Retrieving Values of Json Data Inside JSON Array in Mysql - mysql

Question

I have JSON column, containing the JSON array. My Scenario, is to get all the the records where value of url is
'"example.com/user1"' is present. I have trouble writing the query for this operation.
Record1
[
{
"id": "1",
"firstname": "user1",
"url": "example.com/user1"
},
{
"id": "2",
"firstname": "user2",
"url": "example.com/user2"
}
]
Record2
[
{
"id": "1",
"firstname": "user3",
"url": "example.com/user3"
},
{
"id": "2",
"firstname": "user2",
"url": "example.com/user2"
}
]
......
......
......
Record10
[
{
"id": "1",
"firstname": "user10",
"url": "example.com/user10"
},
{
"id": "2",
"firstname": "user1",
"url": "example.com/user1"
}
]
The Query Which I ran is:
Select internal_id from users_dummy where JSON_EXTRACT(user_friends, '$[0].url') = "example.com/user1" or JSON_EXTRACT(user_friends, '$[1].url') = "example.com/user1";
So o/p was:
Record1, Record10
Is this the proper way to search for the values across the records?
Thanks in advance.

Answer 1

You can use JSON_SEARCH like this:
SELECT *
FROM users_dummy
WHERE JSON_SEARCH(user_friends, 'one', 'example.com/user1', NULL, '$[*].url') IS NOT NULL
demo on dbfiddle.uk
You can use the following solution in case you are using objects instead of arrays:
SELECT *
FROM users_dummy
WHERE JSON_SEARCH(user_friends, 'one', 'example.com/user1', NULL, '$.*.url') IS NOT NULL
demo on dbfiddle.uk