Break lines in bash to HTML format - html

I'm having problems doing a break line between the IP addresses. They appear in 1 long horizontal line. I am able to do a break line on the first script, but it still appears in 1 line.
script #1 (showblock.sh)
command=$(pfctl -t bruteforce -T show)
my_array="${command[#]}"
for i in "${my_array[#]}"
do
:
# do whatever on $i
printf "%s\n" "${my_array[#]}"
done
script # 2 (showBlockOutput.sh)
#!/bin/sh
current_date=$(date)
output=$(showblock.sh)
OUT=oldBlocks/ipblock.html
cat << EOF > $OUT
<html>
<head>
<meta http-equiv="refresh" content="30">
</head>
<body>
<h1>Blocked IPs</h1>
$current_date <br>
$output
<br>
</body>
</html>
EOF

You're not setting $command or $my_array to arrays. You can wrap the variable in () to split it into an array.
my_array=(${command})
And if you want these to be separate lines when the HTML is rendered, you need to put <br> between the lines, not newline.
There's no need for the for loop, printf will automatically loop when given more inputs than format operators.
printf "%s<br>\n" "${my_array[#]}"
The entire showblock.sh script can just be a one-liner:
#!/bin/bash
printf "%s<br>\n" $(pfctl -t bruteforce -T show)

Related

transform multiline text into csv with awk sed and grep

I run a shell command that returns a list of repeated values like this (note the indentation):
Name: vm346
cpu 1 (12%) 6150m (76%)
memory 1130Mi (7%) 1130Mi (7%)
Name: vm847
cpu 6 (75%) 30150m (376%)
memory 12980Mi (87%) 12980Mi (87%)
Name: vm848
cpu 3500m (43%) 17150m (214%)
memory 6216Mi (41%) 6216Mi (41%)
I am trying to transform that data like this (in csv):
vm346,1,(12%),6150m,(76%),1130Mi,(7%),1130Mi,(7%)
vm847,6,(75%),30150m,(376%),12980Mi,(87%),12980Mi,(87%)
vm848,3500m,(43%),17150m,(214%),6216Mi,(41%),6216Mi,(41%)
The problem is that any given dataset like the one above is always on more than one line.
when I pipe that into it awk it drives me mad because even if I use:
BEGIN{ FS="\n" }
to try and stitch the data together in one line, it doesn't work. No matter what I do, awk keeps the name value as a separated line above everything else.
I am sorry I haven't much code to share but I have been spinning my wheels with this for a few hours now and I am running out of ideas...
I can solve this in Perl:
perl -ane 'print join ",", #F[1 .. $#F]; print $F[0] eq "memory" ? "\n" : ","'
It should be easy to translate it to awk if you need it.
How does it work?
-a splits each line on whitespace into the #F array
-n reads the input line by line and runs the code specified after -e for each line
We print all the elements but the first one separated by commas (see join)
We then look at the first column, if it's memory, we are at the last line of the block, so we print a newline, otherwise we print a comma
With AWK, one option is to set RS to "Name: ", and ignore the first record with NR > 1, e.g.
awk -v RS="Name: " 'BEGIN{OFS=","} NR > 1 {print $1, $3, $4, $5, $6, $8, $9, $10, $11}' file
#> vm346,1,(12%),6150m,(76%),1130Mi,(7%),1130Mi,(7%)
#> vm847,6,(75%),30150m,(376%),12980Mi,(87%),12980Mi,(87%)
#> vm848,3500m,(43%),17150m,(214%),6216Mi,(41%),6216Mi,(41%)
awk '{$1=""}1' | paste -sd' \n' - | awk '{$1=$1}1' OFS=,
Get rid of the first column. Join every three rows. Same idea with sed:
sed 's/^ *[^ ]* *//' | paste -sd' \n' - | sed 's/ */,/g'
Something else:
awk '
$1=="Name:" {
sep=ors
ors=ORS
} {
for (i=2;i<=NF;++i) {
printf "%s%s",sep,$i
sep=OFS
}
} END {printf "%s",ors}'
Or if you want to print an ORS based on the first field being "memory" (note that this program may end without printing a terminating ORS):
awk '{for (i=2;i<=NF;++i) printf "%s%s",$i,(i==NF && $1=="memory" ? ORS : OFS)}'
something else else:
awk -v OFS=, '
index($0,$1)==1 {
OFS=ors
ors=ORS
} {
$1=""
printf "%s",$0
OFS=ofs
} END {printf "%s",ors} BEGIN {ofs=OFS}'
This might work for you (GNU sed):
sed -nE '/^ +\S+ +/{s///;H;$!d};x;/./s/\s+/,/gp;x;s/^\S+ +//;h' file
In overview the sed program processes indented lines, already gathered lines (except in the case that the current line is the first line of the file) and non-indented lines.
Turn off implicit printing and enable extended regexp's. (-nE).
If the current line is indented, remove the indent, the first field and any following spaces, append the result to the hold space and if it is not the last line, delete it.
Otherwise, check the hold space for gathered lines and if found, replace one or more whitespaces by commas and print the result. Then prep the current line by removing the first field and any following spaces and replace the hold space with the result.
The solution seems logically back-to-front, but programming in this style avoids having to check for end-of-file multiple times and invoking labels and gotos.
N.B. This solution will work for any number of indented lines.
Here is a ruby to do that:
ruby -e '
s=$<.read
s.scan(/^([^ \t]+:)([\s\S]+?)(?=^\1|\z)/m). # parse blocks
map(&:last). # get data part
# parse and join the data fields:
map{|block| block.split(/\n[ \t]+[^ \t]+[ \t]+/)}.
map{|lines| lines.map(&:strip).join(" ").split().join(",")}.
each{|l| puts "#{l}"}
' file
vm346,1,(12%),6150m,(76%),1130Mi,(7%),1130Mi,(7%)
vm847,6,(75%),30150m,(376%),12980Mi,(87%),12980Mi,(87%)
vm848,3500m,(43%),17150m,(214%),6216Mi,(41%),6216Mi,(41%)
The advantage is that this is not dependent on the number of lines or the number of fields. It is parsing data that is in blocks of the form:
START: ([ \t]+[data_with_no_space])*\n
l1 ([ \t]+[data_with_no_space])*\n
...
START:
...
Works this way:
Parse the blocks with THIS REGEX;
Save an array of the data elements;
Join the sub arrays and then split into data fields;
Join(',') to make a csv.

