I have the following MySQL statement which does what I want:
SELECT scores.score, registrations.parade, AVG(scores.score) as result
FROM scores
JOIN registrations ON scores.registrationId=registrations.id
where registrations.parade=1
GROUP BY scores.registrationId
ORDER BY result DESC
basically, with sqlalchemy I think I would start with:
db.session.query(Scores, func.avg(Scores.score).label('result'))
This is because I do not need the information from registrations (it's linked to each other in the model). I only join the registrations in the MySQL statement because I need to filter on its parade.id
Below is what I have been trying so far but does not work:
scores = db.session.query(Scores,func.avg(Scores.score).label('result'))\
.filter(Registrations.parade == 1)\
.group_by(Scores.registrationId)\
.order_by(desc('result'))
You are missing the join
scores = db.session.query(Scores.score,func.avg(Scores.score).label('result'))\
.join(Registrations)\
.filter(Registrations.parade == 1)\
.group_by(Scores.registrationId)\
.order_by(desc('result'))
Another issue is, that you should have an aggretation function for registrations.parade or else include it in the group_by statement.
Related
When I run the below SQL statement, it correctly shows me what I expect:
SELECT Users.idQuiz as ThisIDQuiz,Rounds.RoundNr as ThisRoundNr, Questions.QuestionNr as ThisQuestionNr, Answer as ThisAnswer, Questions.QuestionScore AS QuestionScoreMax,AnswerCorrect,
(SELECT COUNT(*) as "Aantal Ploegen met dit antwoord"
FROM `Answers`
JOIN Questions on Answers.idQuestion = Questions.idQuestion
JOIN Rounds on Questions.idRound = Rounds.idRound
JOIN Users on Users.idUser = Answers.idUser
where (Users.idQuiz = ThisIDQuiz AND Rounds.RoundNr = ThisRoundNr AND Questions.QuestionNr=ThisQuestionNr AND Answers.Answer = ThisAnswer )
GROUP BY Users.idQuiz,Rounds.RoundNr, Questions.QuestionNr,Answer
) as NrOfTeamsWithThisAnswer,
(SELECT COUNT(*)
FROM Users
WHERE ((Users.idQuiz = ThisIDQuiz) AND (Users.UserType = 0))
) As TotalNrOfTeams,
AnswerCorrect *((Select TotalNrOfTeams)- (SELECT NrOfTeamsWithThisAnswer))as ScoreForThisAnswer
FROM `Answers`
JOIN Questions on Answers.idQuestion = Questions.idQuestion
JOIN Rounds on Questions.idRound = Rounds.idRound
JOIN Users on Users.idUser = Answers.idUser
WHERE Questions.QuestionType = 5
GROUP BY ThisAnswer
ORDER BY ThisIDQuiz, ThisRoundNr, ThisQuestionNr, ThisAnswer;
See Results of the query for what the result looks like.
I then create a VIEW from this statement. The view is created fine, but when I open it, I get the error "#1242 - Subquery returns more than 1 row".
I tried dropping and recreating the view, same result.
When I use the exact same SQL statement but without the penultimate line (GROUP BY ThisAnswer), it works fine (i.e. I can create the view and it opens without an error). This second view suits my purposes fine, so I can continue, but just out of curiosity: can someone explain this behaviour?
I use phpMyAdmin version 5.1.3 to do my SQL manipulations.
As #NickW asks, the statement GROUP BY ThisAnswer expects you to have an aggregate function (i.e. count, avg, max, min, etc.) somewhere in that main SELECT. Having a GROUP BY without an aggregate function will create errors. Either add the aggregate function, or remove the GROUP BY statement in the main (outermost) SELECT.
I am currently doing some SQL magic and wanted to update the stock in my companies ERP program. However if I try to run the following query I get the error mentioned in the title.
update llx_product lp
set stock = (select sum(ps.reel)
from llx_product_stock as ps, llx_entrepot as w
where w.entity IN (1)
and w.rowid = ps.fk_entrepot
and ps.fk_product = lp.rowid
group by ps.rowid)
The subquery by itself returns just one row if used with a rowid for the product.
select sum(ps.reel)
from llx_product_stock as ps, llx_entrepot as w
where w.entity in (1)
and w.rowid = ps.fk_entrepot
and ps.fk_product = 7372
group by ps.rowid
Any help would be appreciated
I would suggest writing the query as:
update llx_product lp
set stock = (select sum(ps.reel)
from llx_product_stock ps join
llx_entrepot w
on ps.fk_product = lp.rowid
where w.entity in (1) and
w.rowid = ps.fk_entrepot
);
An aggregation query with no group by cannot return more than one row. It is unclear how your version is returning more than one row because the key used in the group by also has an equality comparison. Perhaps there is some type conversion issue at play.
But in any case, without the group by, you cannot get the error you are currently getting.
