In your case, it will be: '%m/%d/%Y'
Details:
%d Day of the month as a numeric value (01 to 31)
%m Month name as a numeric value (00 to 12)
%Y Year as a numeric, 4-digit value
Try the following query:
SELECT DATE_FORMAT(STR_TO_DATE(Date, '%a %b %d %Y'), '%m/%d/%Y')
FROM table;
Complete list of available format specifiers can be seen at: https://dev.mysql.com/doc/refman/8.0/en/date-and-time-functions.html#function_date-format
I have a table which contains a varchar field containing date like '15 May 2015 - 03:10 am'
I have to compare all date in this table with the current date to retrieve row which are next the current date and row which are recent to the current date
I found this solution here:
select *
from reunion a
where STR_TO_DATE(a.dateDebut,'%d %b %Y - %I:%i %p')>
DATE_FORMAT(NOW(),'%d %b %Y - %I:%i %p');
but it returns all date: '15 May 2013 - 03:10 AM' ,'15 May 2015 - 03:10 am','15 May 2016 - 03:10 am'
and when I change to "<" it returns 0 rows;
is there any other solution to give the varchar field the ability to be a valid date?
Your query is overkill. You just need to convert your date format to a date. now() is already a date. So try:
select *
from reunion a
where STR_TO_DATE(a.dateDebut,'%d %b %Y - %I:%i %p') > NOW();
How do I convert the following format to unix timestamp?
Apr 15 2012 12:00AM
The format I get from DB seems to have AM at the end.
I've tried using the following but it did not work:
CONVERT(DATETIME, Sales.SalesDate, 103) AS DTSALESDATE,
CONVERT(TIMESTAMP, Sales.SalesDate, 103) AS TSSALESDATE
where Sales.SalesDate value is Apr 15 2012 12:00AM
Here's an example of how to convert DATETIME to UNIX timestamp:
SELECT UNIX_TIMESTAMP(STR_TO_DATE('Apr 15 2012 12:00AM', '%M %d %Y %h:%i%p'))
Here's an example of how to change date format:
SELECT FROM_UNIXTIME(UNIX_TIMESTAMP(STR_TO_DATE('Apr 15 2012 12:00AM', '%M %d %Y %h:%i%p')),'%m-%d-%Y %h:%i:%p')
Documentation: UNIX_TIMESTAMP, FROM_UNIXTIME
You will certainly have to use both STR_TO_DATE to convert your date to a MySQL standard date format, and UNIX_TIMESTAMP to get the timestamp from it.
Given the format of your date, something like
UNIX_TIMESTAMP(STR_TO_DATE(Sales.SalesDate, '%M %e %Y %h:%i%p'))
Will gives you a valid timestamp. Look the STR_TO_DATE documentation to have more information on the format string.
If you want to create a timestamp as returned by java's Date.getTime() you should multiply by 1000.
SELECT UNIX_TIMESTAMP(STR_TO_DATE('Apr 15 2012 12:00AM', '%M %d %Y %h:%i%p'))*1000
Now for a more standard date format use:
SELECT UNIX_TIMESTAMP(STR_TO_DATE('2022-12-14 20:58:00', '%Y-%m-%d %H:%i:%s'))*1000
From http://www.epochconverter.com/
SELECT DATEDIFF(s, '1970-01-01 00:00:00', GETUTCDATE())
My bad, SELECT unix_timestamp(time) Time format: YYYY-MM-DD HH:MM:SS or YYMMDD or YYYYMMDD. More on using timestamps with MySQL:
http://www.epochconverter.com/programming/mysql-from-unixtime.php
For example, I have a column named date on my table post and I want to sort it in ascending.
On my date column I fill it with RCF112 format, eg: Sun, 22 APR 2012 5:21:22.
First I begin with this command:
SELECT *
FROM post
ORDER BY date ASC
But the result appears to be incorrect because it was sorted according to its string, eg. the Sun, 15 APR 2012 will be older than Wed,11 APR 2012 because "Sun" starts with 'S' which is in alphabetic ahead 'W', so the "Sun, 15 APR 2012" appears first.
How to correct this command?
You need to parse the string as datetime to be able to sort it correctly.
Using your format, you can try something like this:
STR_TO_DATE('Sun, 22 APR 2012 5:21:22', '%a, %e %b %Y %h:%i:%S')
which creates the date 2012-04-22 05:21:22.
So, your query should look something like this:
SELECT *
FROM post
ORDER BY
STR_TO_DATE(date, '%a, %e %b %Y %h:%i:%S')
ASC
As others might have already suggested, you could use the datetime field type and format the date in the select (date_format http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format) to fit your requirements.
SELECT *
FROM post
ORDER BY STR_TO_DATE(datestr, '%a, %d %b %Y %T') ASC
I have a column date in MYSQL, i want to display date in day Month year (day of week) format.
For Example :
if date value is 2011-01-01 than it should display as 1 Jan 2012 (Sun). How should i acheive this ?
Refer this MySQL 5.1 Reference Manual for more info
Date and Time Functions
You can use this:
EDITED:
SELECT DATE_FORMAT('2012-01-01', '%d %b %Y (%a)'); will give you 1 Jan 2012 (Sun)
%d = 01;
%b = Jan;
%Y = 2012;
%a = Sun;
For a detailed date formats see: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_date-format
Hope this helps.
you can use DATE_FORMAT in mysql:
DATE_FORMAT(column_name, '%e %b %Y (%a )')
"%m" will give numeric value like '01','02' for Jan, Feb you should use "%b".
and also "%d" will return 2 digits like '01','02' but "%e" will return '1','2'.
check out this link for more details, you can change as per your choice.
http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html#function_date-format
try this
SELECT DATE_FORMAT(Date, '%d %b %Y (%a )') from table;