Remove double quotes if delimiter value is not present in data

An input file is given, each line of which contains quotes for each column and carriage return/ new line character.
If the line contains new lines it has be appended with in the same
line which is inside the quotes i.e for example line 1
Removing of double quotes for each column if the delimiter(,) is
not present.
Removing of Carriage Return characters i.e(^M)
To exemplify, given the following input file
"name","address","age"^M
"ram","abcd,^M
def","10"^M
"abhi","xyz","25"^M
"ad","ram,John","35"^M
I would like to obtain the following output by means of a sed/perl/awk script/oneliner.
name,address,age
ram,"abcd,def",10
abhi,xyz,25
ad,"ram,John",35
Solutions which i have tired it so far
For appending with previous line
sed '/^[^"]*"[^"]*$/{N;s/\n//}' sample.txt
for replacing control-m characters
perl -pne 's/\\r//g' sample.txt
But i didn't achieve final output what i required below
Use a library to parse CSV files. Apart from always wanting to use a library for that here you also have very specific reasons, with embedded newlines and delimiters.
In Perl a good library is Text::CSV (which wraps Text::CSV_XS if installed). A basic example
use warnings;
use strict;
use feature 'say';
use Text::CSV;
my $file = shift or die "Usage: $0 file.csv\n";
my $csv = Text::CSV->new({ binary => 1, auto_diag => 1 });
open my $fh, '<', $file or die "Can't open $file: $!";
while (my $row = $csv->getline($fh)) {
s/\n+//g for #$row;
$csv->say(\*STDOUT, $row);
}
Comments
The binary option in the constructor is what handles newlines embedded in data
Once a line is read into the array reference $row I remove newlines in each field with a simplistic regex. By all means please improve this as/if needed
The pruning of $row works as follows. In a foreach loop each element is really aliased by the loop variable, so if that gets changed the array changes. I used default where elements are aliased by $_, which the regex changes so $row changes.
I like this compact shortcut because it has such a distinct look that I can tell from across the room that an array is being changed in place; so I consider it a sort-of-an-idiom. But if it is in fact confusing please by all means write out a full and proper loop
The processed output is printed to STDOUT. Or, open an output file and pass that filehandle to say (or to print in older module versions) so the output goes directly to that file
The above prints, for the sample input provided in the question
name,address,age
ram,"abcd,def",10
abhi,xyz,25
ad,"ram,John",35
This might work for you (GNU sed):
sed ':a;/[^"]$/{N;s/\n//;ba};s/"\([^",]*\)"/\1/g' file
The solution is in two parts:
Join broken lines to make whole ones.
Remove double quotes surrounding fields that do not contain commas.
If the current line does not end with double quotes, append the next line, remove the newline and repeat. Otherwise: remove double quotes surrounding fields that do not contain double quotes or commas.
N.B. Supposes that fields do not contain quoted double quotes. If that is the case, the condition for the first step would need to be amended and double quotes within fields would need to catered for.
FPAT is the way to go using gnu awk, it handles comma separated files.
remove ^m
clean lines
remove qutes
.
dos2unix sample.txt
awk '{printf "%s"(/,$/?"":"\n"),$0}' sample.txt > tmp && mv tmp sample.txt
"name","address","age"
"ram","abcd,def","10"
"abhi","xyz","25"
"ad","ram,John","35"
awk -v FPAT="([^,]+)|(\"[^\"]+\")" -v OFS=, '{for (i=1;i<=NF;i++) if($i!~",") $i=substr($i,2,length($i)-2)}1' sample.txt
name,address,age
ram,"abcd,def",10
abhi,xyz,25