For anyone wondering the solution to my issue was a very simple query, Gordon pointed in the right direction and I made it harder than it should be.
update llx_product lp
left join llx_product_stock ps on lp.rowid = ps.fk_product
set lp.stock = ps.reel
i have some query and i just know how to query on mysql (phpmyadmin)
i got information if using DB::select we cannot to use paginate, so we need change to DB::table(some query) to using pagination.
but the problem is i am confuse how to convert my query into DB::table(some query)
Here is my code
$daily = DB::select("
SELECT
employees.employee_name,
COUNT(DISTINCT DATE(attendance.attendance_datetime)) as jumlah,
locations.location_name,
TIME(MIN(attendance.attendance_datetime)) as check_in,
CASE
WHEN ISNULL(TIME(MIN(attendance.attendance_datetime))) THEN attendance_absence.remarks
WHEN TIME(MIN(attendance.attendance_datetime)) > '08:05:00' THEN (SELECT TIMEDIFF('08:05:00', MIN(TIME(attendance_datetime))))
WHEN TIME(MIN(attendance.attendance_datetime)) <= '08:05:00' THEN 'Good'
ELSE 'No Record'
END as detail_telat,
attendance_absence.remarks as remarks
FROM
employees
LEFT JOIN attendance ON employees.employee_name = attendance.attendance_name AND DATE(attendance.attendance_datetime) = '$date'
LEFT JOIN locations ON employees.location_id = locations.id
LEFT JOIN attendance_absence ON attendance_absence.employee_name = employees.employee_name AND attendance_absence.absences_date = '$date'
WHERE locations.location_name LIKE '%'
GROUP BY employees.employee_name
ORDER BY employees.employee_name
")->paginate(3);
please help me to convert my query into eloquent or query builder, or any suggestion ?
Currently, pagination operations that use a groupBy statement cannot be executed efficiently by Laravel. If you need to use a groupBy with a paginated result set, it is recommended that you query the database and create a paginator manually.
Check documentation
I want to count how many records from another table in the same select statement , i used Left join
and in the select statement i put count(ag.*)
see the
Example :
$q = Doctrine_Query::create()
->select("a.answer_id,a.date_added , count(ag.content_id) AS agree_count")
->from('Answer a')
->leftJoin("a.Agree ag ON a.answer_id = ag.content_id AND ag.content_type = 'answer' ")
->where('a.question_id= ? ', $questionId)
But its only returning the first record, can i Fix that? or to make another table and make it only for counting ?
You are missing a GROUP BY in your query.
More infos here.
When you don't have a GROUP BY clause, it's normal to get only one row.
Count(*) will only return one record if you don't use Group By. You are asking it to count all the records, so there can be only one result.
The count() SQL function changes how results are returned from the database - without a GROUP BY the database will only return one record, regardless of other colums in the SELECT.
if you add:
group by a.answer_id
to the end of your SQL query, that might DWYM.
MySQL Server Version: Server version: 4.1.14
MySQL client version: 3.23.49
Tables under discussion: ads_list and ads_cate.
Table Relationship: ads_cate has many ads_list.
Keyed by: ads_cate.id = ads_list.Category.
I am not sure what is going on here, but I am trying to use COUNT() in a simple agreggate query, and I get blank output.
Here is a simple example, this returns expected results:
$queryCats = "SELECT id, cateName FROM ads_cate ORDER BY cateName";
But if I modify it to add the COUNT() and the other query data I get no array return w/ print_r() (no results)?
$queryCats = "SELECT ads_cate.cateName, ads_list.COUNT(ads_cate.id),
FROM ads_cate INNER JOIN ads_list
ON ads_cate.id = ads_list.category
GROUP BY cateName ORDER BY cateName";
Ultimately, I am trying to get a count of ad_list items in each category.
Is there a MySQL version conflict on what I am trying to do here?
NOTE: I spent some time breaking this down, item by item and the COUNT() seems to cause the array() to disappear. And the the JOIN seemed to do the same thing... It does not help I am developing this on a Yahoo server with no access to the php or mysql error settings.
I think your COUNT syntax is wrong. It should be:
COUNT(ads_cate.id)
or
COUNT(ads_list.id)
depending on what you are counting.
Count is an aggregate. means ever return result set at least one
here you be try count ads_list.id not null but that wrong. how say Myke Count(ads_cate.id) or Count(ads_list.id) is better approach
you have inner join ads_cate.id = ads_list.category so Count(ads_cate.id) or COUNT(ads_list.id) is not necessary just count(*)
now if you dont want null add having
only match
SELECT ads_cate.cateName, COUNT(*),
FROM ads_cate INNER JOIN ads_list
ON ads_cate.id = ads_list.category
GROUP BY cateName
having not count(*) is null
ORDER BY cateName
all
SELECT ads_cate.cateName, IFNULL(COUNT(*),0),
FROM ads_cate LEFT JOIN ads_list
ON ads_cate.id = ads_list.category
GROUP BY cateName
ORDER BY cateName
Did you try:
$queryCats = "SELECT ads_cate.cateName, COUNT(ads_cate.id)
FROM ads_cate
JOIN ads_list ON ads_cate.id = ads_list.category
GROUP BY ads_cate.cateName";
I am guessing that you need the category to be in the list, in that case the query here should work. Try it without the ORDER BY first.
You were probably getting errors. Check your server logs.
Also, see what happens when you try this:
SELECT COUNT(*), category
FROM ads_list
GROUP BY category
Your array is empty or disappear because your query has errors:
there should be no comma before the FROM
the "ads_list." prefix before COUNT is incorrect
Please try running that query directly in MySQL and you'll see the errors. Or try echoing the output using mysql_error().
Now, some other points related to your query:
there is no need to do ORDER BY because GROUP BY by default sorts on the grouped column
you are doing a count on the wrong column that will always give you 1
Perhaps you are trying to retrieve the count of ads_list per ads_cate? This might be your query then:
SELECT `ads_cate`.`cateName`, COUNT(`ads_list`.`category`) `cnt_ads_list`
FROM `ads_cate`
INNER JOIN `ads_list` ON `ads_cate`.`id` = `ads_list`.`category`
GROUP BY `cateName`;
Hope it helps?