ad,"ram,John",35
All in one go:
dos2unix sample.txt && awk '{printf "%s"(/,$/?"":"\n"),$0}' sample.txt | awk -v FPAT="([^,]+)|(\"[^\"]+\")" -v OFS=, '{for (i=1;i<=NF;i++) if($i!~",") $i=substr($i,2,length($i)-2)}1'
Normally you set Filed Separator FS or F to tell how filed are separated. FPAT="([^,]+)|(\"[^\"]+\")" FPAT tells how the filed looks like using a regex. This regex is complicated and often used with CSV.
(i=1;i<=NF;i++) loop through on by one field on the line.
if($i!~",") if it does not contain comma, then
$i=substr($i,2,length($i)-2) remove first and last character, the "
If a field for some reason do not contain ", this is more robust:
awk -v FPAT="([^,]+)|(\"[^\"]+\")" -v OFS=, '{for (i=1;i<=NF;i++) if($i!~",") {n=split($i,a,"\"");$i=(n>1?a[2]:$i)}}1' file
It will not do any thing to a field not contains double quote.
With perl, please try the following:
perl -e '
while (<>) {
s/\r$//; # remove trailing CR code
$str .= $_;
}
while ($str =~ /("(("")|[^"])*"\n?)|((^|(?<=,))[^,]*((?=,)|\n))/g) {
$_ = $&;
if (/,/) { # the element contains ","
s/\n//g; # then remove newline(s) if any
} else { # otherwise remove surrounding double quotes
s/^"//s; s/"$//s;
}
push(#ary, $_);
if (/\n$/) { # newline terminates the element
print join(",", #ary);
#ary = ();
}
}' sample.txt
Output:
name,address,age
ram,"abcd,def",10
abhi,xyz,25
ad,"ram,John",35

Pass variable from bash script to HTML

I have a bash script that contains a variable. In the same script, I have an HTML section that, for now, outputs "Hello".
I'd like the HTML section of the bash script to retrieve a variable, and display that in the same heading as the "Hello" section. Essentially, the output on the HTML page should be something like this "Hello Adam".
For now, as simple as it gets, my bash script code is as follows:
#!/bin/bash
firstname="Adam"
echo $firstname
cat << _EOF_
<!DOCTYPE html>
<html>
<body>
<h1>Hello</h1>
</body>
</html>
_EOF_
How do I get the variable in the HTML section so that it can display the $firstname variable?
For reference, I currently run the script using git-bash by executing sh {name-of-script} > test.html
You can use regular variable expansion in unquoted here documents:
# Hello Adam
firstname="Adam"
cat << EOF
Hello $firstname
EOF
If you want certain values to not be expanded, escape them:
# $firstname is Adam
cat << EOF
\$firstname is $firstname
EOF
If you don't want any values to be expanded, quote the delimiter:
# $firstname is not expanded in quoted heredocs
cat << "EOF"
$firstname is not expanded in quoted heredocs
EOF

Multiple Condition in grep regex

I want to use grep to search a file for all lines containing <div, except that I do not want lines between <!-- and -->.
I have this regex to find the lines containing <div: ^.*\<div.*$
I have this regex to exclude the lines between <!-- and -->: ^((?!\<!--.*?--\>).)*$ — but it doesn't work. It only matches when the comment is in a single line. How can I fix that?
How can I combine these in one grep line? Or do I have to type two greps?
grep does not support multiline searches like your search for <!-- ... -->. This can be worked around by using various helper commands, but in your case it's not worth it. It's better to just use a more powerful language, such as sed or AWK or Perl:
perl -ne '$on = 1 if m/<!--/; $on = "" if m/-->/; print if !$on and m/<div/' FILE
Edited to add: If you also want to discount instances of <!-- ... <div ... --> on a single line, you can write:
perl -ne ' my $line = $_;
if ($in_comment && s/.*?-->//) {
$in_comment = "";
}
while (!$in_comment && s/<!--.*?(-->)?/) {
$in_comment = 1 if $1;
}
print $line if !$in_comment && m/<div/
' FILE

Editing multiple HTML files using SED (or something similar)

I have about 1000 HTML files to edit which represent footnotes in a large technical document. I have been asked to go through the HTML files one by one and manually edit the HTML, to get it all on the straight and narrow.
I know that this could probably be done in a matter of seconds with SED as the changes to each file are similar. The body text in each file can be different but I want to change the tags to match the following:
<body>
<p class="Notes">See <i>R v Swain</i> (1992) 8 CRNZ 657 (HC).</p>
</body>
The text may change, for example, it could say 'See R v Pinky and the Brain (1992) or something like that but basically the body text should be that.
Currently, however, the body text may be:
<body>
<p class="Notes"><span class="FootnoteReference"><span lang="EN-GB" xml:lang="EN-GB"><span><span
class="FootnoteReference"><span lang="EN-GB" xml:lang="EN-GB" style="font-size: 10.0pt;">See <i>R v Pinky and the Brain</i> (1992) </span></span></span></span></span></p>
</body>
or even:
<body>
<p class="FootnoteText"><span class="FootnoteReference"><span lang="EN-US"
xml:lang="EN-US" style="font-size: 10.0pt;"><span><![endif]></span></span></span>See <i>R v Pinky and the Brain</i> (1992)</p>
</body>
Can anybody suggest a SED expression or something similar that would solve this?
Like this?:
perl -pe 's/Swain/Pinky and the Brain/g;' -i lots.html of.html files.html
The breakdown:
-e = "Use code on the command line"
-p = "Execute the code on every line of every file, and print out the line, including what changed"
-i = "Actually replace the files with the new content"
If you swap out -i with -i.old then lots.html.old and of.html.old (etc) will contain the files before the changes, in case you need to go back.
This will replace just Swain with Pinky and the Brain in all the files. Further changes would require more runs of the command. Or:
s/Swain/Pinky/g; s/Twain/Brain/g;
To swap Swain with Pinky and Twain with Brain everywhere.
Update:
If you can be sure about the incoming formatting of the data, then something like this may suffice:
# cat ff.html
<body>
<p class="Notes"><span class="FootnoteReference"><span lang="EN-GB" xml:lang="EN-GB"><span><span
class="FootnoteReference"><span lang="EN-GB" xml:lang="EN-GB" style="font-size: 10.0pt;">See <i>R v Twain</i> (1992) </span></span></span></span></span></p>
<p class="Notes"><span class="FootnoteReference"><span lang="EN-GB" xml:lang="EN-GB"><span><span
class="FootnoteReference"><span lang="EN-GB" xml:lang="EN-GB" style="font-size: 10.0pt;">See <i>R v Swain</i> (1992) </span></span></span></span></span></p>
</body>
# perl -pe 'BEGIN{undef $/;} s/<[pP][ >].*?See <i>(.*?)<\/i>(.*?)<.*?\/[pP]>/<p class="Notes">See <i>$1<\/i>$2<\/p>/gsm;' ff.html
<body>
<p class="Notes">See <i>R v Twain</i> (1992) </p>
<p class="Notes">See <i>R v Swain</i> (1992) </p>
</body>
Explanations:
BEGIN{undef $/;} = treat the whole document as one string, or else html that has newlines in it won't get handled properly
<[pP[ >] = the beginning of a p-tag (case insensitive)
.*? = lots of stuff, non-greedy-matched i.e. http://en.wikipedia.org/wiki/Regular_expression#Lazy_quantification
See <i> = literally look for that string - very important, since that seems to be the only common denominator
(.*?) = put more stuff into a parentheses group (to be used later)
<\/i> = the end i-tag
(.*?) = put more stuff into a parentheses group (to be used later)
<.*?\/[pP] = the end p-tag and other possible tags mashed up before it (like all your spans)
and replace it with the string you want, where $1 and $2 are what got snagged in the parentheses before, i.e. the two (.*?) 's
g = global search - so possibly more than one per line
s = treat everything like one line (which it is now due to the BEGIN at the top)
First convert your HTML files to proper XHTML using http://tidy.sourceforge.net and then use xmlstarlet to do the necessary XHTML processing.
Note: Get the current version of xmlstarlet for in-place XML file editing.
Here's a simple, yet complete mini-example:
curl -s http://checkip.dyndns.org > dyndns.html
tidy -wrap 0 -numeric -asxml -utf8 2>/dev/null < dyndns.html > dyndns.xml
# test: print body text to stdout (dyndns.xml)
xml sel -T \
-N XMLNS="http://www.w3.org/1999/xhtml" \
-t -m "//XMLNS:body" -v '.' -n \
dyndns.xml
# edit body text in-place (dyndns.xml)
xml ed -L \
-N XMLNS="http://www.w3.org/1999/xhtml" \
-u "//XMLNS:body" -v '<p NEW BODY TEXT </p>' \
dyndns.xml
# create new HTML file (by overwriting the original one!)
xml unesc < dyndns.xml > dyndns.html
To consolidate the span tags you may use tidy (version released on 25 March 2009) as well!
# get current tidy version: http://tidy.cvs.sourceforge.net/viewvc/tidy/tidy/
# see also: http://tidy.sourceforge.net/docs/quickref.html#merge-spans
tidy -q -c --merge-spans yes file.html
You will have to check your input files to verify some assumptions can be made. Based on your two examples, I have made the following assumptions. You will need to check them and take some sample input files to verify you have found all assumptions.
The file consists of a single footnote contained in a single <body></body> pair. The body tags are always present and well formed.
The footnote is buried somewhere inside a <p></p> pair and one or many <span></span> tags. <!...> tags can be discarded.
The following Perl script works for both examples you have supplied (on Linux with Perl 5.10.0). Before using it, make sure you have a backup of your original html files. By default, it will only print the result on stdout without changing any file.
#!/usr/bin/perl
$overwrite = 0;
# get rid of default line separator to facilitate slurping in a $scalar var
$/ = '';
foreach $filename (#ARGV)
{
# slurp entire file in $text variable
open FH, "<$filename";
$full_text = <FH>;
close FH;
if ($overwrite)
{
! -f "$filename.bak" && rename $filename, "$filename.bak";
}
# match everything that is found before the body tag, everything
# between and including the body tags, and what follows
# s modifier causes full_text to be considered a single long string
# instead of individual lines
($before_body, $body, $after_body) = ($full_text =~ m!(.*)<body>(.*)</body>(.*)!s);
#print $before_body, $body, $after_body;
# Discard unwanted tags from the body
$body =~ s%<span.*?>%%sg;
$body =~ s%</span.*?>%%sg;
$body =~ s%<p.*?>%%sg;
$body =~ s%</p.*?>%%sg;
$body =~ s%<!.*?>%%sg;
# Remaining leading and trailing whitespace likely to be newlines: remove
$body =~ s%^\s*%%sg;
$body =~ s%\s*$%%sg;
if ($overwrite)
{
open FH, ">$filename";
print FH $before_body, "<body>\n<p class=\"Notes\">$body</p>\n</body>", $after_body;
close FH;
}
else
{
print $before_body, "<body>\n<p class=\"Notes\">$body</p>\n</body>", $after_body;
}
}
To use it:
./script.pl file1.html
./script.pl file1.html file2.html
./script.pl *.html
Tweak it and when you're happy set $overwrite=1. The script creates a .bak only if it does not already exist.
If you have 1 entry per file, no rigid structure in these files, and possibly multiple lines, I would go for a php or perl script to process them file by file, while emitting suitable warnings when the patterns don't match.
use
php -f thescript.php
to execute thescript.php, which contains
<?php
$path = "datapath/";
$dir = opendir($path);
while ( ( $fn = readdir($dir) ) !== false )
{
if ( preg_match("/html$/",$fn) ) process($path.$fn);
}
function process($file)
{
$in = file_get_contents($file);
$in2 = str_replace("\n"," ",strip_tags($in,"<i>"));
if ( preg_match("#^(.*)<i>(.*)</i>(.*)$#i",$in2,$match) )
{
list($dummy,$p0,$p1,$p2) = $match;
$out = "<body>$p0<i>$p1</i>$p2</body>";
file_put_contents($file.".out",$out);
} else {
print "Problem with $file? (stripped down to: $in2)\n";
file_put_contents($file.".problematic",$in);
}
}
?>
you could tweak this to your needs until the number of misses is low enough to do the last few by hand. You probably need to add some $p0 = trim($p0); etc to sanitize everything.